Oscillations: Review (Chapter 12) Oscillations: motions that are periodic in time (i.e. repetitive) o Swingingobject(pendulum) o Vibratingobject(spring,guitarstring,etc.) o Partofmedium(i.e.string,water)aswavepassesby Oscillation requires o Restoringforce(pushes“system”backtowardequilibrium) o Inertia(keeps“system”goingpastequilibrium) Oscillator example: Mass on a Spring: o Restoringforcefromspring.Varieswith“extension” Hooke’sLaw: Fx kx (linearrestoringforce) Ifmassmdisplacedfromequilibriumthenreleased→willoscillate Ifforceislinearandrestoring(andthusconservative) o Motionissimpleharmonicmotion(SHM) o Systemisasimpleharmonicoscillator(SHO) Acceleration in SHM: not constant → depends on x Newton’s2ndlawsays Fx ma x k a x o ForSHM,implies kx ma x sothat x m k a A v 0 Atmax.positivedisplacementfromequil. x A have x m and x Atequilibrium x 0 have ax 0 and v x vmax k a A v 0 Atmax.negativedisplacementfromequil. x A have x m and x How do we find an expression for x(t) in SHM? First:findanequationforwhichx(t)isthesolution. dx dv x d 2 x Remember: v x dt and a x dt dt 2 k a x Butformassonspring: x m d 2x k x Thisisadifferentialequation. Soformassonspring: dt 2 m d 2x k 2 2 x Moregeneralform: dt 2 Soidentify m formass/spring Functionx(t)thatsatisfiesequation: o OscillateslikeparticledoingSHM→moregeneralthanspringcase o Whatis ? d 2x 2 How do we solve dt 2 x to get x(t)? Tosolvedifferentialequation→guesssolutionthentest! d 2 cos d 2 sin Noticethat: d 2 cos and d 2 sin Sotry: xt A cos t o Important:argument t mustbeinradians o Constants A , ,and mustbefoundfromdetailsofmotion Test xt A cos t : dx dt v x A sin t d 2x 2 2 a A cos t x x dt 2 d 2x 2 So: xt A cos t satisfies dt 2 x Important! d 2x 2 x mustbesatisfiedbyanySHM(i.e. xt A cos t ) 2 dt Foramassonaspring(oneexampleofSHM) k a x o x m k o m (Naturalangularfrequencyforspring/masssystem) ForotherexamplesofSHM, dependsonspecificformofrestoringforceand inertia isnaturalangularfrequencyofSHO.Unitsareradians/second(reallys‐1) Parameters that describe SHM: xt A cos t t isthephaseinradians. Period(T): o Motionat t T isthesameasmotionat t o Meansthatphaseincreasesby 2 intimeT o So t T t 2 2 T o Result: Frequency: o (angularfrequency)isnumberofradiansbywhichphaseincreases persecond 1 f o T 2 (frequency)isnumberoftimespersecondthatmotion repeats unitsarecycles/secondorHertz(Hz) o so 2 f Phaseconstant o Dependsonwheremotionisincycleatt=0.i.e. x0 A cos Amplitude(A) o xt oscillatesbetween+Aand–A Relations between Position, Velocity, and Acceleration in SHM xt A cos t xA dx A sin t dt (slope of x vs t ), vx Aω vx t d 2x a x t 2 A 2 cos t dt (slope of vx vs t ), a x Aω 2 How do we get parameters , , and A from description of specific motion? Angularfrequency dependsonpropertiesofoscillator o i.e.forspring/masssystem, k / m GetAmplitudeandphaseconstantfromxandvatspecifictime(i.e.t=0) o Ex.:massm,springk.Startclock(sett=0)whenmassatarbitrary xi So x0 xi A cos and v0 vi A sin SolveforA(usetrigonometryidentity): xi2 vi2 2 2 sin cos A 2 A 2 2 1 gives: A x 2 i vi2 2 Solveforphaseconstant: vi sin tan cos xi Check for two simple cases: o If vi 0 ,motionstartsfromrestatmaximumorminimumdisplacement A xi2 xi and tan 0 sothat 0 o If xi 0 ,motionstartsfromequilibriumwithmaximumspeed A vi2 2 1 and tan So x cos t 2 2 vi2 2 EXAMPLES (to finish yourself if not completed on board): Chapter 12, Problem 14: A piston oscillates in an engine with position x 5.00 cm cos2t / 6 . At t 0 s , find (a) position, (b) velocity, and (c) acceleration. (d) Find the period and Amplitude of the motion. Chapter 12, Problem 9: A particle’s motion along the x axis is SHM. It starts from equilibrium at t 0 s and moves to the right. Amplitude is 2.00 cm and frequency is 1.50 Hz. (a) Find an expression for xt . (b) Find the maximum speed and earliest time t 0 at which particle has this speed. (c) Find the maximum acceleration and earliest time t 0 at which particle has this acceleration. Energy and SHM Mechanicalenergy(E=K+U)conservedifnonon‐conservativeforces o ForSHM,alternatesbetweenkineticenergyandpotentialenergy 2 Example:formassmonspringksothat k / m o x A cos t and v A sin t 1 2 1 2 2 K mv kA sin t o KineticEnergy: 2 2 1 2 1 2 2 t U kx kA cos o PotentialEnergy: 2 2 1 2 1 2 2 2 E K U kA sin t cos t kA o MechanicalEnergy: 2 2 1 2 E kA o SototalmechanicalenergyonlydependsonkandA: 2 o From E K U ,alsoget: 1 2 1 2 1 2 2 kA 2 kx 2 mv k 2 2 2 2 v A x A x Givesmassspeedasfunctionofx: m