Other Lindenthal Projects Smithfield Bridge, Pittsburgh 1882 Smithfield Royal Albert Bridge at Saltash 1859 Balance of Forces in Equilibrium Isambard Kingdom Brunel, Engineer Brunel Saltash Balance of Forces in Equilibrium Statics:Hibbeler PULLEYS, FRAMES, AND MACHINES Compute the forces in pulleys, ropes, beam, and frame members that require multiple free-body diagrams. Compute the reactions for compound beams, frames, or similar devices. Show why it is advantageous to: Separate elements at pins and draw multiple FBDs & identify 2-force members 1 Pulley Systems Pulley Systems – Mechanical Advantage T W Free Body Diagrams of Pulley System Pulley Systems – Mechanical Advantage Reaction FBD Top T T T T T FBD A W W Pulley Systems – Other Cuts and FBDs Pulley Systems – Other Cuts and FBDs FBD Fbar FBD Fbar b T T T T T W Statics:Hibbeler W W 2 Pulleys – Method of Joints Approach Pulleys – Method of Joints Approach Pulleys – Method of Joints Approach Cy FBD 2 Ay Pulleys – Method of Sections Approach 10 lb P R R R P R P FBD 3 10 lb 10 lb P FBD 1 100 lb Pulleys – Method of Sections Approach R R P 10 lb 10 lb 100 lb Statics:Hibbeler 3 QUICK PROBLEM SOLVING Given: A frame and loads as shown. Find: The reactions that the pins exert on the frame at A, B, and C. Plan: a) Draw a FBD of members AB and BC. b) Apply the equations of equilibrium to each FBD to solve for the six unknowns. QUICK PROBLEM SOLVING (continued) FBDs of members AB and BC: QUICK PROBLEM SOLVING (continued) FBDs of members AB and BC: BY B 1000N AX BX BX BY BY B B 1000N 0.4m C 0.2m 0.2m 0.2m 0.4m CY Summing moments about A and C on each member, we get: + MA = BX (0.4) + BY (0.4) – 1000 (0.2) = 0 + MC = -BX (0.4) + BY (0.6) + 500 (0.4) = 0 BY = 0 and BX = 500 N BY BX B 0.4m 500N C A X A 45º 500N A 45º AY BX 0.2m 0.2m For FBD AB: 0.2m AY + FX = AX – 500 = 0 ; AX = + FY = AY – 1000 = 0 ; AY = 1,000 N 0.4m CY 500 N For FBD of BC: + FX = 500 – CX = 0 ; CX = 500 N + FY = CY – 500 = 0 ; CY = 500 N WORKING EXAMPLE Given: The wall crane supports an external load of 700 lb. Find: The force in the cable at the winch motor W and the horizontal and vertical components of the pin reactions at A, B, C, and D. Plan: a) Draw FBDs of the frame’s members and pulleys. b) Apply the equations of equilibrium and solve for the unknowns. Statics:Hibbeler 4 EXAMPLE (continued) 350 lb FBD of the Pulley E CX T T 350 lb FBD of pulley C E 700 lb 350 lb Equations of Equilibrium: BY +↑ Fy = 2 T – 700 lb = 0 30° 350 lb T = 350 lb TBD A AY 45° 4 ft BX +Fx = Cx – 350 = 0 lb Cx = 350 +↑ Fy = Cy – 350 = 0 Cy = 350 lb +FX = – Bx + 350 – 350 sin 30° = 0 Bx = 175 lb B +↑ Fy = By – 350 cos 30° = 0 FBD of pulley B By = 303.1 lb EXAMPLE (continued) Note that member BD is a two-force member AX C CY A FBD of member BD 350 lb B 175 lb 303.11 lb 4 ft 2409 lb D 700 lb FBD of member ABC 45 ° +MA = TBD sin 45° (4 ft) – 303.1 (4 ft) – 700 (8 ft) = 0 TBD = 2409 lb +FY = AY + 2409 sin 45° – 303.1 – 700 = 0 At D, the x and y component are AY = – 700 lb +FX = AX – 2409 cos 45° + 175 – 350 = 0 + DX = –2409 cos 45° = –1700 lb B 2409 lb + DY = 2409 sin 45° = 1700 lb AX = 1880 lb Why are trusses like donuts? Analysis of Machines Donuts are not good in compression either After the 5th one you feel kinda sick Both = fun! You can’t drive to school without them If they fall to the ground they are not any good anymore Statics:Hibbeler 5 Pliers, Cutters, and Grips APPLICATIONS Frames are commonly used to support external loads. Find vertical clamping force at E Find all reaction forces and forces at pinned connections in press How is a frame different than a t truss? ? How can you determine the forces at the joints and supports of a frame? Statics:Hibbeler 6 Elevation View of Cairo Bridge (Source: S. Nam, University of Illinois) View of Finite Element Model Acc. (g) 2D Schematic of Cairo Bridge 1 0.5 0 -0.5 -1 0 10 20 30 40 Time (sec) (Source: S. Nam, University of Illinois) Statics:Hibbeler 7 Animation of Bridge Deflection Graph of Maximum Deflection Vertical Displacem ent 10 8 6 4 2 0 0 500 1000 1500 2000 2500 3000 3500 4000 bridge cood. (ft) (Source: S. Nam, University of Illinois) BACK TEDA Stadium Tianjin, China Statics:Hibbeler 8