CHAPTER 12 Circles OBJECTIVES Write an equation for a circle. Graph a circle, and identify its center and radius. CIRCLE A circle is the set of points in a plane that are a fixed distance, called the radius, from a fixed point, called the center. Because all of the points on a circle are the same distance from the center of the circle, you can use the Distance Formula to find the equation of a circle. FORMULA CIRCLE TO WRITE THE EQUATION OF A Write the equation of a circle with center (–3, 4) and radius r = 6. Solution: Use the Distance Formula with (x2, y2) = (x, y), (x1, y1) = (–3, 4), and distance equal to the radius, 6. EXAMPLE Write the equation of a circle with center (4, 2) and radius r = 7. Solution: CIRCLE Notice that r2 and the center are visible in the equation of a circle. This leads to a general formula for a circle with center (h, k) and radius r. EXAMPLE 2A: WRITING OF A CIRCLE THE EQUATION Write the equation of the circle. the circle with center (0, 6) and radius r = 1 Solution: (x – h)2 + (y – k)2 = r2 (x – 0)2 + (y – 6)2 = 12 x2 + (y – 6)2 = 1 EXAMPLE 2B: WRITING OF A CIRCLE THE EQUATION Write the equation of the circle. the circle with center (–4, 11) and containing the point (5, –1) Solution Step 1:Use the distance formula Step 2: Use the equation of the circle 2 2 2 (x + 4) + (y – 11) = 15 2 2 (x + 4) + (y – 11) = 225 CIRCLES The location of points in relation to a circle can be described by inequalities. The points inside the circle satisfy the inequality (x – h)2 + (x – k)2 < r2. The points outside the circle satisfy the inequality (x – h)2 + (x – k)2 > r2. EXAMPLE 3: CONSUMER APPLICATION Use the map and information given in Example 3 on page 730. Which homes are within 4 miles of a restaurant located at (– 1, 1)? TANGENT A tangent is a line in the same plane as the circle that intersects the circle at exactly one point. Recall from geometry that a tangent to a circle is perpendicular to the radius at the point of tangency. EXAMPLE Write the equation of the line tangent to the circle x2 + y2 = 29 at the point (2, 5). Solution: Step 1 Identify the center and radius of the circle. From the equation x2 + y2 = 29, the circle has center of (0, 0) and radius r = . Step 2 Find the slope of the radius at the point of tangency and the slope of the tangent. SOLUTION Step 3 Find the slope-intercept equation of the tangent by using the point (2, 5) and the slope m = 5/2 . SOLUTION The equation of the line that is tangent to 2 y = 29 at (2, 5) is x2 + EXAMPLE Write the equation of the line that is 2 2 tangent to the circle 25 = (x – 1) + (y + 2) , at the point (1, –2). STUDENT GUIDED PRACTICE Do even problems 2-10 in your book page 826 HOMEWORK Do 12-20 in your book page 826 VIDEOS Let’s Watch some videos CLOSURE Today we learned about circles Next class we are going to learn about ellipses