Angular Momentum Module 1, Lecture 4 • Objects rotating about a fixed axis Angular Momentum Vector Cross Product L = Iω • Can relate to Newton’s second law ∑τ = Quick Review: • How did we calculate momentum? • Conservation of momentum • Was momentum a vector or a scalar? • Total angular momentum remains __________ if net external torque acting on system is ______. • When did Conservation of Momentum apply? EF 152 Fall, 2008 Lecture 1-4 dL dt 1 EF 152 Fall, 2008 Lecture 1-4 Example: Clutch Example: Circular platform, part I Given: In a clutch, a disc with I = 1.2 kg-m2 is brought into contact with a spinning flywheel having I = 1.8 kg-m2 Hurricane Katrina and ω = 72 rad/s. Required: Angular velocity after the disc is moving with the flywheel. Given: A 60 kg person stands at the edge of a 6.0 m diameter circular platform with I = 1800 kg-m2 that is initially at rest. Hurricane Katrina Required: Angular velocity of the platform if person runs at: a. 4.2 m/s with respect to the earth b. 4.2 m/s with respect to the platform A. B. C. D. 2 28.8 rad/s 43.2 rad/s 72.0 rad/s 108 rad/s EF 152 Fall, 2008 Lecture 1-4 3 EF 152 Fall, 2008 Lecture 1-4 4 Example: Circular platform, part II R = P ×Q Vector Cross-Product You are standing at the edge of a rotating circular platform. You walk towards the center. What happens? Hurricane Katrina a. platform slows down b. platform speeds up c. rotation speed is unchanged Magnitude R Direction: ___________ to plane containing P and Q; determined using ______________ rule Hurricane Katrina Q P Not commutative: Q× P ≠ P ×Q EF 152 Fall, 2008 Lecture 1-4 5 Vector Cross Product: Applications EF 152 Fall, 2008 Lecture 1-4 6 Vector Cross Product: Basic Cases • General 3-dimensional motion a = α × r + ω × (ω × r ) v= P θ =0 o • Torque Q τ = θ = 90o • Angular momentum P P ×Q = P ×Q = Q • General definition of angular momentum of a particle about a point O is: L= iˆ × iˆ = ˆj × kˆ = iˆ × ˆj = ˆj × iˆ = ^ k ^ i EF 152 Fall, 2008 Lecture 1-4 7 EF 152 Fall, 2008 Lecture 1-4 ^ j 8 Vector Cross Product: General Solution iˆ px ˆj py kˆ pz qx qy qz EF 152 Fall, 2008 Lecture 1-4 P ×Q Torque (Moment): Definition, units, direction Handle: Force: (3iˆ − 1 ˆj + 1kˆ) ft (− 12iˆ + 7 ˆj + 18kˆ)lb Determine torque about origin 9 z EF 152 Fall, 2008 Lecture 1-4 F x y 10