Solving Quadratics

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Integrated Math III
Essential Question
What different methods can be used to
solve quadratic equations?
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Quadratic
Formula
Solving Quadratics
Graphically
Solving Quadratics by Factoring
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Solving Quadratics using the
Quadratic Formula
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Solving Quadratics Graphically
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Solving Quadratics by Factoring
2
x -
9x + 20 = 0
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(Stapel)
Solving Quadratics Graphically
2
x + 4x – 20 = 2
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(Tormoehlen, 2008)
Solving Quadratics using the
Quadratic Formula
2
2x -10x
– 48 = 0
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("The quadratic formula," 2007)
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Here are some helpful hints!
 We must first identify our a, b, and c terms.
 To factor, we have to find the multiples of c that add up to b.
 It is important to remember that a negative times a
negative also gives you a positive.
Example: If c = 36, the multiples are
36 · 1
-36 · -1
18 · 2
-18 · -2
12 · 3
-12 · -3
6·6
-6 · - 6
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 Once the equation is in factored form, we must remember
that it is still equal to zero.
 This means that we must set each one of our linear factors
equal to zero too.
 We then solve for x.
Example: (x + 7)(x – 2) = 0
x+7=0
-7 -7
x = -7
x-2=0
- 2 -2
x = -2
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Your solution is correct!
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2
x - 9x + 20 = 0
(x – 5)(x – 4) = 0
x–5=0
+ 5 +5
x=5
x–4=0
+4
+4
x=4
Sorry, your solution is incorrect.
Here are some helpful hints!
 In order to solve quadratics, the equation must be equal to
zero.
 If not, we have to move all of the terms to one side of the
equation.
Example: x2 – 12x + 15 = -8
+8 +8
x2 – 12x + 23 = 0
Now that the equation is equal to zero, we would
be able to graph it and find its solutions.
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Sorry, your solution is incorrect.
Here are some helpful hints!
 In order to solve quadratics, the equation must be equal to
zero.
 If not, we have to move all of the terms to one side of the
equation.
 When you bring a positive number over an equals sign, you
must perform the opposite operation.
Example: x2 + 8x - 9 = 7
-8 -8
x2 + 8x - 17 = 0
Now that the equation is equal to zero, we would
be able to graph it and find its solutions.
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Your solution is correct!
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2
x +
4x – 20 = 2
-2 -2
x2 + 4x - 22 = 0
We now use our calculator to graph the equation and find its solutions.
x = -6
x=2
Sorry, your solution is incorrect.
Here are some helpful hints!
 We must first identify our a, b, and c terms.
 When plugging the terms into the quadratic formula, we
must remember that –b means to change the sign of b.
Example: 1x2 - 4x - 3 = 0
a
b
c
-4 to +4
 b  b2  4ac
x
2a
4  (4) 2  4(1)( 3)
x
2(1)
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Sorry, your solution is incorrect.
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 We
need to be careful when using our calculator to
simplify the quadratic formula.
Example:  4  (4)
2
2
In our calculator -42 is equal to -16. We know that this is not true. A
negative squared is always equal to a positive. To fix this mistake, we must
insert parenthesis around the negative number. The calculator will then
give us the correct solution.
4  (4) 2  4(1)( 3)
x
2(1)
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2
2x -10x – 48 = 0
10  (10)  4(2)( 48) 10  484 10  22
x


2(2)
4
4
10  22
10  22
x
x
4
4
x 8
x  3
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Exit Ticket 3 – 2 – 1
Please email me the answers.
 Write 3 things you liked about this lesson.
 Write 2 things you learned.
 Write 1 question you have about solving quadratics.
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Resources
Stapel, E. (n.d.). Factoring quadratics: the simple case. Retrieved from
http://www.purplemath.com/modules/factquad.htm
The quadratic formula to solve quadratic equations. (2007). Retrieved from
http://www.mathwarehouse.com/quadratic/the-quadratic-formula.php
Tormoehlen, T. (Producer). (2008). Solving quadratic equations by graphing. [Web]. Retrieved
from http://www.youtube.com/watch?v=8Pk2VN6wzqU
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