2013-04-15

advertisement
4/15/2013 (periods 1,3, & 5)
4/16/2013 (periods 2 & 6)
Standards: 5 (Acids and Bases)
Objectives:
● Complete CST 83-90
● Students will be able to simplify ugly looking calculations
DO NOW:
1. After turning in HW, Get responders and sign-in
2. Review how to calculate a log using my simple estimating log chart
3. CST Problems 83-90 with responders (practice)
HOMEWORK:
NONE
===========================================================
TURNED IN: ● Journal 4/12 (what you learned about how to calculate
the log of a number with a power
of 10)
1. Ch 19.3 Ch 19.2 p. 611-613 19 (a,b,c); 20 (a,b,c) (5 pts) Std 4
2. CST Problems 77-82 (5 pts) Std MISC
(KEEP FOR
NOTEBOOK)
For 4/16, see whiteboard for 4/15
4/17/2013 Standards: 5 (Acids and Bases)
Objectives:
● Students will be able to calculate pH of solutions of STRONG acids or
bases give the concentration of the STRONG acids or bases
● Students will be able to "file dump" for CST
● Students will be able to do neutralization problems
DO NOW:
1. Copy the file dump page
HOMEWORK:
1. Ch 19.3 p. 614 22 (a,b,c,d); p. 616 24-26; p. 621 30,31,32 (5 pts) Std 5
===========================================================
NO STAMPING: ● Journal 4/15 OR 4/16
(what you learned about simplifying
calculations on
CST)
(KEEP FOR
NOTEBOOK)
# left of 1 2 3 4 5 6 7 8 9 10
10x
log of# left 0.00 0.30 0.48 0.60 0.70 0.78 0.85
of
0.90 0.95 1.00
10x
File dump for CST
LeChat
Conversions
Diatomic
elements
↓ ↑
stress
LeChat
does
LeChat
wants
shift
chart
Avo
g <----> mol <----> atoms/molecules
NOH on 17
Trends
vertica
l&
horian
tal
arrows
loose
electronegativity
ionization energy
atom size
ion size
mass
metal
non-met
reactivity
Review of calculating
pH & pOH
Multiply 2 x 2 = 4
Exponent Increases
1 x 10-1
= 0.1
1 x 10-2
= 0.01
1 x 10-3
= 0.001
1 x 10-4
= 0.0001
1 x 10-5
= 0.00001
1 x 10-6
= 0.000001
1 x 10-7
= 0.0000001
1 x 10-8
= 0.00000001
1 x 10-9
= 0.000000001
# left of 10x increases
1 x 10-9 = 0.000000001
2 x 10-9 = 0.000000002
3 x 10-9 = 0.000000003
4 x 10-9 = 0.000000004
5 x 10-9 = 0.000000005
6 x 10-9 = 0.000000006
7 x 10-9 = 0.000000007
8 x 10-9 = 0.000000008
9 x 10-9 = 0.000000009
10 x 10-9 = 0.000000010 = 1 x 10-8
1 x 10-8 = 0.00000001
2 x 10-8 = 0.00000002
3 x 10-8 = 0.00000003
4 x 10-8 = 0.00000004
5 x 10-8 = 0.00000005
6 x 10-8 = 0.00000006
7 x 10-8 = 0.00000007
8 x 10-8 = 0.00000008
9 x 10-8 = 0.00000009
10 x 10-8 = 0.00000010 = 1 x 10-7
1
x 10-7 = 0.0000001
2 x 10-7 = 0.0000002
PATTERN for # left of 10x
and the the log of those numbers
1 x 10-9 ------------> 10 x 10-9
= 1.0 x 10-8
# left of
10x
log of
# left of
10x
1 2 3 4 5 6 7 8 9 10
0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00
1 x 10-7 ------------> 10 x 10-7
= 1.0 x 10-6
# left of
10x
log of
# left of
10x
1 2 3 4 5 6 7 8 9 10
0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00
CONTINUED
1 x 10-8 ------------> 10 x 10-8
= 1.0 x 10-7
# left of
10x
log of
# left of
10x
1 2 3 4 5 6 7 8 9 10
0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00
1 x 10-6 ------------> 10 x 10-6
= 1.0 x 10-5
# left of
10x
log of
# left of
10x
1 2 3 4 5 6 7 8 9 10
0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00
What is the take away of this exercise?
3 x 10-6 = 10-5.52
(6 - .48 = 5.52)
= ph or pOH
-log of 3 = .48
6 - .48 = 5.52 = -log of the number
= ph or pOH
STRONG ACIDS AND BASES
I
O
N
I
Z
E
ionize
100%
strong acids
(memorized)
IONIZE
100%
HCl
HNO3
HClO4
H2SO4
H3PO4
1
0
0
%
(Gp 1 or Gp 2
with OH1-)
HCl -----> H1+ + OH1-
gas
(one piece)
H Cl
strong bases
ion
ion
M1V1a = M2V2b
4/18/2013 Standards: Biology - NCLB practice
Objectives:
● Students will perform well for the State NCLB Bio Test
DO NOW:
1. Read the NCLB background and answer as many of the questions as
you can. Practice Quiz due end of period, you keep background notes.
HOMEWORK:
1.
===========================================================
TURN IN: ● Journal 4/17
(Calculating pH & pOH)
(KEEP FOR
NOTEBOOK)
Download