Find the equivalent resistance of the entire circuit, the current that leaves the battery and the voltage drop across R1.
R1=5Ω
R2=15Ω
120V
R3=30Ω
R4=8Ω
Find the equivalent resistance of the entire circuit. Combine any resistors that you can recognize as being in either series or parallel.
R1=5Ω
R2=15Ω
120V
R3=30Ω
R4=8Ω
Find the equivalent resistance of the entire circuit. Combine any resistors that you can recognize as being in either series or parallel.
R1+2 =20Ω
120V
R3=30Ω
R4=8Ω
Find the equivalent resistance of the entire circuit. Combine any resistors that you can recognize as being in either series or 1/R=1/20+1/30=5/60
parallel.
R=12
R1+2 and 3 =12Ω
120V
R4=8Ω
Find the equivalent resistance of the entire circuit. Now use Ohm's law to find the current through or voltage dropped across each resistor.1/R=1/20+1/30=5/60
R=12
R(1+2 and 3) + 4 =20Ω
120V
Req=20Ω
Vsource=120V
so Isource=6A
Determine whether a single resistor replaced a series or parallel branch. This will determine whether each resistor would have the same current through it or same voltage drop. Then find the other quantity using Ohm's Law.
1/R=1/20+1/30=5/60
R=12
R1+2 and 3 =12Ω
120V
R4=8Ω
Determine whether a single resistor replaced a series or parallel branch. This will determine whether each resistor would have the same current through it or same voltage drop. Then find the other quantity using Ohm's Law.
R1+2 =20Ω
120V
R3=30Ω
R4=8Ω
Determine whether a single resistor replaced a series or `
parallel branch. This will determine whether each resistor would have the same current through it or same voltage drop. Then find the other quantity using Ohm's Law.
R1=5Ω
R2=15Ω
120V
R3=30Ω
R4=8Ω