15 Days One Day Exponential functions are those that have constant base variablepower An example of an exponential function is f ( x) 2 x Domain : ( , ) Range : (0, ) An Exponential Function f with base a f ( x) a x for all x in , where a 0 and a 1. Domain : (, ) Range : (0, ) y - int : (0,1) H.A. : y 0. Note : The exponentia l function is a 1 to 1 function. Graph of f ( x) a x for a 1 is an increasing function. Graph of f ( x) a x for 0 a 1 is a decreasing function. Sketch Graphs for the following function: f ( x) 3 x Sketch Graphs for the following function: 1 f ( x) 4 x We can shift exponential function using the same patterns from before. Use locator point x h f ( x ) a k where (h, k 1) is the locator point. (0,1). y k is the Horizontal Asymptote f ( x) 4 x f ( x) 4 x 2 f ( x) 4 x 2 3 f ( x) a x horizontal flip (across) y - axis f ( x) a x vertical flip (across) x - axis - Both types of reflections will change the position(s) of your intercepts and should be done before shifting. The exponentia l function f given by f ( x) a x for 0 a 1 or a 1 is one to one. Thus the following conditions are satisfied for x1 and x2 : 1. If x1 x2 , then a x1 a x2 . 2. If a x1 a x2 , then x1 x2 . We will use this one alot! To solve equations with variables in the exponents we need to: 1. Re-write both sides as the same base using exponent rules. 2. Set the exponents equal using condition 2 of our theorem on exponential functions. 3. Solve for the variable. 7 x6 73 x4 35 x 8 9 x 2 27 x 1 9 2 x 3 Writing an exponential function f ( x) ba given the y-int and a point on the function. x 1. Substitute the y-int into your equation and solve for b. 2. Re-write your equation with a value for b. 3. Substitute other point into your equation from step 2 and solve for a. 4. Re-write your equation with values for a and b. Find an exponential function of the form f ( x) ba that has the given y-int and passes through the point P y int 8; P(3,1) x Read 4.1; pg292 (# 2,4,7,9,11b - h, 13,14, 16 - 18, 25 NO TI’s for the graphs) Two Days The Compound Interest Formula : nt r A P1 where : n A is the total amount after t years P is the principal invested r is the annual interest rate (as a decimal) n is the number of interest periods per year t is the number of years. You have an account that returns 7% annual interest compounded monthly. If you invest $1500 for a total of 10 years, how much money will you have in the account? If n is a positive integer, then n 1 1 e 2.71828 as n . n The Natural Exponentia l Function f is definded by f ( x) e x for every real number x. The natural exponentia l function is one of the most useful functions in advanced mathematic s and applicatio ns. The Continuous ly Compound Interest Formula : A Pe rt where : A is the total amount after t years P is the principal invested r is the annual interest rate (as a decimal) t is the number of years. An initial investment of $35000 is continuously compounded at 8.5% interest. How much is the investment worth after 5 years? After 15 years? Law of Growth and Decay Formula : Let q0 be the value of a quantity q at time t 0. If q changes instantane ously at a rate proportion al to its current va lue, then : q q(t) q0 e rt where r 0 is the rate of growth (or r 0 is the rate of decay) Since 1980, world population in millions closely fits .0156x the exponential function defined by y 4481e where x is the number of years since 1980. The world populations was about 5,320 million in 1990. How closely does the function approximate this value? Use this model to approximate the population in 2012. Read 4.2; pg 303 (# 1-7,9,11-13,15,19,21,25) pg 292 (# 32,37,38,(53 use TI)); pg 304 (# 22,24 (45 & 51 use TI)) Four Days The following expressions are equivalent. a x y log a x y Examples 1) 32=9 3) log 4 64 3 2) xa+b=9 4) log M G r log a x y The expression above is read “The log of x base a equals y” x>0 (the number you take a log of must be positive) If you don’t see an “a” value the base is assumed to be 10. ◦ log 4 = log10 4 A natural log (ln) has a base of e. ◦ ln 4=loge4 1) 2) 3) log 5 125 10 ln e log 2 ( x 3) 3 4) log 2 (2x 7) log 2 (3x 1) Pg 317 #1,3,9,11,14(skip e), 17-27 odd. No TI Begin 4.3.2 log a a n n Evaluate 1) 2) log 2 2 e 3 ln 7 1 3) log 3 27 a loga n n a) b) Remember that f(x)=logax and f(x)=ax are inverse functions. This means that logarithmic functions will look like exponential functions except their x’s and y’s will be flipped. Graph f(x)=log2x Graph f(x)=log2(x+2)-1 Domain of f(x)=log x Range of f(x)=log x (0,∞) (-∞,∞) Remember you can’t take the log of a negative number or zero. However… logs can equal negative numbers. Ex: log(1/2) Pg 317 #4,10,12,16, 33(a-g) No calc 47,59,63,65 Begin 4.3.3 ◦ Idea: Rewrite in exponential form. Plug in y’s to find x’s Graph f(x)=log4(2x-1) Find asymptotes, intercepts, domain and range Logarithmic Functions Worksheet pg 59 # 8, 11 - 14 pg 60 1-3, 5 - 17, 20,21 graph 20 & 21(no TI) One Days Loga(xy)= Logax+Logay Loga(x/y)= Logax-Logay Logaxn= nLogax Note: log(x+y) is not equal to log (x)+ log(y) Note: log(x-y) is not equal to log (x)-log(y) 1) Loga(xy)= Logax+Logay Loga(x/y)= Logax-Logay Logaxn= nLogax Expand Each Log Log3(4x) Write as a single log 4) 3log(x)+2log(y) 2) Ln(3e) 5) ½Ln(4x)-yLn(6) 3) Log(2x3/y4) 6) 2ln(xy)-3ln(x)+6ln(y) Solve 1) Log4(2x+4)= 2log43+ log45 2) ln(x)+ln(x+3)=½ln(324) Pg 328 #1-15 odd, 18, 20, 22-26 Three Days 3 5 x log 10 ( x) log a ( x) log 10 (a ) or ln( x) log a ( x) ln( a) log 6 (64) log 6 ( 4) 1 log( x 5) log( 2 x 6) log x 3x2 3 7 2 x 1 e 4e 32 0 2x x e 4e x x 3 Read 4.5 pg 339 (# 1-3,5,9,10,17,18,20,41,42,45) pg 340 (# 11,13,15,21,22,25,31,32,43,44,57) How long does it take for an initial investment of $5000 to grow to $60000 in an account that earns 8.5% interest compounded monthly? The populations N(t) (in millions) of the United States t years after 1980 may be approximated by the formula N (t ) 227e.007t . When will the populations be twice what is was in 1980? A 100g sample of a radioactive substance has a half life of 30 minutes. After how many hours will 20g remain? Solving Equations Worksheet Review for Quiz