SAT Prep A.) Vocabulary Monomials – Any number or variable or product of number(s) and variable(s) Ex. Evaluate 3a 2 b when a = -4 and b = 0.5. 3 4 0.5 2 3 16 0.5 24 Binomials – 2 monos separated by +/- 2x 3 Trinomials – 3 monos separated by +/- 2 x2 3x 1 B.) Simplifying Polynomials !!** ADD OR SUBTRACT LIKE TERMS ONLY **!! Like terms – same variable(s) and same exponent(s). Ex. Simplify 3 x 2 4 x 2 x 2 5 x. 2 2 3 x 2 x 4x 5x 5x2 9 x Multiplying Monomials - Mult. Coeffecients and add exponents of like bases Ex. Simplify the following: (3 xy z )(2 x y) 2 3 3 2 x x 2 y y z 2 3 2 6 x y z 3 3 3 Dividing MonomialsDiv. coeff. And subtract exponents of like bases (6 x 4 y 2 z 3 ) Ex. Simplify the following: (2 x 2 z ) 6 x 4 y 2 z 3 2 2 x 1 z 3 x 42 y 2 z 31 1 1 1 1 3 x 2 y 2 z 2 C.) Factoring and Expanding FOIL – First Outer Inner Ex . Expand the following: Last x 33x 7 FIRST: OUTER: INNER: x 3x x 7 3 3x LAST: 3 7 3x 2 7 x 9 x 21 3 x 2 2 x 21 Three important binomial products ( x y )( x y ) x 2 y 2 ( x y ) x 2 xy y 2 2 2 ( x y ) 2 x 2 2 xy y 2 Ex. If (a – b) = 17.5 and (a + b) = 10, what does a2 – b2 =? a2 b2 a b a b a2 b2 17.510 175 Ex. If x2 + y2 = 36 and (x + y) 2 = 64 what is xy? x y 2 x 2 2 xy y 2 64 x 2 2 xy y 2 64 2 xy 36 28 2xy xy 14 D.) MORE FACTORING GCF, Common Monomials, and Product/sum table 2 Ex. Find all real solutions of x x 6 0 x 2 x 3 0 FACTORS (-6) SUM (-1) 1, 6 5 1, 6 2, 3 5 2, 3 1 1 x 2 0 or x 3 0 x 2 or x 3 2 3 x Ex. Find an equivalent expression for 2 12 . x 4x 4 3 x2 4 2 x 4x 4 3 x 2 3 x 2 x 2 x 2 x 2 x 2 1 1 Ex. Find the sum of reciprocals of 2 and 2 . x y x2 + y2 A.) Single Equations Ex. Solve the following for x: 1 x 3( x 2) 2( x 1) 1 2 1 x 3x 6 2 x 2 1 2 1 2 x 3x 6 2 x 3 2 x 6 x 12 4 x 6 7 x 12 4 x 6 3x 18 x6 Ex. If a = b(c + d), solve for d in terms of a, b, and c. a bc bd a bc bd a bc d b a bc a d or d c b b Ex. If 3 x 1 5 , then x = ? 3 x 6 x4 x 2 x 2 2 2 Ex. If 2x – 5 = 98, then 2x + 5 = ? 2 x 5 2 x 5 10 108 2 x 5 98 10 Ex. For what value of x is 3 6 5 x 3x 30 4 3 10 ? x 5 x 10 Ex. If y 5 x 2 3 , solve for x. y 3 5x2 y 3 x2 5 y 3 x 5 Ex. If x 2 4 125 , then x = ? x 2 121 x 2 121 x 11 2 2 x 3x 0 . Ex. Find the largest value of x that satisfies x 2 x 3 0 x 0 or 2 x 3 0 3 x 2 w 3 w 1 4 8 Ex. If , what is w? 2 2 w 3 2 2 w 3 2 3 w 1 2 3 w 1 2w 6 3w 3 2 w 3 3 w 1 w 9 B.) Systems of Equations/Inequalities Use appropriate method Substitution, elimination, graphing, matrices Ex. Solve for x and y if x + y = 10 and x – y = 2. x y 10 x y2 2 x 12 x6 6 y 10 y4 6, 4 Ex. If 3a + 5b = 10 and 5a + 3b = 30, what is the average of a and b? 3a 5b 10 5a 3b 30 8a 8b 40 8 ab 5 ab 5 2 2 5 2 READ, READ, READ, READ, and READ AGAIN!!! A.) Strategies 1.) Substitution i.e., “Plugging it in” Why??? - Numbers make more sense than letters. - Choose numbers easy to work with, but not 0 and 1. - 2,3,5, etc. are good choices for algebra problems. - Multiples of 100 for percent problems. - Multiples of 60 for time problems. When??? -You have NO idea how to do the problem -There is a variable in the question and the answers are all numbers -The problem is about “some number” and you have no clue as to what that number is. B.) Examples Ex. The price of an item in a store is d dollars. If the sales tax on the item is s%, what is the total cost of x such items, including tax? a.) xds b.) xds 1 xd s 1 c.) 100 d.) 100 x(d ds ) e.) xd ( s 100) 100 Let’s choose some numbers for d, s, and x. d 10 s 5% x 10 The total price for 1 item = 10 10(.05) $10.50 The total price for 10 items = 10 $10.50 $105.00 Which choice gives us $105.00? – Start with A xds 10 10 5 500 Obviously, B.) is out NO C.) xd s 1 10 10 5 1 6 100 100 NO D.) 100 x(d ds) 100 10 10 105 25000 NO xd ( s 100) E.) 100 10 10 (5 100) 105 YES!!! 100 Ex. Vehicle A travels at x miles per hour for x hours. Vehicle B travels a miles faster than Vehicle A, and travels b hours longer than Vehicle A. Vehicle B travels how much farther than Vehicle A, in miles? a.) x 2 ab 2 2 a b b.) c.) ax bx ab d.) x abx ab 2 e.) 2x2 a b x ab Let’s choose some numbers for x, a, and b. Vehicle A = 20 20 400 Vehicle B = x 20 a 10 b5 30 25 750 Vehicle B – Vehicle A = 750 400 350 By substitution – A.) x 2 ab 202 10(5) 350