living with the lab College of Engineering & Science Ohm’s Law 1.5V π£πππ‘πππ = ππ’πππππ‘ β πππ ππ π‘ππππ 1.5V π£πππ‘π = ππππ β πβππ π =πΌβπ © 2012 David Hall living with the lab DISCLAIMER & USAGE The content of this presentation is for informational purposes only and is intended only for students attending Louisiana Tech University. The author of this information does not make any claims as to the validity or accuracy of the information or methods presented. Any procedures demonstrated here are potentially dangerous and could result in injury or damage. Louisiana Tech University and the State of Louisiana, their officers, employees, agents or volunteers, are not liable or responsible for any injuries, illness, damage or losses which may result from your using the materials or ideas, or from your performing the experiments or procedures depicted in this presentation. If you do not agree, then do not view this content. The copyright label, the Louisiana Tech logo, and the “living with the lab” identifier should not be removed from this presentation. You may modify this work for your own purposes as long as attribution is clearly provided. 2 living with the lab electric current and voltage electron shortage + electron supply - electric resistance 3 living with the lab units for electric current The electric current I is the amount of charge passing a point per unit time. 1 πππ = πΆ π΄= π 6.24 10 18 πππππ‘ππππ πππ π πππ π πππππ‘ 1 πΆππ’ππππ πΆ = = π πππππ π πππππ π π€βπππ 1πΆ = 6.24 10 18 πππππ‘ππππ teams of 2 Class Problem A battery powers a flashlight. If the battery supplies a steady current of 1.3A over 8 minutes, how many electrons leave the negative terminal of the battery during this time period? 4 living with the lab 1C units of voltage 1C the unit for voltage V is the volt 1 π½ππ’ππ 1 π£πππ‘ = πΆππ’ππππ ππ π½ π= πΆ 1.5V 1.5V π€πππ = 1.5π β 1πΆ = 1.5π½ 1.5V One Coulomb flows through each light bulb. π€πππ = 1.5π + 1.5π β 1πΆ = 3π½ The voltage across a bulb is doubled when two batteries are used. The work done when two batteries are used is twice as much as the work done when one battery is used, even though the same number of electrons flow through each bulb. Doubling the voltage doubles the work . . . and gives off much more light. 5 living with the lab voltage / water pressure analogy depth of water between surface of lake and surface of river voltage & pressure are both measures of a potential difference Glen Canyon Dam in Arizona, USA Wikipedia The work done per gallon of water passing through a turbine will double (theoretically) when the water depth (pressure) is doubled. Likewise, the work done per Coulomb of charge passing through a resistor will double (theoretically) when the voltage is doubled. 6 living with the lab units of resistance The resistance R is a measure of the frictional resistance encountered by electrons as they attempt to pass through a material. R = πβππ ππ Ω a pile of electrical resistors 7 living with the lab circuit symbols We frequently draw diagrams that represent various types of electric circuits. The most simple diagram is that of a direct current (DC) power source and a resistive element such as a light bulb or resistor. + - circuit symbol for a DC power source . . . 1.5 volts in this case 1.5V circuit symbol for a resistor . . . 220 ohms in this case 220 β¦ For resistors, you don’t need to worry about which side is + and which side is – (they will work either way). straight lines depict conductors with an assumed resistance of zero 8 living with the lab circuit diagrams We can put together a series of circuit symbols to depict an electric circuit. + 6V - 12 β¦ The voltages of power sources arranged end-to-end in this way can be added. Thus, four 1.5V batteries in series has a total voltage of 6V. 9 living with the lab Ohm’s law Ohm’s law relates voltage, current and resistance as follows . . . π£πππ‘πππ = ππ’πππππ‘ β πππ ππ π‘ππππ π£πππ‘π = ππππ β πβππ π =πΌβπ + 6V 12 β¦ - I conventional current teams of 2 Class Problem Use Ohm’s law to determine . . . (a) the current delivered to the resistor (light bulb) for the circuit above. (b) the number of electrons that leave the battery pack over 2 minutes. 10