Algebra 2

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Assignment, pencil, red pen,
highlighter, GP notebook, calculator
1. Solve the equation
|2x – 1| – 9 = 14.
|2x – 1| – 9 = 14
+9 +9
|2x – 1| = 23 +1
+1
2x – 1 = 23 or
2x = 24
x = 12 +1
2. Graph the equation y = 3|x + 2| – 6
and determine the following
information.
+1
2x – 1 = –23
2x = –22
x = –11 +1
domain: ____________
range: _____________
locator: ____________
asymptote(s):________
total:
12
2. Graph the equation y = 3|x + 2| – 6 and
determine the following information.
Find the locator point.
y
10
Stretch/compression factor
is 3.
 ,   +1
domain: ____________
+1
[  6,  )
range: _____________
+1
(–2, –6)
–10
locator: ____________
None +1
asymptote(s):________
+2
5
x
–5
5
–5
–10
+1
10
Today is a work day!
Complete the worksheets.
Some problems from the
worksheets.
Absolute Value Equations & More
1) Solve for x.
a) 3x  36
3x = 36 or
3
3
x = 12
or
i) 4 x  7  3  13
3x = -36
3
3
x = -12
+3 +3
4 x  7  16
4
4
x 7  4
x = -12, 12
x – 7 = 4 or
+7 +7
x = 11
x – 7 = -4
+7 +7
or
x = 3, 11
x=3
10. Graph the equations and determine the following
information. A sketch of the parent graph might help.
a) y  2 x  3  5
10
y
Find the locator point.
Adjust for the negative
orientation and stretch
factor of 2.
5
x
–10
–5
5
–5
–10
10
10. Graph the equations and determine the following
information. A sketch of the parent graph might help.
c) y  2( x  2)3  3
10
y
Find the locator point.
Adjust for the negative
orientation and stretch
factor of 2.
5
x
–10
–5
5
–5
–10
10
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