Frederick Griffith Observe the following data – explain what is going on 1928 Conclusion: heat-killed, virulent bacteria must have released genetic material transferred to R (non virulent strain) cells Transformation – DNA from dead cells cut into fragments & exits cell → healthy cells pick up free floating DNA and integrate chromosomes via recombination Oswald Avery Colin MacLeod Maclyn McCarty Avery, McCarty & MacLeod ◦ purified DNA & proteins separately from Streptococcus pneumonia bacteria Experimental Question: which will transform non-pathogenic bacteria? ◦ 1. injected protein into bacteria Mice lived! ◦ 2. injected DNA into bacteria transformed bacteria Mice died! 1952 | 1969 Martha Chase Alfred Hershey Protein coat labeled DNA labeled with 32P 35 with S T2 bacteriophages are labeled with Which radioactive isotopes radioactive S vs. P marker is found inside the cell? This will be the molecule containing genetic info! 35S bacteriophages infect bacterial cells bacterial cells are agitated to remove viral protein coats from bacteria cell radioactivity found in the medium of protein coat 32P radioactivity found in the bacterial cells Watson and Crick 1952 1947 DNA composition: “Chargaff’s rules” ◦ varies from species to species ◦ all 4 bases not in equal quantity ◦ bases present in characteristic ratio humans: A = 30.9% Rules T = 29.4% A=T C=G G = 19.9% C = 19.8% purine pyrimidine http://academic.brooklyn.cuny.edu/biology/bio4fv/page/ molecular%20biology/dna-structure.html How do your techniques compare with those used by all of our important researchers visited today? How have advances in technology changed our way of thinking and approach to a scientific question? Given the times, do you think the experiments we reviewed today were scientifically valid then? How about today? Is there anything you would change about their experiments to make them more scientifically sound in today’s world? Identify those changes and explain. ◦ base pairing suggests that each side can serve as a template for a new strand “It has not escaped our notice that the specific pairing we have postulated immediately suggests a possible copying mechanism for the genetic material.” — Watson & Crick Bacterial DNA is circular Eukaryotic DNA is linear ◦ Can you think of any problems this may pose in the successful completion of replication? ◦ Cells can lose 30-200 base pairs each time a cell divides. ◦ Telomerase enzyme adds the TTAGGG sequence to the 3’ end of the DNA at the telomere regions Animation http://highered.mcgrawhill.com/novella/MixQuizProcessingServle http://articles.mercola.com/sites/articles/archive/2010/02/23/scien ce-finally-reveals-how-you-can-actually-revese-aging.aspx utechdmd2015.wikispaces.com/file/vi ew/unit_2_Replication_r_1_.ppt (1957) Mathew Meselson and Franklin Stahl grew the bacterium Escherichia coli on medium that contained 15N in the form of ammonium chloride. The 15N became incorporated into DNA (nitrogenous bases). The resulting heavy nitrogen-containing DNA molecules were extracted from some of the cells. DNA Replication is semiconservative experimental proof When subject to density gradient centrifugation, they accumulated in the high-density region of the gradient. The rest of the bacteria were transferred to a new growth medium in which ammonium chloride contained the naturally abundant, lighter 14N isotope. utechdmd2015.wikispaces.com/file/view /unit_2_Replication_r_1_.ppt In the experiments by Meselson and Stahl that demonstrated semiconservative replication of DNA, the researchers cultivated bacteria in a medium containing a heavy isotope of nitrogen, 15N. They then moved the bacteria to a medium containing 14N, the lighter, more common isotope. After each round of replication, the researchers extracted the DNA and centrifuged the solution to separate the DNA bands by density. The test tubes below illustrate the possible banding pattern found after two bacterial generations (two rounds of replication). Which test tube best illustrates the bands predicted by the semiconservative replication model of DNA replication? The test tubes below illustrate the possible banding pattern found after two bacterial generations (two rounds of replication). Which test tube best illustrates the bands predicted by the semiconservative replication model of DNA replication? A scientist is using an ampicillin-sensitive strain of bacteria that cannot use lactose because it has a nonfunctional gene in the lac operon. She has two plasmids. One contains a functional copy of the affected gene of the lac operon, and the other contains the gene for ampicillin resistance. Using restriction enzymes and DNA ligase, she forms a recombinant plasmid containing both genes. She then adds a high concentration of the plasmid to a tube of the bacteria in a medium for bacterial growth that contains glucose as the only energy source. This tube (+) and a control tube (-) with similar bacteria but no plasmid are both incubated under the appropriate conditions for growth and plasmid uptake. The scientist then spreads a sample of each bacterial culture (+ and -) on each of the three types of plates indicated below. If no new mutations occur, it would be most reasonable to expect bacterial growth on which of the following plates? a. 1 and 2 only b. 3 and 4 only c. 5 and 6 only d. 4, 5, and 6 only e. 1, 2, 3, and 4 only DNA How does DNA code for cells & bodies? proteins cells bodies The county fair is coming to town and every year there is the famous Cookie Contest. You’ve been experimenting in the kitchen and have come up with the MOST delicious cookies you can think of (mmm chocolate chip). Just to make sure it’s perfect, you want your best friend to taste them. One problem: your best friend lives in California. You need to get the recipe to your friend. Do you send your original recipe information? Why or why not? If not, what steps do you take to pass on the information? Remember, your success lies in the perfect execution of this recipe! Flow of genetic information in a cell ◦ DNA to proteins? DNA replication RNA protein trait suggest genes code for enzymes ◦ Disruptions in pathways result in lack of an enzyme disease variation of phenotype metabolic pathway A disease B disease C disease D disease E Make a model! Steps o Structures o ribose sugar N-bases ◦ uracil instead of thymine ◦ U:A ◦ C:G single stranded many RNAs ◦ mRNA, tRNA, rRNA, siRNA… DNA transcription RNA Making mRNA ◦ transcribed DNA strand = template strand ◦ untranscribed DNA strand = coding strand ◦ synthesize complementary RNA strand transcription bubble ◦ Enzymes involved RNA polymerase coding strand Helicase 5 DNA A G T A T C T A 3 mRNA build RNA 53 5 G C A G C A T C G T T G C A U C G U C G T A G C A A T 3 A T RNA polymerase A C T A G C T G A T 3 5 template strand 3 types of RNA polymerases 1. RNA polymerase 1 transcribe rRNA genes ONLY makes ribosomes 2. RNA polymerase 2 transcribe genes into mRNA 3. RNA polymerase 3 transcribe tRNA genes ONLY **each has a specific promoter sequence it recognizes** Promoter region - site marking the start of gene ◦ TATA box binding site ◦ transcription factors (ie. proteins, hormones?) - on/off switch; trigger binding of RNA pol ◦ RNA polymerase Enhancer region ◦ binding site far upstream ◦ turns transcription on HIGH Eukaryotic genes contain “fluff” – spliced ◦ exons = expressed / coding DNA ◦ introns = the junk; inbetween sequence; now thought to be involved in switches 5’ Cap & PolyA tail added (modified in the nucleus) intron = noncoding (inbetween) sequence ~10,000 bases eukaryotic DNA exon = coding (expressed) sequence primary mRNA transcript mature mRNA transcript pre-mRNA ~1,000 bases spliced mRNA snRNPs “snurps” ◦ small nuclear RNA exon ◦ Proteins ◦ Done in nucleus before 5' leaving nucleus snRNPs snRNA intron exon 3' Spliceosome ◦ several snRNPs ◦ recognize splice site sequence spliceosome 5' 3' cut & paste gene Introns have specific 2 base codes in front and end of intron to 5' identify them mature mRNA exon 5' lariat 3' exon 3' excised intron Enzymes in cytoplasm attack mRNA – protection is needed add 5 GTP cap add poly-A tail longer the tail, longer mRNA lasts: produces more protein 3' mRNA 5' P G P P A Transcription mRNA processing mRNA splicing Make a model! Steps o Structures o DNA 4ATCG TAC GCA CAT TTA CGT ACG CGG mRNA AUG CGU GUA AAU GCA UGC GCC 4AUCG ? protein 20 Met Arg Val Asn Ala Cys Ala How can you code for 20 amino acids with only 4 nucleotide bases (A,U,G,C)? 20 different amino acids aa’s coded for by THREE nucleotides –codons 4 bases, 3 per codon: 43 = 64 total possible combinations WOBBLE Code is redundant ◦ several codons for each amino acid ◦ 3rd base “wobble” ◦ Most codons = aa’s Start codon AUG methionine Stop codons UGA, UAA, UAG “Clover leaf” structure ◦ anticodon on “clover leaf” end ◦ amino acid attached to 3 end Aminoacyl tRNA synthetase - enzyme bonds aa’s to tRNA ◦ requires energy ATP AMP bond is unstable can easily release amino acid at ribosome Trp C=O OH OH Trp C=O O H 2O activating enzyme tRNATrp anticodon tryptophan attached to tRNATrp Trp O mRNA tRNATrp binds to UGG codon of mRNA RIBOSOMES!!! Facilitate binding of tRNA anticodon to mRNA codon Organelle or enzyme?? Structure ◦ rRNA & proteins ◦ 2 subunits large small ◦ 3 sites A site (aminoacyl-tRNA site) ◦ tRNA carrying next aa to be added to chain binds here P site (peptidyl-tRNA site) ◦ holds tRNA carrying growing polypeptide chain Met Met E site (exit site) ◦ empty tRNA leaves ribosome from exit site 5' UU AA CC AA UU GG E E PP AA 3' Initiation ◦ brings together mRNA, ribosomal subunits, initiator tRNA (amino acid methionine) Elongation ◦ adding amino acids based on codon sequence Termination ◦ end codon 3 2 1 Transcription & translation simultaneous in bacteria ◦ DNA in cytoplasm ◦ no mRNA editing ◦ ribosomes read mRNA as transcribed ◦ Faster than in eukaryotes (DNA to protein ~1hr) Prokaryotes ◦ DNA in cytoplasm ◦ circular chromosome ◦ naked DNA ◦ no introns ◦ continuous process Eukaryotes ◦ DNA in nucleus ◦ linear chromosomes ◦ DNA wound on histone proteins ◦ introns vs. exons ◦ mRNA processing Translation Animation Protein Synthesis