If we had a rectangular prism that was 3 inches by 4
inches by 6 inches what would be the units of the
perimeter measurement?
If we had a rectangular prism that was 3 inches by 4
inches by 6 inches what would be the units of the
perimeter measurement?
inches
If we had a rectangular prism that was 3 inches by 4
inches by 6 inches what would be the units of the
area of a face measurement?
inches
If we had a rectangular prism that was 3 inches by 4
inches by 6 inches what would be the units of the
area of a face measurement?
inches
inches²
If we had a rectangular prism that was 3 inches by 4
inches by 6 inches what would be the units of the
volume measurement?
inches
inches²
If we had a rectangular prism that was 3 inches by 4
inches by 6 inches what would be the units of the
volume measurement?
inches
inches²
inches³
If we double (x2)all the side measurements, what
happens to the perimeter?
sides
x2
inches
inches²
inches³
If we double (x2)all the side measurements, what
happens to the area?
sides
x2
inches
x2
inches²
inches³
If we double (x2)all the side measurements, what
happens to the volume?
sides
x2
inches
x2
inches²
x2²
inches³
If we double (x2)all the side measurements, what
happens to the volume?
sides
x2
inches
x2
inches²
x2²
inches³
x2³
If we quadrupled (x4)all the side measurements, what
happens to the perimeter, area and volume?
sides
x2
inches
x2
inches²
x2²
inches³
x2³
If we quadrupled (x4)all the side measurements, what
happens to the perimeter, area and volume?
sides
x2
x4
inches
x2
x4
inches²
x2²
x4²
inches³
x2³
x4³
Tuesday, April 22
Chapter 11
Review
A paperweight has a triangular base with an area of
15 square meters. If the height is 1.5 meter, what is
the volume of the paperweight?
A paperweight has a triangular base with an area of
15 square meters. If the height is 1.5 meter, what is
the volume of the paperweight?
Since the base has an area of 15 m² , you just
multiply by the height.
V = Bh
15 m² · 1.5m = 22.5 m³
Chapter 11 Review
1. A shop records the number of specialty shirts
sold each month. What is the mean number of Tshirts sold?
A. 75
B. 83
C. 85
D. 92
Chapter 11 Review
1. A shop records the number of specialty shirts
sold each month. What is the mean number of Tshirts sold?
A. 75
B. 83
C. 85
D. 92
75 + 68 + 75 + 92 + 105 = 415 ÷ 5 = 83
Answer: B
Chapter 11 Review
2. Javon’s bill at the bakery was $12. He bought 12
egg bagels for $0.50 each. If an onion bagel costs
$0.75, how can he find how much he spent on
onion bagels?
F. Add $0.50 and $0.75.
G. Subtract the product of 12 and $0.50 from $12.00.
H. Multiply $0.75 and 12.
I. Divide 12 by $0.50.
Chapter 11 Review
2. Javon’s bill at the bakery was $12. He bought 12
egg bagels for $0.50 each. If an onion bagel costs
$0.75, how can he find how much he spent on
onion bagels?
F. Add $0.50 and $0.75.
G. Subtract the product of 12 and $0.50 from $12.00.
H. Multiply $0.75 and 12. $12 - 12 · $.50 = x · $.75
I. Divide 12 by $0.50.
Answer: G
Chapter 11 Review
3. What is the median of the following ages of
people attending a concert: 2, 7, 41, 25, 19, 22, 28,
32, and 24?
A. 17
B. 22
C. 24
D. 41
Chapter 11 Review
3. What is the median of the following ages of
people attending a concert: 2, 7, 41, 25, 19, 22, 28,
32, and 24?
A. 17
2, 7, 19, 22, 24, 25, 28, 32, 41
B. 22
Answer: C
C. 24
D. 41
Chapter 11 Review
4. GRIDDED RESPONSE Teresa had a family
1
photo with the dimensions of 12 inches by 16
2
inches. Find the area of the photo, in square
inches.
Chapter 11 Review
4. GRIDDED RESPONSE Teresa had a family
1
photo with the dimensions of 12 inches by 16
2
inches. Find the area of the photo, in square
inches.
1
2
A = 12 in · 16 in = 198 in²
Chapter 11 Review
5. GRIDDED RESPONSE Use the frequency table
below to determine the mean number of hours of
sleep.
Chapter 11 Review
5. GRIDDED RESPONSE Use the frequency table
below to determine the mean number of hours of
sleep.
Mean: 6.85
5+ 5+ 5.5+ 6+ 6+ 6+ 6.5+
7+ 7+ 7+ 7+ 7+ 7.5+ 7.5+
7.5+ 7.5+ 8+ 8+ 8+ 8=137
137 ÷ 20 = 6.85
Chapter 11 Review
6. Martha was making place cards fora party that
1
used of a piece of papereach. If she needed to
3
make place cardsfor 31 people, how many pieces of
paperwould she need?
F. 93
G. 34
H. 11
I. 10
Chapter 11 Review
6. Martha was making place cards fora party that
1
used of a piece of papereach. If she needed to
3
make place cardsfor 31 people, how many pieces of
paperwould she need?
F. 93
31 x 13= 10 13
G. 34
H. 11
Answer: H
I. 10
Chapter 11 Review
7. The lengths of the longest bridges in the United States
are shown. Which statement is supported by the data?
A. If the lengths of the bridges were
distributed equally among all five
bridges, each would measure
95,250 feet in length.
B. There is no bridge length that
occurs more often than another.
C. The lengths of the bridges have a range of 82,000 feet.
D. The majority of the bridges are greater than 97,000 feet
in length.
Chapter 11 Review
7. The lengths of the longest bridges in the United States
are shown. Which statement is supported by the data?
A. If the lengths of the bridges were
distributed equally among all five
bridges, each would measure
95,250 feet in length.
B. There is no bridge length that
occurs more often than another.
C. The lengths of the bridges have a range of 82,000 feet.
D. The majority of the bridges are greater than 97,000 feet
in length.
Chapter 11 Review
8. GRIDDED RESPONSE A train is traveling 54.8
miles per hour. At this speed, how far will the train
travel, in miles, in 3.2 hours?
Chapter 11 Review
8. GRIDDED RESPONSE A train is traveling 54.8
miles per hour. At this speed, how far will the train
travel, in miles, in 3.2 hours?
54.8 mph · 3.2 hrs = 175.36 miles
Chapter 11 Review
3
4
9. Craig planted acre with vegetables. He divided
1
of
6
the garden into sections that were
an acre.
How many different sections will Craig have?
1
F. 4
2
1
G. 3
2
2
H.
9
1
I.
8
Chapter 11 Review
3
4
9. Craig planted acre with vegetables. He divided
1
of
6
the garden into sections that were
an acre.
How many different sections will Craig have?
1
F. 4
2
1
G. 3
2
2
H.
9
1
I.
8
3
4
1
÷
6
1
=4
2
Answer: F
Chapter 11 Review
10. SHORT RESPONSE The table shows students’
favorite track and field events. If 300 students were
surveyed, how many would prefer long jump?
Chapter 11 Review
10. SHORT RESPONSE The table shows students’
favorite track and field events. If 300 students were
surveyed, how many would prefer long jump?
26% of 300 is 78
Calculator
26, 2nd, %, 300, =
Chapter 11 Review
11. The weight of a small dog is about 10 times the
weight of a guinea pig shown. What is the
estimated weight of the small dog?
A. 0.2 lb
B. 10 lb
C. 20 lb
D. 200 lb
Chapter 11 Review
11. The weight of a small dog is about 10 times the
weight of a guinea pig shown. What is the
estimated weight of the small dog?
A. 0.2 lb
B. 10 lb
C. 20 lb
D. 200 lb
10 times 2 lbs = 20 lbs
Answer: C
Chapter 11 Review
12. The table shows the number of goals scored by
Major League Soccer players in a recent year.
Which measure of center best represents the data?
F. outlier
G. mode
H. range
I. mean
Chapter 11 Review
12. The table shows the number of goals scored by
Major League Soccer players in a recent year.
Which measure of center best represents the data?
F. outlier
G. mode
H. range
I. mean
Range and outliers are not a
measure of center. Since there are no outliers, the mean
would be the best.
Answer: I
Chapter 11 Review
13. What is the solution to the equation 1.7t = 8.5?
A. 5
B. 6.8
C. 10.2
D. 14.45
Chapter 11 Review
13. What is the solution to the equation 1.7t = 8.5?
A. 5
1.7t = 8.5
B. 6.8
C. 10.2
1.7𝑡
8.5
=
1.7
1.7
D. 14.45
t=5
Answer: A
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part A Find the mean, median,
mode, and range.
Part B How does the outlier
affect the values you found for Part A?
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part A Find the mean, median,
mode, and range.
Mean: 265+70+85+120+135=675÷5=135
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part A Find the mean, median,
mode, and range.
Mean: 265+70+85+120+135=675÷5=135
Median: 70, 85, 120, 135, 265
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part A Find the mean, median,
mode, and range.
Mean: 265+70+85+120+135=675÷5=135
Median: 70, 85, 120, 135, 265
Mode: no mode
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part A Find the mean, median,
mode, and range.
Mean: 265+70+85+120+135=675÷5=135
Median: 70, 85, 120, 135, 265
Mode: no mode
Range: 265 – 70 = 195
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part B How does the outlier
affect the values you found for
Part A?
Chapter 11 Review
14. EXTENDED RESPONSE Kamilah is
researching the number of channels available from
different cable and satellite companies. The table
shows the results.
Part B How does the outlier
affect the values you found for
Part A?
The number 265 makes the measures of center much
higher. It also makes the range much larger.
Chapter 11 Review
Agenda Notes
Homework–
Homework Practice OAA – CH11a
Due Wednesday, April 23