Chapter 10_Interactive Lecture Notes_completed to

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Chapter 10: The Mole
Mole: Unit used in chemistry to quantify atoms because atoms are so
tiny.
Mole = 602, 213, 670, 000, 000, 000, 000, 000 or 6. 02 X 1023
This is Avogadro’s number.
How many eggs are in 12 dozen?
12 π‘‘π‘œπ‘§π‘’π‘› π‘₯
12 𝑒𝑔𝑔𝑠
= 144 𝑒𝑔𝑔𝑠
1 π‘‘π‘œπ‘§π‘’π‘›
How many eggs are in 12 moles?
6.02 π‘₯ 1023 𝑒𝑔𝑔𝑠
12 π‘šπ‘œπ‘™π‘’π‘  π‘₯
= 7.224 π‘₯ 10 24 𝑒𝑔𝑔𝑠
1 π‘šπ‘œπ‘™π‘’
I have 246 eggs, how many dozen do I have?
246 𝑒𝑔𝑔𝑠 π‘₯
1 π‘‘π‘œπ‘§π‘’π‘›
= 20.5 π‘‘π‘œπ‘§π‘’π‘› π‘œπ‘“ 𝑒𝑔𝑔𝑠
12 𝑒𝑔𝑔𝑠
If I have 5.60 X 1023 eggs, how many moles of eggs do I have?
5.60 π‘₯ 1023 𝑒𝑔𝑔𝑠 π‘₯
1 π‘šπ‘œπ‘™π‘’
= 0.93 π‘šπ‘œπ‘™π‘’π‘ 
6. 02 π‘₯ 1023
How many representative particles are in 3.50 moles of sucrose?
(Representative particle = ANYTHING!!! Usually: Atoms, Molecules,
formula units)
Now: Work Page 323: 1-4 & Page 324: 5 & 6
1. Determine the number of atoms in 2.50 moles of Zn.
6.02 π‘₯ 1023
2.50 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ 𝑍𝑛 π‘₯
= 1.51 π‘₯ 1024 π‘Žπ‘‘π‘œπ‘šπ‘ 
1 π‘šπ‘œπ‘™π‘’
2. Calculate the number of molecules in 11.5 mol of water.
3. How many formula units of AgNO3 are in 3.25 mol of AgNO3?
4. Calculate the number of oxygen atoms in 5 mol of oxygen molecules.
Remember oxygen is diatomic.
5. How many moles contain each of the following?
a. 5.75 x 1024 atoms Al
b. 2.50 x 1020 atoms Fe
6. Identify the representative particles of each formula and convert the
given number of rep. particles to moles.
a. 3.75 x 1024 CO2
b. 3.58 x 1023 ZnCl2
10.2: Mass and the Mole
A mole always contains the same number of particles; however, moles of
different substances have different masses.
Molar mass: the mass in grams of one mole of any pure substance.
Molar mass of an element = atomic mass of that element.
Molar mass of a compound? What is it equal to? Molar mass of a
compound is equal to the mass of each of the elements in the compound.
Ex. NaCl
Na: 1 x 23= 23
Cl: 1 x 35= 35
23 + 35 = 58 grams
Ex. H2SO4
H: 2 x 1 = 2
S: 1 x 32 = 32
O: 4 x 16 = 64
2 + 32 + 64 = 98 grams
Practice: Find the molar mass:
H2O2
H: 2 X 1 = 2
O: 2 x 16 = 32
2 + 32 = 34 grams
CH3COOH
C: 2 x 12= 24
H: 4 x 1= 4
O: 2 x 16 = 32
24 + 4 + 32 = 60 grams
Ca3(PO4)2
Ca: 3 x 40 = 120
P: 2 x 31 = 62
O: 8 x 16 = 128
120 + 62 + 128 = 310 grams
AgNO3
Ag: 1 x 108 = 108
N: 1 x 14 = 14
O: 3 x 16 = 48
108 + 14 + 48 = 170 grams
C2H6O
C: 2 X 12 = 24
H: 6 x 1 = 6
O: 1 x 16 = 16
24 + 6 + 16 = 46 grams
1 dozen jelly beans = 35 grams. How much does 5 dozen weigh?
5 π‘‘π‘œπ‘§π‘’π‘› π‘₯
35 π‘”π‘Ÿπ‘Žπ‘šπ‘ 
1 π‘‘π‘œπ‘§π‘’π‘›
= 175 π‘”π‘Ÿπ‘Žπ‘šπ‘ 
How much does 3 moles of copper weigh?
3 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ 𝐢𝑒 π‘₯
64 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐢𝑒
1 π‘šπ‘œπ‘™π‘’ 𝐢𝑒
= 192 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ 𝐢𝑒
Calculate the mass in grams of 0.0450 mole Cr.
0.0450 π‘šπ‘œπ‘™π‘’ πΆπ‘Ÿ π‘₯
52 π‘”π‘Ÿπ‘Žπ‘šπ‘ 
= 2.34 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ πΆπ‘Ÿ
1 π‘šπ‘œπ‘™π‘’ πΆπ‘Ÿ
Determine the mass in grams of each of the following:
a. 3.57 mole Al
27 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐴𝑙
3.57 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ 𝐴𝑙 π‘₯
= 96.39 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐴𝑙
1 π‘šπ‘œπ‘™π‘’ 𝐴𝑙
b. 42.6 mole Si
42.6 π‘šπ‘œπ‘™π‘’π‘  𝑆𝑖 π‘₯
28 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝑆𝑖
= 1192.8 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝑆𝑖
1 π‘šπ‘œπ‘™π‘’ 𝑆𝑖
525 grams of Ca = ? moles
1 π‘šπ‘œπ‘™π‘’ πΆπ‘Ž
525 π‘”π‘Ÿπ‘Žπ‘šπ‘  πΆπ‘Ž π‘₯
= 13.125 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ πΆπ‘Ž
40 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ πΆπ‘Ž
25.5 grams of Ag = ? Moles
1 π‘šπ‘œπ‘™π‘’ 𝐴𝑔
25.5 grams of Ag x 108 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐴𝑔 = 0.236 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ 𝐴𝑔
300 grams of S = ? Moles
1 π‘šπ‘œπ‘™π‘’ 𝑆
300 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ 𝑆 π‘₯
= 9.37 π‘šπ‘œπ‘™π‘’π‘  𝑆
32 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ 𝑆
If 1 dozen jelly beans weigh 35 grams, how many jelly beans are in 280
grams of jelly beans?
280 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝑗𝑒𝑙𝑙𝑦 π‘π‘’π‘Žπ‘›π‘  π‘₯
1 π‘‘π‘œπ‘§π‘’π‘› 𝑗𝑏
35 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝑗𝑏
π‘₯
12 𝑗𝑏
1 𝑑𝑧 𝑗𝑏
=
96 𝑗𝑒𝑙𝑙𝑦 π‘π‘’π‘Žπ‘›π‘ 
How many atoms of gold are in 31.1 grams of Au?
1 π‘šπ‘œπ‘™π‘’ 𝐴𝑒
6.02 π‘₯ 1023 π‘Žπ‘‘π‘œπ‘šπ‘ 
31.1 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐴𝑒 π‘₯
π‘₯
= 9.50 π‘₯ 1022
197 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐴𝑒
1 π‘šπ‘œπ‘™π‘’ 𝐴𝑒
How many atoms are in the following:
a.
b.
c.
55.2 grams of Li
1 π‘šπ‘œπ‘™π‘’ 𝐿𝑖 6. 02 π‘₯ 1023 π‘Žπ‘‘π‘œπ‘šπ‘ 
55.2 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐿𝑖 π‘₯
π‘₯
7 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐿𝑖
1 π‘šπ‘œπ‘™π‘’ 𝐿𝑖
= 4.75 π‘₯ 1024 π‘Žπ‘‘π‘œπ‘šπ‘  π‘œπ‘“πΏπ‘–
0.230 grams of Pb
1 π‘šπ‘œπ‘™π‘’ 𝑃𝑏
6.02 π‘₯ 1023 π‘Žπ‘‘π‘œπ‘šπ‘ 
0.230 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ 𝑃𝑏 π‘₯
π‘₯
207 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝑃𝑏
1 π‘šπ‘œπ‘™π‘’ 𝑃𝑏
= 6.69 π‘₯ 1020 π‘Žπ‘‘π‘œπ‘šπ‘ 
11.5 grams of Hg
What is the mass of 6.02 π‘₯ 1024 π‘Žπ‘‘π‘œπ‘šπ‘  π‘œπ‘“ 𝐡𝑖?
1 π‘šπ‘œπ‘™π‘’π‘ 
209 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝐡𝑖
6.02 π‘₯ 10 π‘Žπ‘‘π‘œπ‘šπ‘  π‘œπ‘“ 𝐡𝑖 π‘₯
π‘₯
6.02 π‘₯ 1023 π‘Žπ‘‘π‘œπ‘šπ‘ 
1 π‘šπ‘œπ‘™π‘’π‘ 
= 2090 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ 𝐡𝑖
24
What is the mass of 1.00 x 1024 atoms of Mn?
1 π‘šπ‘œπ‘™π‘’ π‘œπ‘“ 𝑀𝑛
55 π‘”π‘Ÿπ‘Žπ‘šπ‘  𝑀𝑛
π‘₯
6.02 π‘₯ 1023 π‘Žπ‘‘π‘œπ‘šπ‘  π‘œπ‘“ 𝑀𝑛 1 π‘šπ‘œπ‘™π‘’ π‘œπ‘“ 𝑀𝑛
= 91.36 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ 𝑀𝑛
1.00π‘₯1024 π‘Žπ‘‘π‘œπ‘šπ‘  π‘œπ‘“ 𝑀𝑛 π‘₯
On separate sheet of paper:
Classwork/Homework: Page 358-359: Problem #’s 84, 86, 88, 90, 91, 92,
93, 94, 95, 99, 102, 103, 104, 108, 109, 110, 112, 113, 116, 119.
Chapter 10.3: Moles of Compounds
Representative Particles:
Elements = atoms
Ionic bonds = Compounds (metal and nonmetal) = formula units
Covalent bonds (nonmetal and nonmetal) = molecules
We find moles of compounds just like we did before, except we use
molar mass.
Answer:
How many moles of Cl- are in 2.5 moles ZnCl2?
2 π‘šπ‘œπ‘™π‘’π‘  𝐢𝑙 −
2.5 π‘šπ‘œπ‘™π‘’π‘  𝑍𝑛𝐢𝑙2 π‘₯
=5
1 π‘šπ‘œπ‘™π‘’ 𝑍𝑛𝐢𝑙2
How many moles of oxygen atoms are present in 5 moles of P2O5?
5 π‘šπ‘œπ‘™π‘’π‘  𝑃2 𝑂5 π‘₯
5 π‘šπ‘œπ‘™π‘’π‘  𝑂
1 π‘šπ‘œπ‘™π‘’π‘ƒ2 𝑂5
= 25 moles O
What is the molar mass of the following?
NaOH
Na: 1 x 23 = 23
O: 1 x 16 = 16
H: 1 x 1 = 1
HCN
H: 1 x 1 = 1
C: 1 x 12 = 12
23 + 16 + 1 = 40 grams
N: 1 x 14 = 14 1 + 12+ 14 = 27 grams
CaCl2
CCl4
What is the mass of 2.50 moles of (C3H5)2S?
C: 6 x 12 = 72
H: 10 x 1 = 10
S: 1 x 32 = 32 72+10+32 = 114 grams
2.5 π‘šπ‘œπ‘™π‘’π‘  x
114 π‘”π‘Ÿπ‘Žπ‘šπ‘ 
= 285 π‘”π‘Ÿπ‘Žπ‘šπ‘ 
1 π‘šπ‘œπ‘™π‘’
How many moles are in 325 grams of Calcium Hydroxide, Ca(OH)2?
1 π‘šπ‘œπ‘™π‘’ πΆπ‘Ž(𝑂𝐻 )2
325 π‘”π‘Ÿπ‘Žπ‘šπ‘  π‘œπ‘“ πΆπ‘Ž(𝑂𝐻)2 x
74 π‘”π‘Ÿπ‘Žπ‘šπ‘  πΆπ‘Ž(𝑂𝐻 )2
= 4.39 π‘šπ‘œπ‘™π‘’π‘  π‘œπ‘“ πΆπ‘Ž(𝑂𝐻)2
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