Impulse & Momentum From Newton 2: • Previously: Work-Energy SF=ma multiply both sides by d S F d= m a d (note a d = ½ Dv2) S F d= ½ m Dv2 S W = DKE Define Work and Kinetic Energy 08 From Newton 2: Two New Concepts Impulse & Momentum Fnet ma Dv Fnet m Dt Fnet Dt m Dv Impulse N-s Change In Momentum Kg m/s I Fnet Dt Impulse = Change in Momentum Momentum; p mv Momentum is vector in direction of velocity. Impulse is vector in direction of force. m N s kg s Preflight 1 A few weeks ago I did a lecture demonstration where I yanked a tablecloth out from under some dishes. Can you briefly explain why the dishes were not given much impulse by the tablecloth. Impulse is defined as force time the change in time. If the change in time is very small, the impulse is going to be small. The dishes just didn’t feel like moving… The cloth may have been made out of a slick material (i.e. silk) so the friction is negligible… 11 Preflight 2 & 3 Is it possible for a system of two objects to have zero total momentum while having a non-zero total kinetic energy? 67% 1. YES 33% 2. NO correct yes, when two objects have the same mass and velocities and they push off each other..momentum is zero and kinetic energy is nonezero. 2 balls traveling at the same speed hit each other head-on. Change in Momentum ACT If the bear and the ball have equal masses, which toy experiences the greater change in momentum? Change in momentum: Dp = pafter - pbefore Teddy Bear: Dp = 0-(-mv) = mv Bouncing Ball: Dp = mv-(-mv) = 2mv Change in Momentum ACT2 A 10 kg cart collides with a wall and changes its direction. What is its change in x-momentum Dpx? y x a. -30 kg m/s b. -10 kg m/s c. 10 kg m/s d. 20 kg m/s e. 30 kg m/s ACTs You drop an egg onto 1) the floor 2) a thick piece of foam rubber. In both cases, the egg does not bounce. In which case is the impulse greater? A) Floor B) Foam C) the same I = DP Same change in momentum same impulse In which case is the average force greater A) Floor Dp = F Dt B) Foam F = Dp/Dt C) the same Smaller Dt = larger F Pushing Off… Fred (75 kg) and Jane (50 kg) are at rest on skates facing each other. Jane then pushes Fred w/ a constant force F = 45 N for a time Dt=3 seconds. Who will be moving fastest at the end of the push? A) Fred B) Same Fred F = +45 N (positive direct.) I = +45 (3) N-s = 135 N-s I = Dp = mvf – mvi I/m = vf - vi vf = 135 N-s / 75 kg = 1.8 m/s C) Jane Jane F = -45 N Newton’s 3rd law I = -45 (3) N-s = -135 N-s I = Dp = mvf – mvi I/m = vf - vi vf = -135 N-s / 50 kg = -2.7 m/s Note: Pfred + Pjane = (1.8) 75 + (-2.7) 50 = 0! Momentum Change ACT A car w/ mass 1200 kg is driving north at 40 m/s, and turns east driving 30 m/s. What is the magnitude of the car’s change in momentum? A) 0 B) 12,000 C) 36,000 D) 48,000 E) 60,000 Pinitial = m vinitial = (1200 Kg) x 40 m/s = 48,000 kg m/s North Pfinal = m vfinal = (1200 Kg) x 30 m/s = 36,000 kg m/s East North-South: Pfinal – Pinitial = (0 – 48000) = -48,000 kg m/s 30 m/s East-West: Pfinal – Pinitial = (36000 - 0) = +36,000 kg m/s Magnitude : Sqrt(P2North – P2East ) = 60,000 kg m/s 40 m/s Impulse and Momentum Summary FaveDt I = pf - pi = Dp • For single object…. • F = 0 momentum conserved (Dp = 0) • For collection of objects … • SFext = 0 total momentum conserved (DPtot = 0) • Fext = mtotal a • 4. •• IP Two air track carts move toward one another on an air track. Cart 1 has a mass of 0.45 kg and a speed of 1.1 m/s. Cart 2 has a mass of 0.65 kg. (a) What speed must cart 2 have if the total momentum of the system is to be zero? (b) Since the momentum of the system is zero, does it follow that the kinetic energy of the system is also zero? (c) Verify your answer to part (b) by calculating the system’s kinetic energy. • 9. • In a typical golf swing, the club is in contact with the ball for about 0.0010 s. If the 45-g ball acquires a speed of 67 m/s, estimate the magnitude of the force exerted by the club on the ball. • • • 5. •• A 0.150-kg baseball is dropped from rest. If the magnitude of the baseball’s momentum is just before it lands on the ground, from what height was it dropped?