Int 1 Unit 2 NAB Revision
Integer Coordinates
Integer Addition
DST
Pythagoras
Stem and Leaf
Pie Chart
Frequency Table
Scatter Diagram
Mode
Median
Mean
Range
Probability
Integer Coordinates
What are the
C
coordinates of the point A
B
y
6
A
(
5
-2
50
,
3
-4 4
)
4
3
2
1
-6 -5 -4 -3 -2 -1
-1
1
2
3
4
5 6 x
-2
-3
-4
-5
C
B
-6
Start at the centre and decide whether to go left - or right +
Point is below centre so x coord is 0
Is
Is the
the point
point above
above ++ or
or below
below --
Where is the Point
Where is the point
y
6
P ( -5 , -2 )
5
4
3
2
Q ( 0
, -3
)
R ( 3
, -5
)
1
-6 -5 -4 -3 -2 -1
-1
P
1
2
3
4
5 6 x
-2
-3
Q
-4
-5
R
-6
As x is 0 the point will be either above or below the centre
Click Coordinates
5
4
3
2
1
-5
-4
-3
-2
-1
1
-1
-2
-3
-4
-5
“Touch” the correct point
Start
2
3
4
A( 4
,
5
)
B( 4
, -1
)
C( -4
, 3
)
D( -4
, -1
)
E( 0
, 3
)
F( -5
, 0
)
G( -5
, -2
)
H( 0
, -5
)
I(
,
0
)
, -3
)
4
J( -1
Adding Integers
Scores are for a quiz. 1 pt for correct answer.
1 pt deducted if answer is incorrect.
Totals are added
Jill
Fred
Kevin
Round 1
-4
5
-3
Round 2
-3
-1
2
Round 3
5
-2
-4
Total
-2
Jill scores ( - 4 ) + ( -3 ) + 5
= ( - 7 ) + 5 = -2
Add negatives together then positives
( -4 ) + ( - 3 ) = ( - 7 )
Fred’s Score
Scores are for a quiz. 1 pt for correct answer.
1 pt deducted if answer is incorrect.
Totals are added
Jill
Fred
Kevin
Round 1
-4
5
-3
Round 2
-3
-1
2
Round 3
5
-2
-4
Total
-2
2
Fred scores 5 + ( -1 ) + ( -2 )
=5+(-3)= =2
There
two
negatives
( - 1 ) is 1 down;
5 + ( - are
3 ) is
5 up
then 3 down
( - 2) is 2 down so ( -1 ) + ( -2 ) =
-3
Kevin’s Score
Scores are for a quiz. 1 pt for correct answer.
1 pt deducted if answer is incorrect.
Totals are added
Jill
Fred
Kevin
Round 1
-4
5
-3
Round 2
-3
-1
2
Round 3
5
-2
-4
1
-5
Total
-2
Kevin scores ( - 3 ) + 2 + ( - 4 )
=(-7) +2= -5
Cover up the 2 … work out ( - 3 ) + ( - 4 )
-7
Integer Practice
(a)
6
+
( -2 )
+
( -3 )
=
(b)
( -3 )
+
10
+
( -6 )
=
(c)
( -2 )
+
11
+
( -5 )
(d)
5
+
( -7 )
+
( -3 )
=
(e)
( -4 )
+
( -3 )
+
2
=
=
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
Next
0
Distance
Slope indicates speed
Stopped
Fast
Time
Slower
Interpreting a graph
Distanc
Time
Graph
Distance
– Time
Graph
200
Crawley
Distance (km)
160
120
Sandford
Barnstow 80
A
B
D
C
40
Leigh
0700
0800
0900
1000
Time (hours)
Slope
not
as
steep
as
AB
so travelling
slower
CLeaves
Barnstow
Stopped
as
at
0900
Barnstow
for
hour
BHorizontal.
…Leave
Atis0800
arrive
at00
Barnstow
80
km1 from
Leigh
Leigh
at 07
1100
Finding Distance
Speed= 15
D
S
X
X
m/s
D=SxT
D= 15 x 12
T
=
180 miles
Can find distance
Time = 12
sec
What is the Speed
S = D ÷T
375
÷
S
D
x
x
S = 375 ÷ 5
÷
T
S=
5
km/hr T=
min
hr
T=
S=
75
hr
5
min
hr
D=
375
km
How long is the journey
T = D ÷S
88
÷
D
S
x
44
x
T = 88 ÷ 44
÷
T
T=
44
min
hr
T=
S=
2
km/hr T=
hr
min
hr
D=
88
km
Pythagoras
a=
When you have both
sides of the right angle
you ADD the squares
b=
3
22.4
Use
c
22.4
3
c² = a² + b²
c²= a² + b²
c²=
=
c=
=
0
(-)
On
C √ ²
Opposite of ² is √
Start
Ans
7 8 9 x
Next
4
5 6 ÷
1
2 3
0
.
-
= +
Stem and Leaf
50
54
67
79
5
0
4
0
7
2
92
62
50
68
6
7
2
8
7
1
67
57
52
96
7
9
3
8
61
84
73
94
8
4
7
6
92
78
87
86
9
2
6
4
Key
5
0
2
is 50
92 represented by leaf 2 in level 9
Each row is called a level
Level 7 contains 79, 73 and 78
A key must be included so that the data can be interpreted
Pie Chart
A Pie chart is used to compare
categories which can be chosen from
BBC1
other
STV
SKY
This pie chart compares the channels
80 pupils watched at 8pm one evening
Which was the most popular
The small square indicates that the angle for BBC is
¼ of the pupils were watching BBC 1
¼ of 80 = 80 ÷ 4 = 20
SKY
90°
Frequency Table
58
57
60
61
56
59
58
58
59
56
60
60
57
59
59
61
60
57
59
59
Diameter
56
58
60
58
Tally
62
60
59
57
60
59
61
62
58
61
59
59
60
58
60
61
Frequency
56
lIII
57
lIl
58
lIII
lIll
59
lIII
lIll
9
9
60
lIII
lI
8
61
lIII
62
lIII
7
lI
3
5
lI
The tally
last diameter
be entered
The
marks aretothen
countedis 60
7
58
59
62
58
59
62
59
60
ScatterGraph
Sales of Hot Soup
32
Draw a line of
BEST FIT
28
24
20
16
12
8
4
0
0
5
10
15
20
25
30
35
Temperature
°C °C
Temperature
A scattergraph shows the connection between two quantities
nd March the temperature was
On
the23nd
5°and
and
28cups
cupswere
were
On
the temperature
was
20
24the
bowl
ofMarch
soup were
sold on March
1st8°
when
the
sold
sold
temperature was 5°
Line of Best Fit
Sales of Hot Soup
32
Draw a line of
BEST FIT
28
24
20
16
12
8
4
0
0
5
10
15
20
25
30
35
Temperature °C
The Scattergraph shows a connection between the temperature
outside and the cups of Hot Soup sold
The line shows roughly where the point are. Some above.
Some below.
Using a Best Fit Line
Sales of Hot Soup
32
How many bowls
when temperature
is 5°C
28
24
20
16
12
8
4
0
0
5
10
15
20
25
30
Temperature °C
Once the line is drawn you do not need the points. The line shows
the connection ( correlation ) between temperature and sales.
For a temperature
Estimate
how manyof
bowls
5° about
of soup
25 would
bowls be
would
soldbe sold
9 bowls sold
when the temperature is 20°C.
35
Line of Best Fit
Sales of Hot Soup
32
Draw a line of
BEST FIT
28
24
20
16
12
8
4
0
0
5
Temperature
10
16
15
20
25
30
Bowls of Soup
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
Start
Next
Temperature
35
Temperature °C
0
Statistics … Mode
2
7
11
11
2
12
12
17
16
14
4
2
20
Sort
Mode is the number which there is MOre of
Mode =
1
To find the median the data needs to be in order.
It is easier to find the Mode and the Range if the data is in order
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
New Data
0
Finding the Range
The range is the difference between the highest number and the lowest number.
10
Range
20
=
=
10
25
High
-
30
8
Low
-
=
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
Next
0
Median
The MEDIAN of data is the middle value when put in order.
5, 7, 7, 10, 14, 16, 16, 18
8÷2=4
There are 8 values.
Split into two equal groups of four
5 , 7 , 7 , 10 , 14 , 16 , 16 , 18
No number in the middle so find the number
halfway between 10 and 14
Median =
10 + 14
2
=
24
2
=
24 ÷ 2 = 12
What is the Median
5
3
9
19
9
17
5
9
9
17
19
Sort
3
Can have two groups of
Median =
9
3
(9+9)÷2
Working
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
New Data
0
Find the Median
Sort
Split into two groups of
Median =
3
Working
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
New Data
0
Mean of 4 numbers
17
29
16
10
Total
Mean
=
How Many
Mean =
=
=
Total
29+17+16+10
How Many
4
72
÷
18
4
Mean of 6 numbers
11
26
19
22
26
22
Total
Mean
=
How Many
Mean =
=
=
26+11+19+22+26+22
How Many
6
126
÷
21
Total
6
Probability
Probability=
Favourable
3
Possible
P(9) =
16
Favourable
Possible
16 different numbers
are possible with this
spinner
Only one position will win
when the spinner stops
at 9
1
16
15
4
Probability of a 9
1
2
14
5
13
6
7
12
8
9
Win
11
10
Probability
What is the Probability of getting a four on the throw of a dice
P(4) =
Favourable
Possible
Possible
6
Favourable
Possible outcomes
1
Favourable outcome
0
(-)
Ans
On
C √ ²
7 8 9 x
√ ² C x
÷
5 6 7 8 9
+
-
On
0 1 2 3 4
.
=
Ans
(-)
0
4
5 6 ÷
1
2 3
0
.
-
= +