Current and Resistance PHY2054: Chapter 17 1 What You Will Learn in This Chapter ÎNature ÎDrift of electric current speed and current ÎCurrent and voltage measurements ÎConductivity ÎOhm’s and resistivity law ÎTemperature variations of resistance ÎSuperconductors ÎPower in electric circuits ÎElectrical activity in the heart PHY2054: Chapter 17 2 Current ÎThe electric current is defined as (a) Amount of charge per time (b) Amount of charge per volume (c) Amount of charge per area (d) Amount of charge (e) None of these PHY2054: Chapter 17 I= Δq Δt 3 EMF ÎEMF device performs work on charge carriers Converts energy to electrical energy Moves carriers from low potential to high potential Maintains potential difference across terminals ÎVarious types of EMF devices Battery Generator Fuel cell Solar cell Thermopile ÎExample: Electrolytic reaction Magnetic field Oxidation of fuel Electromagnetic energy Nuclear decay battery Two electrodes (different metals) Immersed in electrolyte (dilute acid) One electrode develops + charge, the other – charge PHY2054: Chapter 17 4 Common dry cell battery PHY2054: Chapter 17 5 Electric Current ÎConnecting the terminals of a battery across device leads to an electric circuit Charge begins to flow: electric current Units: 1 Coulomb/s = 1 Ampere (A) ÎSymbol: + - or Δq I= Δt + V - PHY2054: Chapter 17 6 Direction of the current ÎIn conductors, electrons are free and carry the charge ÎBut direction of current is defined as flowing from the positive to the negative terminal +++ PHY2054: Chapter 17 --- 7 Example of Electron Flow ÎConsider a current of 1A. Find the number of electrons flowing past a point per second Δq = 1 A ⇒ 1 coulomb / sec Δt ÎSo, in one second, number of electrons passing a point is Ne = 1 coulomb 1.6 ×10−19 = 6.2 × 1018 electrons PHY2054: Chapter 17 8 Current and Electron Drift Speed ÎConsider a material where current (electrons) is flowing Let ne = # free charge carriers / m3 Let q = charge per charge carrier Let A = cross sectional area of material ÎTotal - - - - I charge ΔQ in volume element moving past a point ΔQ = ( ne AΔx ) q ÎIf charges move with average drift speed vd, Δx = vd Δt ΔQ = ( ne Avd Δt ) q ÎThus, current can be written in terms of basic quantities i= ΔQ = ne qAvd Δt PHY2054: Chapter 17 9 Example of Drift Speed Î10A flowing through a copper wire of diameter 2mm Density of Cu = 8.92 g/cm3 = 8920 kg/m3 1 free electron per Cu atom Atomic mass ACu = 63.5 ÎFind e drift speed vd using i = ne eAvd is charge Find A: Obtain ne = ρCu mCu e = 1.6 ×10−19 ( A = π r = 3.14 × 10 2 −3 ) 2 = 3.14 × 10−6 m 2 ne = #electrons/m3 = #Cu atoms/m3 from Cu density ×1 = 8920 63.5 × 10−3 / 6.02 ×1023 = 8.46 × 1028 /m3 PHY2054: Chapter 17 10 Example of Drift Speed (cont.) ÎSolve for electron drift speed vd i 10 = = 2.4 × 10−4 m/s vd = ne eA 8.46 × 1028 1.6 × 10−19 3.14 × 10−6 ( ÎThus ÎThis )( ) vd is 0.24 mm/sec: ~1 hour to move 1 m ÎCalculate vavg )( thermal speed vavg 1 m v2 2 e avg = 32 k BT T ≅ 300K 3k BT 3 ×1.38 × 10−23 × 300 5 1.17 10 m/s = = = × − 31 me 9.11×10 is ~ 5 × 108 times larger than drift speed! PHY2054: Chapter 17 11