Ex. 26.2 A concave mirror has a 30 cm radius of curvature. If an object is placed 10 cm from the mirror, where will the image be found? f = R/2 = 15 cm, p = 10 cm Case 5: p < f 1/p + 1/q = 1/f 1/10 + 1/q = 1/15 3/30 + 1/q = 2/30 1/q = -1/30 q = -30 cm Real or Virtual M = -q/p = 3 q < 0 Magnified or Reduced Up-right or Upside-down Q. An upright image that is one-half as large as an object is needed to be formed on a screen in a laboratory experiment using only a concave mirror with 1 m radius of curvature. If you can make this image, I will give you $10. If you can’t you should pay me $10. Deal or no deal? Why? 1/p + 1/q = 1/f = 2/R > 0 M = -q/p = ½ > 0 should be a real image: q > 0 M = -q/p cannot be positive, if q > 0. No deal!!! Refraction and Lenses Optical illusion: the pencil is not bent at the air-water boundary. caused by non-trivial passage of light rays. Refraction Details, 1 Light may refract into a material where its speed is lower The angle of refraction is less than the angle of incidence • The ray bends toward the normal Refraction Details, 2 Light may refract into a material where its speed is higher The angle of refraction is greater than the angle of incidence • The ray bends away from the normal The Index of Refraction When light passes from one medium to another, it is refracted because the speed of light is different in the two media The index of refraction, n, of a medium can be defined speed of light in a vacuum c n speed of light in a medium v Index of Refraction, cont For a vacuum, n = 1 For other media, n > 1 n is a unitless ratio Frequency Between Media As light travels from one medium to another, its frequency does not change • Both the wave speed and the wavelength do change • The wavefronts do not pile up, nor are created or destroyed at the boundary, so ƒ must stay the same Index of Refraction Extended The frequency stays the same as the wave travels from one medium to the other v=ƒλ The ratio of the indices of refraction of the two media can be expressed as various ratios c 1 v 1 n1 n2 2 v 2 c n1 n2 Snell’s Law All three beams (incident, reflected, and refracted) are in one plane. sin q1 v1 sin q 2 v2 q1 q1 n = c/v :index of refraction v: speed of light in a medium n > 1 v1 = c/n1, v2 = c/n2 n1sinq1 = n2sinq2 q2 Index of Refraction material n = c/v for = 589 nm vacuum 1.00 air 1.00029 water 1.33 ice 1.31 typical glass 1.52 polycarbonate 1.59 diamond 2.42 n depends on . Dispersion q1 q1 q2 water q1> q2 Total Internal Reflection Total internal reflection can occur when light attempts to move from a medium with a high index of refraction to one with a lower index of refraction • Ray 5 shows internal reflection Critical Angle A particular angle of incidence will result in an angle of refraction of 90° • This angle of incidence is called the critical angle n2 sin q for n1 n2 n1 Critical Angle, cont For angles of incidence greater than the critical angle, the beam is entirely reflected at the boundary • This ray obeys the Law of Reflection at the boundary Total internal reflection occurs only when light attempts to move from a medium of higher index of refraction to a medium of lower index of refraction Total internal reflection q2 n2 n1 (> n2) q1 n1sin(q1) = n2sin(q2) Total internal reflection when q2 = 90 sin(qc) = n2/n1 < 1 qc: critical angle How could fish survive from spear fishing? Fish vision qf = 2qc qc = sin-1(1/1.33) = 49 ncore >nclad Q. What is the critical angle for a glass to air surface if the Index of refraction for glass is 1.5. sinqc = na/ng = 1.0/1.5 = 0.667 qc = 42 q1() 10 20 30 40 50 60 70 80 q2() 7.5 14.9 22.0 28.8 35.0 40.5 44.8 47.6 sinq1/sinq2 1.33 1.33 1.33 1.33 1.33 1.33 1.33 1.33 sin q1 v1 const sin q 2 v2 v1 = c/n1, v2 = c/n2 n1sinq1 = n2sinq2 q1 q1 air water q2 A fish swims below the surface of the water. Suppose an observer is looking at the fish straight above the fish. The observer sees 1. 2. 3. 4. the fish at a greater depth than it really is. the fish at the same depth. the fish at a smaller depth than it really is. no fish due to total internal reflection. Q. There are three layers of different media as shown in the figure. A beam of light bends as shown in the figure when it passes through the media. What can we say about the materials? nIsinqI = nIIsinqII qII > qI nI > nII I nIIsinqII = nIIIsinqIII qIII > qII nII > nIII II III nI > nII > nIII Dispersion of Index of Refraction for Glass wavelength (nm) 361 (near UV) 434 (dark blue) 486 (green) 589 (yellow) 656 (red) 768 (dark red) 1200 (IR) 2000 (far IR) n 1.539 1.528 1.523 1.517 1.514 1.511 1.505 1.497 In glass n (red) ≈ 1.51 n (purple) ≈ 1.53 http://science.howstuffworks.com/