8/28/2013 That tireless teacher who gets to class early and stays late and dips into her own pocket to buy supplies because she believes that every child is her charge -- she’s marching. (Applause.) That successful businessman who doesn’t have to, but pays his workers a fair wage and then offers a shot to a man, maybe an ex-con, who’s down on his luck -- he’s marching. (Cheers, applause.) The father who realizes the most important job he’ll ever have is raising his boy right, even if he didn’t have a father, especially if he didn’t have a father at home -- he’s marching. The graduate student who not only posts his comment, but comments on other peoples comments on Piazza, he is marching. (Cheers, applause.) The mother who pours her love into her daughter so that she grows up with the confidence to walk through the same doors as anybody’s son -she’s marching. 50 years since the man’s dream 1 8/28/2013 That tireless teacher who gets to class early and stays late and dips into her own pocket to buy supplies because she believes that every child is her charge -- she’s marching. (Applause.) That successful businessman who doesn’t have to, but pays his workers a fair wage and then offers a shot to a man, maybe an ex-con, who’s down on his luck -- he’s marching. (Cheers, applause.) The father who realizes the most important job he’ll ever have is raising his boy right, even if he didn’t have a father, especially if he didn’t have a father at home -- he’s marching. The graduate student who not only posts his comment, but comments on other peoples comments on Piazza, he is marching. (Cheers, applause.) The mother who pours her love into her daughter so that she grows up with the confidence to walk through the same doors as anybody’s son -she’s marching. 50 years since the man’s dream 2 8/28/2013 That tireless teacher who gets to class early and stays late and dips into her own pocket to buy supplies because she believes that every child is her charge -- she’s marching. (Applause.) That successful businessman who doesn’t have to, but pays his workers a fair wage and then offers a shot to a man, maybe an ex-con, who’s down on his luck -- he’s marching. (Cheers, applause.) The father who realizes the most important job he’ll ever have is raising his boy right, even if he didn’t have a father, especially if he didn’t have a father at home -- he’s marching. The graduate student who not only posts his comment, but comments on other peoples comments on Piazza, he is marching. (Cheers, applause.) The mother who pours her love into her daughter so that she grows up with the confidence to walk through the same doors as anybody’s son -she’s marching. 50 years since the man’s dream 3 (Static vs. Dynamic) Environment (perfect vs. Imperfect) (Full vs. Partial satisfaction) Goals (Observable vs. Partially Observable) (Instantaneous vs. Durative) (Deterministic vs. Stochastic) What action next? A: A Unified Brand-name-Free Introduction to Planning Subbarao Kambhampati Representation Mechanisms: Logic (propositional; first order) Probabilistic logic Learning the models How the course topics stack up… Search Blind, Informed SAT; Planning Inference Logical resolution Bayesian inference Topics Covered in CSE471 • • Table of Contents (Full Version) Preface (html); chapter map Part I Artificial Intelligence 1 Introduction 2 Intelligent Agents Part II Problem Solving 3 Solving Problems by Searching 4 Informed Search and Exploration 5 Constraint Satisfaction Problems 6 Adversarial Search Part III Knowledge and Reasoning 7 Logical Agents 8 First-Order Logic 9 Inference in First-Order Logic 10 Knowledge Representation Part IV Planning 11 Planning (pdf) 12 Planning and Acting in the Real World • Part V Uncertain Knowledge and Reasoning 13 Uncertainty 14 Probabilistic Reasoning 15 Probabilistic Reasoning Over Time 16 Making Simple Decisions 17 Making Complex Decisions Part VI Learning 18 Learning from Observations 19 Knowledge in Learning 20 Statistical Learning Methods 21 Reinforcement Learning Part VII Communicating, Perceiving, and Acting 22 Communication 23 Probabilistic Language Processing 24 Perception 25 Robotics Part VIII Conclusions 26 Philosophical Foundations 27 AI: Present and Future Topics Covered in CSE471 • • Table of Contents (Full Version) Preface (html); chapter map Part I Artificial Intelligence 1 Introduction 2 Intelligent Agents Part II Problem Solving 3 Solving Problems by Searching 4 Informed Search and Exploration 5 Constraint Satisfaction Problems 6 Adversarial Search Part III Knowledge and Reasoning 7 Logical Agents 8 First-Order Logic 9 Inference in First-Order Logic 10 Knowledge Representation Part IV Planning 11 Planning (pdf) 12 Planning and Acting in the Real World • Part V Uncertain Knowledge and Reasoning 13 Uncertainty 14 Probabilistic Reasoning 15 Probabilistic Reasoning Over Time 16 Making Simple Decisions 17 Making Complex Decisions Part VI Learning 18 Learning from Observations 19 Knowledge in Learning 20 Statistical Learning Methods 21 Reinforcement Learning Part VII Communicating, Perceiving, and Acting 22 Communication 23 Probabilistic Language Processing 24 Perception 25 Robotics Part VIII Conclusions 26 Philosophical Foundations 27 AI: Present and Future Agent Classification in Terms of State Representations Type State representation Focus Atomic States are indivisible; No internal structure Search on atomic states; Propositional (aka Factored) States are made of state variables that take values (Propositional or Multivalued or Continuous) Search+inference in logical (prop logic) and probabilistic (bayes nets) representations Relational States describe the objects in the world and their inter-relations Search+Inference in predicate logic (or relational prob. Models) First-order +functions over objects Search+Inference in first order logic (or first order probabilistic models) Pendulum Swings in AI • Top-down vs. Bottom-up • Ground vs. Lifted representation – The longer I live the farther down the Chomsky Hierarchy I seem to fall [Fernando Pereira] • Pure Inference and Pure Learning vs. Interleaved inference and learning • Knowledge Engineering vs. Model Learning vs. Data-driven Inference • Human-aware vs. Stand-Alone vs. Humandriven(!) Markov Decision Processes Atomic Model for stochastic environments with generalized rewards •Based in part on slides by Alan Fern, Craig Boutilier and Daniel Weld •Some slides from Mausam/Kolobov Tutorial; and a couple from Terran Lane 16 Atomic Model for Deterministic Environments and Goals of Attainment Deterministic worlds + goals of attainment Atomic model: Graph search Propositional models: The PDDL planning that we discussed.. What is missing? Rewards are only at the end (and then you die). What about “the Journey is the reward” philosophy? Dynamics are assumed to be Deterministic What about stochastic dynamics? 17 Atomic Model for stochastic environments with generalized rewards Stochastic worlds +generalized rewards An action can take you to any of a set of states with known probability You get rewards for visiting each state Objective is to increase your “cumulative” reward… What is the solution? 18 (Static vs. Dynamic) Environment (perfect vs. Imperfect) (Full vs. Partial satisfaction) Goals (Observable vs. Partially Observable) (Instantaneous vs. Durative) (Deterministic vs. Stochastic) What action next? A: A Unified Brand-name-Free Introduction to Planning Subbarao Kambhampati Optimal Policies depend on horizon, rewards.. - - - - Markov Decision Processes An MDP has four components: S, A, R, T: (finite) state set S (|S| = n) (finite) action set A (|A| = m) (Markov) transition function T(s,a,s’) = Pr(s’ | s,a) Probability of going to state s’ after taking action a in state s How many parameters does it take to represent? bounded, real-valued (Markov) reward function R(s) Immediate reward we get for being in state s For example in a goal-based domain R(s) may equal 1 for goal states and 0 for all others Can be generalized to include action costs: R(s,a) Can be generalized to be a stochastic function Can easily generalize to countable or continuous state and action spaces (but algorithms will be different) 25 Assumptions First-Order Markovian dynamics (history independence) Pr(St+1|At,St,At-1,St-1,..., S0) = Pr(St+1|At,St) Next state only depends on current state and current action First-Order Markovian reward process Pr(Rt|At,St,At-1,St-1,..., S0) = Pr(Rt|At,St) Reward only depends on current state and action As described earlier we will assume reward is specified by a deterministic function R(s) i.e. Pr(Rt=R(St) | At,St) = 1 Stationary dynamics and reward Pr(St+1|At,St) = Pr(Sk+1|Ak,Sk) for all t, k The world dynamics do not depend on the absolute time Full observability Though we can’t predict exactly which state we will reach when we execute an action, once it is realized, we know what it is 27 Policies (“plans” for MDPs) Nonstationary policy [Even though we have stationary dynamics and reward??] π:S x T → A, where T is the non-negative integers π(s,t) is action to do at state s with t stages-to-go What if we want to keep acting indefinitely? Stationary policy π:S → A π(s) is action to do at state s (regardless of time) specifies a continuously reactive controller If you are 20 and are not a liberal, you are heartless If you are 40 and not a conservative, you are mindless -Churchill These assume or have these properties: full observability Why not just consider history-independence sequences of actions? deterministic action choice # non-stationary policies: |A||S|*T # stationary policies: |A||S| Why not just replan? 28 Value of a Policy How good is a policy π? How do we measure “accumulated” reward? Value function V: S →ℝ associates value with each state (or each state and time for non-stationary π) Vπ(s) denotes value of policy at state s Depends on immediate reward, but also what you achieve subsequently by following π An optimal policy is one that is no worse than any other policy at any state The goal of MDP planning is to compute an optimal policy (method depends on how we define value) 29 Finite-Horizon Value Functions We first consider maximizing total reward over a finite horizon Assumes the agent has n time steps to live To act optimally, should the agent use a stationary or non-stationary policy? Put another way: If you had only one week to live would you act the same way as if you had fifty years to live? 30 Finite Horizon Problems Value (utility) depends on stage-to-go hence so should policy: nonstationary π(s,k) k V (s)is k-stage-to-go value function for π expected total reward after executing π for k time steps (for k=0?) k V ( s ) E [ R | , s ] k t t 0 k E [ R( s t ) | a t ( s t , k t ), s s 0 ] t 0 Here Rt and st are random variables denoting the reward received and state at stage t respectively 31 Computing Finite-Horizon Value Can use dynamic programming to compute k V (s) Markov property is critical for this (a) V0 ( s) R(s), s (b) Vk ( s ) R( s ) s'T (s, (s, k ), s' ) V immediate reward k 1 ( s' ) expected future payoff with k-1 stages to go π(s,k) 0.7 0.3 Vk Vk-1 32 Bellman Backup How can we compute optimal Vt+1(s) given optimal Vt ? Vt Compute Expectations Compute Max Vt+1(s) s1 0.7 a1 0.3 s 0.4 a2 0.6 s2 s3 s4 Vt+1(s) = R(s)+max { 0.7 Vt (s1) + 0.3 Vt (s4) 0.4 Vt (s2) + 0.6 Vt(s3) } 33 Value Iteration: Finite Horizon Case Markov property allows exploitation of DP principle for optimal policy construction no need to enumerate |A|Tn possible policies Value Iteration V ( s) R( s), s 0 Bellman backup V ( s ) R( s) max T ( s, a, s' ) V s ' a k * ( s, k ) arg max s' T ( s, a, s' ) V k 1 k 1 ( s' ) ( s' ) a Vk is optimal k-stage-to-go value function Π*(s,k) is optimal k-stage-to-go policy 34 Value Iteration Optimal value depends on stages-to-go (independent in the infinite horizon case) V3 V1 V2 V0 s1 0.7 0.7 0.7 0.4 0.4 0.4 0.6 0.6 0.6 0.3 0.3 0.3 V1(s4) = R(s4)+max { 0.7 V0 (s1) + 0.3 V0 (s4) 0.4 V0 (s2) + 0.6 V0(s3) s2 s3 s4 } 35 Value Iteration V3 V1 V2 V0 s1 0.7 0.7 0.7 0.4 0.4 0.4 0.6 0.6 0.6 0.3 0.3 P*(s4,t) = max { 0.3 s2 s3 s4 } 36 9/10/2012 37 Value Iteration Note how DP is used optimal soln to k-1 stage problem can be used without modification as part of optimal soln to k-stage problem Because of finite horizon, policy nonstationary What is the computational complexity? T iterations At each iteration, each of n states, computes expectation for |A| actions Each expectation takes O(n) time Total time complexity: O(T|A|n2) Polynomial in number of states. Is this good? 38 Summary: Finite Horizon Resulting policy is optimal V * ( s) V ( s), , s, k k k convince yourself of this Note: optimal value function is unique, but optimal policy is not Many policies can have same value 39 Discounted Infinite Horizon MDPs Defining value as total reward is problematic with infinite horizons many or all policies have infinite expected reward some MDPs are ok (e.g., zero-cost absorbing states) “Trick”: introduce discount factor 0 ≤ β < 1 future rewards discounted by β per time step k t t V ( s) E [ R | , s ] t 0 Note: V ( s) E [ R t 0 t max 1 max ] R 1 Motivation: economic? failure prob? convenience? 40 Notes: Discounted Infinite Horizon Optimal policy maximizes value at each state Optimal policies guaranteed to exist (Howard60) Can restrict attention to stationary policies I.e. there is always an optimal stationary policy Why change action at state s at new time t? We define V * (s) V (s) for some optimal π 41 Computing an Optimal Value Function Bellman equation for optimal value function V * ( s ) R( s ) β max T ( s, a, s' ) V *( s ' ) s ' a Bellman proved this is always true How can we compute the optimal value function? The MAX operator makes the system non-linear, so the problem is more difficult than policy evaluation Notice that the optimal value function is a fixed-point of the Bellman Backup operator B B takes a value function as input and returns a new value function B[V ]( s ) R( s) β max T ( s, a, s' ) V ( s' ) s ' a 42 Value Iteration Can compute optimal policy using value iteration, just like finite-horizon problems (just include discount term) V ( s) 0 0 V ( s) R( s) max T ( s, a, s' ) V s ' a k k 1 ( s' ) Will converge to the optimal value function as k gets large. Why? 43 Convergence B[V] is a contraction operator on value functions For any V and V’ we have || B[V] – B[V’] || ≤ β || V – V’ || Here ||V|| is the max-norm, which returns the maximum element of the vector So applying a Bellman backup to any two value functions causes them to get closer together in the max-norm sense. Convergence is assured any V: || V* - B[V] || = || B[V*] – B[V] || ≤ β|| V* - V || so applying Bellman backup to any value function brings us closer to V* by a factor β thus, Bellman fixed point theorems ensure convergence in the limit When to stop value iteration? when ||Vk - Vk-1||≤ ε this ensures ||Vk – V*|| ≤ εβ /1-β 44 Contraction property proof sketch Note that for any functions f and g We can use this to show that |B[V]-B[V’]| <= |V – V’| f B[V ]( s ) R( s ) β max T ( s, a, s' ) V ( s' ) s' a B[V ' ]( s ) R( s ) β max T ( s, a, s' ) V ' ( s' ) s' a g Subtract one from other ( B[V ] B[V ' ])( s ) β[ max T ( s, a, s' ) V ( s' ) max T ( s, a, s' ) V ' ( s' )] s' s' a a β max [ T ( s, a, s' ) (V ( s' ) V ' ( s' ))] s' a 45 How to Act Given a Vk from value iteration that closely approximates V*, what should we use as our policy? Use greedy policy: greedy[V ]( s) arg max T ( s, a, s' ) V ( s' ) s' k k a Note that the value of greedy policy may not be equal to Vk Let VG be the value of the greedy policy? How close is VG to V*? 46 How to Act Given a Vk from value iteration that closely approximates V*, what should we use as our policy? Use greedy policy: greedy[V ]( s) arg max T ( s, a, s' ) V ( s' ) s' a k k We can show that greedy is not too far from optimal if Vk is close to V* In particular, if Vk is within ε of V*, then VG within 2εβ /1-β of V* (if ε is 0.001 and β is 0.9, we have 0.018) Furthermore, there exists a finite ε s.t. greedy policy is optimal That is, even if value estimate is off, greedy policy is optimal once it is close enough 47 Improvements to Value Iteration Initialize with a good approximate value function Instead of R(s), consider something more like h(s) Well defined only for SSPs Asynchronous value iteration Can use the already updated values of neighors to update the current node Prioritized sweeping Can decide the order in which to update states As long as each state is updated infinitely often, it doesn’t matter if you don’t update them What are good heuristics for Value iteration? 48 9/14 (make-up for 9/12) Policy Evaluation for Infinite Horizon MDPS Policy Iteration Why it works How it compares to Value Iteration Indefinite Horizon MDPs The Stochastic Shortest Path MDPs With initial state Value Iteration works; policy iteration? Reinforcement Learning start 49 Policy Evaluation Value equation for fixed policy V ( s) R( s) β T ( s, ( s), s' ) V ( s' ) s' Notice that this is stage-indepedent How can we compute the value function for a policy? we are given R and Pr simple linear system with n variables (each variables is value of a state) and n constraints (one value equation for each state) Use linear algebra (e.g. matrix inverse) 50 Policy Iteration Given fixed policy, can compute its value exactly: V ( s) R( s) T ( s, ( s), s' ) V ( s' ) s' Policy iteration exploits this: iterates steps of policy evaluation and policy improvement 1. Choose a random policy π Policy improvement 2. Loop: (a) Evaluate Vπ (b) For each s in S, set ' ( s) arg max T ( s, a, s' ) V ( s' ) s' a (c) Replace π with π’ Until no improving action possible at any state 51 P.I. in action Iteration 0 Policy Value The PI in action slides from Terran Lane’s Notes P.I. in action Iteration 1 Policy Value P.I. in action Iteration 2 Policy Value P.I. in action Iteration 3 Policy Value P.I. in action Iteration 4 Policy Value P.I. in action Iteration 5 Policy Value P.I. in action Iteration 6: done Policy Value Policy Iteration Notes Each step of policy iteration is guaranteed to strictly improve the policy at some state when improvement is possible [Why? The same contraction property of Bellman Update. Note that when you go from value to policy to value to policy, you are effectively, doing a DP update on the value] Convergence assured (Howard) intuitively: no local maxima in value space, and each policy must improve value; since finite number of policies, will converge to optimal policy Gives exact value of optimal policy Complexity: There are at most exp(n) policies, so PI is no worse than exponential time in number of states Empirically O(n) iterations are required Still no polynomial bound on the number of PI iterations (open problem)! 59 Improvements to Policy Iteration Find the value of the policy approximately (by value iteration) instead of exactly solving the linear equations Can run just a few iterations of the value iteration This can be asynchronous, prioritized etc. 60 Value Iteration vs. Policy Iteration Which is faster? VI or PI It depends on the problem VI takes more iterations than PI, but PI requires more time on each iteration PI must perform policy evaluation on each step which involves solving a linear system Can be done approximately Also, VI can be done with asynchronous and prioritized update fashion.. ***Value Iteration is more robust—it’s convergence is guaranteed for many more types of MDPs.. 61 Need for Indefinite Horizon MDPs We have see Finite horizon MDPs Infinite horizon MDPs In many cases, we neither have finite nor infinite horizon, but rather some indefinite horizon Need to model MDPs without discount factor, knowing only that the behavior sequences will be finite 62 Stochastic Shortest-Path MDPs: Definition Bertsekas, 1995 SSP MDP is a tuple <S, A, T, C, G>, where: • • • • • • S is a finite state space (D is an infinite sequence (1,2, …)) A is a finite action set T: S x A x S [0, 1] is a stationary transition function C: S x A x S R is a stationary cost function (= -R: S x A x S R) G is a set of absorbing cost-free goal states Under two conditions: • There is a proper policy (reaches a goal with P= 1 from all states) – No sink states allowed.. • Every improper policy incurs a cost of ∞ from every state from which it does not reach the goal with P=1 63 [SSP slides from Mausam/Kolobov Tutorial] SSP MDP Details • In SSP, maximizing ELAU = minimizing exp. cost • Every cost-minimizing policy is proper! • Thus, an optimal policy = cheapest way to a goal 64 Not an SSP MDP Example No cost-free “loops” allowed! C(s1, a2, s1) = 7.2 a2 C(s1, a1, s2) = 1 a1 S1 S2 a1 C(s2, a1, s1) = -1 C(sG, a2, sG) = 0 C(s2, a2, sG) = 1 T(s2, a2, sG) = 0.3 a2 a2 SG C(s2, a2, s2) = -3 T(s2, a2, sG) = 0.7 a1 C(sG, a1, sG) = 0 No dead ends allowed! a1 C(s3, a1, s3) = 2.4 S3 a2 C(s3, a2, s3) = 0.8 65 SSP MDPs: Optimality Principle For an SSP MDP, let: Exp. Lin. Add. Utility – Vπ(s,t) π = Es,t[C1 + C2 + …] for all s, t For every s,t, the value of a policy is well-defined! Every policy either takes a Then: finite exp. # of steps to reach a goal, or has an infinite cost. – V* exists, π* exists, both are stationary – For all s: V*(s) = mina in A [ ∑s’ in S T(s, a, s’) [ C(s, a, s’) + V*(s’) ] ] π*(s) = argmina in A [ ∑s’ in S T(s, a, s’) [ C(s, a, s’) + V*(s’) ] ] 66 SSP and Other MDP Classes IHDR SSP FH • SSP is an “indefinite-horizon” MDP • Can compile FH by considering a new state space that is <S,T> (state at epoch) • Can compile IHDR to SSP by introducing a “goal” node and adding a probability transition from any state to goal state. 67 Algorithms for SSP • Value Iteration works without change for SSPs – (as long as they *are* SSPs—i.e., have proper policies and infinite costs for all improper ones) – Instead of Max operations, the Bellman update does min operations • Policy iteration works *iff* we start with a proper policy (otherwise, it diverges) – It is not often clear how to pick a proper policy though SSPs and A* Search • The SSP model, being based on absorbing goals and action costs, is very close to the A* search model – Identical if you have deterministic actions and start the SSP with a specific initial state – For this case, the optimal value function of SSP is the perfect heuristic for the corresponding A* search – An admissible heuristic for A* will be a “lower bound” on V* for the SSP • Start value iteration by initializing with an admissible heuristic! • ..and since SSP theoretically subsumes Finite Horizon and Infinite Horizon models, you get an effective bridge between MDPs and A* search • The bridge also allows us to “solve” MDPs using advances in deterministic planning/A* search.. Summary of MDPs • There are many MDPs, we looked at those that – aim to maximize expected cumulative reward (as against, say, average reward) – Finite horizon, Infinite Horizon and SSP MDPs • We looked at Atomic MDPs—states are atomic • We looked at exact methods for solving MDPs – Value Iteration (and improvements including asynchronous and prioritized sweeping) – Policy Iteration (and improvements including modified PI) • We looked at connections to A* search Other topics in MDPs (that we will get back to) • Approximate solutions for MDPs – E.g. Online solutions based on determinizations • Factored representations for MDPs – States in terms of state variables – Actions in terms of either Probabilistic STRIPS or Dynamic Bayes Net representations – Value and Reward functions in terms of decision diagrams Modeling Softgoal problems as deterministic MDPs • Consider the net-benefit problem, where actions have costs, and goals have utilities, and we want a plan with the highest net benefit • How do we model this as MDP? – (wrong idea): Make every state in which any subset of goals hold into a sink state with reward equal to the cumulative sum of utilities of the goals. • Problem—what if achieving g1 g2 will necessarily lead you through a state where g1 is already true? – (correct version): Make a new fluent called “done” dummy action called Done-Deal. It is applicable in any state and asserts the fluent “done”. All “done” states are sink states. Their reward is equal to sum of rewards of the individual states.