REMINDERS • HW#11 posted. Try these method of sections problems by Thursday’s class • Read section 6.6 Frames and Machines • Frames this Thursday • Machines next Tuesday (along w/ quiz #6) REMAINING SCHEDULE • Finish chapter six by Nov 10 • Review session in class Nov 12 • Test #3 Monday Nov 16, 6 – 8 pm Ball Hall 210 • Chapters 5 & 6 • Nov 17: 7.1 Internal Forces • Nov 19: 8.1 & 8.2 Dry Friction • Nov 24: 9.1 Centers of Gravity, Mass, Centroids • Dec 1: 9.2 Composite Bodies • Dec 3: 10 Moments of Inertia • Dec 8: Final Exam Review • Dec 15: Final exam scheduled for 3 – 6 pm AGENDA • Quiz #5 • Finish 6.4 Method of Sections • Section 6.6 Frames--maybe QUIZ #5 Please take everything off your desk except a pencil and calculator. BACK TO METHOD OF SECTIONS, LESSON 16 FRAMES Today’s Objectives: Students will be able to: a) Draw the free body diagram of a frame and its members. b) Determine the forces acting at the joints and supports of a frame READING QUIZ 1. Frames and machines are different as compared to trusses since they have ___________. A) Only two-force members B) Only multiforce members C) At least one multiforce member D) At least one two-force member 2. Forces common to any two contacting members act with _______ on the other member. A) Equal magnitudes but opposite sense B) Equal magnitudes and the same sense C) Different magnitudes and the opposite sense D) Different magnitudes and the same sense APPLICATIONS Frames are commonly used to support various external loads. How is a frame different than a truss? To be able to design a frame, you need to determine the forces at the joints and supports. APPLICATIONS (continued) “Machines,” like those above, are used in a variety of applications. How are they different from trusses and frames? You must determine the loads at the joints and supports. These forces and moments are required when designing the machine’s members. FRAMES AND MACHINES: DEFINITIONS Frame Machine Frames and machines are composed of pin-connected members, that have at least one multi-force member. (Recall that trusses have nothing but two-force members). Frames are generally stationary and support external loads. Machines contain moving parts and are designed to alter the effect of forces. STEPS FOR ANALYZING A FRAME OR MACHINE 1. Draw a FBD of the frame or machine and its members, as necessary. Hints: a) Identify any two-force members, b) Note that forces on contacting surfaces (usually between a pin and a member) are equal and opposite, and, FAB c) For a joint with more than two members or an external force, it is advisable to draw a FBD of the pin. STEPS FOR ANALYZING A FRAME OR MACHINE 2. Develop a strategy to apply the equations of equilibrium to solve for the unknowns. Look for ways to form single equations and single unknowns. 3. Use the E of E to solve for the unknown forces Problems are going to be challenging since there are usually several unknowns. A lot of practice is needed to develop good strategies and ease of solving these problems. FAB EXAMPLES To the overhead projector… EXAMPLE Given: The frame supports an external load and moment as shown. Find: The horizontal and vertical components of the pin reactions at C and the magnitude of reaction at B. Plan: a) Draw FBDs of the frame member BC. Why pick this part of the frame? b) Apply the equations of equilibrium and solve for the unknowns at C and B. EXAMPLE (continued) 800 N m 400 N CX CY 1m 1m 2m B 45° FBD of member BC FAB Please note that member AB is a two-force member. Equations of Equilibrium: Start with ∑ MC since it yields one unknown. + ∑ MC = FAB cos 45° (1) – FAB sin 45° (3) + 800 N m + 400 (2) = 0 FAB = 1131 N EXAMPLE (continued) 800 N m 400 N CX CY 1m 1m 2m B 45° FBD of member BC FAB Now use the x and y-direction Equations of Equilibrium: → + ∑ FX = – CX + 1131 cos 45° = 0 CX = 800 N ↑ + ∑ FY = – CY + 1131 sin 45° – 400 = 0 CY = 400 N CONCEPT QUIZ 1. The figures show a frame and its FBDs. If an additional couple moment is applied at C, how will you change the FBD of member BC at B? A) B) C) D) No change, still just one force (FAB) at B. Will have two forces, BX and BY, at B. Will have two forces and a moment at B. Will add one moment at B. GROUP PROBLEM SOLVING Given: A frame supports a 50 lb load as shown. Find: The reactions exerted by the pins on the frame members at B and C. Plan: a) Draw a FBD of member BC and another one for AC. b) Apply the equations of equilibrium to each FBD to solve for the four unknowns. Think about a strategy to easily solve for the unknowns. GROUP PROBLEM SOLVING (continued) CY FBDs of members BC and AC CX 50 lb 3.5 ft 6 ft 8 ft AX Note how forces at “C” are shown in opposite directions in the 2 diagrams AY Applying E-of-E to member AC: +∑ MA = – CY (8) + CX (6) + 50 (3.5) = 0 CX = [CY(8) - 50 (3.5)]/6 GROUP PROBLEM SOLVING (continued) FBDs of members BC and AC CY CX 50 lb 3.5 ft 6 ft 8 ft AX Applying E-of-E to member BC: + ∑ MB = – 50 (2) – 50 (3.5) + CY (8) = 0 ; AY CY = 34.38 = 34.4 lb; You can use previous eq. to find CX: CX= [CY(8) - 50 (3.5)]/6 ; CX = 16.67 = 16.7 lb → + ∑ FX = 16.67 + 50 – BX = 0 ; BX = 66.7 lb ↑+ ∑ FY = BY – 50 + 34.38 = 0 ; BY = 15.6 lb