5-8 Applying Special Right Triangles Objectives Justify and apply properties of 45°-45°-90° triangles. Justify and apply properties of 30°- 60°- 90° triangles. Holt Geometry 5-8 Applying Special Right Triangles A diagonal of a square divides it into two congruent isosceles right triangles. Since the base angles of an isosceles triangle are congruent, the measure of each acute angle is 45°. So another name for an isosceles right triangle is a 45°-45°-90° triangle. Holt Geometry 5-8 Applying Special Right Triangles Holt Geometry 5-8 Applying Special Right Triangles Example 1A: Finding Side Lengths in a 45°- 45º- 90º Triangle Find the value of x. Give your answer in simplest radical form. By the Triangle Sum Theorem, the measure of the third angle in the triangle is 45°. So it is a 45°-45°90° triangle with a leg length of 8. Holt Geometry 5-8 Applying Special Right Triangles Example 1B: Finding Side Lengths in a 45º- 45º- 90º Triangle Find the value of x. Give your answer in simplest radical form. The triangle is an isosceles right triangle, which is a 45°-45°-90° triangle. The length of the hypotenuse is 5. Rationalize the denominator. Holt Geometry 5-8 Applying Special Right Triangles Example 1c Find the value of x. Give your answer in simplest radical form. By the Triangle Sum Theorem, the measure of the third angle in the triangle is 45°. So it is a 45°-45°90° triangle with a leg length of x = 20 Holt Geometry Simplify. 5-8 Applying Special Right Triangles Example 1d Find the value of x. Give your answer in simplest radical form. The triangle is an isosceles right triangle, which is a 45°-45°-90° triangle. The length of the hypotenuse is 16. Rationalize the denominator. Holt Geometry 5-8 Applying Special Right Triangles A 30°-60°-90° triangle is another special right triangle. You can use an equilateral triangle to find a relationship between its side lengths. Holt Geometry 5-8 Applying Special Right Triangles Example 2A: Finding Side Lengths in a 30º-60º-90º Triangle Find the values of x and y. Give your answers in simplest radical form. 22 = 2x Hypotenuse = 2(shorter leg) 11 = x Divide both sides by 2. Substitute 11 for x. Holt Geometry 5-8 Applying Special Right Triangles Example 2B: Finding Side Lengths in a 30º-60º-90º Triangle Find the values of x and y. Give your answers in simplest radical form. Rationalize the denominator. y = 2x Hypotenuse = 2(shorter leg). Simplify. Holt Geometry 5-8 Applying Special Right Triangles Example 2c Find the values of x and y. Give your answers in simplest radical form. Hypotenuse = 2(shorter leg) Divide both sides by 2. y = 27 Holt Geometry Substitute for x. 5-8 Applying Special Right Triangles Check It Out! Example 2d Find the values of x and y. Give your answers in simplest radical form. y = 2(5) y = 10 Holt Geometry Simplify. 5-8 Applying Special Right Triangles Lesson Quiz: Part I Find the values of the variables. Give your answers in simplest radical form. 1. 2. x = 10; y = 20 3. Holt Geometry 4. 5-8 Applying Special Right Triangles Lesson Quiz: Part II Find the perimeter and area of each figure. Give your answers in simplest radical form. 5. a square with diagonal length 20 cm 6. an equilateral triangle with height 24 in. Holt Geometry