Dihybrid Crosses Crosses involving two traits Dihybrid Crosses Constructing a Punnett square for a dihybrid cross is similar to the method used for a monohybrid cross First, determine the alleles produced in the gametes of each parent Next, construct a Punnett square Then, combine the gametes for each cell Finally, calculate genotypic or phenotypic ratios Determining alleles In Mendel’s peas, let’s consider pea color and pea shape Y = yellow, y = green R = round, r = wrinkled First determine the genotype for the 2 traits of the individual (YYRR, yyrr, YyRr, etc…) The “FOIL” method (from Algebra) may be helpful in determining allele possibilities for an individual (YY)(RR) = YR, YR, YR, YR (yy)(rr) = yr, yr, yr, yr (Yy)(Rr) = YR, Yr, yR, yR Let’s use a YyRr x YyRr cross since it is the most complex Constructing a Punnett square Mendel’s laws support the creation of four combinations of gametes for each individual Remember that meiosis produces 4 unique daughter cells Since each parent produces 4 different combinations of alleles in the gametes, draw a 4 square by 4 square Punnett square Gamete 1 Gamete 1 Gamete 2 Gamete 3 Gamete 4 Gamete 2 Gamete 3 Gamete 4 Combining gametes List the gametes for Parent 1 along one edge of the Punnett YR Yr yR yr square List the gametes for Parent 2 YR YYRR YYRr YyRR YyRr along the other edge of the Punnett square Yr YYRr YYrr YyRr Yyrr Fill out the squares with alleles from both parents (keeping similar letters together) yR YyRR YyRr yyRR yyRr The result is the prediction of all possible combinations of YyRr Yyrr yyRr yyrr yr genotypes for the offspring of the dihybrid cross Calculating Ratios Yellow & Round (Y_R_): 9 green & Round (yyR_): 3 Yellow & wrinkled (Y_rr): 3 green & wrinkled (yyrr): 1 YR Yr yR yr YR YYRR YYRr YyRR YyRr Yr The phenotypic result of 2 heterozygotes in a dihybrid cross will always be 9:3:3:1 (2 dom; 1dom/1rec; 1rec/1dom; yR 2 rec) yr The genotypic result is a bit more complex YYRr YYrr YyRr Yyrr YyRR YyRr yyRR yyRr YyRr Yyrr yyRr yyrr Practice!!! In pea plants, purple flowers (F) are dominant to white flowers (f) and tall stems (T) are dominant to short stems (t). If a tall (heterozygous), purple (homozygous) flowered pea plant is crossed with a short, white flowered pea plant. What are the possibilities of having offspring of: 1. Tall, Purple 8/16 = 50% 2. Tall, White 0/16 = 0% 3. Short, Purple 8/16 = 50% 4. Short, White 0/16 = 0% Review Questions 1. Differentiate between monohybrid and dihybrid crosses. 2. Explain the four basic steps to solving a dihybrid cross. 3. Explain how to determine the alleles for each parent that are part of the Punnett square. 4. Explain how to combine gametes and alleles in a dihybrid Punnett square. 5. Use a Punnett square to solve dihybrid genetics crosses.