Physics 12 Review – Chapter 1 – Vectors This chapter deals with

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Physics 12 Review – Chapter 1 – Vectors
This chapter deals with:
Vectors (adding, subtracting, resolving),
Projectiles, Ramps, Tension and Pulleys,
Free body diagrams
200 N
30o
18 kg
12 kg
µ = 0.400
1.
Draw a labeled free body diagram for block #1
2.
Determine the acceleration of the entire system
3.
Determine the amount of tension on the rope connecting the two blocks.
vi = 0.50 m/s [down]
8.0 m
µ = 0.400
A 2.0 kg brick slides down the roof
of a house with an initial velocity of
0.50 m/s. The length of the roof
is 8.0 m.
30o
4.0 m
4.
Draw a labeled free body diagram for the brick sliding on the roof
5.
Determine the acceleration of the brick on the roof.
6.
Determine the final speed of the brick on the roof
7.
The brick slides off of the roof at the same angle as the roof line.
Find the components of the initial velocity for the projectile motion.
8.
Determine the time of flight.
9.
Determine the range of the brick (horizontal distance)
10.
Determine the velocity of the brick at impact.
11.
Determine the acceleration of the system below.
70o
All masses are 8.0 kg.
35o
µ=0.10
Physics 12 Review – Chapter 2 – Circular Motion / Gravity
Uniform circular Motion – The Object
.
Magnitude of the
Velocity
constant
The object’s Speed
Velocity
constant
changing
changing
Acceleration
constant
Magnitude of the
Acceleration
constant
changing
changing
changing
constant
The direction of the acceleration is
.
1.
Using a string that will break if the tension exceeds 48 N, a 3.0 kg mass is spun in a horizontal
circle with radius 70 cm at every increasing speeds. At what speed will the string break?
2.
A 40 kg child stands on a merry-go-round that is rotating with a period of 3.0 seconds. If µs=0.64,
what is the farthest they can stand from the centre without slipping?
3.
A 6.1 kg object on the end of a massless connecting rod moves in uniform circular motion
in a vertical circle with radius 1.2 m. The period of revolution is 0.80 s.
Calculate the tension at the bottom of its path
4.
What is the normal force from the seat of a rollercoaster on a 50 kg rider at the top of a vertical
loop that has a diameter of 12 m if the coaster is traveling at 15 m/s?
5.
Draw the free body diagram from the man in the amusement park ride shown below
6.
A small toy airplane suspended as shown below flies in a circular path.
Which of the following free body diagrams best describes the forces acting on the airplane at
the position shown?
The airplane has a mass of 1.8 kg.
The string has a length of 2.5m and the tension in the string is 23 N.
Determine the speed of the airplane.
Gravity Forces and Gravitational Field Strength
Force Between any two masses:
For the Earth,
F=
g=
Orbits
7.
Oberon is a moon of the planet Uranus. It
has an orbital radius of 5.83 × 108 m and an orbital
period of 1.16 × 106 s. What is the mass of Uranus?
8.
A satellite travels around a planet at 9000
m/s with an orbital radius of 7.4 × 106 m. What
would be the speed of a satellite with twice the
mass orbiting at one half this radius?
Kepler’s Laws
1. Planets orbit in ellipses
2. Equal Time = Equal Area Arcs
3.
T 2 4π 2
=
r 3 GM
Physics 12 Review – Chapter 3 – Momentum/Energy
This chapter deals with:
Collisions (2D) & Momentum
Conservation of Energy,
Impulse
Examine the question
Forces , Distances
Forces, Times
Single Objects changing height and speed
subject to applied and frictional forces
Collisions & Explosions with 2 or more objects
The MAIN Equation:
The MAIN Equation:
pi
mgh + 12 mv 2 + Fa d = mgh + 12 mv 2 + F f d
=
pf
IS this a 2-Dimensional problem???
If so, you must use either,
Fa d =
a) Components:
Ff d =
Is the object every going higher than mountains?
mgh + 12 mv 2 + Fa d = mgh + 12 mv 2 + F f d
or b) Vectors: (use a
)
Fa (N)
Impulse = shoving an object
d (m)
Ff (N)
Fa (N)
d (m)
W E Fd
Power: P =
= =
= Fv
t
t
t
t (s)
v
Height of orbit = h = 1000 m
Mass of Winnebago = m = 6000 kg
Radius of Asteroid = R = 4000 m
Mass of Asteroid = M = 2.0 ×1015 kg
Orbital Radius?
Force of Gravity in Orbit?
Potential Energy on the Surface?
Velocity while in Orbit?
Potential Energy in Orbit?
Kinetic Energy in Orbit?
Total Energy in Orbit?
Acceleration of Gravity at the
Asteroid’s Surface?
1.
How much work is required to lift the Winnebago from the surface to a place infinitely far from
the Asteroid?
mgh + 12 mv 2 + Fa d = mgh + 12 mv 2 + F f d
Fg (N)
r (m)
2.
How much work is required to lift the Winnebago to an altitude of 1000 m above the surface?
mgh + 12 mv 2 + Fa d = mgh + 12 mv 2 + F f d
Fg (N)
r (m)
3.
During a crash landing, the Winnebago descends vertically downward from an altitude of 1000 m.
Small retro rockets fire in an attempt to slow the decsent. The initial downward speed of the
Winnebago is 14 m/s and it strikes the asteroid at a speed of 4.0 m/s.
Determine the average force from the rockets.
mgh + 12 mv 2 + Fa d = mgh + 12 mv 2 + F f d
4.
A cyclist travelling at 10 m/s applies her brakes and stops in 25 m. The graph shows the
magnitude of the braking force versus the distance travelled. What is the total mass of bike and
cyclist?
a)
20 kg
b)
40 kg
c)
64 kg
d)
80 kg
This question is about:
Work/Energy or
Momentum/Impulse?
This question is about:
Work/Energy or
Momentum/Impulse?
5.
6.
This question is about:
7.
Work/Energy or
Momentum/Impulse?
A 5.0 kg object travelling at 1.6 m/s collides with an object of unknown mass m2 that is travelling
at 2.5 m/s. The two objects stick together and move towards the right as shown in the diagram.
Find the mass of object m2
This question is about:
Work/Energy or
Momentum/Impulse?
8.
A 2000 kg car traveling WEST at 5.0 m/s collides and sticks with a 3000 kg van traveling
SOUTH at 8.0 m/s. Determine the velocity of the entangled vehicles after the collision.
This question is about:
9.
Work/Energy or
Momentum/Impulse?
Determine the amount, if any, of heat that is released during the collision.
This question is about:
Work/Energy or
Momentum/Impulse?
Physics 12 Review – Chapter 4 – Equilibrium
This chapter deals with:
Balanced Forces:
Balanced Torques:
(Translational Equilibrium)
(Rotational Equilibrium)
Examine the question
Knots
Sticks
Equations:
Equations:
Techniques:
Techniques:
This question is about:
Sticks (Pivot Location)
or
Knots (Components/Triangle)
2.
3.
4.
5.
6.
Physics 12 Review – Question 5 - Chapter 5 – Electrostatics
This chapter deals with:
Forces & Fields:
Parallel Plates:
Energy and Voltage(Potential)
(Newtons)
(Fields and Voltages together)
(Joules)
Examine the question
Forces and Fields:
(Vector – use your head)
F =q E
F=
1.
kQq
r2
E=
Parallel Plates:
(Vector – use your head)
Energy and Voltage:
(Scalar – trust the math)
V
d
Ep = q V
E=
kQ
r2
Electric Field is uniform
Forces from the Field are uniform
Ep =
kQq
r
V=
kQ
r
An electron is accelerated from rest using parallel plates that have a potential difference of 840 V.
a)
Determine the final velocity of the electron
b)
If the acceleration of the electron is 3.513x1015 m/s2, determine the separation distance
2.
For the charge arrangement below,
Q1 = +3.5x10-6 C
1.4 m
A
Q2 = -2.4x10-6 C
B
1.6 m
1.4 m
a)
Determine the potential difference between locations A and B
b)
How much work is required to move an electron from location A to location B?
c)
If a proton was released from location A with a velocity of 2.3x102 m/s, what is its velocity at
location B?
3.
For the location below,
6.0 m
+
X
Q1 = +2.0x10-6 C
6.0 m
- Q2
An electron at location X experiences a total electric field of 625 N/C
a)
Determine the size of the negative charge Q2.
b)
Determine the size and direction of the total force on the electron at location “X”.
4.
An electron orbits a single proton in a Hydrogen atom.
The radius of the circular orbit is 5.3 × 10−11 m.
a)
Determine the speed of the electron in its orbit.
+
b)
Determine the Kinetic, Potential and Total Energy for the electron as it orbits.
5.
Some similarities and differences of the forces cause by Electric (E) and Magnetic (B) fields
Similarities –
Differences-
Physics 12 Review – Chapter 6 – Electric Circuits
Physics 12 Review – Question 7 - Chapter 7 –Electromagnetism
Review of What We Have Seen So Far:
A) Magnetic Fields lines
B) Magnetic Fields from STEADY currents
1) Straight Wires
2)
Solenoids
B=
µo I
2π r
B = µo
C) Forces on Moving Charges and Currents
2)
1) Force on a Charge
moving in a B field
→
→
F = q v×B
D)
Creating Voltages
2)
Changing Flux in a Coil
ε = − N ∆∆φt
5)
Motors and Back Emf
N
I = µo n I
L
Force on Currents
in B fields
→
→
F = L I ×B
3) Wires cutting across B
ε =B Lv
6) Transformers
Physics 12 Review – Graphing Questions
y = mi x + b
Example #1 “The Kinetic Energy of a small bike was determined at various velocities and the following
data was recorded”
v2
v (m/s)
Ek (J)
1.4
15.7
1.6
20.5
1.8
26.0
Ek
20
10
1
2
3
v2
4
Example #2 “An unknown charge q2 is placed at various distances from a known charge
of q1= 2.33 × 10−3 C and the force between the two charges was measured and recorded”
r (m)
Fe (N)
0.6
117
0.8
66
0.9
52
Label the horizontal axis with a “function of r” that will yield a straight line graph and then calculate this
function of r in the table above to plot the graph.
Fe
120
80
40
1
Determine the slope of the graph
2
3
Determine the size of the charge q2
Example #3 “Various sizes of applied forces are applied to a 10 kg block of wood sitting on a rough
floor and the resulting acceleration is recorded in each case”
Fa (N)
a (m/s2)
35
1.54
55
3.54
65
4.54
10
Plot the acceleration as a function of the applied force.
a
4
2
Fa
10 20 30 40 50 60 70
−2
Determine the slope of the graph
Determine the coefficient of friction
Example #4 “A spring scale holds up a conducting bar in a magnetic field. The resulting measurements
from the spring scale and the current in the bar are recorded below”
I (A)
Fs (N)
1.5
1.54
2.5
3.54
3.5
4.54
Plot the Spring Scale force as a function of the applied current
Fs
6
4
2
I
1
Determine the magnetic field strength
2
3
4
Determine the weight of the bar
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