§7.3 ADDING AND SUBTRACTING RATIONAL EXPRESSION WITH COMMON DENOMINATORS AND LEAST COMMON DENOMINATOR (LCD) In §7.2 we learned: To multiply and divide rational expressions, we use the same methods that we used to multiply and divide fractions. To multiply rational expressions, first factor the numerators and denominators completely. Then multiply the numerators (straight across), multiply the denominators (straight across), and then simplify (divide out common factors. To divide rational expressions, multiply the first by the reciprocal of the second. Reciprocal means the same for rational expressions as it does for fractions – flip it over. By “flip it over” I mean to switch the numerator and the denominator. ADDING AND SUBTRACTING RATIONAL EXPRESSIONS WITH COMMON DENOMINATORS Just like multiplication/division of rational expressions is very similar to multiplication/division of fractions, we add/subtract rational expressions just like we add/subtract fractions. Remember, to add and subtract two (or more) fractions, they must have common denominators. If they have a common denominator, then we simply add/subtract the numerators and then place the sum/difference over that common denominator. Ex. 3 2 3 2 5 7 7 7 7 Don’t forget to simplify (if possible) after we add/subtract the numerators. Ex. 3 2 3 2 5 1 10 10 10 10 2 If you have a common denominator, don’t simplify before you add/subtract the numerators. If you do, you’ll no longer have a common denominator. Ex. 3 2 3 1 10 10 10 5 Although this is true, we lost our common denominator and will have to get it back again before we can perform the operation. To add/subtract rational expressions that have a common denominator add/subtract the numerators, place the sum/difference over the common denominator, and then simplify (if possible). Ex. 9 3 93 12 x2 x2 x2 x2 Practice 1, page 451 Add: 7a a 4b 4b Since 12 and (x+2) have no common factors, we can’t simplify our answer. Practice 2, page 451 Subtract: 3x 2 3x 2 3x 2 Practice 3, page 451 Subtract: 4 x 2 15 x 8 x 15 x3 x3 FINDING THE LCD (LEAST COMMON DENOMINATOR) OF RATIONAL EXPRESSIONS In the above examples, we were adding rational expressions that already had a common denominator. Just as with fractions, if we want to add rational expressions with unlike denominators, we first must find the LCD. Ex. Suppose we want to calculate 5 9 . We must first find the LCD. We then rewrite the fractions as equivalent 12 42 fractions, each over the LCD. Finally, we add the numerators, place the sum over the LCD and then simplify. To find the LCD of fractions, we look at the prime factorizations of the denominators. (12 = 223 and 42 = 237) The LCD is the smallest number which is a multiple of both 12 and 42; it is the LCM (Least Common Multiple) of the denominators. . Another way to say this is the LCD is the smallest number that is divisible by both 12 and 21 with no remainder. This means that the LCD must contain all factors of 12 and all factors of 42. So our LCD is 2237 = 84. Our LCD must contain every factor that appears in each factorization, and we use it the greatest number of times it appears in any one factorization. We now rewrite our equation with equivalent fractions that have 84 as their denominators. 5 9 5 7 9 4 35 36 35 36 71 = 12 42 12 7 42 4 84 84 84 84 Multiplying by 1 gives an equivalent fraction. Using 7/7 and 4/4 will give us fractions over 84. HOW TO FIND THE LCD OF RATIONAL EXPRESSIONS 1. Completely factor the denominator of each expression 2. Form a product of all unique factors found in Step 1 and raise each one to a power equal to the greatest number of times that the factor appears in any one factored denominator. (If Step 2 is difficult to understand in a sentence, it will probably make more sense after we do some examples) Practice 4, page 452, part b Find the LCD of the given pair of rational expressions. 4 11 , 9 y 15 y 3 9y = 33y = 32y STEP 1: Factor the denominators 15y3 = 35yyy = 35 y3 STEP 2: The unique factors from step are: 3, 5, y The greatest number of times that the factor 3 appears in any one factorization is 2 so 32 is a factor of our LCD. The greatest number of times that the factor 5 appears in any one factorization is 1 so 51 = 5 is a factor of our LCD. The greatest number of times that the factor y appears in any one factorization is 3 so y3 is a factor of our LCD. Therefore, the LCD = 32 5 y3 = 45y3 Practice 5, page 453. Find the LCD of a. 16 3 y 3 , y 5 y 4 b. 8 5 , a a2 Practice 6, page 453. Find the LCD of 2x3 5x , 2 (2 x 1) 6 x 3 Practice 7, page 453. Find the LCD of x5 x8 , 2 x 5 x 4 x 16 Practice 8, page 454 Find the LCD of 2 5 4 , 3 x x 3 Here are some things to think about. We’ll talk more about them in the next section when we use the LCD to add/subtract rational expressions. (These are questions from the exercise set in §7.4) #85, page 463 Explain (in words) when the LCD of the rational expressions in a sum is the product of the denominators. #86, page 463 Explain (in words) when the LCD is the same as one of the denominators of a rational expression to be added or subtracted. If you’re not sure of the answers to these questions, look at the examples we just did and do some homework problems. WRITING EQUIVALENT RATIONAL EXPRESSIONS In order to use the LCD, we have to be able to use it. This means we have to be able to write rational expressions as an equivalent rational expression with a given denominator. To do this we multiply by a form of 1. Practice 9, page 454 Write each rational expression as an equivalent rational expression with the given denominator. a. 3x 5 y 35 xy 2 b. 9x 4 x 7 8 x 14 Practice 10, page 455 Write the rational expression as an equivalent rational expression with the given denominator. 3 x 2 x 15 ( x 2)( x 3)( x 5) 2 CHALLENGE QUESTIONS: If the examples we did in class were easy for you, try #83 and #84 on page 457. The answer to 83 is in the back of your book. The approach to finding the answer is more interesting than the actual number. See if you can explain how to find the answer and why this is the method to use. I WON’T put questions like this on the test or on the homework and these are NOT required problems.