KU BIDMAS 2 Brackets & order of operations 2 HW Answers

advertisement

BIDMAS 2 Homework Answers

1. Work out the following using the rules of BIDMAS.

1. (4 + 2) × (12 – 2)

= 6 x 10 = 60

2. 5 + (2 × 3) – 7 = 5 + 6 - 7 = 11 - 7 = 4

3. 9 + 7 – 12 ÷ 2 9 + 7 - 6 = 16 - 6 = 10

4. 3 × 4 + 10 ÷ 2 = 3 x 4 + 5 = 12 + 5 = 17

5. 4 + 2 2 × 6 = 4 + 4 x 6 = 4 + 24 = 28

6. 16 – 8 ÷ 2 2 = 16 - 8 ÷ 4 = 16 - 2 = 14

7. 4 2 – 8 × 2 = 16 - 8 x 2 = 16 – 16 = 0

8. 34 + 2 – (4 × 3 2 ) = 34 + 2 - (4 x 9) = 34 + 2 - 36 = 36 - 36 = 0

2. Look at questions 7 and 8. Did you notice that the second parts subtracted the answer to the first parts? Write five of your own calculation strings which give an answer of zero.

8 2 – 32 × 2 = 0 E.g. 4 x 6 - (20 + 2²) = 0 E.g. (12 + 6) - 2 x 3² = 0

5² - (4² + 3²) = 0 E.g. 4 x 3 - 2 x 6 = 0 E.g. (6² + 14) - 5 x 10 = 0

HSNP © Hamilton 2013 Keeping Up Term 2 Page 25

BIDMAS 2 Homework Answers

3. Use 2, 3, 4, brackets, ×, - and a square to create calculations with as many different answers as you can.

Use all three numbers, both operations and one square once only in each calculation but in any order. For example 4 2 × (3 – 2) . Try to find more than

10 different answers?

4 2 × (3 – 2) = 16 E.g. (4 - 3)² x 2 = 2

E.g. 4² - (2 x 3) = 10 E.g. (4 x 3 - 2)² = 100

E.g. (2² x 3) - 4 = 8 E.g. (2 x 4 - 3)² = 25

E.g. 2² x (4 - 3) = 4

E.g. 3² x (4 - 2) = 18

E.g. (4 - 2)² x 3 = 12

E.g. (4 - 2)² x 3 = 6

E.g. (2 x 3)² - 4 = 32

E.g. (2 x 4)² - 3 = 61 just right too hard too easy

How did you find these problems?

Page 26

Download