B-field points into page 1900-01 Studying the deflection of these rays in magnetic fields, Becquerel and the Curies establish rays to be charged particles 1900-01 Using the procedure developed by J.J. Thomson in 1887 Becquerel determined the ratio of charge q to mass m for : q/m = 1.76×1011 coulombs/kilogram identical to the electron! : q/m = 4.8×107 coulombs/kilogram 4000 times smaller! Discharge Tube Thin-walled (0.01 mm) glass tube Noting helium gas often found trapped in samples of radioactive minerals, Rutherford speculated that particles might be doubly ionized Helium atoms (He++) 1906-1909 Rutherford and T.D.Royds develop their “alpha mousetrap” to collect alpha particles and show this yields a gas with the spectral emission lines of helium! to vacuum pump & Mercury supply Radium or Radon gas Mercury Status of particle physics early 20th century Electron J.J.Thomson 1898 nucleus ( proton) Ernest Rutherford 1908-09 Henri Becquerel 1896 Ernest Rutherford 1899 g P. Villard X-rays Wilhelm Roentgen 1895 1900 Periodic Table of the Elements Fe 26 55.86 Co 27 58.93 Ni 28 58.71 Atomic “weight” values averaged over all isotopes in the proportion they naturally occur. Through lead, ~1/4 of the elements come in “single species” Isotopes are chemically identical (not separable by any chemical means) but are physically different (mass) 6 The “last” 11 naturally occurring elements (Lead Uranium) Z=82 recur in 3 principal “radioactive series.” 92 238 92U 234 Th 90 234 Pa 91 234 U 230 Th 90 226 Ra 88 92 234 92U 222 Rn 86 214 Pb 82 214 83Bi 214 Po 84 210 82Pb 210 Pb 82 210 83Bi 210 Po 84 206 82Pb “Uranium I” “Uranium II” “Radium B” “Radium G” 4.5109 years 2.5105 years 218 Po 84 U238 U234 radioactive Pb214 stable Pb206 214 82Pb Chemically separating the lead from various minerals (which suggested their origin) and comparing their masses: Thorite (thorium with traces if uranium and lead) 208 amu Pitchblende (containing uranium mineral and lead) 206 amu “ordinary” lead deposits are chiefly 207 amu Masses are given in atomic mass units (amu) based on 6C12 = 12.000000 Mass of bare hydrogen nucleus: 1.00727 amu Mass of electron: 0.000549 amu number of protons number of neutrons Starting from the defining relation of a Fourier transform: 1 ikx F (k ) f ( x)e dx 2 we can integrate this “by parts” f(x) g'(x) g(x)= i +ikx e k 1 f ( x ) g ( x ) f ' ( x ) g ( x )dx 2 1 if ( x ) ik x i ik x e f ' ( x ) e dx 2 k k f(x) is bounded oscillates in the complex plane over-all amplitude is damped at ± i 1 F (k ) k 2 1 2 f ' ( x )e f ' ( x )e ikx dx ikx dx ikF (k ) Similarly, starting from: 1 f ( x) 2 F ( k )e ikx dk 1 2 F' ( k ) e ikx dk ixf ( x ) And so, specifically for a normal distribution: f(x)=ex 2/22 d x f ( x) 2 f ( x) dx d i 1 ~ ik~x ~ f ( x) 2 F' (k )e dk dx 2 differentiating: from the relation just derived: Let’s Fourier transform THIS statement 1 i.e., apply: 2 eikxdx ikF (k ) i 2 i 2 on both sides! 1 ikx 1 ~ ~ ~ -ikx F'(k)e dk e dx 2 2 ~ ~ ~ 1 ei(k-k)x dx F' (k )dk 2 ~ (k – k) ikF (k ) i 2 ~ ~ ~ 1 ei(k-k)x dx F' (k )dk 2 ~ (k – k) ikF (k ) i F' (k ) 2 ~ selecting out k=k k rewriting as: dF ( k' ) / dk' dk' F ( k') 0 k k dk' 2 0 1 2 2 ln F ( k ) ln F (0) k 2 1 2k 2 F (k ) e 2 F (0) F (k ) F (0)e 1 2k 2 2 f ( x) e x2 / 2 2 Fourier transforms of one another F (k ) F (0)e 1 2k 2 2 Gaussian distribution about the origin Now, since: we expect: 1 ikx F (k ) f ( x ) e dx 2 i0 x e 1 1 F (0) f ( x)dx 2 1 x2 / 2 2 F (0) dx 2 e 2 f ( x) e x2 / 2 2 x Both are of the form of a Gaussian! F (k ) 2e k 1/ 1 2k 2 2 x k 1 or giving physical interpretation to the new variable x px h