Circular Motion Ranker PHYSICS TEST CIRCULAR MOTION 1. A wheel of perimeter 220 cm rolls on a level road at a speed of 9 km/h. How many revolutions does the wheel make per second? A) 3 rev 7 s B) 3 rev 11 s C) 25 rev 22 s D) None of these 2. A solid cylinder is released from rest from the top of an incline of inclination and length l . If the cylinder rolls without slipping, what will be its speed when it reaches the bottom? 4 2 5 gl sin gl sin gl sin A) gl sin B) C) D) 3 3 2 3. A force F acts tangentially at the highest point of a solid sphere of mass m kept on a rough horizontal plane. If the sphere rolls without slipping, find the acceleration of the centre of the sphere. A) 4. 10 F 7 m B) F/3 C) 3F 2m D) 5F 7m A sphere of mass M and radius r shown in figure slips on a rough horizontal plane. At some instant it has translational velocity v0 and rotational velocity about the centre v0 . 2r Find the translational velocity after the sphere starts pure rolling. w= v0 2r r v0 A f A) 5. 3v0 5 B) 2v0 5 C) v0 D) 6 v0 7 A solid sphere, a hollow sphere and a disc, all having same mass and radius , are placed at the top of a smooth incline and released . Least time will be taken in reaching the bottom by A) the solid sphere B) the hollow sphere C) the disc D) all will take same time Page 1 Circular Motion 6. Ranker Solid sphere, a hollow sphere and a disc, all having same mass and radius, are placed at the top of an incline and released. The friction coefficients between the objects and the incline are same and not sufficient to allow pure rolling. Least time will be taken in reaching the bottom by, 7. A) the solid sphere B) the hollow sphere C) the disc D) all will take same time In the previous question the smallest kinetic energy at the bottom of the incline will be achieved by 8. 9. A) the solid sphere B) the hollow sphere C) the disc D) all will achieve same kinetic energy. A cylinder rolls on a horizontal plane surface. If the speed of the centre is 25 m/s, what is the speed of the highest point? A) 50m/s B) 100m/s C) 150m/s D) 200m/s A sphere of mass m rolls on a plane surface. Find its kinetic energy at an instant when its centre moves with speed v . A) 10. 7 2 mv 5 7 2 mv 2 C) 7 mv 2 10 D) 7 2 mv 6 A string is wrapped over the edge of a uniform disc and the free end is fixed with the ceiling. The disc moves down, unwinding the string. Find the down ward acceleration of the disc. A) g/2 11. B) B) 2g 3 C) g/3 D) g/4 A small spherical ball is released from a point at a height h on a rough track shown in figure. Assuming that it does not slip anywhere find its linear speed when it rolls on the horizontal part of the track? h 10g h 3 gh B) gh C) D) None of these 7 5 A small disc is set rolling with a speed v on the horizontal part of the track of the previous problem from right to left. To what height will it climb up the curved part? v2 3v 2 v2 3v 2 A) B) C) D) 2g 2g g 4g A sphere starts rolling down an incline of inclination . Find the speed of its centre when it has covered a distance l . 10g 2 l sin gl cos A) gl sin B) gl cos C) D) 7 7 A) 12. 13. Page 2 Circular Motion 14. Ranker Figure shows a rough track, a portion of which is in the form of a cylinder of radius R. with what minimum linear speed should a sphere of radius r set rolling on the horizontal part so that it completely goes round the circle on the cylindrical part. R 15. 16. 17. 18. 19. 20. 21. 27 g R r 7 10 g R r 7 A thin spherical shell of radius R lying on a rough horizontal surface is hit sharply and horizontally by a cue. Where should it be hit so that the shell does not slip on the surface? R 2R A) Below the centre B) above the centre 2 3 2R C) Below the centre D) None 3 A thin spherically shell lying on a rough horizontal surface is hit by a cue in such a way that the line of action passes through the centre of the shell. As a result, the shell starts moving with a linear speed v without any initial angular velocity. Find the linear speed after it starts pure rolling on the surface. 3v 3v A) B) v / 2 C) v / 5 D) 5 4 A hollow sphere of radius R lies on smooth horizontal surface. It is pulled by horizontal force acting tangentially from the highest point. Find the distance traveled by the sphere during the time it makes one full rotation. R 4 R A) 2 R B) C) D) R 2 3 A solid sphere of mass 0.50kg is kept on a horizontal surface. The coefficient of static friction between the surfaces in contact is 2/7. What maximum force can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface? (Take g 10m / s 2 ) A) 1.1N B) 2.2N C) 3.3N D) 4.4N A small block slides down from the top of a hemisphere of radius r. It is assumed that there is no friction between the block and hemisphere. At what height h, will the block loose contact with the surface of the sphere. r 2r r r A) B) C) D) 3 3 2 4 Two particles P and Q are located at distance rP and rQ respectively from the centre of rotating disc such that rP > rQ A) Both P and Q have the same acceleration B) Both P and Q do not have the same acceleration C) P has greater acceleration than Q D) Q has greater acceleration than P A) B) g R r C) g R r D) A bucket filled with water is revolved in a vertical circle of radius 4m. If g 10 ms -2, the time period of revolution will be nearest to A) 4 s B) 5 s C) 8 s D) 10 s Page 3 Circular Motion 22. 23. 24. 25. 26. Ranker A body of mass ‘m’ is moving in a circle of radius ‘r’ with a constant speed ‘v’. The work done by the centripetal force in moving the body over half the circumference of the circle is A) mv2 r B) zero C) mv2/r D) r2/mv2 A particle of mass m is describing a circular path of radius r with uniform speed. If L is the angular momentum of the particle about the axis of the circle, the kinetic energy of the particle is given by: A) L2/mr2 B) L2/2mr2 C) 2L2/mr2 D) mr2L Two particles of equal masses are revolving in circular paths of radii r1 and r2 respectively with the same period. The ratio of their centripetal force is: r2 / r1 A) r1/r2 B) C) (r1/r2)2 D) (r2/r1)2 A vehicle is moving with a velocity v on a curved road of width b and radius of curvature R. For counteracting the centrifugal force on the vehicle, the difference in elevation required in between the outer and inner edges of the road is: v 2b vb 2 vb vb A) B) C) D) 2 Rg Rg Rg Rg A simple pendulum of length L and mass (bob) M is oscillating in a plane about a vertical line between angular limits and . For an angular displacement where | | | | the tension T in the string and the velocity V of the bob are related as under in the above conditions: MV 2 B) T Mg cos L A) T cos =Mg 27. 28. C) T =Mg cos D) none of these An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 rpm, the acceleration of point on the tip of the blade is about: A) 16000 ms-2 B) 4740 ms-2 C) 2370 ms-2 D) 5055 ms-2 A motor car of mass m travels with a uniform speed v on a convex bridge of radius r. When the car is at the middle point of the bridge, then the force exerted by the car on the bridge is A) mg 29. 30. B) mg mv2 r C) mg mv2 r D) mg mv2 r A simple pendulum consists of light string from which a spherical bob of mass M is suspended. The distance between the point of suspension and centre of the bob is l. The bob is given a tangential velocity v at the equilibrium position (i.e at the lowest point). What can be maximum value of velocity v, so that the pendulum oscillates without the string becoming slack? A) gl B) 2gl C) 4gl D) 5gl A weightless thread can support tension up to 30 N. A stone of mass 0.5 kg is tied to it and is revolved in a circular path of radius 2m in a vertical plane. If g=10ms-2, then the maximum angular velocity of the stone will be: A) 5 rad/s B) 30 rad/s C) 60 rad/s D) 10 rad/s Page 4 Circular Motion Ranker KEY 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. C B A D D D B A C B A D C A B A C C B C A B B A A B B C B A Page 5 Circular Motion Ranker SOLUTIONS 1. C 2. B v r KE = and 3. 1 2 1 2 3 2 mv I mv 2 2 4 3 2 mv mgl sin 4 A F f ma (Pseudo) for translational and 2 2 Fr fr I mr 2 ma 5 r 5 10 F Solving a 7 m 4. D Initial angular momentum L Lcm Mrvo 6 Mrvo 5 Also , the angular momentum about A Lcm Mrv 7 2 v Mr 2 Mrv Mrv 5 5 r 6 7 Mrvo Mrv 5 5 6 v vo 7 5. 6. 7. D Since the surface is smooth, only sliding takes place. Hence all reaches simultaneously D In sufficient friction cannot constitute rolling Hence all reaches simultaneously B We have 8. 2 1 2 Mr 2 Mr 2 Mr 2 I solid I disc I Hollow 5 2 3 Hollow sphere haves maximum moment of inertia , for same A VH 2Vc 2 25 50m / s 9. C 1 1 7 KE mv 2 I 2 mv 2 2 2 10 10. B 1 mar I mr 2 .......1 2 2 r 2g ma mg a 3 Page 6 Circular Motion Ranker ma . mg 11. A 1 2 1 2 2 mv I where I mr 2 2 2 5 10 v gh 7 mgh 12. D 1 2 1 2 using mgh mv 2 I 2 13. 3v2 h 4g C k2 2 r2 5 g sin 5 g sin a k2 7 1 2 R 10 gr sin Now v 7 for sphere h v 14. A mv 2 mg v 2 R r g............1 Rr 12 1 1 1 Also mr 2 2 mu 2 mg 2 R 2r mv2 I 2 25 2 2 2 7 mg 2 R r mg R r 10 27 R 27r 71 mu 2 mg 5 2 10 u 15. 27 g R r 7 B from law of conservation of angular momentum mvh I mvh h 2 mR2 3 2 R 3 Page 7 Circular Motion Ranker F .h R 16. A 2 2 R from conservation of angular momentum 3 2 2 5 vR VR R R VR VR vR 3 3 3 5 3 vR VR V v 3 5 mvR mVR 17. C 2 3F 1 MR 2 and ot t 2 given 3 2 MR 2 1 3F 2 F 2 8MR 2 and ac t t 2 2 MR 3F M 1 4 R S ac t 2 gives S 2 3 F R M I 18. C f mg . 2 F R f R I R mg MR 2 ......1 5 2 F mg ma 5 mg F a .........2 M 15 & 2 F = 3.3 N 19. B velocity at point s is v [2 g (r h)] centripetal acceleration = 1 2 v2 g cos r 2 g (r h) h 2r g h r r 3 20. C aR ( 2 )2 (r )2 r 4 2 21. same for both P & Q ap > aQ (as rp > rQ) A gR 2 10 T 22. & 2 R 4s v B Page 8 Circular Motion 23. Ranker In circular motion, centripetal force acting on the body is always r to the velocity vector. B L= mvr 24. L 1 , K mv 2 L2 / 2mr 2 mr 2 A T1 T2 2 r1 2 r2 V r or 1 1 v1 v1 V2 r2 F1 mv12 r2 F2 r1 mv22 2 F V r r2 r r 1 1 2 12 2 1 F2 V2 r1 r2 r1 r2 25. A v2 Rg x Sin b tan x b 2 x v v 2b or x b Rg Rg sin tan 26. B Mv 2 T-Mg cos = L 27. B 28. centripetal acceleration = w2 R = C 2 f 2 R 4740 m / s 2 mv 2 Mg –f = r F=mg29. mv 2 r B 1 Mgl Mv 2 V 2 gl 2 30. A Page 9 Circular Motion Ranker T max m r 2 g 30 0.5 2 w 2 10 w 5 rad / sec. Page 10