th 8 Grade Math Workbook Aligned to Durham Public Schools Curriculum Table of Contents Unit 1: Real Numbers 1.1 1.2 1.3 1.4 1.5 Classifying Real Numbers Operations with real numbers Exponents Scientific Notation Equations Unit 2: The Pythagorean Theorem 2.1 Proving the Formula 2.2 Solving for the missing side of a right triangle 2.3 Real word applications 2.4 Using the Pythagorean Theorem to find distance 2.5 Finding perimeter and area using distance Unit 3: Geometry 3.1 Transformations by Translation 3.2 Transformations by Reflections over x or y – axis 3.3 Transformation by Rotations 3.4 Dilations 3.5 Dilations with Transformations 3.6 Special Angles created by a transversal and two parallel lines 3.7 Volume of a Cylinder 3.8 Volume of a Cone 3.9 Volume of a Sphere Unit 4: Functions 4.1 What is a function? 4.2 Analyzing a real – life graph 4.3 Determining functions from graphs, maps, and points 4.4 Graphing points Unit 5: Linear Equations 5.1 Graphing using an input/output table 5.2 Graphing using the linear equation 5.3 Graphing Horizontal and Vertical lines 5.4 Graphing by solving the linear equation 5.5 Writing the equation of a line from a graph 5.6 Writing the equation of a line from the slope and a point 5.7 Writing the equation of a line from two points 5.8 Writing the equation of a line from a table 5.9 The linear equation in real life scenarios 5.10 Scatterplots and how do they correlate 5.11 Experimenting with Scatterplots Unit 6: Systems of Linear Equations 6.1 Solving by graphing 6.2 Solving using substitution 6.3 Solving special situations 6.4 Solving real life scenarios 1.1 Classifying Real Numbers When you first started to learn how to count you started with 1 then 2, 3, and so forth. Then a little later as you progressed in school you learned that the first number was 0 then 1, 2, 3, and so forth, which are called whole numbers. Next you learned that there were numbers 6 between 1 and 2 like 1.2 or which are called rational numbers. 5 Finally, in the sixth grade came the other side of numbers called negative numbers like -1, -2, -3 and so forth or integers. Now is the last set of numbers that makes up the real numbers which are irrational numbers. These are numbers like rational numbers as they are in between whole numbers, but cannot be turned into a fraction like √8 or π. Below is a diagram of real numbers: REAL NUMBERS Rational Numbers Irrational Numbers .25 -1 .3̅ -2 -3 Whole Numbers -4 2 3 4 5 -7 π 4 0 1 -5 1.625 1 Integers 1 √2 3 √15 -6 -8 13 8 or 1 5 8 √8 √32 *It is important to understand that a number can belong to more than one group and where it starts you work your way out. For example 1 starts as a whole number but as you work your way out you see integers and rational numbers. So 1 belongs to the set of whole, integer, and rational numbers. Directions: Define each vocabulary word based on the reading and in your own words on a separate sheet of paper. 1) Whole Numbers 2) Integers 3) Rational Numbers 4) Irrational Numbers 5) Real Numbers Directions: Based on your definitions create a matching multiple choice section. Please follow the model below: 6) _____ Whole Number a. your definition for any vocab word 7) _____ Integer b. your definition for any vocab word 8) _____ Rational Number c. your definition for any vocab word 9) _____ Irrational Number d. your definition for any vocab word 10) _____ Real Number e. your definition for any vocab word Directions: Classify each number as either a whole, integer, rational, or irrational. It is possible for a number to belong to more than one group. 11) 5 19) 20 5 12) -8 13) 1.3 20) - √3 14) √84 15) 2π 22) 2.4̅ 23) 3 21) 0 1 2 16) -1.8 17) 24) 0.37654 2 8 25) 18) √16 8 2 ** EOG Prep** 26) Look at the following diagram and circle which numbers are not in the correct group and explain why? Rational 2.5 -8 √12 2 7 Irrational √49 5π ̅̅̅̅ .78 √4 7 2 -3.25641 1.2 Operations with Real Numbers (Integers) When adding or subtracting integers the most important thing to understand is calculators do not apply. It is important to realize that for those of us who want to go to college you will be expected to take either the SAT or ACT which is a timed test and spending time to type in a basic operation in the calculator is not going to led to a promising score. So below I will give some basic rules that you need to practice until you have them down. Adding or Subtracting Do not worry about if it tells you to add or subtract simply look at the two numbers and if the signs are the same you add and if they are different you subtract. Same Example 1: 4 + 5 = 9 Example 2: -4 – 3 = -7 Both the 4 and 5 are positive both 4 and 3 are negative Different Example 3: 5 – 8 = -3 Example 4: -6 + 8 = 2 The 5 is positive but the 8 is negative The 6 is negative and the 8 is positive Subtract 8 and 5 which is 3 but it is a Subtract 8 and 6 which is 2 but it negative 3 because 8 is bigger than 5 is a positive 2 because 8 is bigger ** The only problem you have to be careful on is when you are subtracting a negative number for example: 5 – (-2) = 7 because when you have two negative signs side by side they actually turn into a positive. 5 – (-2) 5 + 2 = 7 Multiplying or Dividing When multiplying or dividing if the numbers have the same sign the answer will be positive. If the numbers have different signs then the answer will be negative. *Only true looking at 2 numbers at a time.* Example 5: (-5) • (-8) = 40 Both the 5 and 8 are negative so they have the same signs so the product was a positive 40 Example 6: −32 4 = -8 The 32 is negative and the 4 is positive so the signs are different so the quotient was a negative 8 Directions: State whether you will add or subtract the following problems. You do not need to solve the problems. Put all your answers on a separate sheet of paper. 1) -6 + 10 2) 5 + 9 3) -2 – 8 4) -4 + (-3) 5) -3 – (-2) 6) 9 – 12 Directions: Create 2 addition and 2 subtraction problems that equal -4. 7) 8) 9) 10) Directions: Solve the following operations. 11) -5 – 8 = ___ 12) -6 + (-2) = ___ 13) 7 – 9 = ___ 14) 8 + (-7) = ___ 15) 1 – (-3) = __ 16) 12 – 5 = ___ 17) -9 + 3 = ___ 18) -5 – (-9) = ___ 19) 2 – 5 = ___ 20) -7 + (6) = ___ 21) 3 – 5 + 9 + 1 = ___ 22) 6 – 5 – 4 – 2 = ___ Directions: State whether you will have a positive or negative product or quotient. You do not need to solve the problems. 23) (-4) • (-7) 24) 5 • (-3) 25) -5 • 2 26) 48 ÷ (-9) 27) 40 10 28) −18 −3 Directions: Create 2 multiplication and two division problems that will equal – 6. 29) 30) 31) 32) Directions: Solve the following operations. 33) -9 • 8 = ___ 34) (-3) (-4) = ___ 35) 7 • (-5) = ___ 36) 12 • 6 • (-2) = ___ 37) −42 7 = ___ 38) −72 −6 = ___ 39) 108 9 = ___ 40) 36 ÷ -3 ÷ -2 = ___ 1.2 Operations with Real Numbers (Fractions) Fractions for whatever reason make many students nervous or even force students to simply give up (IDK). However the fact remains that if you know your multiplication table at least up to 12 dealing with fractions may take a little more time, but they are not hard. The keys to dealing with fractions are below: If adding or subtracting you need to find a common denominator first If multiplying simply multiply the numerators then the denominators 2 Always make a mixed number like 1 into an improper fraction by 5 multiplying the whole number to the bottom number and adding the top 7 number so you get 1 • 5 = 5 + 2 = 7 5 Example 1 Example 2 Converting a decimal to a fraction. Adding or Subtracting Fractions ̅̅̅̅ .45 .25 3 25 Repeating is 100 Reduce by dividing 4 5 + =? 9 Step 1: Find a common denominator by mult. the not over 100 bottom numbers or finding the first number that 4 and 9 ÷25 biggest number it is 1 less 45 that goes into both both go into. ÷9 99 4 • 9 = 36 Step 2: Rename (new numerators) the two fractions with 36 as their denominator 1 5 4 11 3 4 Example 3 27 36 because 4 • 9 = 36 so I had to multiply 3 • 9 to get 27 Multiplying 3 5 Dividing (KCF) 5 3 6 5 • =? Multiply Numerators then denominators. 3 So you get 15 30 reduce ÷ 15 5 1 2 20 5 9 6 Because 9 • 4 = 36 so I had to multiply 5 • 4 to get 20 ÷ =? Keep the first fraction change division to mult. and flip 2nd fraction 3 • 5 = 15 and 5 • 6 = 30 5 Step 3: 6 18 27 5 25 36 • = 36 + 20 36 Add the renamed fractions = 47 36 and that is it because it cannot be reduced Directions: Convert each decimal to a fraction. Make sure to show your work and always reduce when necessary. 1) .43 2) .7 ̅̅̅̅ 4) .23 3) .6 ̅̅̅̅ 5) .57 6) .6̅ 7) .28 8) 2.3 Directions: Convert each fraction to a decimal. Make sure to simply divide the numerator by the denominator until there is no remainder left. 2 Example: 5 5 2 5 cannot go into 2 so you put a decimal behind it and add a 0 5 2.0 5 goes into 20 exactly 4 times so the answer is 0.4 or .4 9) 4 10) 5 5 8 11) 7 12) 5 3 *13) 10 5 6 Directions: Simplify each fraction by either adding or subtracting. Remember you must have a common denominator to add or subtract. 1 4 2 5 14) + = ? 7 2 8 3 18) – =? 2 1 3 4 15) + = ? 6 1 7 4 19) – = ? 5 3 8 4 16) + = ? 20) 9 10 3 – =? 4 3 1 5 6 17) 1 + 3 = ? 2 5 5 8 21) 2 – = ? Directions: Simplify each fraction by either multiplying or dividing. 2 5 3 6 6 2 7 3 22) • = ? 26) ÷ = ? 8 1 5 2 8 1 9 3 23) • = ? 27) ÷ = ? 4 6 9 11 5 3 2 8 24) • =? 28) ÷ = ? 2 1 7 4 25) • 3 = ? 29) **EOG Prep** ̅̅̅̅ as a fraction in lowest terms. 30) Write the decimal .36 12 5 1 ÷3 =? 2 1.3 Exponents (Simplifying, expanded form, 0, and negative exponents) When you began learning math you learned that 2 + 2 + 2 = 6 and then you learned instead of adding all these you could have simply multiplied. Since there are three two’s you could have done 2 • 3 which still equals six and means the same thing. Now you are going to learn a shortcut for multiplication which is exponents. For example instead of saying 2 • 2 • 2 = 8 you could have said 23 which is still 8 since there are three two’s. Below is a diagram that represents exponents. 2 5 Base Exponent 25 is in exponent form to put it in expanded form you simply need to write out how many times the base is getting multiplied. 25 expanded form = 2 • 2 • 2 • 2 • 2 and simplified form would be doing the math. Exponent form: 25 = Expanded form: 2 • 2 • 2 • 2 • 2 = Simplified: 32 ** Exponent Rule 1: Anything to the 0 power = 1** Example 20 = 1 -20 = -1 Directions: Put each expanded form problem into exponent form. 1) 3 • 3 • 3 • 3 2) –(2 • 2 • 2 • 2 • 2 • 2) 3) 5 • 5 4) –(4 • 4) Directions: Write each exponential expression in expanded form. 4) 15 5) 43 6) -37 7) 51 8) 28 9) -34 10) 72 Directions: Simplify each exponential expression. 11) 24 12) 33 18) -70 19) 22 13) -43 20) 53 14) -26 21) .250 15) 92 16) 27 17) 40 22) -1.2520 **Exponent Rule 2: Negative exponents mean the base is in the wrong place. In order to make the exponent positive you must flip the base in other words if it is in the numerator take the base and exponent to the denominator and the exponent will be positive. If it is in the denominator take the base and exponent to the numerator and the exponent will now be positive.** Examples 1 Example 2 2-3 because the exponent is negative you must flip the base. The 2 is in the numerator so take it to the denominator then the -3 will become positive. This happens because a negative exponent means the base is in the wrong place. 1 1 1 2-3 23 2•2•2 8 Exponent Expanded Simplified 1 2−4 Negative exponent so flip base 24 2•2•2•2 16 Directions: Simplify the following problems. Show the exponent form, expanded form, and simplified form. 23) 3-2 24) 4-3 25) 7-2 26) 1 2−5 27) 1 4 −2 1.3 Exponents Operation Rules The purpose for rules in math is to allow short – cuts to simplify or solve problems faster. However the key thing to any rule is the fact that it requires memorization. In life you are going to memorize many things such as social security numbers, passwords for school or email, and the list goes on. Now you could simply write all these on a piece of paper and carry it with you at all times to prevent memorizing it, but in the end it is just easier to memorize the needed information. Math is no different memorization is something in your control that just makes math easier. Rule 3: Multiplying with like bases Example: 23 • 22 = ? 2•2•2 2•2 if you count the number of 2’s you get 5 so the answer is 25 The short – cut to this problem is when you have the same base and are multiplying all you need to do is to add the exponents and keep the same base (do not change the base) Rule 4: Dividing with like bases Example: 27 23 expanded form below 2•2•2•2•2•2•2 24 2•2•2 The short – cut to this problem is when you have the same base and are dividing all you need to do is to subtract the exponents and keep the same base. Rule 5: Raising an exponent to an exponent Example: (24)3 The three as the exponent outside the parenthesis is simply saying you multiplying three sets of 24 (24)•(24)•(24) (2•2•2•2)(2•2•2•2)(2•2•2•2) if you count up the 2’s you should see 12 so the exponential answer is 212 The short – cut to this problem is to simply multiply the exponents and keep the same base. Directions: Simplify each question making sure to give the exponential answer and simplify it to a number in standard form. 1) 33 • 32 7) 29 23 14) (23)2 2) 2-3 • 2-4 8) 37 32 9) 15) (34)2 3) 3 • 32 85 87 10) 16) (58)0 4) 53 • 5-5 23 2−3 11) 5) 42 • 4-6 3−1 12) 33 17) (4-1)3 6) 210 • 2-7 25 13) 29 18) (9-2)-1 60 6−2 19) (24)-3 Review Sections 1.1 – 1.2 20) Which group or groups does – 5 belong? 21) Which group or groups does √20 belong? 22) 8 – 11 = ? 23) -2 – 4 = ? 24) -7 + (-2) = ? 25) -9 • 8 = ? 26) −84 −12 27) (-4)(-2)(-3) **EOG Prep** 28) In the list belong group the numbers as whether they are rational or irrational. ̅̅̅̅, 3, 9, - 1 , √64 2−3 , √40 , -3π, 1.37 5 2 ̅̅̅̅ as a fraction in lowest terms. 29) Write .21 30) Write .3̅ as a fraction in lowest terms. 31) Write .35 as a fraction in lowest terms. 32) Simplify 23 • 25 • (22)-3 33) 35 4−2 33 42 34) 2−3 25 38 26 32 34 35) 24 5−2 2−1 5−5 1.4 Scientific Notation (Writing, standard form, operations) Scientific notation is basically an easier way to write a very large or small number. For example when measuring a large distance like from one planet to another planet scientific notation does not require you to write out all the 0’s instead you can used a shortened form called scientific notation. For example the distance from earth to Neptune is 2,900,000,000 miles. In scientific notation I can write the same number like this: 2.9 x 109. Meanwhile for a small number like the size of a nucleus which is 0.0000000000000025 meters can be written in scientific notation as 2.5 x 10-15. Below is a more descriptive analysis of scientific notation. The Exponent tells you how many times you have to move the decimal in order to make it a single digit number. Also a positive exponent means a big number while a negative exponent means a small number. 8.2 x 107 The first number is always between 1 and 9.9 in other words it must be a single digit number. The x 10 relates to moving the decimal because we use a base 10 number system Multiplying with Scientific Notation Dividing with Scientific Notation (2.3 x 105) (5.2 x 106) Remembering your exponent rules this is a multiplication problem with like bases as they are both 10 so you can add the exponents. Then you need to multiply the single digit numbers. 5.2 X 2.3 156 After multiplying we have two numbers after the decimal so your answer should have 1040 two numbers after the decimal 1196 1011 11.96 x The only problem is 11.96 is a two digit number so we have to move the decimal one more time which will also change the exponent by 1 1.196 x 1012 1.2 𝑥 104 1.5 𝑥 107 Remembering your exponent rules this is a division problem so exponents must be subtracted. Then you need to divide the single digit numbers. 15 12.0 First 1.5 turns to 15 by moving the 120 decimal 1 to the right so we do the 0 same thing for 1.2. Now 15 does not go into 12 so we put a decimal carry it up and add a 0. 15 goes into 120 exactly 8 times so we get 0.8 0.8 x 10-3 Must move decimal 1 time and change the exponent by making it 1 smaller 8.0 x 10-4 Directions: Write each number that is in standard form in scientific notation. 1) 5,100,000 2) 423,000,000,000 3) 185 4) 50,200 5) 1,750 6) 807,540 7) .00034 8) 0.024 9) 0.00000000000423 10) .0000072 11) 0.49 12) .0007 Directions: Write each number that is in scientific notation in standard form. 13) 5.6 x 10-2 14) 7.5 x 108 15) 2.35 x 105 18) 2.8 x 103 19) 6.408 x 107 16) 8.257 x 10-4 20) 9.9 x 10-6 21) 5.0002 x 102 17) 9.4 x 106 22) 3 x 104 Directions: Simplify the following scientific notation multiplication problems. 23) (3 x 104) (2 x 103) 24) (2.4 x 105) (1.2 x 106) 26) (2.3 x 10-2) (4 x 107) 27) (2.6 x 106) (5 x 107) 25) (3.5 x 10-4) (2 x 10-3) 28) (6 x 10-2) (5 x 108) Directions: Simplify the following scientific notation division problems. 29) 33) 9 𝑥 104 4 𝑥 108 8.4 𝑥 107 2.5 𝑥 10−4 30) 34) 8 𝑥 105 −3 2 𝑥 10 9.2 𝑥 109 4.5 𝑥 102 31) 35) 6.2 𝑥 10−3 2.1 𝑥 107 7.22 𝑥 10−8 5 𝑥 106 32) 36) 7 𝑥 10−5 3.5 𝑥 10−3 3 𝑥 109 5 𝑥 10−3 **EOG Prep** 37) In the list belong group the numbers as whether they are rational or irrational. 9 - 18, √4 , π, 3.14, - , 9, √18 , 2√81 5 ̅̅̅̅ as a fraction in lowest terms. 38) Write 0.24 39) Simplify 40) Simplify 23 •2−5 •52 25• 54 (2-2)3 41) The moon has 3.2 x 109 cubic feet of moon rock on its surface if the surface area is 1.4 x 1015 feet2 how many moon rocks are on the moon? 1.5 Equations (one and two – step equations) Equations are the foundations of Algebra as an equation is simply solving for something that is not known. In math and life you have many unknowns, but for math there is a definite solution for the variable while in life many people simply just go for it. The only problem with that is if you make the wrong choice you simply cannot go back and correct the problem like in math. The idea behind equations at this point in time is to get a student to think logically about all the possible ways to solve a problem so that can be taken forth in life to make the right choices by thinking about all the possible consequences behind each choice. 3 Rules to Solve Equations 1. Isolate the variable (Draw a line down the equal sign and determine what side the letter is on either the left or the right of the line) 2. Use Inverse operations (Once you know what side the letter is on begin getting rid of everything on that side by using opposite operations) 3. Do the Same thing to both side (If you do something to one side of the equation you must do the same thing on the other side) One – step Two – step 1) x + 4 = -2 2) 5 = x – 8 3) 3n = 12 4) x + 4 = -2 5=x–8 3n = 12 (2) - 4 -4 x =-6 +8 13 = x +8 3 3 n=4 𝑛 2 𝑛 2 = -7 = -7 (2) n = - 14 𝑥 5) 2x + 3 = -5 6) 4 = – 2 7 2x + 3 = -5 -3 -3 2x = -8 2 2 x = -4 𝑥 4= –2 7 +2 6= +2 𝑥 7 𝑥 (7)6 = (7) 7 42 = x Directions: Solve the following one – step equations. 1) n + 3 = -7 6) 3p = 6 12) 𝑚 3 = -5 2) 12 = n – 3 7) -2p = -14 13) - 𝑚 2 3) 4 + n = 1 8) 12 = -p =8 14) -6 = 4) -2 = 6 + n 9) -20 = 5p 𝑚 𝑚 15) -3 = - 4 6 5) 7 = n + 4 10) 32 = -2p 16) 𝑚 5 = 12 11) -40 = -8p 17) – 9 = 𝑚 8 Directions: Solve the following two – step equations. 18) 2w – 7 = 9 𝑛 22) + 8 = -2 7 1 27) 4 – p = 7 2 19) -14 = 4m + 6 𝑧 23) 12 = + 7 3 20) 8 – 2x = 10 𝑘 24) 6 - = - 2 2 28) 13 = x + 5 3 4 21) -17 = 5 – 2y 25) 9 = 5 + 29) -1 = 8 + 4m 𝑡 8 26) 5 – n = -1 3 30) w – 9 = 3 4 Directions: Solve for y. Use the same rules to get y all by itself. 31) ay = t 32) y + t = r 33) 4 = y – x 34) h = 𝑦 𝑛 35) x – ay = t 36) 𝑦 𝑤 +r=7 Directions: Write the equation then solve. 37) Four less than a number is six 38) Five more than twice a number is eleven 39) The quotient of a number and eight is negative five 40) Three more than the product of a number and six is twenty-one **EOG Prep** 41) What group or groups of numbers does -21 belong to? 42) Write 0.2̅ as a fraction in lowest terms. 43) Simplify to a fraction in lowest terms. 33 61 3−1 63 44) Lake Erie has a surface area of 3.2 x 105 kilometers if there are 2.8 x 102 bottles of water for each kilometer how many bottles of water are in Lake Erie? 1.5 Equations (distribute, combine like terms, variables on both sides) Now that you know how to solve the most basic equation it is time to build to a more realistic equation. However it is important to remember the 3 rules as they do not change and every equation will come down to those basic equations as you solve it. Example 1: Distribute Example 2: Combine like terms The word distribute means you need to multiply typically the number that is outside a parenthesis to everything in the parenthesis. Like terms simply means you have two like terms on one side of the equation that can be combined whether it is numbers or letters. 2(x – 4) = 6 4x – 6 + 3x = 8 Step 1: Distribute 2(x – 4) = 6 4x – 6 + 3x = 8 2x – 8 = 6 7x – 6 = 8 Step 2: Draw your line and begin getting rid of everything on the same side as the letter 2x – 8 = 6 +8 +8 2x = 14 2 2 x = 7 Step 1: combine like terms Step 2: get rid of all +6 + 6 terms on same side as x 7x = 14 7 7 x =2 *Notice when I combined like terms I circled the sign in front of the letter because that is part of that term. Example 3: Variables on both sides 4x – 5 = 7x + 10 Step 1: Draw the line and begin moving any term you want. I -4x -4x will move the 4x first so it will be a two – step equation. - 5 = 3x + 10 -10 -10 -15 = 3x now divide by 3 and you find that x = -5 Directions: Solve the following equations using the distributive property. 1) 3(x + 5) = 6 5) -8 = 4(x + 1) 2) 2(3x – 4) = 4 6) 10 = -5(x + 4) 3) 4(6 – x) = 12 4) -2(x – 5) = -6 7) 13 = 2(6 – 4x) 8) 9 = -3(x – 5) Directions: Solve the following equation by combining like terms. 9) 3x – 8 + 2x = 7 10) 12 = 6x + 7 – x 13) 8 – 2x + 13 = -1 14) 9 = 7 + 5x – 8 11) 4x – 7 – 6x = 13 15) 18 = 8 – 4x – 2 12) -6 = 8 – 3x – 4x 16) 3 + 7x – 8 = 16 Directions: Solve the following equations with variables on both sides. 17) 3n – 8 = 5n + 2 18) 7 – n = 4n + 12 19) 6n + 8 = 3n – 13 20) -7 + 2n = 8 – n 21) 12 + 6x = 4x – 14 22) n – 9 = 5n + 11 23) 2 + 7n = 6n – 3 24) 5n – 17 = 3n + 1 **EOG Prep** 25) Solve. 1 2 (4x – 12) + 3x – 10 = 6 – 4(2x – 9) + 5x + 3 26) Classify the following number into its correct group or groups. 9 27) Simplify. 25 3−2 3−4 22 ̅̅̅̅ 28) Write as a fraction in lowest terms. .72 29) It was found that the average home has 1.2 x 104 dust particles for every square foot. If the average house is 1.5 x 103 square feet how many dust particles are in the house? 30) Solve. Five multiplied by the sum of six and a number is equal to twice the number less than nine. Unit 1 Basic Test Directions: Match the word to its correct definition. 1) ___ Irrational a. A number that can be made into a fraction 2) ___ Whole Number b. Any number that can be a fraction or not 3) ___ Rational Number c. A counting number that can be positive or negative 4) ___ Integer d. A number that cannot be made into a fraction. 5) ___ Real Number e. The counting numbers including 0. Directions: Classify the number into the correct group or groups of real numbers. 7) √18 6) -8 8) 50 9) 5 6 Directions: Identify which numbers are rational numbers and which numbers are irrational numbers in the list below. 4 1 7 5 16.2, - , √6 , 33 , 2-3 , 4π, 3.2̅ , 2 , -2√10 10) Directions: Simplify the following rational numbers. 11) 5 – 9 = __ 12) -3 – 7 = __ 13) -5 – (-7) = __ 14) -8 + 7 = __ 15) 2 + (-8) = __ 16) (-4) • (-6) = ___ 17) (7) (-9) = ___ 18) (-2) (-3) (-5) = ___ 19) 20) −36 = ___ 21) −4 −2 8 18 −3 = ___ 3 5 2 5 4 6 3 6 = ___ 22) 5 – 3 • 7 + 2 = ___ 23) + = ___ 24) 2 – = __ 7 2 6 3 8 3 7 8 25) • = ___ 26) ÷ = ___ Directions: Write the following exponential numbers in expanded form. 27) 45 = 28) 7-2 = 29) -24 = 30) 3-6 = Directions: Write the following numbers in standard form or exponential form if the number is greater than 100. 31) 43 • 44 = 32) 22 • 2-5 = 33) (53)-2 = 34) (26)0 = 35) 23 = −6 36) 2 3−1 32 = Directions: Write the following numbers in scientific notation. 37) 1,200,000 38) .00000000973 39) 401 40) 0.0008 Directions: Write the following numbers in standard form. 41) 2.3 x 107 42) 1.52 x 10-3 43) 7.524 x 104 44) 3 x 10-8 Directions: Simplify and make sure your final answer is in scientific notation. 45) (4.2 x 105) (2 x 103) 46) (3.12 x 10-4) (2.3 x 10-8) 47) 8.2 𝑥 103 2.1 𝑥 109 48) 9.24 𝑥 10−5 1.5 𝑥 102 Directions: Solve the following equations. 49) x – 3 = -7 54) 13 = 2m – 1 58) 3(a – 6) = 9 50) 8 = -2x 51) n + 7 = -2 55) -6 = 10 – 2w 52) 9 = 56) 9 – 𝑝 5 𝑛 4 =3 59) 8 = -2(4v – 3) 60) 3x – 7 = x + 9 62) 6 – 5g = 13 + 2g 63) 5n – 8 = n 1 64) n – 7 = 5 2 𝑟 53) + 8 = -2 4 57) 4n – 7 + n = 8 61) 19 = 6 – 4h + 1 3 65) w + = -2 4 Unit 1 EOG Test 1) Solve. 1 3 (3x – 12) + 3x – 10 = 6 – 4(3x – 5) + 5x + 4 2) Write the equation and solve. The difference of a number and four multiplied by 6 is equal to eight less than four times the number. 3) Solve. 4 + 2(3n – 7) = n – 3(4n – 9) 4) Classify the following list of real numbers as either rational or irrational. 5 12 9 4 ̅̅̅̅ , -13, 3√5 , -7π , ,0. 78 , 3.8 , √25 5) Classify the following number into the correct group or groups. 6) Simplify. 7) Simplify. -7 28 3−5 3−3 22 23 27 32 3−4 39 25 ̅̅̅̅ 8) Write as a fraction in lowest terms. 0.24 9) Write as a fraction in lowest terms. 0.5̅ 10) At the end of the day the average person has 2.5 x 104 bacteria in their mouth for every square foot. If the surface area of the average human mouth is 1.2 x 105 millimeters how many bacteria are in the human mouth at the end of the day? 11) Find the value of x. 2𝑥−8 3 = 12 2.1 Proving the Pythagorean Theorem The illustration above simply proves how the squares of the sums of each leg of a right triangle will always equal the square of the hypotenuse. Vocabulary (3 things to know) Hypotenuse – is always the ___________________ side in a right triangle Hypotenuse – is always _____________________ the right angle Hypotenuse – is always the ___________________ side of a right triangle. Example 1: Determine if the sides make right triangle using the Pythagorean Theorem. 4, 8, 5 *8 must be the hypotenuse a2 + b2 = c2 (4)2 + (5)2 = (8)2 16 + 25 = 64 41 = 64 This is not true as 41 does not equal 64 so this is not a right triangle. Example 2: Determine if the sides make a right triangle using the Pythagorean Theorem. 5, 12, 13 a2 + b2 = c2 (5)2 + (12)2 = (13)2 25 + 144 = 169 169 = 169 This is a right triangle as both sides equal the same number. Directions: Determine if the following sides of a triangle will make a right triangle by using the Pythagorean Theorem. 1) 5, 3, 4 2) 9, 10, 12 3) 4, 10, 11 4) 6, 10, 8 5) 7, 9, 15 6) 25, 24, 7 7) 9, 30, 31 8) 16, 12, 9 9) 2.5, 3.2, 7 10) 3 2 1 , , 10 5 4 11) 24, 26, 10 12) 1, 2, 6 Review: Unit 1 Scientific Notation and exponents Directions: Simplify. -4 -5 13) (3.5 x 10 ) (3 x 10 ) 17) 42 14) 8.45 x 108 18) (4.1 x 103) (2.3 x 102) 4 −5 15) 2-5 • 22 2.5 x 103 19) 7 𝑥 104 16) (32)-3 20) 33 • 3 4 𝑥 105 Review: Unit 1 Real Numbers 21) -5 – 8 = ? 3 5 4 6 8 2 9 3 25) – = ? 29) ÷ = ? 22) (-3) (-5) (-6) = ? 1 3 3 5 26) 2 + = ? 23) -4 + (-2) = ? 7 4 8 9 27) • = ? 24) 6 – (-1) = ? 1 28) .28 • = ? 2 30) What group or groups of real numbers does 12 belong? Review: Unit 1 Equations 31) 4 – 7x = -10 34) 6(n – 4) = -6 32) -8 = 3t + 10 – t 𝑛 35) + 6 = -2 5 33) 4n – 9 = 7n + 12 36) 2 – 3(x – 5) = -7 2.2 Finding the missing side n 15 12 The diagram above shows a right triangle with an unknown side. Since it is a right triangle immediately we should go to the Pythagorean Theorem. The KEY to using this formula is to make sure you know what to plug in for the hypotenuse as mixing up the legs will not change your solution. a2 + b2 = c2 n2 + (12)2 = (15)2 n2 + 144 = 225 at this point it is like solving an equation so let’s get the letter by itself - 144 - 144 n2 = 81 in order to get the letter by itself we must get rid of the exponent (2) n2 = 81 n =9 by doing the opposite which is called the square root (√ ) the square root gets rid of the 2 as an exponent and breaks 81 down to 9 because 9 • 9 or 92 is 81 so the 2 is now gone and what is left is 9 Directions: Fill in the table that shows square roots and perfect squares 1) # #•# 1 2 1 •1 2•2 Perfect Square Square Root 1 4 1 2 3 4 5 6 7 8 9 10 11 12 13 14 Directions: Define each vocabulary term in your own words based on your knowledge of the example and table. 2) What is a Perfect Square? 3) What is a Square Root? Symbol? 4) What is a Perfect Cube? 5) What is a Cube Root? Symbol? 6) What 3 things do you know about the hypotenuse? Directions: Find the square root of the following numbers. 7) 25 8) 64 9) 121 10) 81 11) 196 12) 1 13) Which 2 numbers in the table are perfect cubes? (when you do the cube root you will get a whole number) Directions: Estimate what two whole numbers between the square root of the following irrational numbers. Example √32 Look at the table and find the 2 perfect squares that 32 is between. 25 and 36 The √25 = 5 and the √36 = 6 So the √32 is between 5 and 6 14) √8 17) √96 15) √45 16) √72 18) √118 19) √24 Directions: Find the missing sides. 20) 12 21) 13 24 25 2.3 Real World Applications of the Pythagorean Theorem Typically most people do not even give the Pythagorean Theorem any thought in life instead we simply guess and test most of the time like when putting a ladder against a wall or dropping an anchor. With these examples we simply guess and test it out then again and again until we have these in the right spot. This seems simply enough, but time might have been saved if you would have used the Pythagorean Theorem to determine exactly where you wanted the ladder or anchor. If you look up you will see something you cannot guess and test. The roof above many of your heads is based on the Pythagorean Theorem based on the load (weight) it can hold using this formula along with the pitch (slant) needed to repel weather. The wrong pitch of the roof can actually lead water to defy gravity and curl up the roof until it destroys the roof. Example 1 Example 2 A firefighter has to reach a window that is 12 feet off the ground. If the ladder is 13 feet how far from the house will he need to put the ladder? An anchor is dropped from a boat and the length of the anchor is 15 feet. When the anchor was dropped the boat floated another 9 feet before stopping, what is the depth of the water? **Key** A ladder is laid slanted against a house and the hypotenuse is always slanted. house 12 **Key** The length of the anchor will be slanted as the boat floats till it stops and slanted is the hypotenuse. 13 n Ladder 9 n 2 2 2 a + b = c plug in what you know (12) + n = (13) 144 + b = 169 2 2 2 2 - 144 15 a2 + b2 = c2 plug in n2 + (9)2 = (15)2 n2 + 81 = 225 - 81 - 144 b2 = 25 sq. root n = 5 anchor n2 - 81 = 144 sq. root n = 12 Directions: Solve the following real life scenarios using your knowledge of the Pythagorean Theorem.