Chapter 1 Measuring Temperature LecturePLUS Timberlake 1 Temperature Particles are always moving. When you heat water, the water molecules move faster. When molecules move faster, the substance gets hotter. When a substance gets hotter, its temperature goes up. LecturePLUS Timberlake 2 Learning Check Suppose you place water in a freezer. A. The water particles move 1) faster 2) slower 3) the same B. The water will get 1) hotter 2) colder 3) stay the same C. The temperature of the water will be 1) higher 2) lower LecturePLUS Timberlake 3) the same 3 Solution Suppose you place water in a freezer. A. The water particles move 2) slower B. The water will get 2) colder C. The temperature of the water will be 2) lower LecturePLUS Timberlake 4 Temperature Measures the hotness or coldness of an object Determined by using a thermometer that contains a liquid that expands with heat and contracts with cooling. LecturePLUS Timberlake 5 Temperature Scales Fahrenheit Celsius Water boils Kelvin _____°F _____°C ______K Water freezes _____°F _____°C ______K LecturePLUS Timberlake 6 Temperature Scales Fahrenheit Celsius Kelvin Water boils 212°F 100°C 373 K Water freezes 32°F 0°C 273 K LecturePLUS Timberlake 7 Units of Temperature between Boiling and Freezing Fahrenheit Celsius Water boils 212°F 180° Water freezes 32°F 100°C 100°C 0°C LecturePLUS Timberlake Kelvin 373 K 100K 273 K 8 Learning Check A. Temperature of freezing water 1) 0°F 2) 0°C 3) 0 K B. Temperature of boiling water 1) 100°F 2) 32°F 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 100 2) 180 3) 273 LecturePLUS Timberlake 9 Solution A. Temperature of freezing water 2) 0°C B. Temperature of boiling water 3) 373K C. Number of Celsius units between the boiling and freezing points of water 1) 100 LecturePLUS Timberlake 10 Fahrenheit Formula 180°F 5°C = Zero point: 9°F = 1°C 1.8°F 100°C 0°C = 32°F °F = 9/5 T°C + 32 °F = 1.8 T°C + 32 or LecturePLUS Timberlake 11 Celsius Formula Rearrange to find T°C °F = 1.8 T°C + 32 °F - 32 = 1.8T°C ( +32 - 32) °F - 32 = 1.8 T°C 1.8 °F - 32 1.8 = T°C 1.8 LecturePLUS Timberlake 12 Temperature Conversions A person with hypothermia has a body temperature of 29.1°C. What is the body temperature in °F? °F = 1.8 (29.1°C) + 32 exact tenth's = 52.4 + 32 = 84.4°F exact tenth’s LecturePLUS Timberlake 13 Learning Check The normal temperature of a chickadee is 105.8°F. What is that temperature in °C? 1) 73.8 °C 2) 58.8 °C 3) 41.0 °C LecturePLUS Timberlake 14 Solution 3) 41.0 °C Solution: °C = = = (°F - 32) 1.8 (105.8 - 32) 1.8 73.8°F 1.8° LecturePLUS Timberlake = 41.0°C 15 Learning Check Pizza is baked at 455°F. What is that in °C? 1) 437 °C 2) 235°C 3) 221°C LecturePLUS Timberlake 16 Solution Pizza is baked at 455°F. What is that in °C? 2) 235°C (455 - 32) = 235°C 1.8 LecturePLUS Timberlake 17 Learning Check On a cold winter day, the temperature falls to -15°C. What is that temperature in °F? 1) 19 °F 2) 59°F 3) 5°F LecturePLUS Timberlake 18 Solution 3) 5°F Solution: °F = 1.8(-15°C) + 32 = -27 + 32 = 5°F LecturePLUS Timberlake 19 Kelvin Scale On the Kelvin Scale 1K = 1°C 0 K is the lowest temperature 0K K K = = - 273°C °C °C + 273 LecturePLUS Timberlake 20 Learning Check What is normal body temperature of 37°C in kelvins? 1) 236 K 2) 310 K 3) 342 K LecturePLUS Timberlake 21 Solution What is normal body temperature of 37°C in kelvins? 2) 310 K K = = = °C + 273 37 °C + 273 310. K LecturePLUS Timberlake 22