Wire lengths of AC and DC discrete signals on field side of I/O modules. Purpose To explain what determines the length of wire that can be used on the field side of I/O modules. Question How long can the wire be from an I/O module to a field device? Why doesn’t Modicon specify that length of wire? Units affected All discrete I/O modules for Modicon’s 200,500,800 series I/O platforms as well as Quantum’s I/O. IR drop How does IR drop affect the length of wiring? IR drop is the product of the resistance of the wire (depends on wire gauge size) and the current drawn by the load. (IR = volts) After calculating the IR drop of the field wire what you have left is available at the module input. IR drop calculation example Here is an example of calculating the IR drop to see if enough is left over to turn on an I/O module/s input point. Assume a B805 which needs 80 VAC min turn on volts and assume a field source of 120 VAC. The current drawn by the B805 is 6ma. Consult the vendor of the wire to get the resistance of the wire (usually as ohms per 1000 feet and this depends on gauge and length of wire. In this example assume the total resistance of the wire length is 1000 ohms. .006 (ma) X 1000 (ohms res of the field wire) = 6 (VAC) 120 VAC minus 6 VAC = 114 VAC (plenty left over to turn on B805 inputs as minimum needed is 80 VAC.) Additional precautions The IR drop can only be a rough estimate along with empirical testing to fine tune the wiring length. Neither Modicon nor any one else can declare what the length of wiring can be due to the following unknown variables. Shielded verses non-shielded wire. Single verses wiring pairs. Wire impedance. Electrical noise. Routing of wiring such as running in parallel with hi voltage that can induce capacitive and inductive coupling of noise spikes.