Hydrology (CE 424) CHAPTER 4 Abstractions From Precipitation Instructor: Dr. Saleh AlHassoun -1 LOSSES FROM PRECIPITATION - Evaporation and transpiration are transferred to the atmosphere as water vapor. In engineering hydrology, runoff is the prime subject of study and evaporation and transpiration phases are treated as "losses “. - Before the rainfall reaches the outlet of a basin as runoff, certain demands of the catchment such as interception, depression storage and infiltration have to be met. If the precipitation is not available for surface runoff is defined as "loss" -2 Evaporation Process Is the process in which a liquid changes to the gaseous state(water vapor) at the free surface below the boiling point through the transfer of heat energy. *When some molecules possess sufficient kinetic energy, they may cross over the water surface. The net escape of water molecules from the liquid state to the gaseous state constitutes evaporation. •Evaporation occurs from : 1. Water bodies such as ….., 2. Soil : saturated, bare, vegetation -3 Influencing Factors 1. Vapor pressures at the water surface(es) and air above(e) : the rate of evaporation is proportional to the difference between the saturation vapor pressure at the water surface. 2. Air and water temperature(t ; tw) : the rate of evaporation increases with an increase in the water temperature. 3. Wind : the rate of evaporation increases with the wind speed up to critical speed beyond which any further increase in the wind speed has no influence on the evaporation rate 4. Atmospheric pressure: a decrease in the barometric pressure ( as in high altitudes), increases evaporation. -4 5. Quality of water: under identical conditions evaporation from sea water is about 2-3% less than from fresh water. 6. Size of water body : E ^ as A ^ Methods of Estimating Evaporation 1. Water budget( storage equation) method : ( P+ I ) - ( O + E ) = ΔS so E = I – O – ΔS + P 2. Energy budget method -5 3. Aerodynamic method : Dalton’s law E = C (es – e) E : rate of evaporation (mm/day) es : the saturation vapor pressure at the water surface; (milibar or mm of mercury) (mb or mm Hg) e : the actual vapor pressure of air (mb or mm Hg) -6 C : a coefficient depends on wind speed, atmospheric pressure and other factors, C= a+ bu a , b are constants ; u : wind speed (m/s) ; ( u2 : wind speed at height 2m.) Values of constants for different empirical methods Method Lake Hefner Meyer Harbeek -7 u E a b u Units of 0 0.122 u4 m/s mm/day 3.6 0.064 u8 m/s mm/day 0 0.29A^-0.05 u2 m/s mm/day Unit of Example : If E = f(u) (es – e) Given : C = f(u) = 0.14 u and : Δe = es - e = 5.6 mb. , u = 30 km/hr. What is daily E from lake ? Solution : Since C = a + bu so: a = 0 ; b = 0.14 u= 30 km/hr = 8.33 m/sec. E = 0.14(8.33)(5.6) = 6.53 mm/day or daily E = 6.53 mm. For lake Hefner method : a= 0 , b= 0.122 , u4 = 9.24 m/s. Then -8 E = 0.122(9.24) (5.6) = 6.3 mm/day . Evaporation Measurement 1. EVAPORIMETER CLASS A Evaporation Pan - - -9 The most widely used method of measuring or monitoring the water body evaporation. The standard National Weather Bureau Class A pan : ( 1.21 m diameter, 25.5 cm depth, it is placed on a wooden structure of 15 cm height). Pan Coefficient : Cp The actual evaporation from a nearby leak is less than that of pan evaporation Why ? - The sides of the pan is exposed to the sun. - The temperature over the pan is higher that over the lake. Lake evaporation = Cp pan evaporation E = Cp Ep Cp = pan coefficient = 0.7 for Class A Pan. -10 Evaporation Estimations Empirical Evaporation Equation Most of empirical formulae are based on the Dalton-type equation: E = Kf(u) (ew - ea) E = lake evaporation in mm / day, es = saturated vapor pressure at the water-surface temperature; e = actual vapor pressure of overlying air at a specified height; f(u) = wind-speed correction function and K = a coefficient. The term e is measured at the same height at which wind speed in measured. -11 Evaporation Estimations Meyer's Formula (1915): E = KM (es - e) ( I + u8/16 ) u8 = monthly mean wind velocity about 8 m above ground KM = coefficient of 0.36 for large deep waters and 0.50 for small, shallow waters The limitations of the formula that at best be expected to give an approximate magnitude of the evaporation. -12 Evaporation Measurement 1. Analytical methods The analytical methods for the determination of lake evaporation can be broadly classified into three categories as : I. Water-budget method, 2. energy-balance method, and 3. mass-transfer method -13 I. Water-budget method, It involves writing the hydrological continuity equation for the lake and determining the evaporation from a knowledge or estimation of other variables. Thus considering the daily average values for a lake, the continuity equation is written as: EL = P + (Vis-Vos) + (Vig-Vog) – TL – Δ S All quantities are in units of volume (m3) or depth (mm) over a reference Area. p,.Vis,Vos and Δ S can be measured. However, it is not possible to measure Vig,Vog and TL and therefore these quantities can only be estimated. -14 If the unit of time is kept large, say weeks or months, better accuracy in the estimate of EL is possible. In view of the various uncertainties in the estimated values and the possibilities of errors in measured variables, the water-budget method cannot be expected to give very accurate results. EVAPOTRANSPIRATION TRANSPIRATION Transpiration is the process by which water leaves the body of a living plant and reaches the atmosphere as water vapor. The water is taken up by the plant-root system and escapes through the leaves. The important factors affecting transpiration are : - atmospheric vapor pressure, - temperature, - wind, light intensity and -characteristics of the plant, such as the root and leaf systems. Measurement of T : -15 Phytometer EVAPOTRANSPIRATION Evapotranspiration takes place at the land where plants exist ; also lose moisture by the evaporation of water from soil and water bodies. In hydrology and irrigation practice, it is found that evaporation and transpiration processes can be considered advantageously under one term as Evapotranspiration. The term consumptive use is also used to denote this loss by evapotranspiration. -16 EVAPOTRANSPIRATION Equations Penman’s Equation Is based on sound theoretical reasoning and is obtained by a combination of energy-balance and mass-transfer approach. E = Δ/(Δ + γ) Qn + γ /(Δ + γ) Ea Measurement of ET : •Tanks •Lysimeters •Field Plots -17 Interception It is the segment of precipitation that is prevented to reach the ground by vegetation and subsequently evaporates rainfall Interception = Rainfall – stemflow – throughfall throughfall -18 stemflow Influencing Factors 1. Storm characteristics : rainfall intensity, duration, wind …etc 2. The vegetation : species, age, density of plants and trees 3. Season of the year: time of plant growing It is estimated of that : of the total rainfall in area during plant-growing season, the interception loss is 10-20 %. -19 % Rainfall Interception loss as Influencing Factors 100 80 60 40 20 5 10 15 20 30 Rainfall (mm) -20 Estimation of interception can be significant in annual or long-term models For heavy rainfalls during individual storm events interception is neglected Estimation of Interception Most interception loss develops during the initial storm period and the rate of interception rapidly approach to zero. Horton: Ii = Si + KEt Ii SI Ki E t -21 Li = 0.015+ 0.23 P (ash trees) Li = 0.03+ 0.22 P (oak trees) = the volume of water intercepted (mm) = the interception storage whose values varies from 0.25 to 1.5 depending on the nature of vegetation = ration of vegetal surface area to its projected area = Evaporation rate in (mm/h) during the precipitation = duration of rainfall in hours Depression Storage When the precipitation of a storm reaches the ground, it must fill up all depressions before it can flow over the surface The volume of water trapped in these depressions called depression storage -22 Influencing Factors -23 1. Type of soil : 0.50 cm for sand, 0.25 cm fro clay; 2. The condition of the surface : amount and nature of depression ; 3. The slope of Catchment ; 4. The soil moisture Infiltration Is the process by which precipitation moves down through the surface of the earth and replenishes soil moisture recharge aquifers, and ultimately support runoff quantities. Soil water zone – max depth from which water can be returned to surface through capillary action or ET. Gravitational water – flow direction is vertical due to gravity. (unsaturated zone or zone of aeration) Capillary zone, less than atmospheric pressure -24 Groundwater, saturation at atmospheric pressure Unsaturated zone Transmission zone, uniform moisture content, not saturated Wetting Front Infiltration Capacity Infiltration capacity (Ic): The maximum rate at which a given soil at a given time can a absorb water (cm/h) The actual rate of infiltration f can be expressed as : I = Ic when i ≥ Ic I = i when i < Ic Where i = the intensity of rainfall The infiltration capacity of a soil is high at the beginning of a storm and has and extensional decay at the time elapses. -25 Measurement of Infiltration There are two kinds of infiltrometers : 1. Flooding-type infiltrometer, and This is, a simple instrument consisting essentially of a metal cylinder, 30 cm diameter and 60 cm long, open at both ends. This cylinder is driven into the ground to a depth. Water is poured into the top part to a depth of 5 cm and a pointer is set to mark the water level. As infiltration proceeds, the volume is made up by adding water from from a burette to keep the water level at the tip of the pointer. Knowing the volume of water added at different time intervals, the plot of the infiltration capacity vs time is obtained -28 Horton’s Infiltration Model - If the rainfall supply exceeds the infiltration capacity, the infiltration tends to decrease in exponential manner I t I f ( I o I f )e kh t Where : fct : the infiltration capacity (depth/time) at any time t from the start of the rainfall ffc: a final or equilibrium capacity fco: the initial infiltration capacity Kh: a constant representing the rate of decrease in f capacity td: duration of the rainfall -29 -INDEX - index is determined for a single storm and not applicable to other storm and - Large storm on wet soil and Infiltration rate may be assumed to be relatively uniform - Volume losses includes the interception, depression storage and infiltration Runoff volume Intensity Volume Losses -30 Time Example 3.5 A storm with 10.0 cm precipitation produce a direct runoff of 5.8 cm given the time distribution of the storm as below, estimate the - INDEX of the storm? Time from start (h) Incremental rainfall in each hour (cm) -31 1 2 3 4 5 6 7 8 0.4 0.9 1.5 2.3 1.8 1.6 1.0 0.5 Solution: Total infiltration = 10.0-5.8 = 4.2 cm Assume the time of rainfall excess = 8 hr (for the first trail) Then Ф = 4.2/8 = 0.525 cm/h This value makes the rainfall of the first hour and eight hour ineffective as their magnitude is less than 5.25 cm/h. Assume the time of rainfall excess = 6 hr (for the second trail) Infiltration = 10-0.4-0.5-5.8 = 3.3 cm Then Ф = 3.3/6 = 0.55 cm/h and by calculating the rainfall excesses Time from start (h) 1 Rainfall excesses (cm) 0 -32 2 3 4 5 6 7 0.9-0.55 = 0.35 0.95 1.75 1.25 1.05 0.45 then total rainfall excesses= 5.8 cm. = total runoff 8 0