Section 4.5 Graphing Tangent and Cotangent (part 2) Discovering the graphs of y = tanx and y = cotx: Answer the following questions. Fist, be sure your calculator is in radians and your xoom is in ZTrig. 1. Graph y = tanx. Describe what the graph of y = tanx looks like. How long is one period of the graph of y = tanx? 2. y = tyanx is an asymptotic function. Where are the asymptotes located? Describe the domain of y = tanx. 3. Where will the graph of y = tanx have zeros? 4. What is the range of y = tanx? 5. Graph y = cotx. Describe what the graph of y = tanx looks like. How long is one period of the graph of y = cotx? 6. y = cotx is also asymptotic. Where are its asymptotes located? Describe the domain of y = cotx. 7. Where will the graph of y = cotx have zeros? 8. What is the range of y = cotx? As you have seen….. Both the Tangent and Cotangent functions are asymptotic. Tangent is undefined for all x = 2 +nπ and Cotangent is undefined for all x = 0 + nπ, where n is an integer. Within each period, tangent goes down on the left (-∞) and up on the right (∞). Cotangent does the opposite. The periods of each are broken up into four parts, defined by 5 key points, like those of sine and cosine. For tangent and cotangent, the 5 key points are: asymptote, inflection point, intercept, inflection point, asymptote. Tangent: y = atan(bx ± c) ± d │a│ determines the distance between the points of inflection and the x-axis. π/b is the period (horizontal stretch or shrink) c determines phase shift (left or right shift) to find the new starting point for a period, use the first asymptote of y = tanx, which is x 2 . d determines vertical shift. Cotangent: y = acot(bx ± c) ± d to find the new starting point for a period, use the first asymptote of y = cotx, which is x = 0 Examples: Graph two full periods 1. y = (1/3)tanx 2. y = (1/4)tan3x 3. y = -2tanπx 4. y = 2cot(x - 2 ) Assignment: text p.401 #2,4,5,6,9,10,13,14,21,22,24,25,27,28,31,34,35,37,40,46,51 ..and sketch the graphs of: y = 2tan(0.5x), y cot x 2 Y = 3tan2x + 1 Warm-up 04/25/2012 1. Evaluate cos(15π/2). 2. For what value of x, on [0,2π) would the graph of y = csc(x – π/4) have a local maximum? A local minimum? 3. For the function given in #2, describe where its vertical asymptotes would be located. 4. Use your graphing calculator. Graph y = secx and y = cscx in the same viewing screen. For what values of x will the graphs intersect? 5. Using the same graph from #4, describe how you could obtain the graph of y = secx from the graph of y = cscx and vice versa.