New topics – energy storage elements Capacitors Inductors EE 42 and 100, Fall 2005 Week 3b 1 Books on Reserve for EE 42 and 100 in the Bechtel Engineering Library “The Art of Electronics” by Horowitz and Hill (2nd edition) -- A terrific source book on practical electronics “Electrical Engineering Uncovered” by White and Doering (2nd edition) – Freshman intro to aspects of engineering and EE in particular ”Newton’s Telecom Dictionary: The authoritative resource for Telecommunications” by Newton (“18th edition – he updates it annually) – A place to find definitions of all terms and acronyms connected with telecommunications. TK5102.N486 Shelved with dictionaries to right of entry gate. EE 42 and 100, Fall 2005 Week 3b 2 The Capacitor Two conductors (a,b) separated by an insulator: difference in potential = Vab => equal & opposite charges Q on conductors +Q -Q + - Vab Q = CVab (stored charge in terms of voltage) where C is the capacitance of the structure, positive (+) charge is on the conductor at higher potential Parallel-plate capacitor: • area of the plates = A (m2) • separation between plates = d (m) • dielectric permittivity of insulator = (F/m) => capacitance A C d EE 42 and 100, Fall 2005 (F) F Week 3b 3 + or Symbol: C C C Electrolytic (polarized) capacitor Units: Farads (Coulombs/Volt) (typical range of values: 1 pF to 1 mF; for “supercapacitors” up to a few F!) Current-Voltage relationship: dQ dvc dC ic C vc dt dt dt If C (geometry) is unchanging, iC = dvC/dt ic + vc – Note: Q (vc) must be a continuous function of time EE 42 and 100, Fall 2005 Week 3b 4 Voltage in Terms of Current; Capacitor Uses t Q (t ) ic (t )dt Q (0) 0 t t 1 Q ( 0) 1 vc (t ) ic (t )dt ic (t )dt vc (0) C0 C C0 Uses: Capacitors are used to store energy for camera flashbulbs, in filters that separate various frequency signals, and they appear as undesired “parasitic” elements in circuits where they usually degrade circuit performance EE 42 and 100, Fall 2005 Week 3b 5 EE 42 and 100, Fall 2005 Week 3b 6 Schematic Symbol and Water Model for a Capacitor EE 42 and 100, Fall 2005 Week 3b 7 Stored Energy CAPACITORS STORE ELECTRIC ENERGY You might think the energy stored on a capacitor is QV = CV2, which has the dimension of Joules. But during charging, the average voltage across the capacitor was only half the final value of V for a linear capacitor. Thus, energy is 1 QV 2 1 CV 2 2 . Example: A 1 pF capacitance charged to 5 Volts has ½(5V)2 (1pF) = 12.5 pJ (A 5F supercapacitor charged to 5 volts stores 63 J; if it discharged at a constant rate in 1 ms energy is discharged at a 63 kW rate!) EE 42 and 100, Fall 2005 Week 3b 8 A more rigorous derivation ic + vc – t t Final v VFinal dQ v VFinal w v c ic dt dt vc v c dQ t t Initial v VInitial dt v VInitial v VFinal 1 1 2 2 w Cv dv CV CV c c Final Initial 2 2 v VInitial EE 42 and 100, Fall 2005 Week 3b 9 Example: Current, Power & Energy for a Capacitor t v (V) 1 0 1 2 4 5 1 2 EE 42 and 100, Fall 2005 3 4 v(t) 10 mF t (ms) vc and q must be continuous functions of time; however, ic can be discontinuous. dv iC dt i (mA) 0 3 i(t) – + 1 v(t ) i( )d v(0) C0 5 Week 3b t (ms) Note: In “steady state” (dc operation), time derivatives are zero C is an open circuit 10 p (W) i(t) 0 1 2 3 4 5 – + v(t) 10 mF t (ms) p vi w (J) 0 t 1 2 EE 42 and 100, Fall 2005 3 4 5 Week 3b t (ms) 1 2 w pd Cv 2 0 11 Capacitors in Parallel i(t) i1(t) i2(t) + C1 C2 v(t) – + Ceq i(t) v(t) Ceq C1 C2 – dv i Ceq dt Equivalent capacitance of capacitors in parallel is the sum EE 42 and 100, Fall 2005 Week 3b 12 Capacitors in Series + v1(t) – + v2(t) – i(t) C1 C2 + i(t) Ceq v(t)=v1(t)+v2(t) – 1 1 1 Ceq C1 C2 EE 42 and 100, Fall 2005 Week 3b 13 Capacitive Voltage Divider Q: Suppose the voltage applied across a series combination of capacitors is changed by Dv. How will this affect the voltage across each individual capacitor? Dv Dv1 Dv2 DQ1=C1Dv1 Q1+DQ1 C1 v+Dv + – -Q1DQ1 Q2+DQ2 C2 Q2DQ2 + v1+Dv1 – Note that no net charge can can be introduced to this node. Therefore, DQ1+DQ2=0 + v2(t)+Dv2 – C1Dv1 C2Dv2 C1 Dv2 Dv C1 C2 DQ2=C2Dv2 Note: Capacitors in series have the same incremental charge. EE 42 and 100, Fall 2005 Week 3b 14 MEMS Airbag Deployment Accelerometer Chip about 1 cm2 holding in the middle an electromechanical accelerometer around which are electronic test and calibration circuits (Analog Devices, Inc.) Hundreds of millions have been sold. EE 42 and 100, Fall 2005 Airbag of car that crashed into the back of a stopped Mercedes. Within 0.3 seconds after deceleration the bag is supposed to be empty. Driver was not hurt in any way; chassis distortion meant that this car was written off. Week 3b 15 Application Example: MEMS Accelerometer to deploy the airbag in a vehicle collision • Capacitive MEMS position sensor used to measure acceleration (by measuring force on a proof mass) MEMS = micro• electro-mechanical systems g1 g2 FIXED OUTER PLATES EE 42 and 100, Fall 2005 Week 3b 16 Sensing the Differential Capacitance – Begin with capacitances electrically discharged – Fixed electrodes are then charged to +Vs and –Vs – Movable electrode (proof mass) is then charged to Vo Circuit model Vs C1 C1 C2 Vo Vs (2Vs ) Vs C1 C2 C1 C2 C1 Vo C2 –Vs EE 42 and 100, Fall 2005 A A Vo g1 g 2 g 2 g1 g 2 g1 Vs A A g 2 g1 const g1 g 2 Week 3b 17 Application: Condenser Microphone Condenser microphone G Sound waves Econst x Electret microphone E c onst X1 G Vout x Cylindrical air-filled cavity Flexible conducting diaphragm Conducting rigid cup Vout ~ x E c onst EE 42 and 100, Fall 2005 Vout Week 3b X1 Vout ~ x Econst Electret: insulator (e.g., teflon) that was bombarded with electrons that remain imbedded in it to “bias” the condenser. Widely used in telephone handsets; available at RadioShack 18 Practical Capacitors • A capacitor can be constructed by interleaving the plates with two dielectric layers and rolling them up, to achieve a compact size. • To achieve a small volume, a very thin dielectric with a high dielectric constant is desirable. However, dielectric materials break down and become conductors when the electric field (units: V/cm) is too high. – Real capacitors have maximum voltage ratings – An engineering trade-off exists between compact size and high voltage rating EE 42 and 100, Fall 2005 Week 3b 19 The Inductor • An inductor is constructed by coiling a wire around some type of form. + vL(t) iL _ • Current flowing through the coil creates a magnetic field and a magnetic flux that links the coil: LiL • When the current changes, the magnetic flux changes a voltage across the coil is induced: Note: In “steady state” (dc operation), time derivatives are zero L is a short circuit EE 42 and 100, Fall 2005 Week 3b diL vL (t ) L dt 20 Symbol: L Units: Henrys (Volts • second / Ampere) (typical range of values: mH to 10 H) Current in terms of voltage: 1 diL vL (t )dt L t 1 iL (t ) vL ( )d i(t0 ) L t0 iL + vL – Note: iL must be a continuous function of time EE 42 and 100, Fall 2005 Week 3b 21 Schematic Symbol and Water Model of an Inductor EE 42 and 100, Fall 2005 Week 3b 22 Stored Energy INDUCTORS STORE MAGNETIC ENERGY Consider an inductor having an initial current i(t0) = i0 p(t ) v(t )i(t ) t w(t ) p( )d t0 1 2 1 2 w(t ) Li Li0 2 2 EE 42 and 100, Fall 2005 Week 3b 23 Inductors in Series di v Leq dt + v1(t) – + v2(t) – + v(t) – L1 i(t) L2 i(t) v(t) + – Leq + v(t)=v1(t)+v2(t) – di di di di v L1 L2 L1 L2 Leq dt dt dt dt Leq L1 L2 Equivalent inductance of inductors in series is the sum EE 42 and 100, Fall 2005 Week 3b 24 Inductors in Parallel + i1 i(t) L1 + i2 i(t) v(t) L2 Leq v(t) – – t t t 1 1 i i1 i2 vd i1 (t0 ) vd i2 (t0 ) L1 t0 L2 t0 1 i vd i (t0 ) Leq t0 1 1 t i vd i1 (t0 ) i2 (t0 ) L1 L2 t0 1 1 1 with i (t0 ) i1 (t0 ) i2 (t0 ) Leq L1 L2 EE 42 and 100, Fall 2005 Week 3b 25 Summary Capacitor Inductor dv iC dt 1 2 w Cv 2 di vL dt 1 2 w Li 2 v cannot change instantaneously i can change instantaneously Do not short-circuit a charged capacitor (-> infinite current!) n cap.’s in series: n 1 1 n ind.’s in series: Ceq i 1 Ci n cap.’s in parallel: Ceq EE 42 and 100, Fall 2005 i cannot change instantaneously v can change instantaneously Do not open-circuit an inductor with current (-> infinite voltage!)n n C i 1 i Leq Li i 1 n 1 1 n ind.’s in parallel: Leq i 1 Li Week 3b 26 Transformer – Two Coupled Inductors + + v1 v2 - - N1 turns N2 turns |v2|/|v1| = N2/N1 EE 42 and 100, Fall 2005 Week 3b 27 AC Power System Flowing water or Steam produced from Fuel oil, Natural gas, Coal, or Nuclear energy 35,000 volts Turbine 130,000 volts Generator Generating Plant Step-up Transformer (for efficient transmission at higher voltage, lower current) 21,000 volts Step-down Transformer (for local distribution) Transmission-line support towers 120-240 volts Step-down transformer mounted on power pole Customer Simplified representation of the transmission and distribution systems that bring electric power from a generating station to customers. In the generating station, a turbine driven by any of the means indicated at the upper left is coupled to a generator, turning it to produce three-phase alternating voltages. EE 42 and 100, Fall 2005 Week 3b 28 High-Voltage Direct-Current Power Transmission http://www.worldbank.org/html/fpd/em/transmission/technology_abb.pdf Highest voltage +/- 600 kV, in Brazil – brings 50 Hz power from12,600 MW Itaipu hydropower plant to 60 Hz network in Sao Paulo EE 42 and 100, Fall 2005 Week 3b 29 Relative advantages of HVDC over HVAC power transmission • Asynchronous interconnections (e.g., 50 Hz to 60 Hz system) • Environmental – smaller footprint, can put in underground cables more economically, ... • Economical -- cheapest solution for long distances, smaller loss on same size of conductor (skin effect), terminal equipment cheaper • Power flow control (bi-directional on same set of lines) • Added benefits to the transmission (system stability, power quality, etc.) EE 42 and 100, Fall 2005 Week 3b 30 Summary of Electrical Quantities Quantity Variable Unit Unit Symbol Typical Values Defining Relations Charge Q coulomb C 1aC to 1C magnitude of 6.242 × 1018 electron charges qe = 1.602x10-19 C Current I ampere A 1mA to 1kA 1A = 1C/s Important Equations i = dq/dt N node I n 1 Voltage V volt V 1mV to 500kV 1V = 1N-m/C 0 n N loop V n 1 EE 42 and 100, Fall 2005 Week 3b Symbol n 0 31 Summary of Electrical Quantities (concluded) Power P watt W 1mW to 100MW 1W = 1J/s P = dU/dt; P=IV Energy U joule J 1fJ to 1TJ 1J = 1N-m U = QV Force F newton N Time t second s Resistance R ohm 1N = 1kgm/s2 1 to 10M V = IR; P = V2/R = I2R R Capacitance Inductance C L farad henry EE 42 and 100, Fall 2005 F H 1fF to 5F 1mH to 1H Week 3b Q = CV; i = C(dv/dt);U = (1/2)CV2 v = L(di/dt); U = (1/2)LI2 C L 32