Lecture 37 Nuclear magnetic resonance Nuclear magnetic resonance The use of NMR in chemical research was pioneered by Herbert S. Gutowski of Department of Chemistry, University of Illinois, who established the relationship between chemical shifts and molecular structures. He also discovered spinspin coupling. Foundation of magnetic spectroscopy. Proton NMR. Circular electric current = magnet Electrons in p, d, f orbitals Electron spin Nuclear spin charge magnetic moment q m= l 2m mass angular momentum Magnet-magnetic-field interaction high energy Classical DE = - m × B Quantum Ĥ1 = - m̂ × B low energy q ˆ =l ×B 2m qB ˆ =lz 2m Tesla C J T (Tesla) qB DE = lz 2m kgm2/s kg 1 T = 1 V s / m2 Nikola Tesla Public domain image from Wikipedia Field strength in 500 MHz NMR ($0.5M) = 11.7 T Field strength in 1 GHz NMR ($20M) = 23.5 T Strongest continuous magnetic field = 45 T (National High Magnetic Field Lab at Tallahassee, FL) Electrons in p, d, f orbitals First-order perturbation theory qB (0) ˆ (0) qB DE = Y 0 lz Y 0 = ml 2m 2m e Bohr magneton = ml B = mB ml B −24 9.724×10 J/T 2me qB ˆ Ĥ 1 = lz 2m ml = +2 ; DE = +2 mB B (2 l + 1)-fold degeneracy (field off) ml = +1 ; DE = +1mB B ml = 0 ; DE = 0 mB B ml = -1 ; DE = -1mB B ml = -2 ; DE = -2 mB B Zeeman effect (field on) Electron spin Quantum electrodynamics DEorbit = mBml B DEe-spin = ge mBms B g-value 2.002319… α 2-fold degeneracy (field off) 1 1 ms = + ; DE = + ge mB B 2 2 ge mB B β 1 1 ms = - ; DE = - ge mB B 2 2 ESR or EPR (field on) Nuclear magneton e 1800 times smaller than Bohr magneton 2mp Nuclear spin DEe-spin = ge mBms B DEn-spin = - gI mN ms B Negative sign positive nuclear charge Nuclear g-factor proton: 5.586 β 2-fold degeneracy (field off) Proton mass 1 1 ms = - ; DE = + gI mN B 2 2 gI mN B α 1 1 ms = + ; DE = - gI mN B 2 2 NMR (field on) Proton NMR Sweep coils β gI mN B α Radio freq Sample Proton NMR spectra (1) Overall intensity (2) Groups of peaks (3) Relative intensities of groups of peaks (4) Pattern in each group (hyperfine structure) Overall intensity β N b = Na exp ( -DE / kBT ) » Na (1- DE / kBT ) DE = gI mN B α Na excess α spins Intensity of a NMR signal ~ energy of RF radiation absorbed / time ~ ΔE × number of excess α spins ~ B2 / T Stronger magnet + lower temperature Group of peaks: chemical shifts Resonance freq. Chemical shift β DE = gI mN B α Resonance freq. of TMS Si(CH3)4 n -n 6 d= ´10 n “ppm” Group of peaks: chemical shifts Resonance freq. Shielding constant n -n 6 d= ´10 n hn = gI mN Blocal = gI mN (1- s ) B Chemical shift B Blocal Group of peaks: chemical shifts hn = gI mN Blocal = gI mN (1- s ) B B + Blocal Shielding constant Group of peaks: chemical shifts hn = gI mN Blocal = gI mN (1- s ) B Shielding constant Group of peaks: chemical shifts n -n d= ´10 6 n RCH3 -CH2-CHROH ArOH Ar-H -CHO -COOH 14 12 10 8 6 4 2 0 δ Relative intensities C2H6O OH H H2 CH2 RCH3 -CH2- H3 ROH CH3 4 2 δ CH3CH2OH 0 Hyperfine structure Spin-spin coupling: hJms ms¢ H β CH3CH2OH nearby H 1 - hJ 4 β α OH CH2 CH3 gI mN B 1 gI mN B - hJ 2 1 gI mN B + hJ 2 α α β Hyperfine structure Spin-spin coupling: hJms ms¢ H CH3CH2OH OH CH2 CH3 β H2 H β α gI mN B α α β ββ βα, αβ αα αα αβ, βα ββ Hyperfine structure Pascal’s triangle CH3CH2OH 1 nearby H OH CH2 1 1 CH3 nearby H2 1 nearby H3 nearby H4 1 1 2 3 4 1 3 6 1 4 1 Hyperfine structure CH3CH2OH OH CH2 ? CH3 Q: Why doesn’t the proton in the OH group cause splitting? A: The proton undergoes a rapid exchange with protons in other ethanol or water molecules; its spin is indeterminate in the time scale of spectroscopic transitions; this causes lifetime broadening of spectral line rather than splitting. Hyperfine structure CH3CH2OH OH CH2 ? CH3 ? Q: Why is there no spin-spin coupling between the two protons in the CH2 group? A: There is spin-spin coupling between them; however, its effect on the peaks is null and undetectable; this is because these protons are chemically and magnetically equivalent. Hyperfine structure CH3CH2OH ì a (1) a ( 2 ) ï Triplet ï a (1) b ( 2 ) + b (1) a ( 2 ) í magnetic ï b (1) b ( 2 ) ïî Singlet a (1) b ( 2 ) - b (1)a ( 2 ) non-magnetic MS = 1 MS = 0 S =1 M S = -1 MS = 0 S=0 DEspin-orbit = 12 hcA { j ( j +1) - l ( l +1) - s ( s +1)} DEspin-spin = 12 hJ {S ( S +1) - s ( s +1) - s¢ ( s¢ +1)} = 12 hJ {S ( S +1) - 23 } M S = -1 MS = 0 MS = 1 no spin-spin coupling + 14 hJ + 14 hJ No change in spacing + 14 hJ with spin-spin coupling Spin-spin coupling constant 1 J HH 2 J HH 3 J HH H H H H C C H C H Spin-spin coupling constant H Fermi contact H Fermi contact DE = hJ ( 12 ) ( - 12 ) < 0 1 J HH > 0 Covalent bond singlet-coupling higher energy?? Fermi contact lower energy! Spin-spin coupling constant H Fermi contact C H Hund Fermi contact Covalent bond singlet coupling Covalent bond singlet coupling DE = hJ ( 12 ) ( 12 ) < 0 2 J HH < 0 Spin-spin coupling constant H C C H H j C H Karplus equation 3 J HH = A + Bcosj + C cos2j Martin Karplus Department of Chemistry University of Illinois Image (c) University of Illinois ILLIAC Magnetic resonance imaging: MRI Resonance frequency ~ location (x) x Intensity ~ number of protons (in water) at x Public domain image from Wikipedia Paul Lauterbur (far right) Department of Chemistry University of Illinois Summary We have studied the foundation of magnetic interactions and magnetic spectroscopy. We have learned the theory of proton NMR as an essential tool for chemical structural analysis. The origins of chemical shifts, hyperfine structures, and spin-spin coupling constants are discussed as well as their relation to molecular structures.