CB & AO workshop

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College Bowl & Academic Olympiad
Workshop
Thursday, October 1st, 2015
www.shpeucf.com
Upcoming Events
• Network Workshop
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Date: Tuesday, October 6th 2015
Time: 7:00 pm
Location: CREL building, Room 121
• Study Lock Down
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Date: Wednesday, October 7th 2015
Time: 6:00 pm
Location: Library, Room 433
• Hispanic Heritage Month – Cultural Potluck Day
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Date: Friday, October 9th 2015
Time: TBA
Location: TBA
Upcoming Events
• Tailgate
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Date: Saturday, October 10th 2015
Time: TBA
• Conference Checklist Overview – MANDATORY
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Date: Monday, October 12th 2015
Time: TBA
Location: TBA
What is College Bowl?
HENAAC College Bowl
• A two-day, high energy competition in which
teams of college students, coached and
judged by industry and government
representatives, focus on showcasing their
talents, teamwork and leadership skills.
• Each round of competition addresses
carefully selected topics relevant to career
success
• Opportunity for students to win scholarships
for first, second, and third placing teams.
HENAAC College Bowl
• Offers students the chance to gain
a perspective from corporate
mentors and more important
sharpen their skills in areas of
communication and teamwork
• The event is both a rewarding
opportunity for students to interact
and compete with their peers and a
chance to interact with STEM
professionals.
How can I prepare?
Things to keep in
mind
• Resumes
• Creativity
• Boastful
• Teamwork
• Resourceful
• Outgoing
What is Academic Olympiad?
Academic Olympiad
• Team competition designed to test
the technical knowledge of SHPE's
Hispanic Technical Talent
• Award to each competing team
member:
First Place: $1250
Second Place: $1000
Third Place: $750
• Mandatory for each chapter has a
team to represent.
Academic Olympiad
• Technical areas to be covered in the
competition may include, but are
not limited to, the following:
- Mechanics
- Chemical Engineering
- Chemistry (Organic &
Inorganic)
- Civil Engineering
- Computer Engineering/
Computer Science
- Electrical Engineering
- General Science (Trivia)
- Mathematics
- Mechanical Engineering
- Physics Materials
- Manufacturing
• Written exam & oral competition
How can I prepare?
Things to keep in
mind
• Refresh on Previous Topics
• Communicate
• Teamwork
• Calculator!!
Extreme Engineering
• Non-stop 24-hour
competition interview and
potential foot leading
engineering companies in
the nation
• The program engages
teams against each other to
find out who can OUTDESIGN, OUT-DEVELOP,
and OUT-PROMOTE the
others in a race against
time, talent and creativity
• Cash prizes for the team
who wins
Trivia Competition
1) What is the standard form of the equation of
the line tangent to a circle centered at the origin
with a radius of 5 at the point (3,4)?
a) π‘₯ =
−4
𝑦
3
3
25
−
4
b) 𝑦 = 4 π‘₯ +
c) 𝑦 =
d) 𝑦 =
−3
π‘₯
4
−3
π‘₯
4
25
4
9
+
4
+
25
4
D) π’š =
−πŸ‘
𝒙
πŸ’
+
πŸπŸ“
πŸ’
The slope of the radius line to point (3,4) is 4/3. Therefore, the slope of the
tangent line is -3/4
The point-slope form of a straight line with (π‘₯1 , 𝑦1 ) = (3,4) is
−3
𝑦−4=
(π‘₯ − 3)
4
The standard form is
−3
9
𝑦=
π‘₯+
+4
4
4
−3
25
=
π‘₯+
4
4
2) A graph of the equation, π’š = 𝒙 + πŸ‘
would consist of which one of the following?
a) One straight line
b) Two parallel straight lines
c) One curved line
d) Two straight lines
D) Two straight lines
Note the absolute value, therefore; Y is always positive. A plot of the equation is
shown in the figure below.
3) What are the horizontal and
vertical components of
reaction at C and the tension
in the cable AB for the truss?
a) 𝑇𝐴𝐡 = 6.89π‘˜π‘ , 𝐢π‘₯ = 5.11π‘˜π‘ , 𝐢𝑦 = 5.05π‘˜π‘
b) 𝑇𝐴𝐡 = 3.89π‘˜π‘ , 𝐢π‘₯ = 4.11π‘˜π‘ , 𝐢𝑦 = 4.05π‘˜π‘
c) 𝑇𝐴𝐡 = 5.89π‘˜π‘ , 𝐢π‘₯ = 5.11π‘˜π‘ , 𝐢𝑦 = 4.05π‘˜π‘
d) 𝑇𝐴𝐡 = 4.05π‘˜π‘ , 𝐢π‘₯ = 5.89π‘˜π‘ , 𝐢𝑦 = 5.11π‘˜π‘
C) 𝑻𝑨𝑩 = πŸ“. πŸ–πŸ—π’Œπ‘΅ , π‘ͺ𝒙 = πŸ“. πŸπŸπ’Œπ‘΅ , π‘ͺπ’š = πŸ’. πŸŽπŸ“π’Œπ‘΅
4) What is the maximum possible positive
oxidation number for the element Br?
a) +1
b) +3
c) +4
d) +7
D) +7
Bromine has an oxidation number of -1, which means that it normally
accepts one electron to complete its outer shell of eight electrons.
Alternatively, it could give up seven electrons to have a full outer shell.
5) What is the Thevenin equivalent
circuit between terminals A and B
looking to the left for the following
circuit?
a) π‘‰π‘’π‘ž = 10 𝑉, π‘…π‘’π‘ž = 10 Ω
b) π‘‰π‘’π‘ž = 100 𝑉, π‘…π‘’π‘ž = 18 Ω
c) π‘‰π‘’π‘ž = 110 𝑉, π‘…π‘’π‘ž = 4 Ω
d) π‘‰π‘’π‘ž = 120 𝑉, π‘…π‘’π‘ž = 12 Ω
D) 𝑽𝒆𝒒 = 𝟏𝟐𝟎 𝑽, 𝑹𝒆𝒒 = 𝟏𝟐 𝜴
The Thevenin equivalent circuit consists of a voltage source in series with a
resistor. The equivalent voltage is the open-circuit voltage betweeb terminals
A and B, with 𝑅𝐿 disconnected. The voltage will be the same as that across the 12 Ω
π‘‰π‘’π‘ž = 𝐼𝑅 = 10 𝐴 12 Ω
= 120 V
The equivalent resistance is found by open-circuiting the current source. The equivalent
resistance is the resistance across terminals A and B
π‘…π‘’π‘ž = 12 Ω
6) Given the slope-intercept form of a line
as y = mx + b, which one of the following
is true?
a) m/b is the y-axis intercept
b) b is the x-axis intercept
c) y – b is the slope of the line
d) -b/m is the x-axis intercept
D) -b/m is the x-axis intercept
For the slope-intercept form of a line; y = mx + b
b is the y-intercept where x = 0
𝑑𝑦
m is the slope 𝑑π‘₯
-b/m is the x-intercept where y = 0
7) Inflation can be best be defined as
which one of the following?
a) The rise of prices over time
b) An increased demand
c) An increase in interest rate that a bank charges for capital
d) The rise or fall of interest rates over time
A) The rise of prices over time
Inflation is the rise of prices over time. Webster
defines inflation as the rise in prices related to an
increased volume of money and credit resulting in
a loss of currency.
8) A bag contains 100 balls numbered 1 to
100. One ball is drawn from the bag. What
is the probability that the number on the
ball selected will be odd or greater than 80?
a) 0.1
b) 0.5
c) 0.6
d) 0.7
C) 0.6
Find the probability of each of the outcomes being tested for.
50
𝑃 π‘π‘Žπ‘™π‘™ 𝑖𝑠 π‘œπ‘‘π‘‘ =
= 0.5
100
20
𝑃 π‘π‘Žπ‘™π‘™ > 80 =
= 0.2
100
It is possible for the number on the selected ball to be both odd and greater than 80.
Use the law of total probability
P(A + B) = P(A) + P(B) – P(A,B)
= P(A) + P(B) – P(A)P(B)
P(odd or > 80) = 0.5 + 0.2 – (0.5)(0.2)
= 0.6
9) What is standard temperate and
pressure (STP)?
a) 0 Deg F and 14.7 psia
b) 0 Deg C and 1 liter volume
c) 32 Deg F and 0 psia
d) 32 Deg F and 1 atm
D) 32 Deg F and 1 atm
Standard temperature = 0 deg C (32 deg F)
Standard pressure = 1 atm (14.7 psia)
10) Which one of the following is a heat
treating process?
a) Calcification
b) De-nitrification
c) Annealing
d) Pressurization
C) Annealing
Annealing is a process where a material is heated to just
above its critical point and then allowed to slowly cool.
This process relieves internal stresses and softens the
material.
11) Solve the following differential equation.
π’š′′ + πŸ’π’š′ + πŸ’π’š = 𝟎
π’š 𝟎 =𝟏
π’š′ 𝟎 = 𝟎
a) 𝑦 = 1 − 2π‘₯ 𝑒 2π‘₯
b) 𝑦 = 2 − π‘₯ 𝑒 −2π‘₯
c) 𝑦 = 2 + π‘₯ 𝑒 −2π‘₯
d) 𝑦 = 1 + 2π‘₯ 𝑒 −2π‘₯
D) π’š = 𝟏 + πŸπ’™ 𝒆−πŸπ’™
The characteristic equation for the second-order, homogeneous linear equation is
π‘Ÿ 2 + 4π‘Ÿ + 4 = 0
The roots are
π‘Ÿ1,2 = −π‘Ž ± π‘Ž2 − 𝑏 = −2 ± 22 − 4
= -2, -2
2
Since π‘Ž = 𝑏, the solution is
𝑦 = 𝐢1 + 𝐢2 π‘₯ 𝑒 π‘Ÿπ‘₯ = 𝐢1 + 𝐢2 𝑒 −2π‘₯
Evaluate the equation at the initial conditions
y(0) = 1
1 = 𝐢1 + 𝐢2 0 𝑒 −2
0
→ 𝐢1 = 1
Diffferentiate the expression for y to obtain y’
𝑦 ′ = 𝐢1 + 𝐢2 π‘₯ 𝑒 −2π‘₯ −2 + 𝐢2 𝑒 −2π‘₯
y’(0) = 0
0 = −2𝑒 −2 0 𝐢1 + 𝐢2 0 𝑒 −2 0 = −2 1 + 𝐢2 → 𝐢2 = 2
12) The electrical charge associated with
one electron is:
a) 1 eV
b) -1 Coulomb
c) 6.25 x 1018 Coulombs
d) -1.60 x 10 -19 Coulombs
D) -1.60 x 10 -19 Coulombs
The charge on one electron = -1.60 x 10 -19 Coulombs
1 eV is a unit of energy or work, 1 eV = -1.60 x 10 -19 Joules
13) Which one of the following states
the fundamental modes of heat transfer?
a) Friction, Convection, Nuclear reactions
b) Conduction, Convection, Radiation
c) Ionization, Evaporation, Radiation
d) Chemical reaction, Electrical resistance, Nuclear reactions.
A) Conduction, Convection, Radiation
The fundamental modes of heat transfer are conduction,
convection, and radiation.
14) A 10 kg mass block is initially pushed at a velocity of
1 m/sec along a horizontal track. If the block travels 10
meters before it stops, what is the coefficient of kinetic
friction (uk) between the block and track?
a) 0.005
b) 0.250
c) 0.450
d) 0.500
A) 0.005
For a conservative system w/friction
PE1 + KE1 + W 1,2 = PE2 + KE2
KE = ½mv2
Work done by friction = x F dx
uk = Friction Force / Normal force
Since PE is the same for initial and final conditions and the final velocity is 0
KE1 + W 1,2 = 0
½mv2 + x F dx = 0
Since friction force is constant οƒ  ½mv2 + F (x2 - x1) = 0
F = -½mv2 / (x2 - x1)
F = -½(10 kg)(1 m/sec)2 / 10 m)
F = - 0.5 N
Normal = Weight of block since table is horizontal
Normal = mg = 10kg(9.8 m/sec2) = 98 Newtons
uk = 0.5/98 = 0.0051
15) What is the value of matrix element
(c2,3), given C = A + B + A, where:
a) 9
b) 6
c) 12
d) 15
C) 12
c
= a i j+ b i j + a
i = 2, j = 3
ij
ij
Substitute
c2,3 = a2,3 + b2,3 + a2,3
c2,3 = 3 + 6 + 3 = 12
16) The ship is pushed through the water using an A-36
steel propeller shaft that is 8 m long, measured from the
propeller to the thrust bearing D at the engine. If it has
an outer diameter of 400 mm and a wall thickness of 50
mm, determine the amount of axial contraction of the
shaft when propeller exerts a force on the shaft of 5 kN.
The bearing at B and C are journal bearings.
a) −3.64 10−6 π‘šπ‘š
b) −3.64 10−3 π‘šπ‘š
c) 2.64 10−3 π‘šπ‘š
d) 4.64 10−3 π‘šπ‘š
B) −πŸ‘. πŸ”πŸ’ 𝟏𝟎−πŸ‘ π’Žπ’Ž
17) The velocity distribution for laminar flow between parallel plates is given by
𝟐
𝒖
πŸπ’š
=𝟏 −
π’–π’Žπ’‚π’™
𝒉
where h is the distance separating the plates and the origin is placed midway
between the plates. Consider a flow of water at 15° C, with π’–π’Žπ’‚π’™ = 0.10m/s and
h= 0.1 mm. What the shear stress on the upper plate and the direction.
a) −3.24
𝑁
π‘š2
b) −4.56
𝑁
π‘š2
c) 4.56
𝑁
π‘š2
d) −5.56
𝑁
π‘š2
B) −πŸ’. πŸ“πŸ”
τ𝑦π‘₯
𝑡
π’ŽπŸ
𝑁
= −4.56 2
π‘š
18) The thermal resistance for one-dimensional steady
conduction heat transfer through a cylindrical wall in
the radial direction is which of the following?
a) Linear
b) Logarithmic
c) Exponential
d) Polynomial
B) Logarithmic
For heat flow radically through cylindrical pipe walls, the logarithmic mean area is
used.
π΄π‘š =
𝐴0 − 𝐴𝑖
𝐴
ln 𝐴0
𝑖
Since thermal resistance is L/kA, the thermal resistance is logarithmic.
19) A car starts from rest and with constant acceleration
achieves a velocity of 15 m/s when it travels a distance of
200 m. What is the acceleration of the car and the time
required.
a) 26.7
π‘š
𝑠 2 , 0.56
𝑠
b) 0.89
π‘š
𝑠 2 , 15.7
𝑠
c) 0.56
π‘š
𝑠 2 , 26.7
𝑠
d) 1.56
π‘š
𝑠 2 , 36.7
𝑠
C) 𝟎. πŸ“πŸ”
π’Ž
π’”πŸ
, πŸπŸ”. πŸ• 𝒔
20) Air is compressed isentropically such that its
pressure is increased by 50%. The initial temperature is
70°C. What is the final temperature?
a) 80°C
b) 110°C
c) 140°C
d) 240°C
B) 110°C
For a closed isentropic (constant entropy) process,
𝑇1 = 70°C + 273 = 343K
(1−π‘˜)/π‘˜
𝑇1
𝑝2
=
𝑇2
𝑝1
𝑇2 = 𝑇1
𝑝1
𝑝2
(1−π‘˜)/π‘˜
(1−1.4)/1.4
1
=
1.5
= 385.1𝐾
𝑇2 = 385.1𝐾 − 273
= 112°C (110°C)
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