Algebra 1A Practice Benchmark
1. Simplify the expression: 6  6  4  3  1 [A] -1
[B] 12
[C] 25
[D] –6
2. Evaluate x² – 4x – 7 when x = –5.
[A] 6
[B] –14
[C] -56
[D] 38
3. Simplify the expression: –10 – 14
[A] 24
[B] –24
[C] –4
[D] 4
4. In which quadrant is the point (7, –2) located?
[A] I
[B] II
[C] III
[D] IV
5. Which property is illustrated by the statement 2 + (3 + 4) = (2 + 3) + 4?
[A] Commutative Property
[B] Associative Property
[C] Distributive Property
[D] Identity Property
6. Simplify using the distributive property. 3(5x – 4y)
[B] 15x – 4y
[A] 15x + 12y
7. Simplify. –4n – 7n + 3
[A] 11n + 7
[D] 5x – 12y
[C] 15x - 12y
[B] –8n + 7
[C] –8n2 + 7
[D] –11n+ 3
8. Solve the inequality: x + 23 < –10
[A] x < –33
[B] x > –33
[C] x < 33
[D] x < 33
9. Solve the inequality: –4x > 48
[A] x > –12
[B] x < 12
[C] x < –12
[D] x > 12
10.The length of a rectangle is 8 feet more than the width. The perimeter is 52 feet. Find the dimensions.
[A] length = 26ft, width = 9 ft
[B] length = 17ft, width = 9ft
[C] length = 17ft, width = 7ft
[D] length = 30 ft, width = 14ft
11. Simplify the expression:  4 
2
12. Simplify the expression:
13. Evaluate
3(4  2)  6
32  3
[A] 16
[B] -16
[C] 8
[D] -8
[A] 7
[B] 5
[C] 2
[D] 4
y
 z , for x = 1, y = 8, and z = 4.
2x
14. Solve for x: x 
15. Solve for x:
4 3

20 5
5
x  60
7
[A] 0
[A] x 
17
20
[A] x = 81
[B] 5
[B] x =
[C]
1
2
[B] x = 89
4
15
[C] x = 4
[D]
1
2
[C] x = 85
4
5
[D] x = 6
[D] x = 84
16. The ratio of cars to people in New Zealand is 400 to 1000. Write this ratio as a fraction in simplest
form.
3
3
4
2
[A]
[B]
[C]
[D]
5
20
10
5
Algebra 1A Revised 6/5/09
4 x

5 30
[A] 20
[A] x = 2
[B] x = –8
[C] x = –2
[D] x = 8
19. Solve for x: –4x + 9 + 3x + 12 = –4
[A] x = 12
[B] x = 25
[C] x = –12
[D] x = –25
20. Solve for x: 3(x – 5) = 6x + 9
[A] x = –8
[B] x = 7
[C] x = -7
[D] x = 8
[C] x = 9
[D] x = 10
17. Find the missing term in the proportion
18. Solve for x:
x
5  7
4
[B] 7
7
x  6  15
3
[A] x =
72
5
[B] x = 
22. Solve for x: x – 11x < 20
[A] x 
5
2
[B] x  2
21. Solve for x:
10
3
23. Which ordered pair is a solution of the equation 5x + 3y = 6?
[A] (0,2)
[B] (2,0)
[C] 19
[C] x  
1
3
[C] (2,–1)
24. Find the slope of the line passing through the points (–4, –2) and (–6, –5).
1
3
[A] –2
[B] 
[C]
2
2
25. Find the slope of the line that contains the points (–2, 5) and (5, 5)
9
7
[A]
[B]
[C] 0
7
2
26. Write the equation of the line in slope-intercept form: slope = 3 and y-intercept = –5
5
3
[A] y = –3x + 5
[B] y   x
[C] y   x
3
5
1
27. Evaluate the expression. |-7|
[A] 7
[B] -7
[C] 
7
[D] 24
[D] x  2
[D] (–1,2)
[D] –4
[D] undefined
[D] y = 3x – 5
[D]
1
7
28. Graph the linear equation by finding the x- and y-intercepts. x + y = -2
y
[A]

y
[B]

 x


29. Find f(-2) given f(x) = -3x + 2
Algebra 1A Practice Test Revised 6/5/09
y
[C]

 x


 x

[A] –25
[B] 11
y
D]



 x

[C] 7
[D] 8
2
30. Graph: x = -4
[A]
[B]
y
x
10 x
–10
–10
y
10
10
10
[D]
y
y
10
–10
[C]
10
–10
10
x
–10
–10
10 x
–10
–10
31. State whether the relation defines a function. If it does, state the domain of the function.
x
y
[A] Yes, {0, 1, 2, 3, 4}
0
4
[B] No
1
5
[C] Yes, {4, 4, 5, 6, 7}
2
6
[D] Yes, {0, 1, 2, 3, 3, 4, 4, 4, 5, 6, 7}
3
7
4
4
32. Find an equation of the line containing the points (6, -4) and (1, 6)
1
[A] y = -2x +12
[B] y   x  14
[C] y = -2x +8
[D] y  4 x  14
3
33. Write an equation in slope-intercept form of the line that passes through the point (1, 2) and has
the slope -4.
[A] y = 3x - 4
[B] y = 4x + 6
[C] y = -3x -4
[D] y = -4x + 6
34. Write the slope-intercept form of the equation of the line passing through the point (-1, 6) and
parallel to the line y = -3x - 4
[A] y = -3x + 3
[B] y = -3x - 9
[C] y = 3x - 3 [D] y = 3x - 9
35. Write an equation of the graph in slope-intercept form.
y
[A] y =
10
1
x7
2
[B] y = 2 x  7
10 x
–10
–10
Algebra 1A Practice Test Revised 6/5/09
[C] y = 
1
x7
2
[D] y = 2 x  7
3
36. Graph: x ≥ -3
[A]
–10
–5
0
5
10
[C]
–10
–5
0
5
10
[B]
–10
–5
0
5
10
[D]
–10
–5
0
5
10
37. Select the appropriate graph of the solution of the inequality. 7x + 5 ≥ 5(x + 2)
[A]
–10
–5
0
5
10
[C]
–10
–5
0
5
10
[B]
–10
–5
0
5
10
[D]
–10
–5
0
5
10
–3  –2x + 9  5
38. Solve the inequality.
[A] 2  x  6
[B] -2  x  6
[C] 6  x  2
[D] -2  x  -6
39. Graph: -5 < x ≤ 3
[A]
[B]
–10
–5
0
5
10
–10
–5
0
5
10
[C]
–10
–5
0
5
10
–10
–5
0
5
10
–10
–5
0
5
10
–10
–5
0
5
10
[D]
40. Graph: x – 2 ≤ -7 or x ≥ 1
[A]
[B]
–10
–5
0
5
10
–10
–5
0
5
10
[C]
[D]
41. Solve the absolute-value equation.
[A] -7, -3
x2 5
[B] 7
43. Graph:
[A]
[D] -3
x2 4
42. Solve the absolute-value inequality.
[A] x  –6 or x  –2
[C] 7, -3
[B] –6  x  2
[C] x < –6 or x > –2
[D] –6 < x < 2
x2 5
–10
–5
0
5
10
[C]
[B]
–10
–5
0
5
10
–10
–5
0
5
10
[D]
–10
–5
Algebra 1A Practice Test Revised 6/5/09
0
5
10
4
44. Choose the graph that shows the solution to the inequality. y ≥ 2x + 3
[A]
[B]
y
[C]
y
y



x 


y


 x 

[D]
 x 
 x


45. Use substitution to solve the linear system. y = 3x + 4
y = 2x
[A] (–3, –5)
46. Solve by linear combinations.
[C] (1, 5)
[D] (4, 8)
5x - 6y = 2
3x + 6y = –10
[A] (1, 3)
47. Solve by linear combinations.
[B] (-4, -8)
7

[B]   1,  [C] (19, 3)
6

[D] no solution
x - 2y = 5
3x - 5y = 8
[A] (–9, –7)
[B] (0, –6 )
[C] (–30, –2) [D] no solution
48. Determine if the system has no solutions, one solution, or many solutions.
2x + 3y = 13
4x + 6y = 26
[A] one solution (2, –3) [B] one solution (2, 3)
[C] many solutions [D] no solution
49. Dr. Math bought 5 tickets to a puppet show and spent $30. He bought a combination of child tickets
for $2 each and adult tickets for $3 each. Which system of equations will determine the number of
adult tickets, a, and the number of child tickets, c, he bought?
[A] 2a + 2c = 30
[B] 2a + 3c = 30 [C] 3a + 2c = 30
[D] 3a + 2c = 30
a+c=5
a+c=5
a–c=5
a+c=5
50. Evaluate the expression.  16
51. Find the sum in simplest form.
Algebra 1A Practice Test Revised 6/5/09
3x 5

2 2
[A] -4
[A]
[B] 4
3x  5
8
[B]
15x
4
[C] – 2
[C]
3x  5
2
[D] 2
[D]
3x  5
4
5
52. Write an equation of the graph in slope-intercept form.
y
[A] y = – 5x + 6
10
[C] y =
[B] y = 5x + 6
1
x+6
5
1
[D] y =  x + 6
5
10 x
–10
–10
53. Solve for x: 2 x  5  7
[A] -6 ≤ x ≤ 1 [B] x < -6 or x > 1
54. Graph:
x2 2
[A]
–10
[B]
–5
0
5
10
[C]
–10
[D] -6 ≥ x ≥ 1
[C] x > -6 or x < 1
–10
–5
0
5
10
–5
0
5
10
[D]
–5
0
5
10
–10
55.
Algebra 1A Practice Test Revised 6/5/09
6
Algebra 1A Practice Test
1. A
1.0
29. D
6.0
2. D
2.0
30. C
6.0
3. B
1.0
31. A
16.0
4. D
7th MG 3.2
32. C
6.0
5. B
1.1
33. D
6.0
6. C
1.0
34. A
6.0
7. D
1.0
35. D
6.0
8. A
4.0
36. C
5.0
9. C
4.0
37. B
5.0
10. B
1.0
38. A
5.0
11. A
2.0
39. B
5.0
12. C
1.0
40. B
5.0
13. A
1.0
41. C
3.0
14. D
4.0
42. D
3.0
15. D
4.0
43. D
3.0
16. B
1.0
44. D
6.0
17. D
4.0
45. B
9.0
18. B
4.0
46. B
9.0
19. D
4.0
47. A
9.0
20. A
4.0
48. C
9.0
21. C
4.0
49. D
9.0
22. B
4.0
50. A
2.0
23. A
6.0
51. C
13.0
24. C
6.0
52. C
6.0
25. C
6.0
53. A
3.0
26. D
6.0
54. B
3.0
27. A
3.0
55. A
9.0
28. A
6.0
Algebra 1A Practice Test Revised 6/5/09
7