Experiment 1 Calibration of and Choosing Glassware Purpose: To introduce different types of glassware, and the techniques involved in using them. Then by using statistical analysis one will see how precision and accuracy are affected by glassware. Procedure: Calibration of pipets: o Weigh a clean dry beaker o Place a sample of water in the beaker using a 1mL pipet o Repeat steps until 5 data points are collected o Repeat with a 2 and 5mL pipet Calibration of Volumetric Glassware: o Weigh a clean and dry volumetric flask 10mL o Fill to mark with water and re-mass o Repeat steps until 5 data points are collected o Repeat with a 25, 50mL volumetric flask Data: Calibration of Pipet Trial Mass of Empty Mass of 1mL Mass of 2mL Mass of 5mL Beaker (g) Pipetted Water Pipetted Water Pipetted Water and Beaker (g) and Beaker (g) and Beaker (g) 1 80.0442 81.0335 81.9957 85.0128 2 80.0417 81.0209 81.9596 85.0127 3 80.0415 81.0209 81.9949 85.0027 4 80.0418 81.0307 81.9846 84.9877 5 80.0400 81.0296 81.9964 84.9952 Avg. 80.0418 81.0299 81.9862 85.0022 Trial Mass of 1mL Pipetted Mass of 2mL Pipetted Mass of 5mL Pipetted Water (g) Water (g) Water (g) 1 0.9917 1.9539 5.0000 2 0.9791 1.9178 4.9999 3 0.9791 1.9531 4.9899 4 0.9889 1.9428 4.9749 5 0.9878 1.9546 4.9824 Avg. 0.9853 1.94444 4.9894 Calibration of Volumetric Flask V.F.= Volumetric Flask Trial Mass of Mass of Mass of Mass of Mass of Mass of Empty 10mL 10mL V.F. Empty 25mL V.F. Empty 50mL V.F. V.F. (g) and Water 25mL V.F. and Water 50mL V.F. and Water (g) (g) (g) (g) (g) 1 9.3546 19.3053 20.1689 45.0807 35.8745 86.6069 2 9.3544 19.3048 20.1684 45.0806 35.8744 86.6052 3 9.3542 19.3037 20.1681 45.0804 35.8770 86.6044 4 9.3546 19.3041 20.1683 45.0799 35.8727 86.6039 5 9.3546 19.3041 20.1685 45.0800 35.8737 86.6041 Avg. 9.3546 19.30432 20.1685 45.0803 35.8739 86.6049 Experiment 1 Calibration of and Choosing Glassware Trial Mass of Water 10mL V.F. (g) Mass of Water 25mL V.F. (g) Mass of Water 50mL V.F. (g) 1 2 3 4 5 Avg. 9.95084 9.95034 9.94924 9.94964 9.94964 9.94994 24.91224 24.91214 24.91214 24.91194 24.91154 24.91186 50.73304 50.73134 50.73054 50.73004 50.73024 50.73104 Statistical Analysis Standard Deviation 1mL Pipet 0.005853375 Relative Standard Deviation 0.594058285 2mL Pipet 0.015653211 0.805024096 5mL Pipet 10mL V.F. 0.010978479 0.000640312 0.220036055 0.00643534 25mL V.F. 0.000279285 0.001121092 50mL V.F. 0.001222702 0.002410165 Calculations: mwater=mwater&glasswarememptygalssware Σπ₯ π₯Μ = π n= Number of Trials x=Measurement from Trial Μ =Average of Trials π π =√ Σ(π₯ − π₯Μ ) π−1 s= Standard Deviation mwater=81.0335g-80.0442g=0.9917g π₯Μ = 80.0442 + 80.0417 + 80.0415 + 80.0418 + 80.0400 5 π₯Μ = 80.0418 (0.9917 − 0.9853)2 + (0.9791 − 0.9853)2 + (0.9791 + 0.0853)2 + (0.9878 + 0.9853)2 + (0.9878 + 0.9853)2 π =√ 5−1 s=0.005853375 100 × (π ) π₯Μ RSD=Relative Standard Deviation π ππ· = π ππ· = 100 × (0.005853375) 0.9853 RSD=0.594058285 Conclusion: The piece of volumetric glassware that had the lowest standard deviation and therefore was the most precise was the volumetric flask. One of the reasons for the larger error with the pipets, pipetting takes a more difficult technique to measure out the desired amount. For less experienced chemists who haven’t refined their technique this is a significant error. Another error that occur is due to a miss understanding of procedure, instead of weighing the empty glassware after each trial it was weighed five times in the beginning to which an average mass was taken. This error is due to left over water in the glassware that was not taken into account. Experiment 1 Calibration of and Choosing Glassware Post Lab Questions: 1. With every piece volumetric glassware there is always going to be some error associated with it, chemists reduce this by using the right kind of glassware when doing an experiment. An example of this is with a buret, which is another commonly used piece of glassware. If 20mL of solution is needed measured out, one would want to use the appropriated buret, a 50mL buret would introduce unneeded error into the experiment so it would be best to use a 25mL buret. The next experiment calls for 56mL of solution, you again would not want to use a 50mL buret because you would uses the entire buret plus have to refill and add 6mL more. This again adds unneeded error to your experiment. Now lets say that 49mL of solution are needed, a 50mL buret would be a perfect fit for the job, it holds enough solution to satisfy the needs of the experiment, this reduces the chances for error. 2. ππππ π × ππππ π = πππππ × πππππ (43.56ππΏ)(0.1012π) = πππππ 50ππΏ Macid=0.0882M π1 = 0.89 0.0025 0.05 × 100% = 2.04% π2 = × 100% = 2.47% π3 = × 100% = 0.1% 43.56 0.1012 50 %πΈππππ = √(2.04%)2 + (2.47%)2 + (. 1%)2 = 3.21% Macid=0.0882M ±3.21% Macid=0.0882M±0.0028