7 Applications of Trigonometry and Vectors 7.4 Vectors, Operations, and the Dot Product 7.5 Applications of Vectors Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-1 7.4 Vectors, Operations, and the Dot Product Basic Terminology ▪ Algebraic Interpretation of Vectors ▪ Operations with Vectors ▪ Dot Product and the Angle Between Vectors Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-2 7.4 Example 1 Finding Magnitude and Direction Angle Find the magnitude and direction angle for Magnitude: Direction angle: Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-3 7.4 Example 2 Finding Horizontal and Vertical Components Vector v has magnitude 14.5 and direction angle 220°. Find the horizontal and vertical components. Horizontal component: –11.1 Vertical component: –9.3 Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-4 7.4 Example 3 Writing Vectors in the Form a, b Write each vector in the form a, b. u: magnitude 8, direction angle 135° v: magnitude 4, direction angle 270° w: magnitude 10, direction angle 340° Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-5 7.4 Example 4 Finding the Magnitude of a Resultant Two forces of 32 and 48 newtons act on a point in the plane. If the angle between the forces is 76°, find the magnitude of the resultant vector. because the adjacent angles of a parallelogram are supplementary. Law of cosines Find square root. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-6 7.4 Example 6 Finding Dot Products Find each dot product. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-7 7.4 Example 7 Finding the Angle Between Two Vectors Find the angle θ between the two vectors u = 5, –12 and v = 4, 3. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-8 7.5 Applications of Vectors The Equilibrant ▪ Incline Applications ▪ Navigation Applications Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-9 7.5 Example 2 Finding a Required Force Find the force required to keep a 2500-lb car parked on a hill that makes a 12° angle with the horizontal. The vertical force BA represents the force of gravity. BA = BC + (–AC) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-10 7.5 Example 2 Finding a Required Force (cont.) Vector BC represents the force with which the weight pushes against the hill. Vector BF represents the force that would pull the car up the hill. Since vectors BF and AC are equal, magnitude of the required force. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. gives the 7-11 7.5 Example 2 Finding a Required Force (cont.) Vectors BF and AC are parallel, so the measure of angle EBD equals the measure of angle A. Since angle BDE and angle C are right angles, triangles CBA and DEB have two corresponding angles that are equal and, thus, are similar triangles. Therefore, the measure of angle ABC equals the measure of angle E, which is 12°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-12 7.5 Example 2 Finding a Required Force (cont.) From right triangle ABC, A force of approximately 520 lb will keep the car parked on the hill. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-13 7.5 Example 3 Finding an Incline Angle A force of 18.0 lb is required to hold a 74.0-lb crate on a ramp. What angle does the ramp make with the horizontal? Vector BF represents the force required to hold the crate on the incline. In right triangle ABC, the measure of angle B equals θ, the magnitude of vector BA represents the weight of the crate, and vector AC equals vector BF. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-14 7.5 Example 3 Finding an Incline Angle (cont.) The ramp makes an angle of about 14.1° with the horizontal. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-15 7.5 Example 4 Applying Vectors to a Navigation Problem A ship leaves port on a bearing of 25.0° and travels 61.4 km. The ship then turns due east and travels 84.6 km. How far is the ship from port? What is its bearing from port? Vectors PA and AE represent the ship’s path. We are seeking the magnitude and bearing of PE. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-16 7.5 Example 4 Applying Vectors to a Navigation Problem (cont.) Triangle PNA is a right triangle, so the measure of angle NAP = 90° − 25.0° = 65.0°. The measure of angle PAE = 180° − 65.0 = 115.0°. Law of cosines The ship is about 123.8 km from port. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-17 7.5 Example 4 Applying Vectors to a Navigation Problem (cont.) To find the bearing of the ship from port, first find the measure of angle APE. Law of sines Now add 38.3° to 25.0° to find that the bearing is 63.3°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-18 7.5 Example 5 Applying Vectors to a Navigation Problem A plane with an airspeed of 355 mph is headed on a bearing of 62°. A west wind is blowing (from west to east) at 28.5 mph. Find the groundspeed and the actual bearing of the plane. The groundspeed is represented by |x|. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-19 7.5 Example 5 Applying Vectors to a Navigation Problem (cont.) Law of cosines The plane’s groundspeed is about 380 mph. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-20 7.5 Example 5 Applying Vectors to a Navigation Problem (cont.) Use the law of sines to find α, and then determine the bearing, 62° + α. The bearing is about 62° + 2° = 64°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 7-21 8 Complex Numbers, Polar Equations, and Parametric Equations 8.5 (part I) Polar Coordinates 8.1 Complex Numbers 8.2 Trigonometric (Polar) Form of Complex Numbers 8.3 The Product and Quotient Theorems 8.4 De Moivre’s Theorem; Powers and Roots of Complex Numbers 8.5 (part II) Polar Equations and Graphs Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-22 8.5 Polar Coordinates (part I) Polar Coordinate System ▪ Converting Polar and Rectangular Coordinates Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-23 8.5 Example 1 Plotting Points With Polar Coordinates Plot each point by hand in the polar coordinate system. Then, determine the rectangular coordinates of each point. The rectangular coordinates of P(4, 135°) are Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-24 8.5 Example 1 Plotting Points With Polar Coordinates (cont.) The rectangular coordinates of Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-25 8.5 Example 1 Plotting Points With Polar Coordinates (cont.) The rectangular coordinates of Copyright © 2008 Pearson Addison-Wesley. All rights reserved. are (0, –2). 8-26 8.5 Example 2(a) Giving Alternative Forms for Coordinates of a Point Give three other pairs of polar coordinates for the point P(5, –110°). Three pairs of polar coordinates for the point P(5, −110º) are (5, 250º), (−5, 70º), and (−5, −290º). Other answers are possible. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-27 8.5 Example 2(b) Giving Alternative Forms for Coordinates of a Point Give two pairs of polar coordinates for the point with the rectangular coordinates The point Since 300°. lies in quadrant II. , one possible value for θ is Two pairs of polar coordinates are (12, 300°) and (−12, 120°). Other answers are possible. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-28 8.1 Complex Numbers Basic Concepts of Complex Numbers ▪ Complex Solutions of Equations ▪ Operations on Complex Numbers Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-29 8.1 Example 1 Writing √–a as i√a Write as the product of real number and i, using the definition of Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-30 8.1 Example 2 Solving Quadratic Equations for Complex Solutions Solve each equation. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-31 8.1 Example 3 Solving a Quadratic Equation for Complex Solutions Write the equation in standard form, then solve using the quadratic formula with a = 2, b = –2, and c = 5. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-32 8.1 Example 4 Finding Products and Quotients Involving Negative Radicands Multiply or divide as indicated. Simplify each answer. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-33 8.1 Example 5 Simplifying a Quotient Involving a Negative Radicand Write in standard form. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-34 8.1 Example 6 Adding and Subtracting Complex Numbers Find each sum or difference. (a) (4 – 5i) + (–5 + 8i) = [4 + (–5)] + (–5i + 8i) = –1 + 3i (b) (–6 + 3i) + (12 – 9i) = 6 – 6i (c) (–10 + 7i) – (5 – 3i) = (–10 – 5) + [7i + (3i)] = –15 + 10i (d) (15 – 8i) – (–10 + 4i) + (–25 + 12i) = [15 – (–10) + (–25)] + [–8i – 4i + 12i] = 0 + 0i Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-35 8.1 Example 7 Multiplying Complex Numbers Find each product. (a) (5 + 3i)(2 – 7i) = 5(2) + (5)(–7i) + (3i)(2) + (3i)(–7i) = 10 – 35i + 6i – 21i2 = 10 – 29i – 21(–1) = 31 – 29i (b) (4 – 5i)2 = 42 – 2(4)(5i) + (5i)2 = 16 – 40i + 25i2 = 16 – 40i + 25(–1) = –9 – 40i Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-36 8.1 Example 7 Multiplying Complex Numbers (cont.) (c) (3 – i)(–3 + i) = –9 + 3i + 3i – i2 = –9 + 6i – (–1) = –9 + 6i + 1 = –8 + 6i (d) (9 – 8i)(9 + 8i) = 92 – (8i)2 = 81 – 64i2 = 81 – 64(–1) = 81 + 64 = 145 or 145 + 0i Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-37 8.1 Example 8 Simplifying Powers of i Simplify each power of i. (a) (b) Write the given power as a product involving or . (a) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. (b) 8-38 8.1 Example 8 Simplifying Powers of i (cont.) (c) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-39 8.1 Example 9(a) Dividing Complex Numbers Write the quotient in standard form a + bi. Multiply the numerator and denominator by the complex conjugate of the denominator. Multiply. i2 = –1 Combine terms. Lowest terms; standard form Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-40 8.1 Example 9(b) Dividing Complex Numbers Write the quotient in standard form a + bi. Multiply the numerator and denominator by the complex conjugate of the denominator. Multiply. –i2 = 1 Lowest terms; standard form Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-41 8.2 Trigonometric (Polar) Form of Complex Numbers The Complex Plane and Vector Representation ▪ Trigonometric (Polar) Form ▪ Converting Between Rectangular and Trigonometric (Polar) Forms ▪ An Application of Complex Numbers to Fractals Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-42 8.2 Example 1 Expressing the Sum of Complex Numbers Graphically Find the sum of 2 + 3i and –4 + 2i. Graph both complex numbers and their resultant. (2 + 3i) + (–4 + 2i) = –2 + 5i Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-43 8.2 Example 2 Converting From Trigonometric Form to Rectangular Form Express 10(cos 135° + i sin 135°) in rectangular form. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-44 8.2 Example 3(a) Converting From Rectangular Form to Trigonometric Form Write 8 – 8i in trigonometric form. The reference angle for θ is 45°. The graph shows that θ is in quadrant IV, so θ = 315°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-45 8.2 Example 3(b) Converting From Rectangular Form to Trigonometric Form Write –15 in trigonometric form. –15 = –15 + 0i –15 + 0i is on the negative x-axis, so θ = 180°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-46 8.2 Example 4 Converting Between Trigonometric and Rectangular Forms Using Calculator Approximations Write each complex number in its alternative form, using calculator approximations as necessary. (a) 7(cos 205° + i sin 205°) ≈ –6.3442 – 2.9583i Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-47 8.2 Example 4 Converting Between Trigonometric and Rectangular Forms Using Calculator Approximations (cont.) (b) –7 + 2i x = −7 and y = 2 The reference angle for θ is approximately 15.95°. The graph shows that θ is in quadrant II, so θ = 180° – 15.95° = 164.05°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-48 8.3 The Product and Quotient Theorems Products of Complex Numbers in Trigonometric Form ▪ Quotients of Complex Numbers in Trigonometric Form Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-49 8.3 Product Theorem r1 (cos 1 i sin 1 ) r2 (cos 2 i sin 2 ) Can be written as r1r2 [cos(1 2 ) i sin(1 2 )] Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-50 8.3 Example 1 Using the Product Theorem Find the product of 4(cos 120° + i sin 120°) and 5(cos 30° + i sin 30°). Write the result in rectangular form. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-51 8.3 Quotient Theorem r1 (cos 1 i sin 1 ) r2 (cos 2 i sin 2 ) Can be written as r1 [cos(1 2 ) i sin(1 2 )] r2 Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-52 8.3 Example 2 Using the Quotient Theorem Find the quotient rectangular form. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. Write the result in 8-53 8.3 Example 3 Using the Product and Quotient Theorems With a Calculator Use a calculator to find the following. Write the results in rectangular form. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-54 8.3 Example 3 Using the Product and Quotient Theorems With a Calculator (cont.) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-55 8.4 De Moivre’s Theorem; Powers and Roots of Complex Numbers Powers of Complex Numbers (De Moivre’s Theorem) ▪ Roots of Complex Numbers Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-56 8.4 Example 1 Finding a Power of a Complex Number Find form. First write and express the result in rectangular in trigonometric form. and Because x and y are both positive, θ is in quadrant I, so θ = 45°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-57 8.4 Example 1 Finding a Power of a Complex Number (cont.) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-58 8.4 Example 2 Finding Complex Roots Find the three cube roots of 8 (cos 180o + i sin 180o). Write the roots in rectangular form. Note that [2 (cos 60o + i sin 60o)]3 = 8 (cos 180o + i sin 180o). So one cube root is 2 (cos 60o + i sin 60o) The other 2 are 360 120 apart 3 2 (cos 180o + i sin 180o) and 2 (cos 300o + i sin 300o) If cubed all 3 will yield 8 in rectangular form Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-59 8.4 Example 3 Finding Complex Roots Find all fourth roots of Write the roots in rectangular form. First write in trigonometric form. Because x and y are both negative, θ is in quadrant III, so θ = 240°. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-60 8.4 Example 3 Finding Complex Roots Copyright © 2008 Pearson Addison-Wesley. All rights reserved. (cont.) 8-61 8.5 Polar Equations and Graphs (part II) Graphs of Polar Equations ▪ Converting from Polar to Rectangular Equations ▪ Classifying Polar Equations Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-62 8.5 Example 3 Examining Polar and Rectangular Equations of Lines and Circles For each rectangular equation, give the equivalent polar equation and sketch its graph. (a) y = 2x – 4 In standard form, the equation is 2x – y = 4, so a = 2, b = –1, and c = 4. The general form for the polar equation of a line is y = 2x – 4 is equivalent to Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-63 8.5 Example 3 Examining Polar and Rectangular Equations of Lines and Circles (cont.) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-64 8.5 Example 3 Examining Polar and Rectangular Equations of Lines and Circles (cont.) This is the graph of a circle with center at the origin and radius 5. Note that in polar coordinates it is possible for r < 0. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-65 8.5 Example 3 Examining Polar and Rectangular Equations of Lines and Circles (cont.) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-66 8.5 Example 8 Converting a Polar Equation to a Rectangular Equation #53 r 2sin( ) #58 2 r 4 cos sin #60 r 5csc( ) Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-67 8.5 Example 4 Graphing a Polar Equation (Cardioid) Find some ordered pairs to determine a pattern of values of r. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-68 8.5 Example 4 Graphing a Polar Equation (Cardioid) (cont.) Connect the points in order from (1, 0°) to (.5, 30°) to (.1, 60°) and so on. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-69 8.5 Example 5 Graphing a Polar Equation (Rose) Find some ordered pairs to determine a pattern of values of r. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-70 8.5 Example 5 Graphing a Polar Equation (Rose) (cont.) Connect the points in order from (4, 0°) to (3.6, 10°) to (2.0, 20°) and so on. Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-71 8.5 Example 7 Graphing a Polar Equation (Spiral of Archimedes) Graph r = –θ (θ measured in radians). Go to wzgrapher. Use domain [0, 20π] Copyright © 2008 Pearson Addison-Wesley. All rights reserved. 8-72