Chapter 2.3: Continuity

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Continuity

Chapter 2.3

Importance of Continuity

• Before we define continuity, let’s spend a little time asking why we should care about continuity

From this point on, nearly every theorem you see will begin with something like “Let 𝑓 be a continuous function”

What this means is that the truth of the theorem is conditional on the continuity of the function

Or stated another way, if the function is not continuous over some interval we are interested in, then we can’t use it

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Importance of Continuity

An imprecise but intuitionally useful way to talk about a continuous function is to say that it is a function that can be drawn without lifting pencil from paper

The precise definition is tied to the notion of limits in a particular way

(as you’ll soon see)

In fact, the notion of continuity arises with respect to functions because the number line itself is continuous; i.e., it has no “gaps”

The first example takes advantage of the intuitional view from above

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Example 1: Investigating Continuity

Find the points at which the function 𝑓 shown below is continuous and the points at which it is discontinuous.

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Example 1: Investigating Continuity

Find the points at which the function 𝑓 shown below is continuous and the points at which it is discontinuous.

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Example 1: Investigating Continuity

Find the points at which the function 𝑓 shown below is continuous and the points at which it is discontinuous.

The following are important to note about this function:

• The function “begins” at 𝑥 = 0 , lim 𝑥→0 +

At 𝑥 = 1 , lim 𝑥→1 + 𝑓(𝑥) = 0 but lim 𝑥→1 − 𝑓(𝑥) = 1 𝑓(𝑥) = 1

, and

, hence 𝑓 0 = 1 lim 𝑥→1 𝑓(𝑥) DNE

At 𝑥 = 2 , we have lim 𝑥→2 + 𝑓(𝑥) = 1 and lim 𝑥→2

− 𝑓(𝑥) = 1 so lim 𝑥→2 𝑓 2 = 2 (the limit and the function are different at 𝑥 = 2 ) 𝑓(𝑥) = 1 , however

At 𝑥 = 4 , lim 𝑥→4 − 𝑓(𝑥) = 1

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Conditions for Continuity

From these observations we see that:

A function is not continuous at a given 𝑥 if the limit does not exist there, even if the function is defined at that 𝑥

A function is not continuous at a given 𝑥 if the limit exists, but the function value at 𝑥 is different from the limit

There are 3 conditions necessary for us to say that a function is continuous at a point

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Continuity at a Point

DEFINITION:

A function 𝑦 = 𝑓(𝑥) is continuous at an interior point 𝒄 of its domain if:

• 𝑓(𝑐) is defined

• lim 𝑥→𝑐 𝑓(𝑥) exists

• 𝑓 𝑐 = lim 𝑥→𝑐 𝑓(𝑥)

A function 𝑦 = 𝑓(𝑥) is continuous at a left endpoint 𝒂 or is continuous at a right endpoint 𝒃 of its domain if

• 𝑓(𝑎) or 𝑓(𝑏) is defined, respectively

• lim 𝑥→𝑎 + 𝑓(𝑥) exists or

• 𝑓 𝑎 = lim 𝑥→𝑎 + 𝑓(𝑥) lim 𝑥→𝑏 or

− 𝑓(𝑥) exists, respectively 𝑓 𝑏 = lim 𝑥→𝑏 − 𝑓(𝑥) , respectively

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Continuity at a Point

If any one of the three previous conditions fails to hold at a point 𝑐 in the domain of a function, then we say that 𝑓 is discontinuous at 𝒄

We may also say that 𝑐 is a point of discontinuity of 𝑓

Make sure to note that this definition refers to continuity at a single value of 𝑥

We will eventually want to talk about the continuity (or discontinuity) of a function either over some interval, or perhaps over its entire domain

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Example 2: Finding Points of Continuity and

Discontinuity

Find the points of continuity and the points of discontinuity of the floor function, 𝑓 𝑥 = 𝑥 .

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Example 2: Finding Points of Continuity and

Discontinuity

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Example 2: Finding Points of Continuity and

Discontinuity

Find the points of continuity and the points of discontinuity of the floor function, 𝑓 𝑥 = 𝑥 .

We can define 𝑓 as 𝑓 𝑥 = 𝑎 ∈ ℤ if 𝑎 ≤ 𝑥 < 𝑎 + 1

Now note that, for some value 𝑐 in of (𝑎, 𝑎 + 1) we have 𝑓 𝑐 = 𝑎 lim 𝑥→𝑐 𝑓(𝑥) = 𝑎 and lim 𝑥→𝑐 𝑓(𝑥) = 𝑓(𝑐)

This means that 𝑓 is continuous at every point between the integers 𝑎 and 𝑎 + 1

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Example 2: Finding Points of Continuity and

Discontinuity

Find the points of continuity and the points of discontinuity of the floor function, 𝑓 𝑥 = 𝑥 .

What about 𝑎 = 𝑐 ? We have 𝑓 𝑐 = 𝑓 𝑎 = 𝑎

But lim 𝑥→𝑐 − 𝑓(𝑥) = 𝑎 while lim 𝑥→𝑐

+ 𝑓(𝑥) = 𝑎 − 1

This means that the limit does not exist. Since this is required for continuity, then the function is discontinuous at all integer values.

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Example 2: Finding Points of Continuity and

Discontinuity

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Types of Discontinuity

We will encounter four types of discontinuity

Removable discontinuities

: a function has a “hole” at one or more values of 𝑥 ; these can be removed by defining a value and “plugging” the hole

Jump discontinuities : a function makes a sudden “jump” from function value to another at one or more values of 𝑥 (like the floor function)

Infinite discontinuities : occurs when a function has one or more vertical asymptotes

Oscillating discontinuities : occurs when a function begins to oscillate rapidly as 𝑥 → 𝑐 without settling near one value; we often see this with trigonometric function

The next slide shows examples (from page 80 in your textbook)

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Types of Discontinuity

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Removable Discontinuities

Consider the rational function 𝑥 2 + 3𝑥 + 2 𝑓 𝑥 = 𝑥 2 − 9

The numerator and denominator can be factored to give 𝑥 − 3 𝑥 + 2 𝑥 + 1 𝑓 𝑥 = 𝑥 + 3 𝑥 − 3

The common factors 𝑥 − 3 cancel, but this doesn’t eliminate them from the original function; 𝑓 is not defined at 𝑥 = 3 (nor at 𝑥 = −3 )

But we can remove the discontinuity as shown in the next slide

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Removable Discontinuities

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Continuous Functions

The previous examples, and our definition, are concerned with continuity at a single point

We say that a function is continuous on an interval if and only if it is continuous at every point of the interval

We say that a continuous function is one that is continuous at every point of its domain

A continuous function need not be continuous at every interval

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Continuous Functions

The last statement can be illustrated by considering the function 𝑦 =

1

The domain of this function is −∞, 0 ∪ (0, ∞) and it is continuous 𝑥 at every point in this interval, so we say that it a continuous function

However, we may also say that it is discontinuous at 𝑥 = 0

Also, it is not continuous on any interval that contains zero, such as

[−1,1]

Would it be correct to say that since, by definition, a function is defined at all 𝑥 -values of its domain, then it must be a continuous function? If not, can you give a counterexample?

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Continuous Functions

It is worthwhile to remember that all of the following are continuous functions

Polynomial functions are continuous at all real numbers (we may also say that polynomial functions are everywhere continuous)

Rational functions are continuous at every point of the domains and have points of discontinuity at the zeros of their denominator

The absolute value function is everywhere continuous

Exponential functions are everywhere continuous

Trigonometric functions are continuous at every point of their domains, but only sine and cosine functions are everywhere continuous

Radical functions are continuous at every point of their domains

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Properties of Continuous Functions

THEOREM:

If the function 𝑓 and 𝑔 are continuous at 𝑥 = 𝑐 , then the following combinations are continuous at 𝑥 = 𝑐

1. Sums/differences: 𝑓 ± 𝑔 is continuous at 𝑥 = 𝑐

2. Products: 𝑓𝑔 is continuous at 𝑥 = 𝑐

3. Constant multiples: 𝑘𝑓 is continuous at 𝑥 = 𝑐 , where 𝑘 is a real number

4. Quotients: 𝑓 𝑔 is continuous at 𝑥 = 𝑐 , provided that 𝑔 𝑐 ≠ 0

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Composite of Continuous Functions

THEOREM:

If 𝑓 is continuous at 𝑐 and 𝑔 is continuous at 𝑓(𝑐) , then the composite 𝑔 𝑓 𝑥 is continuous at 𝑐 .

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Example 4: Composition of Continuous

Functions

Show that 𝑓 𝑥 = 𝑥 sin 𝑥 𝑥 2 +2 is continuous.

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Example 4: Composition of Continuous

Functions

Show that 𝑓 𝑥 = 𝑥 sin 𝑥 𝑥 2 +2 is continuous.

If we let 𝑔 𝑥 = |𝑥| and ℎ 𝑥 = 𝑥 +2 theorems, since 𝑥 and sin 𝑥 are everywhere continuous, then by the Product Rule, 𝑥 sin 𝑥 𝑥 sin 𝑥

2

, then 𝑓 𝑥 = 𝑔 ℎ 𝑥 . Using the previous is everywhere continuous. Since everywhere continuous. Since 𝑥 2 + 2 𝑥 2 + 2 cannot equal zero, then 𝑥 sin 𝑥 is a polynomial, then it, too, is 𝑥 2 + 2 is everywhere continuous by the Quotient Rule. Finally, since ℎ and 𝑔 are everywhere continuous, then 𝑓 𝑥 = 𝑔 ℎ 𝑥 is everywhere continuous.

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The Intermediate Value Theorem

THEOREM:

A function 𝑦 = 𝑓(𝑥) that is continuous on a closed interval [𝑎, 𝑏] takes on every value between 𝑓(𝑎) and 𝑓(𝑏) . In other words, if 𝑦

0 there must exist 𝑐 between 𝑎 and 𝑏 such that 𝑦

0 is between

= 𝑓(𝑐) .

𝑓(𝑎) and 𝑓(𝑏) , then

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The Intermediate Value Theorem

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The Intermediate Value Theorem

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Example 5: Using the IVT

Is any real number exactly 1 less than its cube?

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Example 5: Using the IVT

Is any real number exactly 1 less than its cube?

This is the same as asking if there exists a number 𝑥 such that 𝑥 = 𝑥 3 this as 𝑥 3 − 𝑥 − 1 = 0

− 1 . We can rewrite

The problem now comes down to asking if there the function 𝑓(𝑥) = 𝑥 3 root.

− 𝑥 − 1 has a real

Note that 𝑓 1 = −1 < 0 and that 𝑓 2 = 5 > 0 . That is, 𝑓 1 < 0 < 𝑓(2)

We can invoke the IVT and conclude that, since 𝑓 is continuous and since 𝑓 1 < 0 < 𝑓(2) then there must exist (at least one) number 1 < 𝑐 < 2 so that 𝑓 𝑐 = 0 . (Make sure you understand that IVT doesn’t give the number, only guarantees its existence.)

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Exercise 2.3

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