2012 YEAR 12 MID-YEAR EXAMINATION
PHYSICS – MAPPING GRID
Exam Section
Question
Part A:
Multiple
Choice
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
Part B:
Free Response
Marks
Syllabus/Course
Outcomes
Content
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
7
7
4
7
6
5
6
6
7
H9
H6, H9
H9
H6, H9
H2, H6
H6, H9
H2, H6
H3, H9
H6, H9
H2, H9
H12
H3, H9
H3, H7
H7, H9
H10
H9
H9, H10
H2, H9
H7, H10
H3, H5
H6, H9
H2, H6, H9
H1, H3, H6
H3, H7, H9
H7, H9
H3, H7, H9
H3, H10, H11, H13
H2, H9
H1, H2, H5, H10, H12
9.2.1
9.2.2/ 9.2.3
9.2.2
9.2.2
9.2.2
9.2.1
9.2.2
9.3.1
9.3.1
9.3.1
9.3.1
9.3.1
9.3.2/ 9.3.3
9.3.5
9.4.2
9.4.1
9.4.1
9.4.2
9.4.1
9.4.3
9.2.2
9.2.2
9.2.4
9.3.1 / 9.3.2
9.3.4
9.3.1 / 9.3.2
9.3.3
9.4.2 / 9.4.3
9.4.1
Targeted
Performance
Bands
2-4
3-5
3-5
3-5
2-4
2-4
4-5
2-4
4-6
3-4
4-5
2-3
3-4
4-5
3-5
3-5
3-5
3-4
3-4
4-5
2-5
2-6
2-6
2-5
2-5
1-5
2-5
2-5
3-5
Answer
C
D
B
C
A
A
B
D
C
B
D
A
B
D
B
B
A
D
A
C
Disclaimer
Every effort has been made to prepare this Examination in accordance with the Board of Studies documents. No guarantee or warranty is made or
implied that the Examination paper mirrors in every respect the actual HSC Examination question paper in this course. This paper does not constitute
‘advice’ nor can it be construed as an authoritative interpretation of Board of Studies intentions. No liability for any reliance, use or purpose related to
this paper is taken. Advice on HSC examination issues is only to be obtained from the NSW Board of Studies. The publisher does not accept any
responsibility for accuracy of papers which have been modified.
MYPHY12_GUIDELINES
1
2012 YEAR 12 MID-YEAR EXAMINATION
PHYSICS – MARKING GUIDELINES
Part A – 20 marks
Questions 1-20 (1 mark each)
Question
Correct Response
Outcomes Assessed
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
C
D
B
C
A
A
B
D
C
B
D
A
B
D
B
B
A
D
A
C
H9
H6, H9
H9
H6, H9
H2, H6
H6, H9
H2, H6
H3, H9
H6, H9
H2, H9
H12
H3, H9
H3, H7
H7, H9
H10
H9
H9, H10
H2, H9
H7, H10
H3, H5
MYPHY12_GUIDELINES
Targeted
Performance Bands
2-4
3-5
3-5
3-5
2-4
2-4
4-5
2-4
4-6
3-4
4-5
2-3
3-4
4-5
3-5
3-5
3-5
3-4
3-4
4-5
2
Part B – 55 marks
Question 21 (7 marks)
21 (a) (1 mark)
Outcomes Assessed: H6, H9
Targeted Performance Bands: 3-5

Criteria
Mark
1
Criteria
Correct calculation, with direction.
Partial calculation.
Marks
2
1
Correct calculation.
Sample answer
Initially, , uy = 16.sin34 = 8.95 ms-1
21 (b) (2 marks)
Outcomes Assessed: H6, H9
Targeted Performance Bands: 3-5


Sample answer
s = ut + ½ at2
at the landing, y = -4
-4 = 8.95t + ½ x -9.8t2
0 = 4.9t2 -8.95t - 4
t = t2 – 1.83t - 0.82
t = [1.83 ± (1.832 + 4 x 0.82)1/2 ] /2
t = 2.2 s
21 (c) (2 marks)
Outcomes Assessed: H6, H9
Targeted Performance Bands: 2-4
Criteria


Correct calculation and unit.
Partial calculation.
Marks
2
1
Sample answer
ux = 16.cos34 = 13.26 ms-1
X = vx t = 13.26 x 2.2 = 29.2 m
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21 (d) (2 marks)
Outcomes Assessed: H6, H9
Targeted Performance Bands: 4-5


Criteria
Identifies that maximum speed is at the end and gives an explanation involving
components.
Identifies that maximum speed is at the end.
Marks
2
1
Sample answer
The ball achieves max speed at the end, just as it is about to hit the ground. This is because vx
is constant, but vy decreases and then increases, and gets even bigger once below launch
height. This means that the resultant velocity V = vx + vy has the largest value at the end.
Question 22 (7 marks)
22 (a) (2 marks)
Outcomes Assessed: H6, H9
Targeted Performance Bands: 2-4


Criteria
Draws in a suitable line with V being labelled.
Draws in a suitable line without V being labelled.
Marks
2
1
Sample answer
A curved line bending around the planet.
Final v
22 (b) (1 mark)
Outcomes Assessed: H6, H9
Targeted Performance Bands: 3-5
Criteria
 Correctly states answer as no.
Mark
1
Sample answer
No, the sun cannot be used for the sling shot effect.
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22 (c) (2 marks)
Outcomes Assessed: H2, H9
Targeted Performance Bands: 4-5


Criteria
Identifies that V has increased and explains why.
Identifies that V has increased.
Marks
2
1
Sample answer
The velocity of the space probe relative to the sun has increased, and the direction has
changed. This is because of the gravitational attraction from the planet causing the probe to
accelerate.
22 (d) (2 marks)
Outcomes Assessed: H2, H9
Targeted Performance Bands: 5-6


Criteria
Identifies that there is an exchange of momentum and explains how this effects
the planets momentum.
Identifies that there is an exchange of momentum.
Marks
2
1
Sample answer
The space probe and the planet have undergone a type of elastic collision where there has
been an exchange of momentum during the interaction. The space probe’s momentum has
increased while the planets’ momentum has decreased (negligibly), relative to the sun.
Question 23 (4 marks)
23 (a) (1 mark)
Outcomes Assessed: H6
Targeted Performance Bands: 2-4
Criteria

2
Identifies E = mc
Mark
1
Sample answer
The theory of relativity theory states that the rest energy of a particle is given by E = mc2 .
23 (b) (3 marks)
Outcomes Assessed: H1, H3, H6
Targeted Performance Bands: 4-6


Criteria
Describes the medium of light according to classical physics and according to
relativity, and states the difference.
Describes the medium of light according to classical physics and according to
relativity.
Describes the medium of light according to classical physics OR
according to relativity.
Marks
3
2
1
Sample answer
The medium for light according to classical physics is the ether, which is invisible all
pervasive and frictionless. The medium for light according to relativity is very different as it
is not physical, and not the ether. It is a self-propagating electromagnetic field.
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Question 24 (7 marks)
24 (a) (2 marks)
Outcomes Assessed: H3, H9
Targeted Performance Bands: 3-5


Criteria
Identifies the basic shape and labels the coil turns and iron core.
Identifies the basic shape.
Marks
2
1
Sample answer
Iron core
Primary
circuit
N = 18 300
Secondary
circuit
N = 360
24 (b) (3 marks)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 4-5



Criteria
Marks
Describes how AC current induces Eddy currents, the generation of heat, and
3
links in Lenz’s law.
Describes how AC current induces Eddy currents and the generation of heat
2
OR describes the generation of heat and links in Lenz’s law.
Describes how AC current induces Eddy currents OR the generation of heat OR
1
states Lenz’s law.
Sample answer
The core of the transformer is laminated so as to reduce the heat generated. There AC current
in the primary induces Eddy currents in the core and AC current in the secondary. This is due
to Lenz’s law, showing that a change in flux will induce Eddy currents which oppose the
change, given by emf = -/t. The laminations reduce significantly the size of the eddy
currents.
24 (c) (1 mark)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 2-3

Criteria
Identifies the step down transformer.
Mark
1
Sample answer
This is a step down transformer since 18 300 turns go down to 360 turns.
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24 (d) (1 mark)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 3-5
Criteria

Correct calculation
Mark
1
Sample answer
This is a step down transformer
Np / Ns = Vp / Vs
becomes 18300 / 360 = 240 / Vs
Vs = 4.72 V
Question 25 (6 marks)
25 (a) (2 marks)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 2-5
Criteria
 Describes the need for a current carrying conductor in a field AND uses the
equation F = BIL.

Describes the need for a current carrying conductor in a field OR uses the
equation F = BIL.
Marks
2
1
Sample answer
The coil needs an external connection to a battery in order to move because current must flow
in the coil which is sitting in a magnetic field in order for the force F = BIL to push the coil.
25 (b) (2 marks)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 2-4
Criteria


Describes two suitable changes.
Describes one suitable change.
Marks
2
1
Sample answer
The following changes could be made:
- More turns of wire on the coil
- Using an iron core on the armature
- Using stronger magnets
- Using more magnets
25 (c) (1 mark)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 2-4
Criteria

Describes the correct direction.
Mark
1
Sample answer
The coil turns anticlockwise.
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25 (d) (1 mark)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 3-5
Criteria

Correct calculation.
Mark
1
Sample answer
 = NBIA cos  = 1 x 0.211 x 4.1 x 3.6 x 10-2 = 0.031 Nm
Question 26 (5 marks)
26 (a) (2 marks)
Outcomes Assessed: H3, H9
Targeted Performance Bands: 3-5


Criteria
Writes a description which includes the metal frame and the supporting
insulators.
Provides partial description.
Marks
2
1
Sample answer
The transmission tower or pylon that carries high voltage electricity is made from a metal
truss frame that helps the tower become lightweight and strong. The top most wire is earthed
and the transmission lines are supported by glass insulators that are linked onto the tower.
26 (b) (1 mark)
Outcomes Assessed: H3
Targeted Performance Bands: 1-3

Criteria
Identifies need for lightning protection.
Mark
1
Sample answer
The top lines need to be earthed so as to protect the tower from lightning strikes.
26 (c) (2 marks)
Outcomes Assessed: H7, H9
Targeted Performance Bands: 2-4


Criteria
Explanation which includes aluminium and the reasons for its use.
Identifies aluminium or a conductor .
Marks
2
1
Sample answer
The transmission lines are often made of aluminum in a threaded cable form. This is because
it is lightweight, strong and an excellent conductor of electricity.
MYPHY12_GUIDELINES
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Question 27 (6 marks)
27 (a) (1 mark)
Outcomes Assessed: H3, H10
Targeted Performance Bands: 3-5
Criteria

Correct answer.
Mark
1
Sample answer
Z is a heater for the cathode.
27 (b) (2 marks)
Outcomes Assessed: H3, H9
Targeted Performance Bands: 2-4


Criteria
Identifies W is deflection plate and that it uses an electric field.
Identifies W is deflection plate OR that it uses an electric field.
Marks
2
1
Sample answer
Part W is an electric field plate which is there to deflect the beam horizontally to the required
position on the screen.
27 (c) (i) (1 mark)
Outcomes Assessed: H13
Targeted Performance Bands: 2-4

Criteria
Identifies distance between magnet and screen.
Mark
1
Sample answer
Independent variable is the distance between the magnet and the screen.
27 (c) (ii) (2 marks)
Outcomes Assessed: H11, H13
Targeted Performance Bands: 3-5
Criteria


Identifies two factors.
Identifies one factor.
Marks
2
1
Sample answer
The factors that need to be controlled to make this a fair and valid test are as follows;
- the magnet must be the same, the orientation of the magnet must be constant, the voltage
settings on the CRT must be kept constant, other magnetic objects must be kept well away.
MYPHY12_GUIDELINES
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Question 28 (6 marks)
28 (a) (2 marks)
Outcomes Assessed: H2, H9
Targeted Performance Bands: 2-4


Criteria
Calculates E and F and the direction correctly.
Calculates E correctly.
Marks
2
1
Sample answer
E = V/d = 100/0.85 = 117.6 V/m
F = Eq = 117.6 x 1.6 x 10-19 = 1.88 x 10-17 N up the page
28 (b) (1 mark)
Outcomes Assessed: H1, H2
Targeted Performance Bands: 2-4
Criteria

Identifies Thomson.
Mark
1
Sample answer
Thomson first measured the charge to mass ratio of electrons.
28 (c) (3 marks)
Outcomes Assessed: H2, H9,
Targeted Performance Bands: 4-5



Criteria
Equates qvB and Eq and calculates the magnitude and direction of B.
Calculates qvB or Eq.
Partial calculation.
Marks
3
2
1
Sample answer
If the helium nucleus does not accelerate, then FB = FE
qvB = Eq
B = E/v
B = 117.6/68 = 1.73 T to the left
Question 29 (7 marks)
29 (a) (3 marks)
Outcomes Assessed: H1, H2, H10
Targeted Performance Bands: 3-5



Criteria
The relationship is correctly described, both before and during and after the
superconducting phase.
The relationship is correctly described, both before and during the
superconducting phase.
One correct statement about the superconductor curve given.
Marks
3
2
1
Sample answer
The resistance versus temperature relationship for picene (C22H14), in the region 25 K to 0 K
will show line that shows a steady drop in resistance as temp lowers towards 18 K. At 18 K,
the resistance suddenly drops to zero, as it enters the superconducting phase. The resistance
stays at zero thereafter as temperature lowers further.
MYPHY12_GUIDELINES
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29 (b) (2 marks)
Outcomes Assessed: H1, H2, H5
Targeted Performance Bands: 3-5


Criteria
Two benefits of research explained and linked to the article.
One benefit of research clearly explained.
Marks
2
1
Sample answer
Research is important in relation to high-temperature superconductors because it is leading to
discoveries of superconductors that function at higher temperatures, which makes them more
easily accessible and so able to be applied to technologies more cheaply and efficiently. We
are also finding different types of substances, like picene (C22H14), a molecule consisting of
five benzene rings, being able to superconduct, which will add to our knowledge of the
materials science.
29 (c) (2 marks)
Outcomes Assessed: H12
Targeted Performance Bands: 3-4


Criteria
Two benefits of research explained and linked to the article.
One benefit of research clearly explained.
Marks
2
1
Sample answer
The features of the article that make the information more reliable are that it gives details
about the science that can be checked, the date is recent so the information is current, and the
name of the scientist and the institution are given.
MYPHY12_GUIDELINES
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