3x a) y 4 3 b) 3 24 81 c) 3x 4 y 13x 4 y 1 3 3 Section P.5 Factoring is the process of writing a polynomial as the product of two or more polynomials. Prime polynomials cannot be factored using integer coefficients. Factor completely means keep factoring until everything is prime Greatest common factor Difference of two perfect squares Perfect-square trinomials Factoring x2 + bx + c (big X) Factoring ax2 + bx + c (big X) Factor by grouping – use with 4 terms Sum and difference of perfect cubes Find the greatest common factor (GCF) of all terms. Divide each term by the greatest common factor. Write the GCF outside parenthesis, with the rest of the divided terms added together inside 3a2 – 12a 3a is the GCF 2 3a a, 3a 12a 4 3a 3aa 4 a. 18x3 + 27x2 b. x2(x + 3) + 5(x + 3) Works with an even number of terms. Split the terms into two groups. Factor each group separately using GCF. If factor by grouping is possible, the part inside parentheses of each group will be the same. Treat the parentheses as common factors to finish factoring. x 5 x 3 x 15 3 2 x 6 x 2 x 12 3 2 Look for integers r and s such that: ◦ r×s=c c ◦ r+s=b r s b x bx c x r x s 2 x 7 x 12 2 x 5x 6 2 x 5x 6 2 Look for integers r and s such that: ◦ r × s = ac ac ◦ r+s=b r s b Divide r and s by a, then reduce fractions In your factors, any remaining denominator gets moved in front of the x 5 x 13 x 6 2 6 x 11x 3 2 Let A and B be real numbers, variables, or algebraic expressions, 1. A2 + 2AB + B2 = (A + B)2 2. A2 – 2AB + B2 = (A – B)2 Factor: 16x2 – 56x + 49 Factor: x2 + 14x + 49 a b a ba b 2 2 x 9 x 3 x 3 2 4 x 1 2 x 12 x 1 2 25 x 49 y 5 x 7 y 5 x 7 y 2 2 A3 B3 A B A2 AB B 2 Type Example A3 + B3 = (A + B)(A2 – AB + B2) x3 + 8 = x3 + 23 = (x + 2)( x2 – x·2 + 22) = (x + 2)( x2 – 2x + 4) A3 – B3 = (A – B)(A2 + AB + B2) 64x3 – 125 = (4x)3 – 53 = (4x – 5)((4x)2 + (4x)(5) + 52) = (4x – 5)(16x2 + 20x + 25) 125x 8 y 3 3 27 x 1000 3 1. 2. If there is a common factor, factor out the GCF. Determine the number of terms in the polynomial and try factoring as follows: a) If there are two terms, can the binomial be factored by one of the special forms including difference of two squares, sum of two cubes, or difference of two cubes? b) If there are three terms, is the trinomial a perfect square trinomial? If the trinomial is not a perfect square trinomial, try factoring using the big X. c) If there are four or more terms, try factoring by grouping. 3. Check to see if any factors with more than one term in the factored polynomial can be factored further. If so, factor completely. Factor out GCF 2 Count number of terms Check for: •Difference of perfect squares •Sum of perfect cubes •Difference of perfect cubes 3 4 Factor by Grouping 1. Check for perfect square trinomial 2. Use big X factoring Check each factor to see if it can be factored further Page 53 #1-75 Odd In Exercises 1-10, factor out the greatest common factor. In Exercises 11-16, factor by grouping. In Exercises 17-30, factor each trinomial, or state that the trinomial is prime. 1) 18 x 27 3) 3 x 2 6 x 5) 9 x 18 x 27 x 7) x x 5 3 x 5 4 3 2 9) x 2 x 3 12 x 3 11) x 3 2 x 2 5 x 10 13) x 3 x 2 2 x 2 15) 3 x 3 2 x 2 6 x 4 17) x 2 5 x 6 19) x 2 2 x 15 21) x 8 x 15 2 In Exercises 17-30, factor each trinomial, or state that the trinomial is prime. 23) 3 x x 2 2 25) 3 x 25 x 28 2 27) 6 x 11x 4 2 29) 4 x 16 x 15 2 In Exercises 31-40, factor the difference of two squares. 31) x 100 2 33) 36 x 49 2 35) 9 x 25 y 2 37) x 16 4 39) 16 x 81 4 2 In Exercises 41-48, factor any perfect square trinomials, or state that the polynomial is prime. In Exercises 49-56, factor using the formula for the sum or difference of two cubes. 41) x 2 x 1 2 43) x 14 x 49 2 45) 4 x 2 4 x 1 47) 9 x 2 6 x 1 49) x 3 27 51) x 3 64 53) 8 x 1 3 55) 64 x 3 27 In Exercises 57-84, factor completely, or state that the polynomial is prime. 57) 3 x 3 3 x 59) 4 x 2 4 x 24 61) 2 x 4 162