BruteForce

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RAIK 283: Data Structures & Algorithms
Brute Force *
Dr. Ying Lu
ylu@cse.unl.edu
September 20, 2012
*slides referred to
http://www.aw-bc.com/info/levitin
Design and Analysis of Algorithms – Chapter 3
1
Brute force

A straightforward approach usually based on problem
statement and definitions

Examples:
Selection Sort
Graph Traversal
Simple Computational Tasks
Exhaustive Search
1.
2.
3.
4.
Design and Analysis of Algorithms – Chapter 3
2
Graph traversal

Many problems in A.I. and operations research require the
systematic processing of vertices and edges of graphs

Graph traversal algorithms:
• Depth-first search
• Breadth-first search

First, graph representations!
Design and Analysis of Algorithms – Chapter 4
3
Graph representations using data structures

Adjacency Matrix Representation
• Let G = (V, E), n = |V|, m = |E|, V = {v1, v2, …, vn)
• G can be represented by an n  n matrix C
Design and Analysis of Algorithms – Chapter 4
4
Adjacency list representation
Design and Analysis of Algorithms – Chapter 4
5
Traversing graphs

Depth-First Search (DFS) and Breadth-First
Search (BFS)
• Two elementary traversal strategies
• Both provide efficient ways to “visit” each vertex and
edge of a graph
• Both work on directed and undirected graphs
• They differ in the order of “visiting” vertices
Design and Analysis of Algorithms – Chapter 4
6
Depth-first search


Explore graph always moving away from last visited
vertex
Pseudocode for Depth-first-search of graph G=(V,E)
DFS(G)
count :=0
mark each vertex with 0
(unvisited)
for each vertex v V do
if v is marked with 0
dfs(v)
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
7
Example – undirected graph

a
b
c
d
e
f
g
h
dfs(v)
count := count + 1
mark v with count
Depth-first traversal:
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
8
Question

How to rewrite the procedure dfs(v), using a stack to
eliminate recursion
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
9
Non-recursive version of DFS algorithm
Algorithm dfs(v)
s.createStack();
s.push(v);
count := count + 1
mark v with count
while (!s.isEmpty()) {
let x be the node on the top of the stack s;
if (no unvisited nodes are adjacent to x)
s.pop(); // backtrack
else {
select an unvisited node u adjacent to x;
s.push(u);
count := count + 1
mark u with count
}
Design and Analysis of Algorithms – Chapter 4
}
10
Time efficiency analysis

DFS can be implemented with graphs represented as:
• Adjacency matrices:
DFS(G)
count :=0
mark each vertex with 0
(unvisited)
for each vertex v V do
if v is marked with 0
dfs(v)
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
11
Time efficiency analysis

DFS can be implemented with graphs represented as:
• Adjacency linked lists:
DFS(G)
count :=0
mark each vertex with 0
(unvisited)
for each vertex v V do
if v is marked with 0
dfs(v)
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
12
Time efficiency analysis

DFS can be implemented with graphs represented as:
• Adjacency matrices: Θ(V2)
• Adjacency linked lists: Θ(V+E)
DFS(G)
count :=0
mark each vertex with 0
(unvisited)
for each vertex v V do
if v is marked with 0
dfs(v)
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
13
Application: checking graph connectivity and
finding connected components
DFS(G)
count :=0
mark each vertex with 0
(unvisited)
for each vertex v V do
if v is marked with 0
dfs(v)
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
14
Application: checking acyclicity
DFS(G)
count :=0
mark each vertex with 0
(unvisited)
for each vertex v V do
if v is marked with 0
dfs(v)
dfs(v)
count := count + 1
mark v with count
for each vertex w adjacent to
v do
if w is marked with 0
dfs(w)
Design and Analysis of Algorithms – Chapter 4
15
Breadth-first search

Explore graph moving across to all the neighbors of last
visited vertex

Similar to level-by-level tree traversals

Applications: same as DFS, but can also find paths from a
vertex to all other vertices with the smallest number of
edges
Design and Analysis of Algorithms – Chapter 4
16
Example – undirected graph

a
b
c
d
e
f
g
h
Breadth-first traversal:
Design and Analysis of Algorithms – Chapter 4
17
Example – undirected graph


a
b
c
d
e
f
g
h
Depth-first search could be implemented on a stack
How about breadth-first search
Design and Analysis of Algorithms – Chapter 4
18
Breadth-first search algorithm
bfs(v)
count := count + 1
mark v with count
for each vertex v V initialize queue with v
do
while queue is not empty do
if v is marked
a := front of queue
with 0
for each vertex w adjacent to a do
BFS(G)
count :=0
mark each vertex with 0
bfs(v)
if w is marked with 0
count := count + 1
mark w with count
add w to the end of the queue
remove a from the front of the queue
Design and Analysis of Algorithms – Chapter 4
19
Breadth-first search: Notes
 BFS
has same efficiency as DFS and can be
implemented with graphs represented as:
• Adjacency matrices: Θ(V2)
• Adjacency linked lists: Θ(V+E)
Design and Analysis of Algorithms – Chapter 4
20
In-class exercise
 Exercise
3.2.3 Gadget testing
• A firm wants to determine the highest floor of
its n-story headquarters from which a gadget
can fall with no impact on the gadget’s
functionality. The firm has two identical gadgets
to experiment with. Design an algorithm in the
best efficiency class you can to solve this
problem.
Design and Analysis of Algorithms – Chapter 3
21
Brute force polynomial evaluation

Problem: Find the value of polynomial
p(x) = anxn + an-1xn-1 +… + a1x1 + a0
at a point x = x0
Design and Analysis of Algorithms – Chapter 3
22
Brute force polynomial evaluation



Problem: Find the value of polynomial
p(x) = anxn + an-1xn-1 +… + a1x1 + a0
at a point x = x0
Algorithm:
x := x0
p := 0.0
for i := n down to 0 do
power := 1
for j := 1 to i do
power := power * x
p := p + a[i] * power
return p
Efficiency:
Design and Analysis of Algorithms – Chapter 3
23
Brute force polynomial evaluation



Problem: Find the value of polynomial
p(x) = anxn + an-1xn-1 +… + a1x1 + a0
at a point x = x0
Algorithm:
x := x0
p := 0.0
for i := n down to 0 do
power := 1
for j := 1 to i do
power := power * x
p := p + a[i] * power
return p
Efficiency: (n2)
Design and Analysis of Algorithms – Chapter 3
24
Brute force polynomial evaluation




Problem: Find the value of polynomial
p(x) = anxn + an-1xn-1 +… + a1x1 + a0
at a point x = x0
Algorithm:
x := x0
p := 0.0
for i := n down to 0 do
power := 1
for j := 1 to i do
power := power * x
p := p + a[i] * power
return p
Efficiency: (n2)
Can we design aDesign
linear
algorithm for this problem
and Analysis of Algorithms – Chapter 3
25
Polynomial evaluation: improvement



We can do better by evaluating from right to left:
p(x) = anxn + an-1xn-1 +… + a1x1 + a0
at a point x = x0
Algorithm:
x := x0
p := a[0]
power := 1
for i := 1 to n do
power := power * x
p := p + a[i] * power
return p
Efficiency: (n)
Design and Analysis of Algorithms – Chapter 3
26
Polynomial evaluation: improvement




We can do better by evaluating from right to left:
p(x) = anxn + an-1xn-1 +… + a1x1 + a0
at a point x = x0
Algorithm:
x := x0
p := a[0]
power := 1
for i := 1 to n do
power := power * x
p := p + a[i] * power
return p
Efficiency: (n)
Can we design a better than linear algorithm for this
problem
Design and Analysis of Algorithms – Chapter 3
27
Brute force closest-pair algorithm

Closest pair
• Problem: find the closest pair among n points in k-dimensional
space
Design and Analysis of Algorithms – Chapter 3
28
Brute force closest-pair algorithm

Closest pair
• Problem: find the closest pair among n points in k-dimensional
space
• Algorithm: Compute distance between each pair of points and
identify the pair resulting in the shortest distance
• What is (or should be) the basic operation of the algorithm?
Design and Analysis of Algorithms – Chapter 3
29
Brute force closest-pair algorithm

Closest pair
• Problem: find the closest pair among n points in k-dimensional
space
• Algorithm: Compute distance between each pair of points and
identify the pair resulting in the shortest distance
• Basic operation (squaring):
d
k

( xi  yi ) 2
i 1
d 
2
k

( xi  yi ) 2
i 1
Design and Analysis of Algorithms – Chapter 3
30
Brute force closest-pair algorithm

Closest pair
• Problem: find the closest pair among n points in k-dimensional space
• Algorithm: Compute distance between each pair of points and
identify the pair resulting in the shortest distance
• Basic operation:
d
k

( xi  yi ) 2
i 1
d 
2
k

( xi  yi ) 2
i 1
• How many different pairs of points?
Design and Analysis of Algorithms – Chapter 3
31
Principle of counting: Product Rule

The Product Rule
• Suppose that a procedure can be broken down into a sequence of
two tasks. If there are n1 ways to do the first task and for each of
these ways of doing the first task, there are n2 ways to do the second
task, then there are n1n2 ways to do the procedure.
Design and Analysis of Algorithms – Chapter 3
32
Principle of counting: Product Rule

The Product Rule
• Suppose that a procedure can be broken down into a sequence of
two tasks. If there are n1 ways to do the first task and for each of
these ways of doing the first task, there are n2 ways to do the second
task, then there are n1n2 ways to do the procedure.

Calculation
• Applying the product rule, there are n*(n-1) pairs among n points
• Considering (a, b) and (b, a) as the same, we divide the above
number by 2 and thus, there are n*(n-1)/2 different pairs of points
Design and Analysis of Algorithms – Chapter 3
33
Brute force closest-pair algorithm

Closest pair
• Problem: find the closest pair among n points in k-dimensional space
• Algorithm: Compute distance between each pair of points and
identify the pair resulting in the shortest distance
• Basic operation:
d
k

( xi  yi ) 2
i 1
d 
2
k

( xi  yi ) 2
i 1
• Efficiency:
(n2)
Design and Analysis of Algorithms – Chapter 3
34
In-class exercise

Can you design a faster algorithm than the one based on
the brute-force strategy to solve the closest-pair problem
for n points x1, x2, … , xn on the real line?

What is the time efficiency of your algorithm?
Design and Analysis of Algorithms – Chapter 3
35
In-class exercise

Can you design a faster algorithm than the one based on
the brute-force strategy to solve the closest-pair problem
for n points x1, x2, … , xn on the real line?

Algorithm:
• Step1: Sort the numbers in ascending order, O(nlogn)
• Step 2: Compute the differences between adjacent numbers
in the sorted list, (n)
• Step 3: Find the smallest such difference, (n)
Running time of the entire algorithm:
O(nlogn) + (n) + (n) = O(nlogn)
Design and Analysis of Algorithms – Chapter 3
36
Convex hull problem

Convex hull
• Problem:
Find smallest convex polygon enclosing
n points on the plane
• Convex:
– A geometric figure with no
convex
indentations.
– Formally, a geometric figure is
convex if every line segment
connecting interior points is entirely
contained within the figure's
Non-convex
interior.
Design and Analysis of Algorithms – Chapter 3
37
Example: Convex Hull
Input: p1,p2,p3,p4,p5,p6,p7,p8,p9,p10,p11
p9
Output: p2,p9,p11,p4,p5,p6,p8,p2
p11
p4
p1
p2
p3
p7
p8
p10
p6
p5
Convex hull: application domain*

Computer visualization, ray tracing
• (e.g. video games, replacement of bounding boxes)

Path finding
• (e.g. embedded AI of Mars mission rovers)

Geographical Information Systems (GIS)
• (e.g. computing accessibility maps)

Visual pattern matching
• (e.g. detecting car license plates)

Verification methods
• (e.g. bounding of Number Decision Diagrams)

Geometry
• (e.g. diameter computation)
*slide refer to http://www.montefiore.ulg.ac.be/~briquet/algo3-chull-20070206.pdf
Design and Analysis of Algorithms – Chapter 3
39
Convex hull brute force algorithm

p9
Extreme points of the
convex polygon
• Consider all the points in the
polygon as a set. An extreme
point is a point of the set that
is not a middle point of any
line segment with end points
in the set.
p11
p4
p1
p2
p3
p7
p8
p10
p5
p6
Design and Analysis of Algorithms – Chapter 3
40
Convex hull brute force algorithm

p9
Extreme points of the
convex polygon
• Consider all the points in the
polygon as a set. An extreme
point is a point of the set that
is not a middle point of any
line segment with end points
in the set.
p11
p4
p1
p2
p3
p7
p8
p10
p5
p6
Which pairs of extreme points need to be connected
to form the boundary of the convex hull?
Design and Analysis of Algorithms – Chapter 3
41
Convex hull brute force algorithm

A line segment connecting two points Pi and Pj of a
set of n points is a part of its convex hull’s
boundary if and only if all the other points of the
set lies on the same side of the straight line through
these two points.
Design and Analysis of Algorithms – Chapter 3
42
Convex hull brute force algorithm

The straight line through two points (x1, y1), (x2,
y2) in the coordinate plane can be defined by the
following equation
• ax + by = c
where a = y2 – y1, b = x1 – x2, c = x1y2 - y1x2

Such a line divides the plane into two half-planes:
for all the points in one of them: ax + by > c, while
for all the points in the other, ax + by < c.
Design and Analysis of Algorithms – Chapter 3
43
Convex hull brute force algorithm

Algorithm: For each pair of points p1 and p2
determine whether all other points lie to the same
side of the straight line through p1 and p2, i.e.
whether ax+by-c all have the same sign

Efficiency:
Design and Analysis of Algorithms – Chapter 3
44
Convex hull brute force algorithm

Algorithm: For each pair of points p1 and p2
determine whether all other points lie to the same
side of the straight line through p1 and p2, i.e.
whether ax+by-c all have the same sign

Efficiency: (n3)
Design and Analysis of Algorithms – Chapter 3
45
Exhaustive search: definition

A brute force solution to a problem involving
search for an element with a special property,
usually among combinatorial objects such as a
permutations, combinations, or subsets of a set.
Design and Analysis of Algorithms – Chapter 3
46
Exhaustive search: method

Construct a way of listing all potential solutions to
the problem in a systematic manner
• all solutions are eventually listed
• no solution is repeated
Evaluate solutions one by one, perhaps
disqualifying infeasible ones and keeping track of
the best one found so far
 When search ends, announce the winner

Design and Analysis of Algorithms – Chapter 3
47
Example 1: Traveling salesman problem
Given n cities with known distances between each
pair, find the shortest tour that passes through all
the cities exactly once before returning to the
starting city.
 Alternatively: Find shortest Hamiltonian circuit in
a weighted connected graph.
 Example:
2

a
b
5
3
4
8
c
7
d
Design and Analysis of Algorithms – Chapter 3
48
Traveling salesman by exhaustive search

Tour
a→b→c→d→a
a→b→d→c→a
a→c→b→d→a
a→c→d→b→a
a→d→b→c→a
a→d→c→b→a

Efficiency:






Cost
2+3+7+5 = 17
2+4+7+8 = 21
8+3+4+5 = 20
8+7+4+2 = 21
5+4+3+8 = 20
5+7+3+2 = 17
Design and Analysis of Algorithms – Chapter 3
.
49
Traveling salesman by exhaustive search

Tour
a→b→c→d→a
a→b→d→c→a
a→c→b→d→a
a→c→d→b→a
a→d→b→c→a
a→d→c→b→a

Efficiency: (n-1)!/2






Cost
2+3+7+5 = 17
2+4+7+8 = 21
8+3+4+5 = 20
8+7+4+2 = 21
5+4+3+8 = 20
5+7+3+2 = 17
Design and Analysis of Algorithms – Chapter 3
.
50
0-1 Knapsack problem

Given a knapsack with maximum capacity W, and
a set S consisting of n items

Each item i has some weight wi and benefit value vi

Problem: How to pack the knapsack to achieve
maximum total value of packed items?
Design and Analysis of Algorithms – Chapter 3
51
0-1 Knapsack problem: a picture
Weight
Items
This is a knapsack
Max weight: W = 20
W = 20
Benefit value
wi
vi
2
3
3
4
4
5
5
8
9
10
Design and Analysis of Algorithms – Chapter 3
52
0-1 Knapsack problem

Problem, in other words, is to find
max  vi subject to
iT
w W
iT
i
The problem is called a “0-1” problem,
because each item must be entirely accepted or
rejected.
 In the “Fractional Knapsack Problem,” we can
take fractions of items.

Design and Analysis of Algorithms – Chapter 3
53
0-1 Knapsack problem: brute-force approach
Let’s first solve this problem with a
straightforward algorithm

We go through all combinations (subsets) and
find the one with maximum value and with
total weight less or equal to W
Design and Analysis of Algorithms – Chapter 3
54
Example 2: Knapsack Problem
Given n items:
• weights: w1 w2 … wn
• values: v1 v2 … vn
• a knapsack of capacity W
Find the most valuable subset of the items that fit into the
knapsack
Example:
item weight
1
2
2
5
3
10
4
5
value
$20
$30
$50
$10
Knapsack capacity W=16
Design and Analysis of Algorithms – Chapter 3
55
Knapsack by exhaustive search
Subset

{1}
{2}
{3}
{4}
{1,2}
{1,3}
{1,4}
{2,3}
{2,4}
{3,4}
{1,2,3}
{1,2,4}
{1,3,4}
{2,3,4}
{1,2,3,4}
Total weight
0
2
5
10
5
7
12
7
15
10
15
17
12
17
20
22
Total value
$0
$20
$30
$50
$10
$50
$70
$30
$80
$40
$60
not feasible
$60
not feasible
not feasible
not feasible
Most valuable subset?
Efficiency:
Design and Analysis of Algorithms – Chapter 3
56
0-1 Knapsack problem: brute-force approach

Algorithm:
• We go through all combinations and find the one
with maximum value and with total weight less or
equal to W

Efficiency:
• Since there are n items, there are 2n possible
combinations of items.
• Thus, the running time will be O(2n)
Design and Analysis of Algorithms – Chapter 3
57
Brute force strengths and weaknesses

Strengths:
• wide applicability
• simplicity
• yields reasonable algorithms for some important problems
– sorting; matrix multiplication; closest-pair; convex-hull
• yields standard algorithms for simple computational tasks
and graph traversal problems
Design and Analysis of Algorithms – Chapter 3
58
Brute force strengths and weaknesses

Weaknesses:
• rarely yields efficient algorithms
• some brute force algorithms unacceptably slow
– e.g., the recursive algorithm for computing Fibonacci numbers
• not as constructive/creative as some other design techniques
Design and Analysis of Algorithms – Chapter 3
59
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