nuclear fusion

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Chapter 5. Thermonuclear Fusion

1.Introduction

2.Thermonuclear Reactions and Energy Production

3.Fusion in a Hot Medium

4.Progress Towards Fusion Power

5.Stellar Burning

Nuclear Fusion

The Fusion Process

Neutron proton

Two nuclei combine into one nucleus plus a nucleon is called nuclear fusion , a nuclear reaction.

The picture here illustrates the fusion of

2 D + 3 T

4 He + n that releases a lot of energy.

Fusion

Collision

Fusion

2

Penetration through a rectangular energy barrier (height B) of a particle beam, of kinetic energy E (< B), incident from the left. The form of the wave functioni, Ψ is sketched In the upper part of the figure. Inside the barrier, Ψ is an exponentially decaying function of x.

The Coulomb barrier between two hydrogen nuclei is about 200 keV

Nuclear Fusion Energy for D-T Fusion

Estimate the fusion energy for D + T

4 He + n

Estimate the fusion energy Q

The mass excess (MeV) are given below every species.

D + T  4 He + n + Q

13.136 + 14.950 = 2.425 + 8.070 + Q

Q = 17.6 MeV/fusion

This amount is 3.5 MeV/amu compared to 0.8 MeV/amu for fission.

Estimating Q is an important skill. Mass and mass excess can be used, the latter is usually given to unstable nuclides.

4

Nuclear Fusion Energy for Fusion Reactions

Common fusion reactions and their Q values

D + D

4 He + n +

23.85 MeV

H + H

D +

+ + n

+ 1.44 MeV

D + T

4 He + n + 17.6 MeV

D + 3 He

4 He + p + 18.4 MeV

D + D

3 He + n + 3.3 MeV

D + D

3 T + p + 4.0 MeV

See Interactive Plasma Physics Education

Experience : http:// ippex.pppl.gov/

Fusion 5

Effective Cross Section (mb) of Fusion Reactions

Nuclear Fusion

Cross Sections

10000

1000

D + T  4 He + n

100

D + D  3 T + p

10

D + D  3 He + n

1.

0.1

10 20 30 40

D + 3 He  4 He + p

50 60 60 keV

Cross sections data from reactions studied using particles from cyclotron

7 Li (p, n) 7 Be

3 T (p, n) 3 He

1 H (t, n) 3 He

2 D (d, n) 3 He

2 D (t, n) 4 He

3 T (d, n) 4 He

Chapter 5. Thermonuclear Fusion

1.Introduction

2.Thermonuclear Reactions and Energy Production

3.Fusion in a Hot Medium

4.Progress Towards Fusion Power

5.Stellar Burning

FUSION IN A HOT MEDIUM

Fraction

0.003

Maxwell-Boltzmann Distribution is the probability that the speed lies between v and v + dv

The kinetic energy corresponding to the most probable speed is kT

0.002

0.001

4 amu 50 K

4 amu 500 K

Kinetic energies of particles in plasma follow the Maxwell-

Boltzmann distribution

1000 2000

Speed (m/s)

At room temperature, kT is about 0.025 eV

3000

Nuclear Fusion and Plasma

D and T mixtures have to be heated to 10 million degrees. At these temperatures, the mixture is a plasma .

A plasma is a macroscopically neutral collection of charged particles.

Ions (bare nuclei) at high temperature have high kinetic energy and they approach each other within 1 fm, a distance strong force being effective to cause fusion.

Reaction rate

Consider a mixture of two gases consisting, respectively, of n l and n

2 particles per unit volume.

The probability for a particle in the first gas to react with one in the second, per unit distance travelled, is

The distance travelled per unit time is the speed v of the particle

The reaction probability per unit time is total reaction rate per unit volume is

Assume : n l particles have the same speed and that the n particles of the second gas are stationary

2

Reality: Maxwell- Boltzmann distribution

Qualitative plots showing the variation with speed of the Maxwell-Boltzmann probability distribution p(v) and the fusion reaction rate v σ(v). Their product

R(v) (shown dashed), which has a maximum at v m

, corresponding to an effective thermal energy E m

.

Is D-T reaction favourable?

Performance criteria

The plasma will radiate energy to its surroundings at a rate that depends on its temperature T. The primary mechanism for this power loss is bremsstrahlung.

Lawson criterion

A preliminary stage on the way to either the break-even or ignition points is to be able to confine a hot, reacting plasma long enough that the nuclear energy produced exceeds the energy required to create the plasma.

fusion energy output

There are n ions and n electrons in the plasma and, in equilibrium, each has to be given the same initial, average kinetic energy 3/2kT. So, the energy required to create the plasma is

Lawson criterion

D-T plasma, kT = 20 keV,

D-D plasma, kT = l00 keV

Requirements for Fusion

• High Temperatures

• Adequate Densities

• Adequate Confinement

• Lawson Criterion:

n t

>

10

20

s/m

3

4. Progress Towards Fusion Power

Magnetic Confinement

At P, the magnetic field B is uniform in the x direction and so the magnetic. force F acts vertically downwards. However, at point Q, B has a vertical component, which results in the force having a component parallel to the xaxis directing the particle towards the region of lower field

plasma particles constrained in a uniform toroidal field could circulate endlessly

Tokamak : 环形 (toroidal) 、真空室 (kamera) 、

磁 (magnit) 、线圈 (kotushka)

Inertial Confinement Fusion

( 惯性约束聚变 )

Concept

The rate of depletion of fuel atoms dn/dt = -2R

After a time t = Γ, the number remaining n( Γ) certain fraction f of the fuel be consumed in the time Γ

25

For a significant burnup of f ~ 30%, D-T at 20 keV, s n ~

26

Possible Drivers: Lasers (Best Shot)

~1000 large Optics:

192 beam lines:

Engineering challeges at NIF

Advantages:

• Well advanced technology

• Good control of energy release

Disadvantages:

Bad energy conversion

• Very expensive to build

Compare Driver to Target Sizes!

real NIF target

DT capsule

Schematic

Micro- PIXE

PS(聚苯乙烯)靶内壳材

料中掺入过渡金属元素

Br

11.6微米

Two Different Ways to Fusion

 Lawson Criterion: must be achieved

Temperature must be around T = 6 ... 15 eV

Two ways to fulfil Lawson criterion:

(1)

(2)

First solution (magnetically confined plasmas): increase confinement time

Other solution (inertial confinement fusion - ICF): increase density of fusion plasma

Many similarities, but a few decisive differences!

Chapter 5. Thermonuclear Fusion

1.Introduction

2.Thermonuclear Reactions and Energy Production

3.Fusion in a Hot Medium

4.Progress Towards Fusion Power

5.Stellar Burning

Nuclear Fusion of Protons - hydrogen cycle

The Sun derives energy from fusion of protons. There are many possibilities, but two detailed cycles were proposed.

The hydrogen cycle:

3

2

H + H  2 D (+e – ) +  + + n

D + H  3 He + 

He + 3 He  4 He + 2 H

These steps take place in the deep interior of the stars net

4 H = 4 He (+ 2e – ) + 2

 + + 2

 + 2 n + 26.7 MeV

The energy released is slowly transmitted to the star surface, from which energy is lost by way of radiation

Nuclear Fusion of Protons - carbon cycle

fusion of four hydrogen atoms to form a 4 He nuclide could be accomplished with the help of the 12 C nuclide. The 12 C undergoes a cycle of reactions:

The carbon cycle:

12 C + H  13 N + 

13 N  13 C (+ e – ) +  + + n

13 C + H  14 N + 

14 N + H  15 O + 

15 O  15 N (+ e – ) +  + + n

15 N + H  12 C + 4 He +  net

4 H = 4 He (+ 2e – ) + 2  + +4  + 2 n + 26.7 MeV

(similar to the hydrogen cycle) carbon is at both the start and the end of the cycle.

Thus, 12 C is considered a catalyst in the fusion reaction.

34

Nuclear Fusion in Stars

Nuclear fusion reactions

The hydrogen cycle

The carbon cycle

When temperatures at the center of the mass increase to

Others reactions

3 He + 4 He  7 Be 4 + 

7 Be + H  8 B 5 + 

8 B  8 Be +  +

8 Be  2 4 He +  (major)

8 Be + 4 He  12 C (minor)

10,000,000 (ten million) K,

Fusion energy causes the surface to heat up, and eventually, energy escapes from the mass as radiation the hydrogen fusion cycle begins.

Additional reactions

12 C + 4 He  16 O + 2.425 MeV

16 O + 4 He  20 Ne + 4.73 Me

4 He + 20 Ne  24 Mg + 9.31 MeV

(heat and light). When energy released from fusion equals the energy lost by radiation, the steady state is a star .

Fusion 35

Nuclear Fusion in Stars

E = mc 2

1 H, 2 D

3 T, 4 He

Stars are giant fusion reactors.

Nuclear fusion reactions provide energy in the Sun and other stars.

Solar energy drives the weather and makes plants grow.

Energy stored in plants sustains animal lives, ours included.

Fusion 36

Nuclear Fusion and the Sun

The birth of the 4.5e9 year old Sun

Sun-Earth Distance (149,597,870.7 km or 8.3 light minutes) is an

Astronomical Unit (AU).

Alpha (A+B+proxima, Centauri triple star system nearest to the sun parallax angle of 0.76-arcsec) is 4.35-4.22 light years from the

Sun.

Sun Mass is 333,000 times that of the Earth.

The sun is a big nuclear fusion reactor, 75% H and 25% He.

Sun radius (695000 km) is 109 times that of the Earth (6.4e3 km).

Sun emits 3.86

10 26 watts, ~ 8 kwatt/cm 2 , 0.14 watt/cm 2 reach the earth atmosphere ( solar constant ).

Fusion 37

The Sun

Core:

Radius = 0.25 R sun

T = 15 Million K

Density = 150 g/cc

Envelope:

Radius = R sun

5800 K

= 700,000 km T =

Density = 10 -7 g

Life of Star: tug-of-war between Gravity &

Pressure

Fusion 38

Energy – driving force of change

Change is the only constant in the universe.

Changes: winds, rains, storms, thunders, forest fires, earthquakes, waves, plant growth, food decay, ocean tides, formation and melting of ice, combustion, and growing old ... more example please.

What are physical and non-physical changes?

What causes changes?

Heat elasticity gravity electromagnetic wave

Identify changes and energy in everyday events

39

Recognizing energy

Energy plays an important part

And it’s used in all this work;

Energy , yest energy with power so great,

A kind that cannot shirk.

If the farmer had not this energy ,

He would be at a loss,

But it’s sad to think, this energy

Belongs to a little brown horse.

A school verse by Richard Feynman

Nobel laureate for physics

Photo of Feynman and Murray Gell-Men

40

Mechanical Work

Mass: m kg

Acceleration: a m s -2

Force: F = m a N (Newton = kg m s -2 )

Distance: s m

Work: W = F • s J (N m or kg m 2 s -2 )

Potential energy W p

= m g h unites?

Kinetic energy W k

= ½ m v 2 work out unites

Think and deal with quantity of energy

Energy & Nuclear Science

0.1 kg

1 N

41

Properties of PE and KE

PE and KE are state functions – depending on only the final conditions not on how the conditions were arrived (path).

Changes of PE and KE depend on only the initial and final conditions, not on the paths.

PE and KE are inter-convertible, but not destroyed.

Do you know any other properties?

Energy in amusement parks

42

Explain state functions

The Temperature Concept

Objective comparison of energy flow potentials – temperature scales.

0 th law of thermodynamics

Two bodies each equal in temperature to a third body are equal in temperature to each

other. Maxwell (19 th century)

Temperature scales led to the concept of heat

The science of heat thermodynamics.

N

12

0

F

212

98

32

-40

C

100

37

0

K

373.15

310

273.15

-40 233.15

Newton (N), Fahrenheit (F), Celsius ( C), and

Kelvin (K) temperature scales.

Energy & Nuclear Science 43

Hot, Cold and Heat

What are the differences between hot-cold temperature and heat?

Temperatures ( hot and potential for heat flow.

cold ) indicate

Heat, transfers from object to object, elusive.

When heat is transferred between objects, their temperatures change.

They are intensive properties as are color, electrical potentials, concentrations heat capacity , pressures, etc.

Heat is an time, etc.

extensive property are electric charge, length, mechanical work, mass, mole, as

Temperature scales made hot-cold measurements quantitative, but they are not quantities to be added or subtracted.

Heat is measurable in quantities, units being btu, cal, kcal, J, kJ, kwh, etc.

An amount of heat required to raise the temperature of 1.00 g of water from 288.5 to

289.5 K is defined as 1.00 calorie or 4.184 J.

Energy & Nuclear Science 44

Differentiate temperature from heat

The Concept of Heat

Heat is evidently not passive; it is an expansive fluid which dilates in consequence of the repulsion subsisting among its own particles

Joseph Black

(1728-1799)

- is a typical additive quantity

- is different from hot

- inter-convertible to mechanical work (same units)

Is heat a fluid like water?

Energy & Nuclear Science 45

The Energy Concept

Inter-conversion of Heat and Work

Inter-conversion

- discovered unexpectedly by Ben Thompson

(1753-1814) while making cannons.

Joule in his 20s

Thermometer

Conversion factor was determined by J. Joule (1818-

1889) 1 cal = 4.184 J

This entity was called effort,

living force, and travail, before the term energy was coined by Thomas Young

(1773-1829) mgh

Joules experiment demonstrated the generation of heat by mechanical means.

Energy & Nuclear Science 46

Energy

Heat and work are really energy being transferred.

Energy stored in a body is neither heat nor work.

Kinetic energies of gases are proportional to their temperature . Once absorbed, the nature of heat has changed.

Motion of gas molecules gave rise to pressure

- Daniel Bernoulli

(1700-1782)

.

Rudolf J.E. Clausius (1822-1888), James Clerk Maxwell (1831-1879), W. Thomson, and Ludwig E. Boltzmann (1844-1906), studied the relationship between temperature and energy of molecular motion. Many elegant theories have been developed as a result.

Energy & Nuclear Science 47

Forms of Energy

Other driving forces

Heat

Mechanical work

Waves (sound etc)

Electromagnetic radiation (waves)

Electrical (charge transfer)

Chemical

Mass (nuclear)

Benefit chi determination encouragement inspiration love law motivation resolution scarcity

What are the properties of energy in these forms and how to evaluate them?

Energy & Nuclear Science 48

Electric energy, E J oule potential, V V olt charge, q C oulomb

E = V q

E = hg m

1 J = 1 CV = 1 N m etc

Electric Energy

+

+

+

+

+

+

+

-

-

-

-

-

-

-

Be able to evaluate quantities of electric energy

Gravitational field

Energy & Nuclear Science 49

Simple electric energy calculations

Potential difference, V , current i ( = q / t ) and resistance R.

V = i R (Ohm’s law)

Power P , (I/o)

P = V q / t = V i ( i = current )

= R i 2 (Joules law)

Energy and power

E = P t ( unit kilo-watt-hour)

DC and AC

Electric energy, E J oule potential, V V olt charge, q C oulomb

E = V q

E = hg m

1 J = 1 CV = 1 N m etc

Energy & Nuclear Science 50

eV – a special energy unit

Electron-volt, eV, is a very special energy unit, although we have not discussed electricity and electrons yet.

Charge of an electron = 1.6022e-19 C

(one of the fundamental physical constants)

.

The energy required to increase the electric potential of an electron by 1

V is 1 eV = 1.6022e-19 J (

J = C V ) .

Other units used in nuclear energy are keV (1000 eV)

MeV (1e6 eV)

GeV (1e9 eV)

Be able to inter-convert energy quantities in various units Energy & Nuclear Science 51

What is light?

Wave properties?

Massless

Interference

Newton ring diffraction

Particle properties?

Law of reflection law of refraction move in straight line

??

Energy & Nuclear Science 52

Electromagnetic Radiation

Electromagnetic radiation is transfer of energy by EM waves via no medium(?).

EM waves travel in empty space at constant speed

(c = 2.997925e8 m/s constant

).

EM waves are characterized by wavelength  (or frequency n )

Light is part of the EM spectrum .

EM radiation has a very wide spectrum (  or n ).

Energy & Nuclear Science 53

The EM Spectrum

The EM Radiation Spectrum

Long-wave Radio

Broadcast radio band

Short wavelength radio

Infrared

VISIBLE

Ultraviolet

X-rays

Gamma rays

> 600 m

600 - 200 m

200 m - 0.1 mm

0.1 - 0.0007 mm

0.7 - 0.4 um

0.4 um - 1 nm

1 nm - 0.1 pm

0.1 nm

Remember the order of these regions

Energy & Nuclear Science 54

The EM Wave Spectrum

Energy & Nuclear Science 55

The Visible Spectrum

Double rainbow

A color pattern seen in an oil film

Energy & Nuclear Science 56

Photons,

E = h n

Max Planck assumption,

E = h n

, was shown to be true by Einstein’s photoelectric experiment.

Speed of light, c = 3e8 m s -1 wavelength,

 frequency of light, n

= c /

Planck constant, h = 6.62619e-34 J s energy of a photon E = h n

.

A photon is a bundle of energy, and it’s like a particle of light.

Use wave to show

 and n

.

Energy & Nuclear Science

Max Planck

(1858-1947)

Nobel Prize (1918)

57

I

N

T

E

N

S

I

T

Y

The Photon Story

Max Planck assumption,

E = h n

, was shown to be true by

Einstein’s photoelectric experiment.

Kinetic energy of electron

Rayleigh’s

Prediction

Experimental curve and Planck’s prediction

Wien’s Law

Frequency

Threshold

Frequency

Explain the photoelectric effect.

Energy & Nuclear Science 58

Photon Energy

Typical red light, n

= 4.69e14 s -1 (Hz),

= c / n

= 3e8 m s -1 / 4.69e14 s -1 = 640 nm

Wave number = 1 /

= 1 / 6.40e11 m

= 1.56e6 m -1

E = h n

= 6.62619e-34 J s * 4.69e14 s -1

= 3.1 x 10 -19 J (1 eV / 1.6 x 10 -19 J)

= 1.9 eV per photon find wavelength or frequency of a violet photon and carry out similar evaluations.

Energy & Nuclear Science 59

Laser

Light Amplification by Stimulated Emission of Radiation (LASER)

Spontaneous decay

Green photons Stimulated decay,

Red laser

Mirror

Partial mirror

Green pumping light

Energy & Nuclear Science

Red laser

60

4H + 2O

Chemical Energy enthalpy

1469 kJ, bond energy

2H

2

+ O

2

2H

2

O(g)373K

2H

2

O(l)373K

2H

2

O(l)273K

2H

2

O(s)273K

Understand these terms on energy or enthalpy

484 kJ, energy of reaction

81 kJ, energy of vaporization

15 kJ, heat

Bond energy energy of reaction energy related to temperature energy related to states melting, vaporization, phase transition mass loss in chemical reactions

12 kJ, energy of fusion

Energy & Nuclear Science 61

Relative and Zero Masses

Special theory of relativity (by Einstein) shows that mass m of a particle with velocity, v relates to the mass when v = 0, which is called zero mass, m o

.

m = m o v

1 - ( ) c

2 Universal speed

299,792,458 m/s

Energy & Nuclear Science 62

Mass and Energy

Einstein further showed that the relativistic mass, m, of a particle exceeds its rest mass m o

(  m = m - m o

). The increase in kinetic energy  E and increase in mass are related by:

E =  m c 2 or E = m c 2

Implication:

Mass and energy are equivalent. Mass can be expressed in energy unit and vice versa.

241800 J = 241800/ c 2

= 2.7 x 10 -12 kg = 3 ng

Energy & Nuclear Science 63

Power – rate of energy transfer

The SI unit for power P is watt named after James

Watt,

1 watt = 1 J s – 1

Power = m g v , v , pulling velocity mgh

Work out by heart

1 kilowatt-hour = __ J

= __ cal

= __ BTU

Energy & Nuclear Science 64

The law of Conservation of Energy

Energy converts among various forms without any loss or gain.

Energy cannot be created nor destroyed.

Conversions of energy in various forms have definite rates. These rates never change, and we have energy conversion factors .

1 amu = 1 /

12 th of mass of a C 12 atom

1 amu = ( 12 kg / k mol

)/12

= ( 1 kg / k mol

)/(6.022e26 (k mol) -1)

= 1.661e-27 kg = 931.5 MeV

Power = m g v , v , pulling velocity mgh

Energy & Nuclear Science 65

Some conversion factors

1 eV = 1.602 x 10 -19 J

1 eV/molecule = 23045 cal/mol

1 MeV = 1.602 x 10 -13 J

1 amu = 1.66043 x 10 -31 J

= 931.4812 MeV

1 cal = 4.184 J

1 atm L = 101.3 J

1 J = 1 coulomb-volt

1 joule = 10 7 ergs

1 BTU = 252 cal

Transmitting Energy by Sound

Sound intensity (I, watt/m 2 ), level (SIL) is

SIL (dB) = SIL o

+ 10 log (I/I o

)

At 1000 Hz, the threshold

I

SIL

0 o

= 0 dB,

= 10 -12 watt / m 2 )

When I = 1 watt / m 2

SIL = 120 dB (work out)

Comfortable hearing is between 50 and 70 dB, whereas 10 dB is a bel (after A. G. Bell, 1847-1922).

A shock wave is due to a sharp difference in pressure from (nuclear) explosions. Shock waves cause serious injuries to ears, and destroy buildings and structures.

Energy & Nuclear Science 67

Thermodynamics

Thermodynamics was derived from the Greek words therme (heat) and dynamis (force), intensely studied in the 19 th century motivated by the need to convert heat into mechanical work.

0 th law: if T of A, T

A

= T

B

, T

B

= T

C

, then T

A

= T

C

1 st law: law of conservation of energy, recognizing internal energy

E in

= q – w.

2 nd law: not possible for a machine to convert all the heat into work.

3 rd law: changes are caused be energy decrease and entropy increase.

These laws govern engineering of energy transfer.

Energy & Nuclear Science 68

Energy Resources and Utilization

What are possible energy resources?

Solar energy

Geothermal energy

Nuclear energy

???

What technologies are available to utilize these resources?

???

How efficient are some of the technologies?

???

Energy & Nuclear Science 69

Level

Energy crisis and social problems

Demand

These issues affect us all, and please apply basics and human natures to solve these problems so your generation will live happily hereafter.

Cost

Arbitrary Coordinate

Energy & Nuclear Science 70

Chung, Chieh sprott.physics.wisc.edu/lectures/plasma.ppt

Dirk O. Gericke,

1. Introduction

Advantages of Fusion

Inexhaustible Supply of

Fuel

Relatively Safe and Clean

Possibility of Direct

Conversion

The Sun

The sun flare

The corona during an eclipse

The aurora

Fusion 73

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