360040_0001.qxd 1/3/05 0-2 11:16 AM A Precalculus Review CHAPTER 0 0.1 Page 0-2 THE REAL NUMBER LINE AND ORDER ■ ■ ■ ■ Represent, classify, and order real numbers. Use inequalities to represent sets of real numbers. Solve inequalities. Use inequalities to model and solve real-life problems. The Real Number Line Negative direction (x decreases) Positive direction (x increases) x −4 −3 −2 −1 FIGURE 0.1 0 1 2 3 4 The Real Number Line 5 4 −2.6 x −3 −2 −1 0 1 2 3 Every point on the real number line corresponds to one and only one real number. 7 −3 1.85 2.6 13 5 7 3 x −3 −2 −1 0 1 2 3 Every real number corresponds to one and only one point on the real number line. e π x −1 0 FIGURE 0.3 1 2 3 5 4 37 1.85 20 Such numbers are called rational. Rational numbers have either terminating or infinitely repeating decimal representations. Terminating Decimals 2 0.4 5 7 0.875 8 FIGURE 0.2 2 Real numbers can be represented with a coordinate system called the real number line (or x-axis), as shown in Figure 0.1. The positive direction (to the right) is denoted by an arrowhead and indicates the direction of increasing values of x. The real number corresponding to a particular point on the real number line is called the coordinate of the point. As shown in Figure 0.1, it is customary to label those points whose coordinates are integers. The point on the real number line corresponding to zero is called the origin. Numbers to the right of the origin are positive, and numbers to the left of the origin are negative. The term nonnegative describes a number that is either positive or zero. The importance of the real number line is that it provides you with a conceptually perfect picture of the real numbers. That is, each point on the real number line corresponds to one and only one real number, and each real number corresponds to one and only one point on the real number line. This type of relationship is called a one-to-one correspondence and is illustrated in Figure 0.2. Each of the four points in Figure 0.2 corresponds to a real number that can be expressed as the ratio of two integers. Infinitely Repeating Decimals 1 0.333 . . . 0.3* 3 12 1.714285714285 . . . 1.714285 7 Real numbers that are not rational are called irrational, and they cannot be represented as the ratio of two integers (or as terminating or infinitely repeating decimals). So, a decimal approximation is used to represent an irrational number. Some irrational numbers occur so frequently in applications that mathematicians have invented special symbols to represent them. For example, the symbols 2, , and e represent irrational numbers whose decimal approximations are as shown. (See Figure 0.3.) 2 1.4142135623 3.1415926535 e 2.7182818284 *The bar indicates which digit or digits repeat infinitely. 360040_0001.qxd 1/3/05 11:16 AM Page 0-3 SECTION 0.1 0-3 The Real Number Line and Order Order and Intervals on the Real Number Line One important property of the real numbers is that they are ordered: 0 is less than 1, 3 is less than 2.5, is less than 22 7 , and so on. You can visualize this property on the real number line by observing that a is less than b if and only if a lies to the left of b on the real number line. Symbolically, “a is less than b” is denoted by the inequality a < b. For example, the inequality 43 < 1 follows from the fact that 34 lies to the left of 1 on the real number line, as shown in Figure 0.4. 3 4 lies to the left of 1, so 3 4 −1 0 3 4 < 1. 1 x 1 2 FIGURE 0.4 When three real numbers a, x, and b are ordered such that a < x and x < b, we say that x is between a and b and write a < x < b. x is between a and b. The set of all real numbers between a and b is called the open interval between a and b and is denoted by a, b. An interval of the form a, b does not contain the “endpoints” a and b. Intervals that include their endpoints are called closed and are denoted by a, b. Intervals of the form a, b and a, b are neither open nor closed. Figure 0.5 shows the nine types of intervals on the real number line. Intervals that are neither open nor closed Open interval (− ∞, a) (a, b] (a, b) a b a b a<x≤b a<x<b Infinite intervals a (b, ∞) a b x>b (− ∞, a] [b, ∞) [a, b) Closed interval a [a, b] a b a b x≤a (− ∞, ∞) b a≤x≤b STUDY Intervals on the Real Number Line TIP Note that a square bracket is used to denote “less than or equal to” ≤ or “greater than or equal to” ≥. Furthermore, the symbols and denote positive and negative infinity. These symbols do not denote real numbers; they merely let you describe unbounded conditions more concisely. For instance, the interval b, is unbounded to the right because it includes all real numbers that are greater than or equal to b. b x≥b a≤x<b a FIGURE 0.5 b x<a a b 360040_0001.qxd 1/3/05 0-4 11:16 AM Page 0-4 A Precalculus Review CHAPTER 0 Solving Inequalities STUDY TIP Notice the differences between Properties 3 and 4. For example, 3 < 4 ⇒ 32 < 42 and In calculus, you are frequently required to “solve inequalities” involving variable expressions such as 3x 4 < 5. The number a is a solution of an inequality if the inequality is true when a is substituted for x. The set of all values of x that satisfy an equality is called the solution set of the inequality. The following properties are useful for solving inequalities. (Similar properties are obtained if < is replaced by ≤ and > is replaced by ≥.) 3 < 4 ⇒ 32 > 42. Properties of Inequalities Let a, b, c, and d be real numbers. 1. Transitive property: a < b and b < c ALGEBRA a < c ac < bd 2. Adding inequalities: a < b and c < d REVIEW Once you have solved an inequality, it is a good idea to check some x-values in your solution set to see whether they satisfy the original inequality. You might also check some values outside your solution set to verify that they do not satisfy the inequality. For example, Figure 0.6 shows that when x 0 or x 2 the inequality is satisfied, but when x 4 the inequality is not satisfied. 3. Multiplying by a (positive) constant: a < b ac < bc, c > 0 4. Multiplying by a (negative) constant: a < b ac > bc, c < 0 5. Adding a constant: a < b 6. Subtracting a constant: a < b ac < bc ac < bc Note that you reverse the inequality when you multiply by a negative number. For example, if x < 3, then 4x > 12. This principle also applies to division by a negative number. So, if 2x > 4, then x < 2. EXAMPLE 1 Solving an Inequality Find the solution set of the inequality 3x 4 < 5. SOLUTION For x = 0, 3(0) − 4 = − 4. For x = 2, 3(2) − 4 = 2. For x = 4, 3(4) − 4 = 8. x −1 0 1 2 Solution set for 3x − 4 < 5 FIGURE 0.6 3 4 5 6 7 8 3x 4 3x 4 4 3x 1 3x 3 x < 5 Write original inequality. < 54 Add 4 to each side. < 9 Simplify. 1 < 9 3 < 3 1 Multiply each side by 3 . Simplify. So, the solution set is the interval , 3, as shown in Figure 0.6. TRY IT 1 Find the solution set of the inequality 2x 3 < 7. In Example 1, all five inequalities listed as steps in the solution have the same solution set, and they are called equivalent inequalities. 360040_0001.qxd 1/3/05 11:16 AM Page 0-5 SECTION 0.1 0-5 The Real Number Line and Order The inequality in Example 1 involves a first-degree polynomial. To solve inequalities involving polynomials of higher degree, you can use the fact that a polynomial can change signs only at its real zeros (the real numbers that make the polynomial zero). Between two consecutive real zeros, a polynomial must be entirely positive or entirely negative. This means that when the real zeros of a polynomial are put in order, they divide the real number line into test intervals in which the polynomial has no sign changes. That is, if a polynomial has the factored form x r1x r2, . . . , x rn , r1 < r2 < r3 < . . . < rn then the test intervals are , r1, r1, r2, . . . , rn1, rn , and rn, . For example, the polynomial x2 x 6 x 3x 2 can change signs only at x 2 and x 3. To determine the sign of the polynomial in the intervals , 2, 2, 3, and 3, , you need to test only one value from each interval. EXAMPLE 2 Solving a Polynomial Inequality Find the solution set of the inequality x2 < x 6. SOLUTION x2 < x 6 2 x x6 < 0 x 3x 2 < 0 2 < x < 3, x Sign < 0? 3 No Write original inequality. 2 0 No Polynomial form 1 Yes 0 Yes 1 Yes 2 Yes 3 0 No 4 No Factor. So, the polynomial x2 x 6 has x 2 and x 3 as its zeros. You can solve the inequality by testing the sign of the polynomial in each of the following intervals. x < 2, Sign of x 3x 2 x > 3 To test an interval, choose a representative number in the interval and compute the sign of each factor. For example, for any x < 2, both of the factors x 3 and x 2 are negative. Consequently, the product (of two negative numbers) is positive, and the inequality is not satisfied in the interval x < 2. x A convenient testing format is shown in Figure 0.7. Because the inequality is satisfied only by the center test interval, you can conclude that the solution set is given by the interval 2 < x < 3. TRY IT Solution set 2 Find the solution set of the inequality x2 > 3x 10. −2 No (−)(−) > 0 FIGURE 0.7 3 Yes No (−)(+) < 0 (+)(+) > 0 Is x 3x 2 < 0? 360040_0001.qxd 0-6 1/3/05 11:16 AM CHAPTER 0 Page 0-6 A Precalculus Review Application Inequalities are frequently used to describe conditions that occur in business and science. For instance, the inequality 144 ≤ W ≤ 180 describes the recommended weight W for a man whose height is 5 feet 10 inches. Example 3 shows how an inequality can be used to describe the production level of a manufacturing plant. EXAMPLE 3 Production Levels In addition to fixed overhead costs of $500 per day, the cost of producing x units of an item is $2.50 per unit. During the month of August, the total cost of production varied from a high of $1325 to a low of $1200 per day. Find the high and low production levels during the month. SOLUTION Because it costs $2.50 to produce one unit, it costs 2.5x to produce x units. Furthermore, because the fixed cost per day is $500, the total daily cost of producing x units is C 2.5x 500. Now, because the cost ranged from $1200 to $1325, you can write the following. 1200 1200 500 700 700 2.5 280 2.5x 500 ≤ 2.5x 500 500 ≤ 2.5x 2.5x ≤ 2.5 ≤ ≤ x ≤ 1325 Write original inequality. ≤ 1325 500 Subtract 500 from each side. ≤ 825 825 ≤ 2.5 ≤ 330 Simplify. Divide each side by 2.5. Simplify. So, the daily production levels during the month of August varied from a low of 280 units to a high of 330 units, as shown in Figure 0.8. Each day’s production during the month fell in this interval. Low daily production 280 High daily production 330 x 0 100 200 300 400 500 FIGURE 0.8 TRY IT 3 Use the information in Example 3 to find the high and low production levels if, during October, the total cost of production varied from a high of $1500 to a low of $1000 per day. 360040_0001.qxd 1/3/05 11:16 AM Page 0-7 The Real Number Line and Order SECTION 0.1 E X E R C I S E S 0 . 1 In Exercises 1–10, determine whether the real number is rational or irrational. 2. 3678 *1. 0.7 3 3. 2 4. 32 1 5. 4.3451 6. 3 64 7. 8. 0.8177 3 60 9. 22 7 10. 2e In Exercises 11–14, determine whether each given value of x satisfies the inequality. 11. 5x 12 > 0 (a) x 3 (c) x 12. x 1 < 5 2 (b) x 3 3 (d) x 2 2x 3 (b) x 4 (c) x 4 (d) x 3 30. Physiology The maximum heart rate of a person in normal health is related to the person’s age by the equation r 220 A where r is the maximum heart rate in beats per minute and A is the person’s age in years. Some physiologists recommend that during physical activity a person should strive to increase his or her heart rate to at least 60% of the maximum heart rate for sedentary people and at most 90% of the maximum heart rate for highly fit people. Express as an interval the range of the target heart rate for a 20-year-old. The revenue for selling x units of a product is R 115.95x and the cost of producing x units is x2 < 2 4 C 95x 750. (a) x 4 (b) x 10 (c) x 0 7 (d) x 2 14. 1 < 29. Biology: pH Values The pH scale measures the concentration of hydrogen ions in a solution. Strong acids produce low pH values, while strong bases produce high pH values. Represent the following approximate pH values on a real number line: hydrochloric acid, 0.0; lemon juice, 2.0; oven cleaner, 13.0; baking soda, 9.0; pure water, 7.0; black coffee, 5.0. (Source: Adapted from Levine/Miller, Biology: Discovering Life, Second Edition) 31. Profit (a) x 0 13. 0 < 0-7 To obtain a profit, the revenue must be greater than the cost. For what values of x will this product return a profit? 32. Sales A doughnut shop at a shopping mall sells a dozen doughnuts for $3.50. Beyond the fixed cost (for rent, utilities, and insurance) of $170 per day, it costs $1.75 for enough materials (flour, sugar, etc.) and labor to produce each dozen doughnuts. If the daily profit varies between $40 and $250, between what levels (in dozens) do the daily sales vary? 3x ≤ 1 2 (a) x 0 (b) x 5 (c) x 1 (d) x 5 In Exercises 15–28, solve the inequality and sketch the graph of the solution on the real number line. 33. Reimbursement A pharmaceutical company reimburses their sales representatives $0.35 per mile driven and $100 for meals per week. The company allocates from $200 to $250 per sales representative each week. What are the minimum and maximum numbers of miles the company expects each representative to drive each week? 15. x 5 ≥ 7 16. 2x > 3 17. 4x 1 < 2x 18. 2x 7 < 3 19. 4 2x < 3x 1 20. x 4 ≤ 2x 1 21. 4 < 2x 3 < 4 22. 0 ≤ x 3 < 5 3 1 23. > x 1 > 4 4 x 24. 1 < < 1 3 34. Area A square region is to have an area of at least 500 square meters. What must the length of the sides of the region be? x x > 5 2 3 In Exercises 35 and 36, determine whether each statement is true or false, given a < b. 25. x x > 5 2 3 27. 2x 2 x < 6 26. 28. 2x2 1 < 9x 3 * The answers to the odd-numbered and selected even exercises are given in the back of the text. Worked-out solutions to the oddnumbered exercises are given in the Student Solutions Guide. 35. (a) 2a < 2b 36. (a) a 4 < b 4 (b) a 2 < b 2 (b) 4 a < 4 b (c) 6a < 6b (c) 3b < 3a (d) 1 1 < a b (d) a b < 4 4