Engineering Economics
Contemporary Engineering Economics, 5th edition, © 2010
1 . If payments occur more frequently than annual , how do you calculate economic equivalence?
2. If interest period is other than annual, how do you calculate economic equivalence?
3. How are commercial loans structured?
4. How would you manage your debt ?
Contemporary Engineering Economics, 5th edition, © 2010
Nominal Interest
Rate:
Interest rate quoted based on an annual period
Effective Interest
Rate:
Actual interest earned or paid in a year or some other time period
Contemporary Engineering Economics, 5th edition, © 2010
Nominal interest rate
Annual percentage rate (APR)
Interest period
Contemporary Engineering Economics, 5th edition, © 2010
18%
What It Really Means?
Interest rate per month (i)
= 18%/12 = 1.5%
Number of interest periods per year (N) = 12
In words,
Bank will charge 1.5% interest each month on your unpaid balance, if you borrowed money.
You will earn 1.5% interest each month on your remaining balance, if you deposited money.
Question: Suppose that you invest $1 for 1 year at
18% compounded monthly. How much interest would you earn?
F
I
$1(1
i ) 12 12
$1.1956
$1.1956 $1.00
$0.1956
Contemporary Engineering Economics, 5th edition, © 2010
Formula: i a
r
M
) M
1
r = nominal interest rate per year i a
= effective annual interest rate
M = number of interest periods per year
Example :
18% compounded monthly i a
1
0.18
12
12
What It really Means
1.5% per month for 12 months or
19.56% compounded once per year
Contemporary Engineering Economics, 5th edition, © 2010
Practice
Problem
Suppose your savings account pays 9% interest compounded quarterly .
(a)
(b)
(c)
Interest rate per quarter
Annual effective interest rate (i a
)
If you deposit
$10,000 for one year, how much would you have?
Solution:
(a) Interest rate per quarter: i
9%
4
2.25%
(b) Annual effective interest rate: i a
4
(c) Balance at the end of one year (after 4 quarters)
F
F P 25%,4)
Contemporary Engineering Economics, 5th edition, © 2010
Nominal
Rate
4%
5
6
7
8
9
10
11
12
Compounding
Annually
4.00%
5.00
6.00
7.00
8.00
9.00
10.00
11.00
12.00
Effective Rates
Compounding
Semi-annually
Compounding
Quarterly
4.04% 4.06%
5.06
6.09
7.12
8.16
9.20
5.09
6.14
7.19
8.24
9.31
10.25
11.30
12.36
10.38
11.46
12.55
Compounding
Monthly
4.07%
5.12
6.17
7.23
8.30
9.38
10.47
11.57
12.68
Compounding
Daily
4.08%
5.13
6.18
7.25
8.33
9.42
10.52
11.62
12.74
Contemporary Engineering Economics, 5th edition, © 2010
Whenever payment and compounding periods differ from each other, one or the other must be transformed so that both conform to the same unit of time.
Payment period
Interest period
Payment period
Interest period
Contemporary Engineering Economics, 5th edition, © 2010
Effective Interest
Rate per Payment
Period (i)
Formula: i
1
r
CK
C
1
C = number of interest periods per payment period
K = number of payment periods per year
CK = total number of interest periods per year, or M
r/K = nominal interest rate per payment period
Functional Relationships among r, i, and i a
, where interest is calculated based on 9% compounded monthly and payments occur quarterly
Contemporary Engineering Economics, 5th edition, © 2010
Effective Interest Rate per
Payment Period with
Continuous Compounding
Formula: With continuous compounding C
i
C lim 1
e
1 r
CK
C
1
Example : 12% compounded continuously
(a) effective interest rate per quarter
0.12/4
1
3.045% per quarter
(b) effective annual interest rate i a
e 0.12/1
1
12.75% per year
Contemporary Engineering Economics, 5th edition, © 2010
:
Payment Period = Quarter
Interest Period = Quarterly
1 st Q
2 nd Q 3 rd Q 5th Q
1 interest period
Given r = 8%,
K = 4 payments per year
C = 1 interest period per quarter
M = 4 interest periods per year i
r CK ] C
1
1
1
2.000% per quarter
Contemporary Engineering Economics, 5th edition, © 2010
:
Payment Period = Quarter
Interest Period = Monthly
1 st Q
2 nd Q 3 rd Q 5th Q
3 interest periods Given r = 8%,
K = 4 payments per year
C = 3 interest periods per quarter
M = 12 interest periods per year i
r CK ] C
1
3
1
2.013% per quarter
Contemporary Engineering Economics, 5th edition, © 2010
:
Payment Period = Quarter
Interest Period = Weekly
1 st Q
2 nd Q 3 rd Q 5th Q
13 interest periods Given r = 8%,
K = 4 payments per year
C = 13 interest periods per quarter
M = 52 interest periods per year i
[ 1
r CK ]
C
1
[ 1
.
/ ( )( )]
13
1
2 0186% per quarter
Contemporary Engineering Economics, 5th edition, © 2010
:
Payment Period = Quarter
Interest Period = Continuously
1 st Q
2 nd Q 3 rd Q 5th Q
interest periods Given r = 8%,
K = 4 payments per year i
e
1
e 0.02
1
2.0201% per quarter
Contemporary Engineering Economics, 5th edition, © 2010
Summary: Effective Interest Rates per Quarter at
Varying Compounding Frequencies
Case 0 Case 1 Case 2 Case 3
8% compounded quarterly
Payments occur quarterly
8% compounded monthly
Payments occur quarterly
8% compounded weekly
Payments occur quarterly
8% compounded continuously
Payments occur quarterly
2.000% per quarter
2.013% per quarter
2.0186% per quarter
2.0201% per quarter
Contemporary Engineering Economics, 5th edition, © 2010
Step 1 : Identify the payment period (e.g., annual, quarter, month, week, etc)
Step 2 : Identify the interest period (e.g., annually, quarterly, monthly, etc)
Step 3 : Find the effective interest rate that covers the payment period.
Contemporary Engineering Economics, 5th edition, © 2010
Case I: When Payment Period is Equal to
Compounding Period
Step 1: Identify the number of compounding periods (M) per year
Step 2: Compute the effective interest rate per payment period (i)
Step 3: Determine the total number of payment periods (N)
Contemporary Engineering Economics, 5th edition, © 2010
Example 4.4:
Calculating Auto
Loan Payments
Given :
MSRP = $20,870
Discounts & Rebates =
$2,443
Net sale price = $18,427
Down payment = $3,427
Dealer’s interest rate =
6.25% APR
Length of financing = 72 months
Find : the monthly payment
(A)
Solution :
Cont emporary Engineering Economics, 5th edition, © 2010
Suppose you drink a cup of coffee ($3.00 a cup) on the way to work every morning for 30 years. If you put the money in the bank for the same period, how much would you have, assuming your accounts earns a 5% interest compounded daily.
NOTE: Assume you drink a cup of coffee every day including weekends.
Solution:
Payment period = daily
Compounding period = daily
N i
5%
0.0137% per day
365
30 365 10,950 days
F
$76,246
Contemporary Engineering Economics, 5th edition, © 2010
Case II: When Payment Periods Differ from
Compounding Periods
Step 1: Identify the following parameters.
M = No. of compounding periods
K = No. of payment periods per year
C = No. of interest periods per payment period
Step 2: Compute the effective interest rate per payment period.
For discrete compounding i
r CK ] C
1
For continuous compounding i e
1
Step 3: Find the total no. of payment periods.
N = K (no. of years)
Step 4: Use i and N in the appropriate equivalence formula.
Contemporary Engineering Economics, 5th edition, © 2010
Example 4.5 Compounding
Occurs More Frequently than
Payments are Made (Discrete
Case)
Given : A = $1,500 per quarter, r
= 6% per year, M = 12 compounding periods per year, and N = 2 years
Solution:
Find : F
Step 1:
M = 12 compounding periods/year
K = 4 payment periods/year
C = 3 interest periods per quarter
Step 2: i
1
0.06
12
3
1
1.5075% per quarter
F = $1,500 (F/A, 1.5075%, 8)
= $14,216.24
Step 3: N = 4(2) = 8
Contemporary Engineering Economics, 5th edition, © 2010
Example 4.6
Compounding is Less
Frequent than
Payments
Given : A = $500 per month, r =
10% per year, M = 4 quarterly compounding periods per year, and
N = 10 years
Find : F
Step 1:
M = 4 compounding periods/year
K = 12 payment periods/year
C = 1/3 interest period per quarter
Step 2: i
1
0.10
4
1/3
1
0.826%
Step 3: N = 4(2) = 8
Solution:
F = $500 (F/A, 0.826%, 120)
= $101,907.89
Contemporary Engineering Economics, 5th edition, © 2010
A Decision Flow Chart on How to Compute the
Effective Interest Rate per Payment Period
Contemporary Engineering Economics, 5th edition, © 2010
Financial institutions often quote interest rate based on an APR .
In all financial analysis, we need to convert the APR into an appropriate effective interest rate based on a payment period.
When payment period and interest period differ, calculate an effective interest rate that covers the payment period. Then use the appropriate interest formulas to determine the equivalent values
Contemporary Engineering Economics, 5th edition, © 2010