Enzyme Kinetics and Inhibition Andy Howard Introductory Biochemistry, Spring 2008 12 February 2008 12 Feb 2008 What’s the relationship between concentration and reaction rate? In the presence of an enzyme, there is a definable relationship between substrate concentration and reaction rate. Biochemistry: Enzyme Kinetics & inhibition P. 2 of 65 12 Feb 2008 Plans for Today Enzyme kinetics Michaelis-Menten kinetics: overview Kinetic Constants Kinetic Mechanisms Induced Fit Measurements and calculational tools Multisubstrate reactions Biochemistry: Enzyme Kinetics & inhibition Enzyme Inhibition Why study it? The concept Types of inhibitors Kinetics of inhibition Pharmaceutical inhibitors What makes an inhibitor a useful drug? P. 3 of 65 12 Feb 2008 More complex cases More complicated than this if >1 reactant involved or if a catalyst whose concentration influences the production of species B is present. If >1 reactant required for making B, then usually the reaction will be linear in the concentration of the scarcest reactant and nearly independent of the concentration of the more plentiful reactants. Biochemistry: Enzyme Kinetics & inhibition P. 4 of 65 12 Feb 2008 Bimolecular reaction If in the reaction A+DB the initial concentrations of [A] and [D] are comparable, then the reaction rate will be linear in both [A] and [D]: d[B]/dt = v = k[A][D] = k[A]1[D]1 I.e. the reaction is first-order in both A and D, and it’s second-order overall Biochemistry: Enzyme Kinetics & inhibition P. 5 of 65 12 Feb 2008 Forward and backward Rate of reverse reaction may not be the same as the rate at which the forward reaction occurs. If the forward reaction rate of reaction 1 is designated as k1, the backward rate typically designated as k-1. Biochemistry: Enzyme Kinetics & inhibition P. 6 of 65 12 Feb 2008 Multi-step reactions In complex reactions, we may need to keep track of rates in the forward and reverse directions of multiple reactions. Thus in the conversion A B C we can write rate constants k1, k-1, k2, and k-2 as the rate constants associated with converting A to B, converting B to A, converting B to C, and converting C to B. Biochemistry: Enzyme Kinetics & inhibition P. 7 of 65 12 Feb 2008 [ES] Michaelis-Menten kinetics t A very common situation is one in which for some portion of the time in which a reaction is being monitored, the concentration of the enzyme-substrate complex is nearly constant. Thus in the general reaction E + S ES E + P where E is the enzyme, S is the substrate, ES is the enzyme-substrate complex (or "enzymeintermediate complex"), and P is the product We find that [ES] is nearly constant for a considerable stretch of time. Biochemistry: Enzyme Kinetics & inhibition P. 8 of 65 12 Feb 2008 Michaelis-Menten rates Rate at which new ES molecules are being produced in the first forward reaction is equal to the rate at which ES molecules are being converted to (E and P) and (E and S). Rate of formation of ES from left = vf = k1([E]tot - [ES])[S] because the enzyme that is already substrate-bound is unavailable! Biochemistry: Enzyme Kinetics & inhibition P. 9 of 65 12 Feb 2008 Equating the rates Rate of disappearance of ES on right and left is vd = k-1[ES] + k2[ES] = (k-1+ k2)[ES] This rate of disappearance should be equal to the rate of appearance Under these conditions vf = vd. Biochemistry: Enzyme Kinetics & inhibition P. 10 of 65 12 Feb 2008 Derivation, continued Thus since vf = vd. k1([E]tot - [ES])[S] = (k-1+ k2)[ES] Km (k-1+ k2)/k1 = ([E]tot - [ES])[S] / [ES] [ES] = [E]tot [S] / (Km + [S]) But the rate-limiting reaction is the formation of product: v0 = k2[ES] Thus v0 = k2[E]tot [S] / (Km + [S]) Biochemistry: Enzyme Kinetics & inhibition P. 11 of 65 12 Feb 2008 Maximum velocity What conditions would produce the maximum velocity? Answer: very high substrate concentration ([S] >> [E]tot), for which all the enzyme would be bound up with substrate. Thus under those conditions we get Vmax = v0 = k2[ES] = k2[E]tot Biochemistry: Enzyme Kinetics & inhibition P. 12 of 65 12 Feb 2008 Using Vmax in M-M kinetics Thus since Vmax = k2[E]tot, v0 = Vmax [S] / (Km+[S]) That’s the famous Michaelis-Menten equation Biochemistry: Enzyme Kinetics & inhibition P. 13 of 65 12 Feb 2008 Graphical interpretation 0.01 Michaelis-Menten kinetics 0.009 Initial velocity v0, Ms-1 0.008 0.007 Vmax = 0.01 Ms -1 0.006 Km = 0.03M 0.005 [E]tot = 10 -7M 0.004 kcat = 10 5 s-1 0.003 0.002 0.001 0 0 0.1 0.2 0.3 0.4 0.5 0.6 Substrate conc, M Biochemistry: Enzyme Kinetics & inhibition P. 14 of 65 12 Feb 2008 0.7 Physical meaning of Km As we can see from the plot, the velocity is half-maximal when [S] = Km Trivially derivable: if [S] = Km, then v0 = Vmax[S] / ([S]+[S]) = Vmax /2 We can turn that around and say that the Km is defined as the concentration resulting in half-maximal velocity Km is a property associated with binding of S to E, not a property of turnover Biochemistry: Enzyme Kinetics & inhibition P. 15 of 65 12 Feb 2008 Physical meaning of Vmax Vmax is the initial reaction velocity when the substrate concentration is high compared to Km: v0 = Vmax when [S] >> Km. This result follows directly from Michaelis-Menten equation: if [S] >> Km, then [S] + Km ~ [S], so [S]/(Km+[S]) = 1, and v0 = Vmax. Biochemistry: Enzyme Kinetics & inhibition P. 16 of 65 12 Feb 2008 kcat A quantity we often want is the maximum velocity independent of how much enzyme we originally dumped in That would be kcat = Vmax / [E]tot Oh wait: that’s just the rate of our rate-limiting step, i.e. kcat = k2 Biochemistry: Enzyme Kinetics & inhibition P. 17 of 65 12 Feb 2008 What do Vmax and kcat tell us? These are properties associated with the enzyme’s ability to turn over substrate, not its ability to bind substrate. So if we influence an enzyme’s substrate affinity without altering its ability to convert substrate to product, we won’t change Vmax or kcat. Biochemistry: Enzyme Kinetics & inhibition P. 18 of 65 12 Feb 2008 Physical meaning of kcat Describes turnover of substrate to product: Number of product molecules produced per sec per molecule of enzyme More complex reactions may not have kcat = k2, but we can often approximate them that way anyway Some enzymes very efficient: kcat > 106 s-1 Biochemistry: Enzyme Kinetics & inhibition P. 19 of 65 12 Feb 2008 Specificity constant, kcat/Km kcat/Km measures affinity of enzyme for a specific substrate: we call it the specificity constant for the enzyme for that particular substrate Useful in comparing primary substrate to other substrates (e.g. ethanol vs. propanol in alcohol dehydrogenase) Biochemistry: Enzyme Kinetics & inhibition P. 20 of 65 12 Feb 2008 Kinetic Mechanisms If a reaction involves >1 reactant or >1 product, there may be variations in kinetics that occur as a result of the order in which substrates are bound or products are released. Examine figure 5.7 in Horton, which depicts bisubstrate reactions of various sorts. As you can see, the possibilities enumerated include sequential, random, and ping-pong mechanisms. Biochemistry: Enzyme Kinetics & inhibition P. 21 of 65 12 Feb 2008 Historical thought Biochemists, 1935 - 1970 examined effect on reaction rates of changing [reactants] and [enzymes], and deducing the mechanistic realities from kinetic data. In recent years other tools have become available for deriving the same information, including static and dynamic structural studies that provide us with slide-shows or even movies of reaction sequences. But things like fig. 5.7 still help! Biochemistry: Enzyme Kinetics & inhibition P. 22 of 65 12 Feb 2008 Sequential, ordered reactions W.W.Cleland Substrates, products must bind in specific order for reaction to complete A B P Q _____________________________ E EA (EAB) (EPQ) EQ E Biochemistry: Enzyme Kinetics & inhibition P. 23 of 65 12 Feb 2008 Sequential, random reactions Substrates can come in in either order, and products can be released in either order A B P Q EA EQ __ E (EAB)(EPQ) E EB EP B A Q P Biochemistry: Enzyme Kinetics & inhibition P. 24 of 65 12 Feb 2008 Ping-pong mechanism First substrate enters, is altered, is released, with change in enzyme Then second substrate reacts with altered enzyme, is altered, is released Enzyme restored to original state A P B Q E EA FA F Biochemistry: Enzyme Kinetics & inhibition FB FQ E P. 25 of 65 12 Feb 2008 Historical thought Biochemists, 1935 - 1970 examined effect on reaction rates of changing [reactants] and [enzymes], and deducing the mechanistic realities from kinetic data. In recent years other tools have become available for deriving the same information, including static and dynamic structural studies that provide us with slide-shows or even movies of reaction sequences. But things like fig. 5.7 still help! Biochemistry: Enzyme Kinetics & inhibition P. 26 of 65 12 Feb 2008 Induced fit Conformations of enzymes don't change enormously when they bind substrates, but they do change to some extent. An instance where the changes are fairly substantial is the binding of substrates to kinases. Danger:enzyme will catalyze the unproductive hydrolysis of ATP in the same site where the kinase reaction might occur Biochemistry: Enzyme Kinetics & inhibition P. 27 of 65 Daniel Koshland 12 Feb 2008 Kinase reactions unwanted reaction ATP + H-O-H ⇒ ADP + Pi will compete with the desired reaction ATP + R-O-H ⇒ ADP + R-O-P Kinases minimize the likelihood of this unproductive activity by changing conformation upon binding substrate so that hydrolysis of ATP cannot occur until the binding happens. Illustrates the importance of the order in which things happen in enzyme function Biochemistry: Enzyme Kinetics & inhibition P. 28 of 65 12 Feb 2008 Measurements and calculations The standard Michaelis-Menten formulation is v0=f([S]), but it’s not linear in [S]. We seek linearizations of the equation so that we can find Km and kcat, and so that we can understand how various changes affect the reaction. Biochemistry: Enzyme Kinetics & inhibition P. 29 of 65 12 Feb 2008 Lineweaver-Burk Dean Burk Simple linearization of Michaelis-Menten: v0 = Vmax[S]/(Km+[S]). Take reciprocals: 1/v0 = (Km +[S])/(Vmax[S]) = (Km /(Vmax[S])) + [S]/(Vmax[S])) Hans Lineweaver = (Km/Vmax)*1/[S] + 1/Vmax Thus a plot of 1/[S] as the independent variable vs. 1/v0 as the dependent variable will be linear with Y-intercept = 1/Vmax and slope Km/Vmax Biochemistry: Enzyme Kinetics & inhibition P. 30 of 65 12 Feb 2008 How to use this Y-intercept is useful directly: computeVmax = 1/(Y-intercept) We can get Km/Vmax from slope and then use our knowledge of Vmax to get Km; or X intercept = -1/ Km … that gets it for us directly! Biochemistry: Enzyme Kinetics & inhibition P. 31 of 65 12 Feb 2008 Demonstration that the X-intercept is at -1/Km X-intercept means Y = 0 In Lineweaver-Burk plot, 0 = (Km/Vmax)*1/[S] + 1/Vmax For nonzero 1/Vmax we divide through: 0 = Km /[S] + 1, -1 = Km/[S], [S] = -Km. But the axis is for 1/[S], so the intercept is at 1/[S] = -1/ Km. Biochemistry: Enzyme Kinetics & inhibition P. 32 of 65 12 Feb 2008 Graphical form of L-B 1/v0, sLmol-1 1/Vmax, sLmol-1 Slope=Km/Vmax 1/[S], M-1 -1/Km, Lmol-1 Biochemistry: Enzyme Kinetics & inhibition P. 33 of 65 12 Feb 2008 Are those values to the left of 1/[S] = 0 physical? No. It doesn’t make sense to talk about negative substrate concentrations or infinite substrate concentrations. But if we can curve-fit, we can still use these extrapolations to derive the kinetic parameters. Biochemistry: Enzyme Kinetics & inhibition P. 34 of 65 12 Feb 2008 Advantages and disadvantages of L-B plots Easy conceptual reading of Km and Vmax (but remember to take the reciprocals!) Suboptimal error analysis [S] and v0 values have errors Error propagation can lead to significant uncertainty in Km (and Vmax) Other linearizations available (see homework) Better ways of getting Km and Vmax available Biochemistry: Enzyme Kinetics & inhibition P. 35 of 65 12 Feb 2008 Don’t fall into the trap! When you’re calculating Km and Vmax from Lineweaver-Burk plots, remember that you need the reciprocal of the values at the intercepts If the X-intercept is -5000 M-1, then Km = -1/(X-intercept) =(-)(-1/5000 M-1) = 2*10-4M Sanity check: typically 10-5M < Km < 10-3M Typically kcat ~ 10 to 107 s-1 (table 5.1), so for typical [E]=10-7M, Vmax = [E]kcat = 10-6 Ms-1 to 1 Ms-1 Biochemistry: Enzyme Kinetics & inhibition P. 36 of 65 12 Feb 2008 iClicker quiz 1. The kinase reaction just described probably operates according to a (a) sequential, random mechanism (b) sequential, ordered mechanism ( c) ping-pong mechanism (d) none of the above. Biochemistry: Enzyme Kinetics & inhibition P. 37 of 65 12 Feb 2008 iClicker quiz 2. If we alter the kinetics of a reaction by increasing Km but leaving Vmax alone, how will the L-B plot change? (a) X intercept will move toward the origin and the Y intercept will remain as it was (b) X intercept will move away from origin and Y intercept will remain as it was ( c) Y intercept will move away from origin and X intercept will remain as it was (d) Y intercept will move toward origin and X intercept will remin as it was (e) None of the above Biochemistry: Enzyme Kinetics & inhibition P. 38 of 65 12 Feb 2008 L-B plots for ordered sequential reactions http://www-biol.paisley.ac.uk/ kinetics/Chapter_4/chapter4_3.html Plot 1/v0 vs. 1/[A] for various [B] values; flatter slopes correspond to larger [B] Lines intersect @ a point in between X intercept and Y intercept Biochemistry: Enzyme Kinetics & inhibition P. 39 of 65 12 Feb 2008 L-B plots for pingpong reactions Again we plot 1/v vs 1/[A] for various [B] Parallel lines (same kcat/Km); lower lines correspond to larger [B] http://www-biol.paisley.ac.uk/kinetics/ Chapter_4/chapter4_3_2.html Biochemistry: Enzyme Kinetics & inhibition P. 40 of 65 12 Feb 2008 Why study inhibition? • Let’s look at how enzymes get inhibited. • At least two reasons to do this: • We can use inhibition as a probe for understanding the kinetics and properties of enzymes in their uninhibited state; • Many—perhaps most—drugs are inhibitors of specific enzymes. • We'll see these two reasons for understanding inhibition as we work our way through this topic. Biochemistry: Enzyme Kinetics & inhibition P. 41 of 65 12 Feb 2008 The concept of inhibition An enzyme is a biological catalyst, i.e. a substance that alters the rate of a reaction without itself becoming permanently altered by its participation in the reaction. The ability of an enzyme (particularly a proteinaceous enzyme) to catalyze a reaction can be altered by binding small molecules to it sometimes at its active site sometimes at a site distant from the active site. Biochemistry: Enzyme Kinetics & inhibition P. 42 of 65 12 Feb 2008 Inhibitors and Accelerators Usually these alterations involve a reduction in the enzyme's ability to accelerate the reaction; less commonly, they give rise to an increase in the enzyme's ability to accelerate a reaction. Biochemistry: Enzyme Kinetics & inhibition P. 43 of 65 12 Feb 2008 Why more inhibitors than accelerators? Natural selection: if there were small molecules that can facilitate the enzyme's propensity to speed up a reaction, nature probably would have found a way to incorporate those facilitators into the enzyme over the billions of years that the enzyme has been available. Most enzymes are already fairly close to optimal in their properties; we can readily mess them up with effectors, but it's more of a challenge to find ways to make enzymes better at their jobs. Biochemistry: Enzyme Kinetics & inhibition P. 44 of 65 12 Feb 2008 Types of inhibitors Irreversible Inhibitor binds without possibility of release Usually covalent Each inhibition event effectively removes a molecule of enzyme from availability Reversible Usually noncovalent (ionic or van der Waals) Several kinds Classifications somewhat superseded by detailed structure-based knowledge of mechanisms, but not entirely Biochemistry: Enzyme Kinetics & inhibition P. 45 of 65 12 Feb 2008 Types of reversible inhibition Competitive Inhibitor binds at active site Prevents binding of substrate Noncompetitive Inhibitor binds distant from active site Interferes with turnover Uncompetitive (rare?) Inhibitor binds to ES complex Removes ES, interferes with turnover Mixed (usually Competitive + Noncompetitive) Biochemistry: Enzyme Kinetics & inhibition P. 46 of 65 12 Feb 2008 How to tell them apart Reversible vs irreversible dialyze an enzyme-inhibitor complex against a buffer free of inhibitor if turnover or binding still suffers, it’s irreversible Competitive vs. other reversible: Structural studies if feasible Kinetics Biochemistry: Enzyme Kinetics & inhibition P. 47 of 65 12 Feb 2008 Competitive inhibition S Put in a lot of substrate: ability of the inhibitor to get in the way of the binding is hindered: out-competed by sheer #s of substrate molecules. How many substrate molecules it will take to overwhelm the inhibitor depends on how strongly the enzyme is attracted to the substrate as compared to the attraction of the enzyme for the inhibitor. However, once the substrate is bound, the inhibitor does not influence how quickly the enzyme turns the substrate over. Biochemistry: Enzyme Kinetics & inhibition P. 48 of 65 12 Feb 2008 Ic Kinetics of competition Competitive inhibitor hinders binding of substrate but not reaction velocity: Affects the Km of the enzyme, not Vmax. Which way does it affect it? Km = amount of substrate that needs to be present to run the reaction velocity up to half its saturation velocity. Competitive inhibitor requires us to shove more substrate into the reaction in order to achieve that half-maximal velocity. So: competitive inhibitor increases Km, Biochemistry: Enzyme Kinetics & inhibition P. 49 of 65 12 Feb 2008 L-B: competitive inhibitor Km goes up so -1/ Km moves toward origin Vmax unchanged so Y intercept unchanged Biochemistry: Enzyme Kinetics & inhibition P. 50 of 65 12 Feb 2008 Competitive inhibitor: Quantitation of Ki Define inhibition constant Ki to be the concentration of inhibitor that increases Km by a factor of two. Km,obs = Km(1+[Ic]/Ki) So [Ic] that moves Km halfway to the origin is Ki. If Ki = 100 nM and [Ic] = 1 µM, then we’ll increase Km,obs elevenfold! Biochemistry: Enzyme Kinetics & inhibition P. 51 of 65 12 Feb 2008 Noncompetitive I inhibition S Noncompetitive inhibitor has no influence on how available the binding site for substrate is, so it does not affect Km at all However, it has a profound inhibitory influence on the speed of the reaction, i.e. turnover. So it reduces Vmax and has no influence on Km. Biochemistry: Enzyme Kinetics & inhibition P. 52 of 65 12 Feb 2008 L-B for non-competitives Decrease in Vmax 1/Vmax is larger X-intercept unaffected Biochemistry: Enzyme Kinetics & inhibition P. 53 of 65 12 Feb 2008 Ki for noncompetitives Ki defined as concentration of inhibitor that cuts Vmax in half Vmax,obs = Vmax/(1 + [In]/Ki) In previous figure the “high” concentration of inhibitor is Ki Biochemistry: Enzyme Kinetics & inhibition P. 54 of 65 12 Feb 2008 Uncompetitive inhibition Inhibitor binds only if ES has already formed It creates a ternary ESI complex This removes ES, so by LeChatlier’s Principle it actually drives the original reaction (E + S ES) to the right; so it decreases Km But it interferes with turnover so Vmax goes down If Km and Vmax decrease at the same rate, then it’s classical uncompetitive inhibition. Biochemistry: Enzyme Kinetics & inhibition P. 55 of 65 12 Feb 2008 L-B for uncompetitives Km moves toward origin Vmax moves away from the origin Slope ( Km/Vmax) is unchanged Biochemistry: Enzyme Kinetics & inhibition P. 56 of 65 12 Feb 2008 Ki for uncompetitives Defined as inhibitor concentration that cuts Vmax or Km in half Easiest to read from Vmax value Iu labeled “high” is Ki in this plot Biochemistry: Enzyme Kinetics & inhibition P. 57 of 65 12 Feb 2008 iClicker quiz! 3. Treatment of enzyme E with compound Y doubles Km and leaves Vmax unchanged. Compound Y is: (a) an accelerator of the reaction (b) a competitive inhibitor (c) a non-competitive inhibitor (d) an uncompetitive inhibitor Biochemistry: Enzyme Kinetics & inhibition P. 58 of 65 12 Feb 2008 iClicker quiz, question 4 4. Treatment of enzyme E with compound X doubles Vmax and leaves Km unchanged. Compound X is: (a) an accelerator of the reaction (b) a competitive inhibitor (c) a non-competitive inhibitor (d) an uncompetitive inhibitor Biochemistry: Enzyme Kinetics & inhibition P. 59 of 65 12 Feb 2008 Most pharmaceuticals are enzyme inhibitors Inhibitors of enzymes that are necessary for functioning of pathogens Others are inhibitors of some protein whose inappropriate expression in a human causes a disease. Others are targeted at enzymes that are produced more energetically by tumors than they are by normal tissues. Biochemistry: Enzyme Kinetics & inhibition P. 60 of 65 12 Feb 2008 Characteristics of Pharmaceutical Inhibitors Usually competitive, i.e. they raise Km without affecting Vmax Some are mixed, i.e. Km up, Vmax down Iterative design work will decrease Ki from millimolar down to nanomolar Sometimes design work is purely blind HTS; other times, it’s structure-based Biochemistry: Enzyme Kinetics & inhibition P. 61 of 65 12 Feb 2008 Amprenavir Competitive inhibitor of HIV protease, Ki = 0.6 nM for HIV-1 No longer sold: mutual interference with rifabutin, which is an antibiotic used against a common HIV secondary bacterial infection, Mycobacterium avium Biochemistry: Enzyme Kinetics & inhibition P. 62 of 65 12 Feb 2008 When is a good inhibitor a good drug? It needs to be bioavailable and nontoxic Beautiful 20nM inhibitor is often neither Modest sacrifices of Ki in improving bioavailability and non-toxicity are okay if Ki is low enough when you start sacrificing Biochemistry: Enzyme Kinetics & inhibition P. 63 of 65 12 Feb 2008 How do we lessen toxicity and improve bioavailability? Increase solubility… that often increases Ki because the van der Waals interactions diminish Solubility makes it easier to get the compound to travel through the bloodstream Toxicity is often associated with fat storage, which is more likely with insoluble compounds Biochemistry: Enzyme Kinetics & inhibition P. 64 of 65 12 Feb 2008 Drug-design timeline 2 years of research, 8 years of trials -8 Research 0 2 Biochemistry: Enzyme 100 Cost/yr, 106 $ -3 Preliminary toxicity testing 10 Clinical Trials Time, Yrs Kinetics & inhibition 10 P. 65 of 65 12 Feb 2008