Area and Perimeter: Areas of Regular Polygons Review: Inscribed Polygons & Circumscribed Circles Inscribed means written inside Circumscribed means written around (the outside) inscribed polygon circumscribed circle Def: A polygon is inscribed in a circle & the circle is circumscribed about the polygon when each vertex of the polygon lies on the circle. Def: A ________________is a polygon that is equiangular & equilateral. Inscribed Regular Polygons & Triangles Inscribed Regular Pentagon Total of Interior Angles = ___________ Each Interior Angle = ______________ 5 congruent isosceles triangles Total of Central Angles = _________ Each central angle = _____________ Parts of a Regular Polygon A stands for Area A(nonagon) is the area of a regular 9-sided figure. n is the number of sides of a regular polygon p is perimeter, r is radius, s is side a is apothem ____________ – The line segment from the center of a regular polygon to the midpoint of a side or the length of this segment. Sometimes known as the ______________, or the radius of a regular polygon’s inscribed circle. Regular Polygon Area Theorem Given: an inscribed regular n-gon (shown as an octagon) A(n-gon) = 1 n sa 2 1 a(ns) 2 O a X s Y Regular Polygon Area Theorem: The area of a regular polygon is ___________________________________________ ____________________________________________________ Regular Polygon Terminology O X (Regular Octagon) M Y _______________________- the center of the circumscribed circle (O). _______________________- the distance from the center to a vertex (OX). _____________________________- an angle formed by 2 radii drawn to consecutive vertices. ( XOY ) ____________________________- the (perpendicular) distance from the center of the polygon to a side. (OM) Example: Square r = 8 2 . Find a, p, A. r 45 x a hyp leg 2 p ns 8 2 a 2 p 4(2x) xa8 p 4[(2)(8)] s 1 ap 2 1 8(64) 2 A Example: Equilateral Triangle a = 4. Find r, p, A . hyp 2short r 30 p ns p 3(2x) a long 3 short x s x 3(4) A 1 ap 2 Example: Regular Hexagon a = 5 3 . Find r, p, A. long 3 short a 3x r a s 6(2x) 6(2)(5) 60 60 x p ns hyp 2 short r 2(5) r 10 A 1 ap 2 Regular Nonagon r = 10; Find a, p, A. a r a = 10(.9397) a 9.397 X x s 70 opp sin X hyp a sin 70 10 p ns 9(2x) cos X adj hyp x cos 70 = 10 x = 10(.3420) x = 3.420 p = 9(2)(3.420) p = 61.56 1 A ap 2 1 (9.397)(61.56) 2 = 289.24 Examples r r r a a A 1. 8 2 2. 8 5. 5 6. 49 3. 4. r 6 a a p 6 4 7. 12 8. 9 3 A More Examples s r a x 1. r = 4 2 , find A. 2. a = 6, find A. r a x 3. a = 8, find p. 4. r = 12, find s. r a x 5. s = 8, find r.