LECTURE № 15 Theme: Derivatives of benzodiazepine and phenothiazine: properties, analysis, storage, action and use. Derivative of acridine as antiseptic. Associate prof. Mosula L.M. The plan 1. The condensed five-membered heterocycles: - derivatives of indole as anti-inflammatory agent (indometacin). - derivative of benzimidazole as antispasmodic and antihypertensive agent (Bendazoli hydrochloridum, Dibazolum). 2. The condensed six-membered heterocycles: - derivative of 8-hydroxyquinoline as antiseptic (Chinosolum). - derivative of acridine as antiseptic (ethacridine lactate monohydrate). 4 5 3 Derivatives of indole as drugs 2 6 7 N1 H Indole (benzopyrrole, benzoimidol) – is condensed system, which consist of benzene and pyrrole (pentatomic heterocycle with heteroatom of Nitrogen): For indole are characteristic aromatic properties, reactions electrophilic substitution on positions 2, 3 and 6, most reactive is position 3 with max electronic density. Because in the molecule of indole is “pyrrole“ atom of Nitrogen group–NH has weak acid properties. To derivatives of indole concern many natural and synthetic drugs. Indometacin General Notices (Ph Eur monograph 0092) Indometacinum 4 C19H16ClNO4 357.8 DEFINITION Indometacin contains not less than 98.5 per cent and not more than the equivalent of 100.5 per cent of [1-(4chlorobenzoyl)-5methoxy-2-methylindol-3yl]acetic acid, calculated with reference to the dried substance. H3CO 5 3 2 6 7 N1 CH3 C O Cl CH2COOH CHARACTERS A white or yellow, crystalline powder, practically insoluble in water, sparingly soluble in alcohol. IDENTIFICATION First identification A, C. Second identification A, B, D, E. A. Melting point (2.2.14): 158 °C to 162 °C. B. UV-spectroscopy. C. IR-absorption spectrophotometry. D and E – chemical methods. The test substance is practically insoluble in water, therefore the first can make mineralization (for example, melting with mix K2CO3 and KNO3), after that can make all reactions for chlorideiones. - Reaction with si1ver nitrate in the nitric-acid medium; white curdled precipitate is formed: Cl– + Ag+ AgCl AgCl + 2NH4OH = [Ag(NH3)2]Cl + 2H2O - Reaction with oxidizer (for example, К2Cr2O7) in the sulphatic-acid medium; toxic gas Cl2 is alocated: 6KCl + K2Cr2O7 + 7H2SO4 = 3Cl2 + Cr2(SO4)3 + 4K2SO4 + 7H2O Cr2O72– + 14H+ + 6е 2Cr3+ + 7Н2О 2Cl– – 2е Cl2 MnO2 + 4HCl = MnCl2 + Cl2 + 2H2O MnO2 + 4H+ + 2е Mn2+ + 2H2O 2Cl– – 2е Cl2 E. (BrPh). Reaction with dimethylaminobenzaldehyde solution To 0.5 ml of the solution in alcohol prepared in identification test D, add 0.5 ml of dimethylaminobenzaldehyde solution R2. A precipitate is formed that dissolves on shaking. Heat on a water-bath. A bluish-green colour is produced. Continue to heat for 5 min and cool in iced water for 2 min. A precipitate is formed and the colour changes to light greyish-green. Add 3 ml of alcohol R. The solution is clear and violet-pink in colour. D. (BrPh). Reaction of alcoholic solution of test substance with solution of hydroxylamine hydrochloride (hydroxamic reaction) CH2COOH H3CO CH2COOH H3CO O NH2OH . HCl N CH3 + N C O Cl CH3 H Cl Fe O FeCl3 Cl C 3 O N H violet-pink colour C OH N H ASSAY (BrPh). Alkalimetry, direct titration Dissolve 0.300 g in 75 ml of acetone R, through which nitrogen R, free from carbon dioxide, has been passed for 15 min. Maintain a constant stream of nitrogen through the solution. Add 0.1 ml of phenolphthalein solution R. Titrate with 0.1 M sodium hydroxide. Carry out a blank titration. 1 ml of 0.1 M sodium hydroxide is equivalent to 35.78 mg of C19H16ClNO4. CH2COOH H3CO N CH3 + NaOH N C CH3 C O Cl CH2COONa H3CO O Cl Em = М. m. + H2O STORAGE Store protected from light. Action and use Anti-inflammatory; analgesic. Preparations Indometacin Capsules Indometacin Suppositories Ph Eur Derivative of benzimidazole Bendazoli hydrochloridum SP Х Dibazolum N N CH2 . HCl H 2-benzylbenzimidazole hydrochloride or 2(phenylmethyl)-1H-benzimidazole hydrochloride CHARACTERS A white or grayish-white or yellowish-white crystalline powder, hygroscopic, melting point 182–186 С; slightly soluble in water, acetone and chloroform, freely soluble in alcohol, practically insoluble in ether Identification 1. SP Х. Reaction with solution of iodine in the hydrochloric-acid medium (reaction for heterocyclic atoms of Nitrogen) Dissolve 0,02 g in 5 ml of water, add 3 drops of dilute hydrochloric acid HCl, 2–3 drops of 0,05 М solution of iodine I2 and shakes; reddish-silvery precipitate (dibazol periodide) is formed: N 2 + 3J2 + 2H N + HCl CH2 H At temperature not more then 25 С. N 2 N H CH2 . J2 . HJ 2. SP Х. Reaction for chloride-iones after precipitation of dibasol-base by means of solution of ammonia DibasolHCl + NH4OH Dibasol + NH4Cl + H2O base AgNO3 + NH4Cl = AgCl↓ + NH4NO3 white AgCl + 2NH4OH = [Ag(NH3)2]Cl + 2H2O [Ag(NH3)2]Cl + 2HNO3 → AgCl↓ + 2NH4NO3 3. Reaction with solution of alkali DibasolHCl + NаOH Dibasol + NаCl + H2O base Tests 1. Specific impurity - о-phenylendiamine. Reagent iron(ІІІ) chloride FeCl3 in the hydrochloric-acid medium; any pink colour not can be. ASSAY 1. SP Х. Acidimetry, non-aqueous titration Dissolve 0,15 g in 10 ml of anhydrous acetic acid, add 5 ml of mercury acetate solution and titrate with 0,1 М perchloric acid (as indicator – solution of crystalline violet). Ttitrate to occurrence bluish-green colour of solution. Carry out a blank titration. Em = М. m. N 2 N . CH2 + 2HClO4 + Hg(CH3COO)2 CH3COOH HCl H + N H 2 _ N H CH2 . ClO4 + HgCl2 + 2CH3COOH 2. Alkalimetry in the presence of organic solvent (titration of bonded HCl). DibasolHCl + NаOH Dibasol + NаCl + H2O Em = М. м. 3. Argentometry, direct titration in the presence of acetone and solution of sodium acetate (Morh method) T – AgNO3; Ind – solution of K2CrO4 (titrate to occurrence red-orange colour - Ag2CrO4). Acetone add for dibasol-base fixation, solution of sodium acetate add for nitric acid fixation. DibasolHCl + 2AgNO3 Dibasol-Ag + AgCl + HNO3 2AgNO3 + K2CrO4 = Ag2CrO4 + 2KNO3 CH3COONa + HNO3 NaNO3 + CH3COOH Em = М.m. /2 4. Thiocyanatometry, substitute titration To alcoholic solution of test substanse add solution of concentrated AgNO3 in the presence NH4OH; white precipitate of Agsalt of dibasol is formed. Filtrate and precipitate dilute with HNO3. Equivalent quantity of AgNO3 titrate with standard solution of NH4SCN (as indicator – iron ammonium sulphate FeNH4(SO4)2). Titrate to occurrence pink colour. N N AgNO3 NH4OH CH2 C6H5 N H + NH4NO3+ H2O N CH2 C6H5 Ag N N HNO3 N Ag CH2 C6H5 AgNO3 N CH2 C6H5 H AgNO3 + NH4SCN = AgSCN↓ + NH4NO3 3NH SCN + FeNH (SO ) = Fe(SCN) + 2(NH ) SO STORAGE Store protected from light. Action and use Antispasmodic and antihypertensive agent Derivatived of quinoline as drugs Quinoline – is condensed dicyclic compound, which consists of benzene and pyridine cycles (benzopyridine) 5 4 3 6 2 7 8 N 1 Quinoline was discovered in 1834 in coal. Quinoline is bactericidal, antiseptic and antipyretic agent, but quinoline is vetry toxic (nerve toxine!), therefore asdrug quinoline not use. The introduction different substituents to quinoline ring can lower its toxicity. Derivatives of quinoline have different pharmacological activity: 1. Antimalarial agents: derivatives of 4-aminoquinoline, derivatives of 8-aminoquinoline. 2. Antiseptic and antibacterial agents: derivatives of 8hydroxyquinoline. 3. Anesthetic agent: derivative of 4-quinolincarboxylic acid. Derivatives of 8-hydroxyquinoline The non-substituted derivatives of 8-hydroxyquinoline (chinosolum), and substituted derivatives with haloid substituents on the 5 and 7 positions of quinoline cycle (Chiniofonum, Enteroseptol) and substituted derivatives with nitro-group on 5 position of the ring (Nitroxolinum) have antibacterial, antiparasitic and antimicotic activity. Chemical properties Derivatives of 8-hydroxyquinoline is ampholytes. But their acid properties are strongest (influence of heteroatom of Nitrogen on mobility atom of Hydrogen from phenolic hydroxyl (–ОН) unlike phenols. Therefore 8-hydroxyquinoline is soluble in carbonates (this property is used at identification). The second property this derivatives – formation of chelate complexes with cations of metals. Chinosolum N OH SP X H2SO4 2 8-hydroxyquinoline sulphate CHARACTERS A yellow fine-crystalline powder, melting point 175–178 С; freely in water, slightly soluble in alcohol, practically insoluble in ether and chloroform . IDENTIFICATION 1. SP Х. Reaction with iron(ІІІ) chloride (for phenolic hydroxyl) + FeCl3 3 + 3HCl N OH N O Fe 3 bluish-green colour 2. SP Х. Reaction with solution of sodium carbonate To 1 ml of test solution add solution of Na2CO3; precipitate is formed, soluble in excess of reagent. + Na2SO4 + H2O + CO2 H2SO4 + Na2CO3 N OH N OH 2 2 + Na2CO3 + H2O + CO2 2 N OH N ONa 3. SP Х. Reaction for sulphate-iones: а) with solution of ВаCl2 in the medium of HCl: SO42– + Ва2+ ВаSO4 white ASSAY 1. SP Х. Alkalimetry in the presence of chloroform Disolve 0,5 g in 50 ml of water, add 20 ml of chloroform (for extraction and dilution of 8hydroxyquinoline) and titrate with 0,1 М NaOH (as indicator – phenolphthalein). Titrate to occurrence pink colour. H2SO4 + 2NaOH 2 + Na2SO4 + 2H2O N OH N 2 OH Е = М. m./2 STORAGE Store protected from light. Action and use Antiseptic Derivatives of acridine Acridine is the condensed heterocyclic system, which consist of pyridine and two benzene cycles (or quinoline and benzene): 8 9 1 7 2 6 5 N 10 3 4 In the medical practice as drugs are used such derivatives of acridine: quinacrine (antimalarial agent), aminoquinacrine (antimecotic agent), ethacridine lactate monohydrate (antiseptic agent). 2. ГФ Х. Реакция с раствором барий хлорида (наличие NaHCO3) К 10 мл раствора препарата (1:100) прибавляют 5 мл раствора барий хлорида BaCl2; выпадает желтый осадок, растворимый в 2 мл разбавленной хлоридной кислоты. В осадок выпадает белый осадок ВаСО3, цвет которого (желтый) обусловлен наличием в нем примеси 8-окси-7-йод-5-сульфохинолина. Ва2+ + СО32– ВаСО3 3. ГФ Х. Реакция с раствором феррум(ІІІ) хлорида (на фенольный гидроксил) К 10 мл того же раствора прибавляют 1 каплю раствора феррум(ІІІ) хлорида FeCl3; появляется зеленое окрашивание. SO3H SO3H + FeCl3 3 N I OH + 3HCl N I O Fe 3 Ethacridine lactate monohydrate General Notices (Ph Eur monograph 1591 ) Rivanolum Aethacridini lactas C18H21N3O4,H2O 361.4 DEFINITION 7-Ethoxyacridine-3,9-diamine (2RS)-2hydroxypropanoate. Content 99.0 per cent to 101.0 per cent (dried substance). CHARACTERS Appearance Yellow crystalline powder. Solubility Sparingly soluble in water, very slightly soluble in alcohol, practically insoluble in methylene chloride. IDENTIFICATION First identification A. Second identification B, C, D. A. Infrared absorption spectrophotometry (2.2.24). B. Mix 0.1 ml of solution S (see Tests) and 100 ml of water R. The solution is greenish-yellow and shows a strong green fluorescence in ultraviolet light at 365 nm. Add 5 ml of 1 M hydrochloric acid. The fluorescence remains. C. To 0.5 ml of solution S add 1.0 ml of water R, 0.1 ml of a 10 g/l solution of cobalt chloride R and 0.1 ml of a 50 g/l solution of potassium ferrocyanide R. The solution is green. D. Alkalizing of test solution with the subsequent revealing lactate-ions in the filtrate To 50 ml of solution S add 10 ml of dilute sodium hydroxide solution R. Filter. To 5 ml of the filtrate, add 1 ml of dilute sulphuric acid R. 5 ml of the solution obtained gives the reaction of lactates (2.3.1) (add some drops of 0,05 M solution KMnO4 and heat up; violet colouring of solution disappears). Alkali precipitates from ethacridine lactate solution a yellow precipitate of ethacridine-base: Ethacridine lactate + NaOH = Ethacridine + Na-lactate + Н2О yellow In filtrate lactate-ions reveales by means of solution KMnO4 in the sulphatic O is observed : acid medium - decolouration of solution KMnO4 O H 2 H3C H C 5 H3C OH 2 H3C ONa OH H C + H2SO4 C C OH OH O O + 2KMnO4 + H2SO4 = C OH + Na2SO4 C 5 H3C + 5CO2 + 2MnSO4 + K2SO4 + 8H2O C H decolouration of solution Other reaction: 1. Reaction diazotization (for primary aromatic amino group) 5 ml of solution acidify diluted HCl and add 1 ml of sodium nitrite solution NaNO2; there is dark-red colouring (diazonium salt). NH2 NH2 OC2H5 NaNO2,HCl H2N OC2H5 N + N N Cl- N dark red colour of diazonium salt 2. Reaction with solution of iodine 2. Reaction with iodine solution To 5 ml of the same solution add 3 drops of 0,05 M iodine solution I2; the blue-green precipitate, soluble in 95 % alcohol, is formed. NH2 H NH2 OC2H5 . H3C H2N N H H C OH I O C OC2H5 . H3C + 2I2 OH H2N N I blue-green precipitate H C OH O C + 2HI OH ASSAY (BrPh). Acidimetry, non-aqueous titration (see phthivazid) Dissolve 0.270 g in 5.0 ml of anhydrous formic acid R. Add 60.0 ml of acetic anhydride R and titrate with 0.1 M perchloric acid, determining the end-point potentiometrically (2.2.20). 1 ml of 0.1 M perchloric acid is equivalent to 34.34 mg of C18H21N3O4. Other method: Iodochlorometry, back titration NH2 H NH2 OC2H5 . H3C H2N N H H C OH I O C OC2H5 + 2ICl OH + H2N N I ICl + KI = I2 + KCl I2 + 2Na2S2O3 = 2NaI + Na2S4O6 Em (С15Н15N3OС3Н6O3) = М m./4 H3C H C OH + 2HCl O C OH STORAGE Protected from light. Action and use Antiseptic. Ph Eur Thanks for attention!