B.) virtual, 20 cm from the mirror
a.
1/p + 1/q = 1/f, where p is the object
distance, q is the image distance, and f is the focal length. We can plug in
the given values and solve for q:
b.
1/p + 1/q = 1/f 1/10 + 1/q = 1/20 q = -20
cm
c.
The negative sign of q means that the
image is virtual and located behind the mirror. Therefore, the correct answer
is B.) virtual, 20 cm from the mirror.