Trigonometric Ratios - ratios used to find unknown side lengths or angle measures in RIGHT triangles. Recall: Primary Trig Ratios sinA = cosA = tanA = Angle of Elevation - the angle measured ____________ between the horizontal and the line of sight from an observer to an object. Angle of Depression - the angle measured ______________ between the horizontal and the line of sight from an observer to an object. Ex. 1) Solve ΔQRS, if Q = 90o, R = 42o and q = 10.5 cm. Ex. 2) Find θ to the nearest degree. Ex. 3) Two office buildings are 42.3 m apart. From the top of the shorter one, the angle of elevation to the top of the other is 27.5o, while the angle of depression to the base is 78.2o. Find the height of each building. Sine and Cosine Laws Recall from last year: SINE LAW COSINE LAW When do we use: SINE LAW COSINE LAW Ex. 1) Determine the value of x. Ex. 2) Solve Δ PQR. Ex. 3) Find the measure of angle A. Practice: pg. 290 # 1 - 4 (c & d only for each), 5d Applications of Trigonometry Ex. 1) An escalator rises 8m vertically and makes an angle of 25o with the horizontal. What is the length of the escalator to one decimal place? Ex. 2) A surveyor in a helicopter, 9750m directly above ground observes that the angle of depression to two points on the opposite shores of a lake are 32o and 45o, respectively as shown in the diagram. What is the width of the lake (between the two points), to the nearest meter? Sine Law - The Ambiguous Case A weather balloon is tethered by two ropes; one is 7.8m long, which makes an angle of 36o with the ground. The other rope is 5.9m long. Determine the distance between the two ropes. * from the problem, it is not clear how Albert & Belle & the balloon are positioned relative to one another. CASE 2: Assume A & B are on the same side of the balloon. When does the ambiguous case occur? Given two sides and a non-contained angle, the triangle may NOT be unique. (SSA) A) Given angle A , if a > b, one triangle exists B) Given angle A, if a < b, then Number of triangles Condition Ex. 1) How many triangles exist in each case? ) M = 42o m = 9.6cm n = 6.5cm Ex. 2) Solve Δ XYZ, if: X = 33o x = 4.1cm y = 5.4cm b) P = 39o p = 5.6m q = 10.5m c) K = 48o k = 7.5mm l = 8.1mm AMBIGUOUS CHECK-UP: Solve the following triangle. π₯π΄π΅πΆ πππ£ππ∠π΄ = 12π , π = 32 π πππ π = 45 π FIRST identify: How many triangles will we have? Step 1: Use the sine law to calculate οB Step 2: Determine οACB (all angles of a triangle add to 180 degrees) οACB ο½ ______ ο° Step 3: Find the length of AB (using the sine law). οB ο½ ______ ο° AB = ____________ m Consider οAB' C (the one triangle on the left!) Step 4: Seeing that you have an isosceles triangle, calculate οAB' C (marked as z) z ο½ ______ ο° Step 5: Calculate οACB' (all angles of a triangle add to 180 degrees) Step 6: Calculate the length of AB’, using the sine law. Angles in Standard Position Definitions: Let P(x, y) be any point on the terminal arm of angle θ in standard position, r units from the origin. Re-write the primary trig ratios: sin θ = cos θ = tan θ = How can the measure of r be found? IF the terminal arm lies in quadrant I, then θ is the value found using the previous trig ratios. IF the terminal arm lies in quadrants II, III, or IV, there is a principal angle θ, and a RELATED ACUTE ANGLE (RAA). Ex. 1) Find the sinθ, cosθ, tanθ and principal angle θ given the point P is on the terminal arm of an angle θ in standard position. Steps: a) P(7, 24) 1. Decide which quadrant the terminal arm lies in based on the point given. 2. Draw a diagram with the terminal arm in the correct quadrant. 3. Determine the value of r. 4. Determine the ratios. 5. Use the ratios to determine the principal angle or RAA. b) P(-3, -9) c) P(10, -5) Practice:pg. 348 #1abef + principal angle for all #2abefgh + principal angle for all Treat 0 ≤ θ≤ 2π as 0o ≤ θ≤ 360o Correction: 1a) cosθ = 8 17 C.A.S.T. Rule Can you tell what the following all have in common? sin 35o sin 145o sin 215o sin 325o Evaluate: sin 35o sin 325o sin 145o sin 215o Quadrant II 90o ≤ θ ≤ 180o sinθ = cosθ = tanθ = III Quadrant 180o ≤ θ ≤ 270o Quadrant I 0o ≤ θ ≤ 90o sinθ = cosθ = tanθ = sinθ = cosθ = tanθ = C.A.S.T. Rule Quadrant IV 180o ≤ θ ≤ 360o - tells us where each trig ratio is positive sinθ = cosθ = tanθ = We use the CAST rule to determine the correct sign of any trig ratio. Ex. 1) Use the CAST rule to determine the two angles (nearest tenth) associated with cos θ = 0.627 Steps: between 0o ≤ θ ≤ 360o 1. Use CAST to determine which quadrants the terminal arm could lie in. 2. Draw diagram including labels. 3. Find the RAA - by taking the inverse of the POSITIVE Ex. 2) Find the two angles 0o ≤ θ ≤ 360o associated with the followingratio trig ratio. tan θ = - 0.2679 value. 4. Use RAA to find both possible angles of the terminal arm. Ex. 3) If θ is in standard position, with its terminal arm in the specified quadrant and 0o ≤ θ ≤ 360o, find the exact value of the other two trig ratios and the principal angle. cos θ = 4 , quadrant IV 7 Practice: pg. 349 # 6, 7 0o ≤ θ ≤ 360o for all questions Warm up Find <A, to the nearest degree if 0o ≤ θ ≤ 360o. Draw a diagram to support your answers. a) tan A = -1.0355 b) sin A = 0.5299 Special Angles / Triangles Most trig ratios cannot be expressed exactly. For example, sin25o = 0.422618262... is irrational However, some trig ratios can be expressed exactly... Special Triangle #1 sin 45 = cos 45 = tan 45 = Special Triangle #2 sin 30 = cos 30 = tan 30 = Ex. 1) Find the exact value of each trig ratio. Steps: 1. Draw terminal arm on diagram. 2. Determine RAA. 3. Label the special triangle. 4. Find the value required. (use CAST to help determine the sign) o a) sin 60 b) cos 225o c) tan 330o cos 135o Ex. 2) If 0o ≤ θ ≤ 360o, find the possible answers of angle θ. a) sinθ = -1 b) tanθ = -√3 √2 Pg. 348 - 350#3 (include sketches), 11, 18 Pg 353 #1 ab (sine only), #2 ac (cosine only), #4 ab No calculators permitted. Diagrams required. 1. β―Evaluate. a) cos 60oβ―β― b) sin 150oβ―β― c) sin 150oβ―β― d) sin 225oβ―β― e) tan 135oβ―β― f) sin 180oβ―β― g) cos 90oβ―β― 180oβ―β― h) sin 270oβ―β― i) sin 360oβ―β― j) tan No calculators permitted. Diagrams required. Given, 0 ο£ ο± ο£ 360ο°, calculate the value of ο± a.) cos ο± ο½ 3 2 b.) tan ο± ο½ ο3 c.) sin ο± ο½ 0 Review of Unit 5 A. Solve the following triangle οABC (οC = 35ο°, c = 11 m, a = 12 m) B. Angles in Standard Position 1. If the point ( – 2, – 4) lies on the terminal arm of angle, ο± , in standard position: i) Draw a labelled sketch of the terminal arm. ii) Determine the value of r . iii) Determine the value of the related acute angle ο’ . iv) Determine the value of the principal angle ο± . 2. Solve for angle ο± , where 0 ο― ο£ ο± ο£ 360 ο― . a) tan ο± ο½ 0.34432 b) sin ο± ο½ ο0.40674 3. Calculate the exact value of the following: a) tan 330o ο½ x b) sin120o ο½ x